How convert URL building code from Objective-C to Swift? [duplicate] - objective-c

Question

This question already has answers here:
Swift - encode URL
(19 answers)
Closed 3 years ago.
I have Objective-C code to build a URL. How to write in Swift 3 code?
NSString *urlString = [[NSString alloc]initWithFormat:#"http://smartbaba.in/Familynk/api/registration.php?phone_no=%#&email=%#&password=%#&first_name=%#&last_name=%#",txtmobileno.text,txtemail.text,txtpassword.text,txtfirstname.text,txtlastname.text];

Answer 1

Try This
"http://smartbaba.in/Familynk/api/registration.php?phone_no=\(txtmobileno.text)&email=\(txtemail.text)&password=\(txtpassword.text)&first_name=\(txtfirstname.text)&last_name=\(txtlastname.text)"

Answer 2

Swift conversion can be something like this
// I thing code requires no explanation, its self explanatory
func makeUrl(phoneNo: String, email: String, password: String, firstName: String, lastName: String) {
// first way but not recomended
let urlString = "http://smartbaba.in/Familynk/api/registration.php?phone_no=\(phoneNo)&email=\(email)&password=\(password)&first_name=\(firstName)&last_name=\(lastName)"
print("\(urlString)")
// second way, ASAIK this is good way for constructing URL's
var components = URLComponents()
components.scheme = "http"
components.host = "smartbaba.in"
components.path = "/Familynk/api/registration.php"
components.queryItems = [
URLQueryItem(name: "phone_no", value: phoneNo),
URLQueryItem(name: "email", value: email),
URLQueryItem(name: "password", value: password),
URLQueryItem(name: "first_name", value: firstName),
URLQueryItem(name: "last_name", value: lastName)
]
let url = components.url
print(url) // returns URL
print(url?.absoluteString) // returns url path in string
}
// call function
makeUrl(phoneNo: "12345", email: "test#gmail.com", password: "12345678", firstName: "test", lastName: "user")

Answer 3

You can simply use String interpolation to create a String with multiple parameters like,
let urlString = "http://smartbaba.in/Familynk/api/registration.php?phone_no=\(txtmobileno.text)&email=\(txtemail.text)&password=\(txtpassword.text)&first_name=\(txtfirstname.text)&last_name=\(txtlastname.text)"
Now, to get the URL using urlString,
if let url = URL(string: urlString) {
//use url here...
}

Answer 4

post method using URLSession:
let myUrl = URL(string: "http://smartbaba.in/Familynk/api/registration.php");
var request = URLRequest(url:myUrl!)
request.httpMethod = "POST"
let postString = "firstName=James&lastName=Bond";
request.httpBody = postString.data(using: String.Encoding.utf8);
let task = URLSession.shared.dataTask(with: request) { (data: Data?, response: URLResponse?, error: Error?) in
if error != nil
{
print("error=\(error)")
return
}
// You can print out response object
print("response = \(response)")
do {
let json = try JSONSerialization.jsonObject(with: data!, options: .mutableContainers) as? NSDictionary
if let parseJSON = json {
print(parseJSON)
}
} catch {
print(error)
}
}
task.resume()
If you are using Alamofire then,
let parameters: Parameters = [
"Subject": "hallo"
]
let url = "http://mydomain/mydb/mydb_tesT.NSF/api/data/documents/unid/DD026770D91AA23DC1257EF90035E1C4"
Alamofire.request(url, method:.post, parameters:parameters, headers:headers).responseJSON { response in
switch response.result {
case .success:
debugPrint(response)
case .failure(let error):
print(error)
}
}