Converting decimals to [h]:mm in sql query - sql

I need a requirement to convert decimal value to time in sql query like if input is 12.5 it should return 12h 30m, if input is 8.70 it should return 8h 42m.


You could use Oracle's numtodsinterval function to achieve this.
select numtodsinterval(to_number('12.5'), 'hour') from dual;
Returns 0 12:30:0.0
select numtodsinterval(to_number('8.70'), 'hour') from dual;
Returns 0 8:42:0.0


Maintain such conversation into a intermediate table and keep mapping to transform
Create a SP to convert and done


If the format literally needs to be like "12h 30m" and "8h 42m", then the following could work:
WITH sample_data AS
(
SELECT NUMTODSINTERVAL(to_number('12.5'), 'HOUR') ds_interval FROM dual UNION ALL
SELECT NUMTODSINTERVAL(to_number('8.70'), 'HOUR') ds_interval FROM dual UNION ALL
SELECT NUMTODSINTERVAL(to_number('122.25'), 'HOUR') ds_interval FROM dual
)
SELECT ( (EXTRACT(DAY FROM sample_data.ds_interval) * 24) +
EXTRACT(HOUR FROM sample_data.ds_interval) ) || 'h ' ||
EXTRACT(MINUTE FROM sample_data.ds_interval) || 'm ' output
FROM sample_data;
OUTPUT
--------
12h 30m
8h 42m
122h 15m
The format could be expanded to convert hours to days when # of hours >= 24:
WITH sample_data AS
(
SELECT NUMTODSINTERVAL(to_number('122.25'), 'HOUR') ds_interval FROM dual
)
SELECT EXTRACT(DAY FROM sample_data.ds_interval) || 'd ' ||
EXTRACT(HOUR FROM sample_data.ds_interval) || 'h ' ||
EXTRACT(MINUTE FROM sample_data.ds_interval) || 'm '
FROM sample_data;
OUTPUT
---------
5d 2h 15m

Related

how to sum up minutes and seconds ?in oracle

I have a column called duration_d which is varchar2 and the data in that table looks like below
duration_d
-----------
12:25
01:35
12:10
04:21
12:18
12:24
I tried below query
SELECT SUM( to_date( duration_d, 'mi:ss' ))
FROM table
GROUP BY calling_number;
When I execute it following error is coming
ORA-00933: SQL command not properly ended
00933. 00000 - "SQL command not properly ended"
can any one tell me how to make sum it?

To get the total as fractions of a day you can use:
SELECT SUM( TO_DATE( duration_d, 'MI:SS' ) - TO_DATE( '00:00', 'MI:SS' ) ) AS total
FROM your_table
Which gives the result:
TOTAL
------------------------------------------
0.0383449074074074074074074074074074074074
To convert this to an interval data type you can use NUMTODSINTERVAL:
SELECT NUMTODSINTERVAL(
SUM( TO_DATE( duration_d, 'MI:SS' ) - TO_DATE( '00:00', 'MI:SS' ) ),
'DAY'
) AS total
FROM your_table
Which gives the result:
TOTAL
-------------------
+00 00:55:13.000000

Please try below:
with x as
(select sum((regexp_substr(YOUR_COLUMN, '[0-9]+', 1, 1)*60) +
regexp_substr(id, '[0-9]+', 1, 2)) seconds
from YOUR_TABLE)
SELECT
TO_CHAR(TRUNC(seconds/3600),'FM9900') || ':' ||
TO_CHAR(TRUNC(MOD(seconds,3600)/60),'FM00') || ':' ||
TO_CHAR(MOD(seconds,60),'FM00')
FROM x
Will work only if the duration is always [MI:SS].
Also you can add the group by as per your requirement.
Converting Seconds to the required duration format Reference.
Group By
with x as
(select calling_number,sum((regexp_substr(YOUR_COLUMN, '[0-9]+', 1, 1)*60) +
regexp_substr(id, '[0-9]+', 1, 2)) seconds
from YOUR_TABLE
group by calling_number)
SELECT calling_number,
TO_CHAR(TRUNC(seconds/3600),'FM9900') || ':' ||
TO_CHAR(TRUNC(MOD(seconds,3600)/60),'FM00') || ':' ||
TO_CHAR(MOD(seconds,60),'FM00')
FROM x

Use a combination of SUBSTR, to_char, to_date, NVL, INSTR, reverse and SUM.
SELECT "calling_number",
to_char(to_date(SUM(NVL(SUBSTR("duration_d", 0, INSTR("duration_d", ':')-1), "duration_d"))*60 +
SUM(substr("duration_d", - instr(reverse("duration_d"), ':') + 1)),'sssss'),'hh24:mi:ss') AS SUM_DURATION_D
FROM yourtable
GROUP BY "calling_number"
Output
calling_number SUM_DURATION_D
1 00:26:10
2 00:29:03
SQL Fiddle: http://sqlfiddle.com/#!4/9b0a81/33/0

Correct spelling as below
SELECT SUM( TO_DATE( duration_d, 'mi:ss' ) )
FROM YOURTABLE Group By calling_number

SQL filter query output based on difference of two timestamp field [duplicate]

I have a table as follows:
Filename - varchar
Creation Date - Date format dd/mm/yyyy hh24:mi:ss
Oldest cdr date - Date format dd/mm/yyyy hh24:mi:ss
How can I calcuate the difference in hours minutes and seconds (and possibly days) between the two dates in Oracle SQL?
Thanks

You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on.
SQL> select oldest - creation from my_table;
If your date is stored as character data, you have to convert it to a date type first.
SQL> select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi')
- to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours
from dual;
DIFF_HOURS
----------
2.5
Note:
This answer applies to dates represented by the Oracle data type DATE.
Oracle also has a data type TIMESTAMP, which can also represent a date (with time). If you subtract TIMESTAMP values, you get an INTERVAL; to extract numeric values, use the EXTRACT function.

To get result in seconds:
select (END_DT - START_DT)*60*60*24 from MY_TABLE;
Check [https://community.oracle.com/thread/2145099?tstart=0][1]

select
extract( day from diff ) Days,
extract( hour from diff ) Hours,
extract( minute from diff ) Minutes
from (
select (CAST(creationdate as timestamp) - CAST(oldcreationdate as timestamp)) diff
from [TableName]
);
This will give you three columns as Days, Hours and Minutes.

declare
strTime1 varchar2(50) := '02/08/2013 01:09:42 PM';
strTime2 varchar2(50) := '02/08/2013 11:09:00 PM';
v_date1 date := to_date(strTime1,'DD/MM/YYYY HH:MI:SS PM');
v_date2 date := to_date(strTime2,'DD/MM/YYYY HH:MI:SS PM');
difrence_In_Hours number;
difrence_In_minutes number;
difrence_In_seconds number;
begin
difrence_In_Hours := (v_date2 - v_date1) * 24;
difrence_In_minutes := difrence_In_Hours * 60;
difrence_In_seconds := difrence_In_minutes * 60;
dbms_output.put_line(strTime1);
dbms_output.put_line(strTime2);
dbms_output.put_line('*******');
dbms_output.put_line('difrence_In_Hours : ' || difrence_In_Hours);
dbms_output.put_line('difrence_In_minutes: ' || difrence_In_minutes);
dbms_output.put_line('difrence_In_seconds: ' || difrence_In_seconds);
end ;
Hope this helps.

You may also try this:
select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss')
as run_time from some_table;
It displays time in more human readable form, like: 00:01:34.
If you need also days you may simply add DD to last formatting string.

Calculate age from HIREDATE to system date of your computer
SELECT HIREDATE||' '||SYSDATE||' ' ||
TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12) ||' YEARS '||
TRUNC((MONTHS_BETWEEN(SYSDATE,HIREDATE))-(TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12)*12))||
'MONTHS' AS "AGE " FROM EMP;

You could use to_timestamp function to convert the dates to timestamps and perform a substract operation.
Something like:
SELECT
TO_TIMESTAMP ('13.10.1990 00:00:00','DD.MM.YYYY HH24:MI:SS') -
TO_TIMESTAMP ('01.01.1990:00:10:00','DD.MM.YYYY:HH24:MI:SS')
FROM DUAL

In oracle 11g
SELECT end_date - start_date AS day_diff FROM tablexxx
suppose the starT_date end_date is define in the tablexxx

select days||' '|| time from (
SELECT to_number( to_char(to_date('1','J') +
(CLOSED_DATE - CREATED_DATE), 'J') - 1) days,
to_char(to_date('00:00:00','HH24:MI:SS') +
(CLOSED_DATE - CREATED_DATE), 'HH24:MI:SS') time
FROM request where REQUEST_ID=158761088 );

If you want something that looks a bit simpler, try this for finding events in a table which occurred in the past 1 minute:
With this entry you can fiddle with the decimal values till you get the minute value that you want. The value .0007 happens to be 1 minute as far as the sysdate significant digits are concerned. You can use multiples of that to get any other value that you want:
select (sysdate - (sysdate - .0007)) * 1440 from dual;
Result is 1 (minute)
Then it is a simple matter to check for
select * from my_table where (sysdate - transdate) < .00071;

If you select two dates from 'your_table' and want too see the result as a single column output (eg. 'days - hh:mm:ss') you could use something like this.
First you could calculate the interval between these two dates and after that export all the data you need from that interval:
select extract (day from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ' days - '
|| extract (hour from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ':'
|| extract (minute from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
|| ':'
|| extract (second from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
from your_table
And that should give you result like this:
0 days - 1:14:55

select (floor(((DATE2-DATE1)*24*60*60)/3600)|| ' : ' ||floor((((DATE2-DATE1)*24*60*60) -floor(((DATE2-DATE1)*24*60*60)/3600)*3600)/60)|| ' ' ) as time_difference from TABLE1

(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*60*24 sum_seconds,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*24 sum_minutes,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*24 sum_hours,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi')) sum_days

select to_char(actual_start_date,'DD-MON-YYYY hh24:mi:ss') start_time,
to_char(actual_completion_date,'DD-MON-YYYY hh24:mi:ss') end_time,
floor((actual_completion_date-actual_start_date)*24*60)||'.'||round(mod((actual_completion_date-actual_start_date)*24*60*60,60)) diff_time
from fnd_concurrent_requests
order by request_id desc;

If You want get date defer from using table and column.
SELECT TO_DATE( TO_CHAR(COLUMN_NAME_1, 'YYYY-MM-DD'), 'YYYY-MM-DD') -
TO_DATE(TO_CHAR(COLUMN_NAME_2, 'YYYY-MM-DD') , 'YYYY-MM-DD') AS DATEDIFF
FROM TABLE_NAME;

This will count time between to dates:
SELECT
(TO_CHAR( TRUNC (ROUND(((sysdate+1) - sysdate)*24,2))*60,'999999')
+
TO_CHAR(((((sysdate+1)-sysdate)*24)- TRUNC(ROUND(((sysdate+1) - sysdate)*24,2)))/100*60 *100, '09'))/60
FROM dual

Here's another option:
with tbl_demo AS
(SELECT TO_DATE('11/26/2013 13:18:50', 'MM/DD/YYYY HH24:MI:SS') dt1
, TO_DATE('11/28/2013 21:59:12', 'MM/DD/YYYY HH24:MI:SS') dt2
FROM dual)
SELECT dt1
, dt2
, round(dt2 - dt1,2) diff_days
, round(dt2 - dt1,2)*24 diff_hrs
, numtodsinterval((dt2 - dt1),'day') diff_dd_hh_mm_ss
from tbl_demo;

Single query that will return time difference of two timestamp columns:
select INS_TS, MAIL_SENT_TS, extract( hour from (INS_TS - MAIL_SENT_TS) ) timeDiff
from MAIL_NOTIFICATIONS;

select round( (tbl.Todate - tbl.fromDate) * 24 * 60 * 60 )
from table tbl

for oracle sql I justbn did this and works perfect :
SELECT trunc(date_col_1) - trunc(date_col_2)
FROM TABLE;

$sql="select bsp_bp,user_name,status,
to_char(ins_date,'dd/mm/yyyy hh12:mi:ss AM'),
to_char(pickup_date,'dd/mm/yyyy hh12:mi:ss AM'),
trunc((pickup_date-ins_date)*24*60*60,2),message,status_message
from valid_bsp_req where id >= '$id'";

Subtracting the difference between two time intervals in oracle sql [duplicate]

I have a table as follows:
Filename - varchar
Creation Date - Date format dd/mm/yyyy hh24:mi:ss
Oldest cdr date - Date format dd/mm/yyyy hh24:mi:ss
How can I calcuate the difference in hours minutes and seconds (and possibly days) between the two dates in Oracle SQL?
Thanks

You can substract dates in Oracle. This will give you the difference in days. Multiply by 24 to get hours, and so on.
SQL> select oldest - creation from my_table;
If your date is stored as character data, you have to convert it to a date type first.
SQL> select 24 * (to_date('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi')
- to_date('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours
from dual;
DIFF_HOURS
----------
2.5
Note:
This answer applies to dates represented by the Oracle data type DATE.
Oracle also has a data type TIMESTAMP, which can also represent a date (with time). If you subtract TIMESTAMP values, you get an INTERVAL; to extract numeric values, use the EXTRACT function.

To get result in seconds:
select (END_DT - START_DT)*60*60*24 from MY_TABLE;
Check [https://community.oracle.com/thread/2145099?tstart=0][1]

select
extract( day from diff ) Days,
extract( hour from diff ) Hours,
extract( minute from diff ) Minutes
from (
select (CAST(creationdate as timestamp) - CAST(oldcreationdate as timestamp)) diff
from [TableName]
);
This will give you three columns as Days, Hours and Minutes.

declare
strTime1 varchar2(50) := '02/08/2013 01:09:42 PM';
strTime2 varchar2(50) := '02/08/2013 11:09:00 PM';
v_date1 date := to_date(strTime1,'DD/MM/YYYY HH:MI:SS PM');
v_date2 date := to_date(strTime2,'DD/MM/YYYY HH:MI:SS PM');
difrence_In_Hours number;
difrence_In_minutes number;
difrence_In_seconds number;
begin
difrence_In_Hours := (v_date2 - v_date1) * 24;
difrence_In_minutes := difrence_In_Hours * 60;
difrence_In_seconds := difrence_In_minutes * 60;
dbms_output.put_line(strTime1);
dbms_output.put_line(strTime2);
dbms_output.put_line('*******');
dbms_output.put_line('difrence_In_Hours : ' || difrence_In_Hours);
dbms_output.put_line('difrence_In_minutes: ' || difrence_In_minutes);
dbms_output.put_line('difrence_In_seconds: ' || difrence_In_seconds);
end ;
Hope this helps.

You may also try this:
select to_char(to_date('1970-01-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')+(end_date - start_date),'hh24:mi:ss')
as run_time from some_table;
It displays time in more human readable form, like: 00:01:34.
If you need also days you may simply add DD to last formatting string.

Calculate age from HIREDATE to system date of your computer
SELECT HIREDATE||' '||SYSDATE||' ' ||
TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12) ||' YEARS '||
TRUNC((MONTHS_BETWEEN(SYSDATE,HIREDATE))-(TRUNC(MONTHS_BETWEEN(SYSDATE,HIREDATE)/12)*12))||
'MONTHS' AS "AGE " FROM EMP;

You could use to_timestamp function to convert the dates to timestamps and perform a substract operation.
Something like:
SELECT
TO_TIMESTAMP ('13.10.1990 00:00:00','DD.MM.YYYY HH24:MI:SS') -
TO_TIMESTAMP ('01.01.1990:00:10:00','DD.MM.YYYY:HH24:MI:SS')
FROM DUAL

In oracle 11g
SELECT end_date - start_date AS day_diff FROM tablexxx
suppose the starT_date end_date is define in the tablexxx

select days||' '|| time from (
SELECT to_number( to_char(to_date('1','J') +
(CLOSED_DATE - CREATED_DATE), 'J') - 1) days,
to_char(to_date('00:00:00','HH24:MI:SS') +
(CLOSED_DATE - CREATED_DATE), 'HH24:MI:SS') time
FROM request where REQUEST_ID=158761088 );

If you want something that looks a bit simpler, try this for finding events in a table which occurred in the past 1 minute:
With this entry you can fiddle with the decimal values till you get the minute value that you want. The value .0007 happens to be 1 minute as far as the sysdate significant digits are concerned. You can use multiples of that to get any other value that you want:
select (sysdate - (sysdate - .0007)) * 1440 from dual;
Result is 1 (minute)
Then it is a simple matter to check for
select * from my_table where (sysdate - transdate) < .00071;

If you select two dates from 'your_table' and want too see the result as a single column output (eg. 'days - hh:mm:ss') you could use something like this.
First you could calculate the interval between these two dates and after that export all the data you need from that interval:
select extract (day from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ' days - '
|| extract (hour from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date,created_date))),
'day'))
|| ':'
|| extract (minute from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
|| ':'
|| extract (second from numtodsinterval (second_date
- add_months (created_date,
floor (months_between (second_date, created_date))),
'day'))
from your_table
And that should give you result like this:
0 days - 1:14:55

select (floor(((DATE2-DATE1)*24*60*60)/3600)|| ' : ' ||floor((((DATE2-DATE1)*24*60*60) -floor(((DATE2-DATE1)*24*60*60)/3600)*3600)/60)|| ' ' ) as time_difference from TABLE1

