I want to get and select the result of a find and replacement macro and do some operations on it.
Say, this is the text: \[abc\], I want to convert it to abc and then select abc.
Here is the code:
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "(\\\[)(*)(\\\])"
.Replacement.Text = "\2"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchKashida = False
.MatchDiacritics = False
.MatchAlefHamza = False
.MatchControl = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Cut
Here in the last line, Selection.Cut gives an error that the Selection is empty.
I want to select the output of the replacement and Cut it.
From my repository Amin MSWord VBA macros
wdReplaceAll as the Replacement "target" doesn't jump to individual "hits", which is why the Selection is not picking up anything.
Use wdReplaceOne, instead, and the Selection (or Range object, if that is used) will move to the found content.
You might want to test whether something was actually found before issuing the .Cut command as that could have unexpected consequences if nothing is found (delete content at the point where the macro was initiated). For example:
Sub FindReplaceAndCut()
Dim found As Boolean
With Selection.Find
.ClearFormatting
.Replacement.ClearFormatting
.Text = "(\\\[)(*)(\\\])"
.Replacement.Text = "\2"
.Forward = True
.wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchKashida = False
.MatchDiacritics = False
.MatchAlefHamza = False
.MatchControl = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
found = Selection.Find.Execute(Replace:=wdReplaceOne)
If found Then
Selection.Cut
End If
End Sub
Related
I need selection particular content each paragraph in ms word 2013. I try to select content using by vba script..
Sub RepalaceStrong()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "<Strong"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Extend
With Selection.Find
.Text = "</Strong>"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
End Sub
But i tried this code, i can't select one by one text.
Input:
In general, a vector field is a function whose domain is a set of points in <Strong> a vector field is </Strong> a vector field is <Strong>function</Strong> whose domain is a set of points
>In general, a vector field is a function whose <Strong>domain</Strong> is a set of points
Is it possible to select one by one all strong elements...
You need to specify the correct font formatting in your find operation (note the .Font.Bold = True part below):
With Selection.Find
.ClearFormatting
.Font.Bold = True
.Replacement.ClearFormatting
.text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Then, of course, it depends what you want to do with the bold text. Currently the code above just configures the Find object to search for bold text.
It's not strong you're looking for, it's Font.Bold
Option Explicit
Sub FindBold()
Dim myDoc As Document
Set myDoc = ThisDocument
Dim searchRange As Range
Dim foundRange As Range
Set searchRange = myDoc.Range(0, myDoc.Range.End)
With searchRange.Find
.ClearFormatting
.Forward = True
.Font.Bold = True
.Execute
Do While .Found
Set foundRange = searchRange
foundRange.Select
foundRange.Collapse direction:=wdCollapseEnd
MsgBox "Found bold text."
.Execute
Loop
End With
End Sub
My ans:
Sub RepalaceStrong()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "<Strong"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute
Selection.Extend
With Selection.Find
.Text = "</Strong>"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute
Selection.Collapse Direction:=wdCollapseEnd
End Sub
I got it ....
What I need to do is add a Rich Text Content Control to all "xx"'s in a large word document.
I saw a similar thread on highlighting multiple instances. I based the solution that I've tried so far on this:
Options.DefaultHighlightColorIndex = wdYellow
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Highlight = True
With Selection.Find
.Text = "target1"
.Replacement.Text = "target1"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
Now just testing in word to see what command it uses to add the content controls individually I found this command:
Selection.Range.ContentControls.Add (wdContentControlRichText)
What I came up with was:
Sub StandardLanguageVariableSearch()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Range.ContentControls.Add (wdContentControlRichText)
With Selection.Find
.Text = "xx"
.Replacement.Text = "xx"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Swapping out Selection.Range with Selection.Find simply resulted in a "method or data field not found" or something like that. I think Range refers to the currently highlighted range of characters, whereas find refers to whatever the with block... well, finds.
Whatever find is doesn't appear to have the ability to throw some content controls onto it.
You were quite close:
Sub StandardLanguageVariableSearch()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "xx"
'.Replacement.Text = "xx"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Do While Selection.Find.Execute
'Selection.Text = "" 'uncomment if you want to remove xx
Selection.Range.ContentControls.Add (wdContentControlRichText)
Loop
End Sub
I have a document that has a bunch of projects. I've gone through and certain projects are in red font if they are high priority.
I want to make a macro so that Word finds all instances of red font, saves those project names, and then pastes them in a list at the top of my document.
When I tried to do the Macro Recorder, this is what I got.
Sub HotTopics()
'
' HotTopics Macro
'
'
Selection.Find.ClearFormatting
Selection.Find.Font.Color = wdColorRed
With Selection.Find
.Text = ""
.Font.Color = wdColorRed
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Copy
Selection.PasteAndFormat (wdFormatOriginalFormatting)
End Sub
When I try running the macro, it says there is an error with Selection.copy because there is nothing to copy
You didn't click Find while recording the macro. Note second last line.
