Remove duplicates based on common where condition in sql [closed] - sql

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Select * from Table_name i am getting below result.
S.no Emp_id Date Description Amount Splitup amount
2667737 12345 8/12/2019 Icecream 50 30
2667738 12345 8/12/2019 Icecream 50 20
2667739 12346 8/12/2019 Chocolate 50 20
But i need the result
S.no Emp_id Date Description Amount Splitup amount
2667737 12345 8/12/2019 Icecream 50 30
2667738 12345 Icecream 20
2667739 12346 8/12/2019 Chocolate 50 20
i need only the first as amount .For same s.no and same emp_id was to have only one date and amount, remaining rows i want to make it empty.

Answer 1

You can consider using lag() windows analytic function :
select [S.no], [Emp_id],
case when lag([Date],1,null) over
(partition by [Date] order by [S.no]) = [Date] then
null
else
[Date]
end as [Date], [Description],
case when lag([Amount],1,null) over
(partition by [Amount] order by [S.no]) = [Amount] then
null
else
[Amount]
end as [Amount], [Splitup amount]
from tab;
Demo

Answer 2

You can use conditional logic with row_number():
select s.s_no, s.emp_id,
(case when row_number() over (partition by emp_id, description order by s_no) = 1
then date
end) as date,
description,
(case when row_number() over (partition by emp_id, description order by s_no) = 1
then amount
end) as amount,
splitup
from t
order by emp_id, s_no;
Note the outer order by and how it matches the conditions in the window clause. SQL result sets are unordered unless there is an explicit order by. If you want the "first" row to have the values, then you need to be sure that the result set is in the right order.