(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*60*24 sum_seconds,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*60*24 sum_minutes,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi'))*24 sum_hours,
(TO_DATE(:P_comapre_date_1, 'dd-mm-yyyy hh24:mi') - TO_DATE(:P_comapre_date_2, 'dd-mm-yyyy hh24:mi')) sum_days

select to_char(actual_start_date,'DD-MON-YYYY hh24:mi:ss') start_time,
to_char(actual_completion_date,'DD-MON-YYYY hh24:mi:ss') end_time,
floor((actual_completion_date-actual_start_date)*24*60)||'.'||round(mod((actual_completion_date-actual_start_date)*24*60*60,60)) diff_time
from fnd_concurrent_requests
order by request_id desc;

If You want get date defer from using table and column.
SELECT TO_DATE( TO_CHAR(COLUMN_NAME_1, 'YYYY-MM-DD'), 'YYYY-MM-DD') -
TO_DATE(TO_CHAR(COLUMN_NAME_2, 'YYYY-MM-DD') , 'YYYY-MM-DD') AS DATEDIFF
FROM TABLE_NAME;

This will count time between to dates:
SELECT
(TO_CHAR( TRUNC (ROUND(((sysdate+1) - sysdate)*24,2))*60,'999999')
+
TO_CHAR(((((sysdate+1)-sysdate)*24)- TRUNC(ROUND(((sysdate+1) - sysdate)*24,2)))/100*60 *100, '09'))/60
FROM dual

Here's another option:
with tbl_demo AS
(SELECT TO_DATE('11/26/2013 13:18:50', 'MM/DD/YYYY HH24:MI:SS') dt1
, TO_DATE('11/28/2013 21:59:12', 'MM/DD/YYYY HH24:MI:SS') dt2
FROM dual)
SELECT dt1
, dt2
, round(dt2 - dt1,2) diff_days
, round(dt2 - dt1,2)*24 diff_hrs
, numtodsinterval((dt2 - dt1),'day') diff_dd_hh_mm_ss
from tbl_demo;

Single query that will return time difference of two timestamp columns:
select INS_TS, MAIL_SENT_TS, extract( hour from (INS_TS - MAIL_SENT_TS) ) timeDiff
from MAIL_NOTIFICATIONS;

select round( (tbl.Todate - tbl.fromDate) * 24 * 60 * 60 )
from table tbl

for oracle sql I justbn did this and works perfect :
SELECT trunc(date_col_1) - trunc(date_col_2)
FROM TABLE;

$sql="select bsp_bp,user_name,status,
to_char(ins_date,'dd/mm/yyyy hh12:mi:ss AM'),
to_char(pickup_date,'dd/mm/yyyy hh12:mi:ss AM'),
trunc((pickup_date-ins_date)*24*60*60,2),message,status_message
from valid_bsp_req where id >= '$id'";

Get data in range using oracle

Please help me to solve this.
I have a table that contain users check in (checktype = I) and check out (checktype = 0) time everyday, and I would like to get the total amount of check in time per user which occur > 08:00 AM in a specific date range.
I am using the query below, but only handle one day per query not in a range, so I have to loop using javascript to get the amount of delay ( > 08:00 AM) per user for example from 01/06/2012 to 06/06/2012
Please help me to get the amount (count) check in time > 08:00 AM per user (ex: userid 708) from ex:01/06/2012 to 06/06/2012 in a single query.
with tt as
(
select TO_DATE('01/06/2012 08:00:00','dd/mm/yyyy hh24:mi:ss') date1 ,
checktime date2
from
checkinout
where
userid = '708' and
to_char(checktime,'dd/mm/yyyy') = '01/06/2012' and
checktype='I' -- checktype I is check in
) , t2 as
(
select numtodsinterval(date2 - date1,'day') dsinterval from tt
)
select extract(hour from dsinterval) || ' hours ' ||
extract(minute from dsinterval) || ' minutes ' ||
round(extract(second from dsinterval)) || ' seconds' late from t2

I assume you wanted to get how many hours late (i.e. after 08:00) the checkins have been done:
with t2 as (
select userid
,numtodsinterval(sum(checktime - (trunc(checktime)+8/24)),'day') dsinterval
,count(1) cnt
from checkinout
where userid='708'
and checktime > trunc(checktime)+8/24
and trunc(checktime) between to_date('01/06/2012','DD/MM/YYYY') and to_date('06/06/2012','DD/MM/YYYY')
and checktype = 'I'
group by userid
)
select extract(hour from dsinterval) || ' hours ' ||
extract(minute from dsinterval) || ' minutes ' ||
round(extract(second from dsinterval)) || ' seconds' late
,cnt
from t2;
See http://sqlfiddle.com/#!4/c4670/11 for my test case.
edit: added column "cnt" to show how many times

Consider the following example on base of this you can write your own logic
WITH tbl AS
(SELECT SYSDATE dt
FROM DUAL
UNION
SELECT SYSDATE + (1 + (10 / 1440))
FROM DUAL
UNION
SELECT SYSDATE + (2 + (12 / 1440))
FROM DUAL
UNION
SELECT SYSDATE + (3 + (13 / 1440))
FROM DUAL
UNION
SELECT SYSDATE + (6 + (15 / 1440))
FROM DUAL
UNION
SELECT SYSDATE + (8 + (18 / 1440))
FROM DUAL)
SELECT EXTRACT (HOUR FROM dsinterval)
|| ' hours '
|| EXTRACT (MINUTE FROM dsinterval)
|| ' minutes '
|| ROUND (EXTRACT (SECOND FROM dsinterval))
|| ' seconds' late
FROM (SELECT NUMTODSINTERVAL (dt1 - dt2, 'day') dsinterval
FROM (SELECT TO_DATE (TO_CHAR (dt, 'DD/MM/YYYY') || ' 08:00:00',
'DD/MM/YYYY HH24:MI:SS'
) dt1,
TO_DATE (TO_CHAR (dt, 'DD/MM/YYYY HH24:MI:SS'),
'DD/MM/YYYY HH24:MI:SS'
) dt2
FROM tbl
WHERE dt BETWEEN SYSDATE + 2 AND SYSDATE + 5))
As per code you can write like
SELECT EXTRACT (HOUR FROM dsinterval)
|| ' hours '
|| EXTRACT (MINUTE FROM dsinterval)
|| ' minutes '
|| ROUND (EXTRACT (SECOND FROM dsinterval))
|| ' seconds' late
FROM (SELECT NUMTODSINTERVAL (dt1 - dt2, 'day') dsinterval
FROM (SELECT TO_DATE (TO_CHAR (checktime , 'DD/MM/YYYY') || ' 08:00:00',
'DD/MM/YYYY HH24:MI:SS'
) dt1,
TO_DATE (checktime, 'DD/MM/YYYY HH24:MI:SS') dt2
FROM checkinout
WHERE checktime BETWEEN start_date AND end_date
AND checktype='I'))

Help with Sql query for comparing string(HH24MI) to date

We have a configuration table as shown below that stores the start time and the duration.
If the start time is 9:20 pm (3rd one ) add the duration then the time becomes 9:35.
I have to find out if the current time is in between any of the values.
I have to return the output based on the start_time and duration. i.e current time should be between start_time and the start_time + duration. (between 09:20 and and 09:35)
Can you please help me with the sql query or is it better if we go with sql function?
Start_time, duration(minutes) output
1108 5 2
1054 100 5
2120 15 8

I'm not a fan of storing dates and times in VARCHAR2 columns. START_TIME should really be a DATE or a TIMESTAMP column.
That said, you can do something like
with x as (
select '1108' start_time, 5 duration, 2 output from dual
union all
select '1054', 100, 5 from dual
union all
select '2120', 15, 8 from dual
)
select *
from (
select to_date(
to_char(sysdate,'YYYY-MM-DD') || ' ' ||
start_time,
'YYYY-MM-DD HH24MI' ) start_date,
to_date(
to_char(sysdate,'YYYY-MM-DD') || ' ' ||
start_time,
'YYYY-MM-DD HH24MI' ) + duration/24/60 end_date
from x)
where sysdate between start_date and end_date

The following selects all rows where sysdate is within the Start_Time and Start_Time + duration (EDITed as per comment from OP):
SELECT (TRUNC ( SYSDATE ) + TO_NUMBER ( SUBSTR ( Start_Time, 0, 2 ) ) / 24.0 + TO_NUMBER ( SUBSTR ( Start_Time, 3 ) ) / (24.0 * 60.0)) start_date, (TRUNC ( SYSDATE ) + TO_NUMBER ( SUBSTR ( Start_Time, 0, 2 ) ) / 24.0 + TO_NUMBER ( SUBSTR ( Start_Time, 3 ) ) / (24.0 * 60.0) + TO_NUMBER (duration)) end_date FROM configtable;