Selection.Find.ClearFormatting
With Selection.Find
.Text = ""
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchKashida = False
.MatchDiacritics = False
.MatchAlefHamza = False
.MatchControl = False
.MatchByte = False
.CorrectHangulEndings = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = False
.MatchFuzzy = False
End With
Selection.Find.Execute
Selection.Copy
I have a dictionary in MS Word format which I'd like to have cleaned from any paragraph breaks within dictionary entries, and keep only paragraph breaks that separate any two dictionary entries. This is how the layout of the dictionary looks now:
First picture http://img43.imageshack.us/img43/6476/snapshotpr.jpg
I'd need a macro or a regular expression that would first remove all the paragraph breaks, from the document, which would produce this layout:
Second picture http://img824.imageshack.us/img824/5219/snapshot1i.jpg
and then in the next step would add paragraph breaks only before the dictionary entries, which means only before bold phrases followed by the phonetic transcription in square brackets, to get this layout:
Third picture http://img849.imageshack.us/img849/2003/snapshot2qf.jpg
I used this site to help me with the paragraph markers.
Again, I recorded a macro with something did manually with 4 find/replace (two steps were used to make sure that a word followed by a square bracket was matched). Here's the macro:
Sub Separator()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "^13"
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
.MatchFuzzy = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Font.Bold = True
With Selection.Find
.Text = "\["
.Replacement.Text = "^&"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchFuzzy = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Font.Bold = True
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "[a-z\-]# \["
.Replacement.Text = "^p^&"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchFuzzy = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Font.Bold = True
Selection.Find.Replacement.ClearFormatting
With Selection.Find.Replacement.Font
.Bold = False
.Italic = False
End With
With Selection.Find
.Text = "\["
.Replacement.Text = "["
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchFuzzy = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Let me know if there's anything to tweak and I'll try to change it :)
EDIT: Part added for hyphens.
The following code works, but it performs everything on the entire document. I'd like to highlight a block of text, then when I run the macro only have it work on the highlighted text. How do I do that? Thanks...
Sub DoCodeNumberStyle(numchars As String)
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "(^13)([0-9]{" + numchars + "}) "
.Replacement.Text = "\1###\2$$$ "
.Forward = True
.Wrap = wdFindAsk
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Style = ActiveDocument.Styles("CodeNumber")
With Selection.Find
.Text = "###([0-9]{" + numchars + "})$$$"
.Replacement.Text = "\1"
.Forward = True
.Wrap = wdFindAsk
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Sub CodeNumberStyle()
DoCodeNumberStyle ("1")
DoCodeNumberStyle ("2")
End Sub
PostScript:
One additional thing I've discovered: if you do more than one find on a Selection, the first find loses/changes the Selection, so the others are no longer bounded by the original Selection (and a wdReplaceAll will continue to the end of the document). To fix this, capture the Selection into a Range. Here's the final version of my method, which now does everything I need, is restricted to the original highlighted selection (even with 3 find-and-replacements), and has also been minimized, code-wise:
Sub AAACodeNumberStyleHighlightedSelection()
With Selection.Range.Find
.ClearFormatting
.Style = ActiveDocument.Styles("Code")
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
' First line:
.Text = "1 //"
.Replacement.Text = "###1$$$ //"
.MatchWildcards = False
.Execute Replace:=wdReplaceAll
' Rest of lines:
.Text = "(^13)([0-9]{1,2}) "
.Replacement.Text = "\1###\2$$$ "
.MatchWildcards = True
.Execute Replace:=wdReplaceAll
' Now style the line numbers:
.Text = "###([0-9]{1,2})$$$"
.Replacement.Text = "\1"
.Replacement.Style = ActiveDocument.Styles("CodeNumber")
.MatchWildcards = True
.Execute Replace:=wdReplaceAll
End With
End Sub
Change .Wrap to wdFindStop and this should work for you. I think this might be a minor Word bug; the documentation says that the Wrap value
sets what happens if the search begins at a point other than the beginning of the document and the end of the document is reached (or vice versa if Forward is set to False) or if the search text isn't found in the specified selection or range.
But it seems like it forces the Find to go to the end of the document rather than taking the selection into account. Anyway, there's no need for wdFindAsk if you only plan to run this on selections.
I, too, found that even when beginning a FIND loop on a range, the range is redefined by FIND, and so continuous loop on .execute goes beyond the original range to the end of the document. wdFindStop stops only at the end of the document, not at the end of the original range.
So, I inserted an IF statement:
do while .find.found
...
If .find.parent.InRange(doc.Bookmarks("BODY").Range) = False Then Exit Do
...
.execute
loop
Set myRange = Selection.Range
myRange.Select
With Selection.Find
.Text = "Apple"
.Replacement.Text = "Banana"
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
'.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
myRange.Select
With Selection.Find
.Text = "red"
.Replacement.Text = "yellow"
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
'.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll