I've been able to use How do I find the total number of used days in a month? to answer how many TOTAL days we've had cats and dogs which is helpful but I need to know how many days we had:
Cats only: 4
Dogs only: 5
Both: 6
Thank you in advance!
CREATE TABLE "ANIMALGUESTS"
( "ID" NUMBER,
"GUESTNAME" VARCHAR2(20 BYTE),
"GUESTTYPE" VARCHAR2(20 BYTE),
"CHECKIN" DATE,
"CHECKOUT" DATE
);
Insert into ANIMALGUESTS (ID,GUESTNAME,GUESTTYPE,CHECKIN,CHECKOUT) values (1,'Tom','Cat',to_date('01-JAN-19','DD-MON-RR'),to_date('10-JAN-19','DD-MON-RR'));
Insert into ANIMALGUESTS (ID,GUESTNAME,GUESTTYPE,CHECKIN,CHECKOUT) values (2,'Spike','Dog',to_date('03-JAN-19','DD-MON-RR'),to_date('05-JAN-19','DD-MON-RR'));
Insert into ANIMALGUESTS (ID,GUESTNAME,GUESTTYPE,CHECKIN,CHECKOUT) values (3,'Spike','Dog',to_date('08-JAN-19','DD-MON-RR'),to_date('12-JAN-19','DD-MON-RR'));
Insert into ANIMALGUESTS (ID,GUESTNAME,GUESTTYPE,CHECKIN,CHECKOUT) values (4,'Cherie','Cat',to_date('07-JAN-19','DD-MON-RR'),to_date('09-JAN-19','DD-MON-RR'));
Insert into ANIMALGUESTS (ID,GUESTNAME,GUESTTYPE,CHECKIN,CHECKOUT) values (5,'Tyke','Dog',to_date('10-JAN-19','DD-MON-RR'),to_date('15-JAN-19','DD-MON-RR'));
Using conditional aggregation and inline calendar table:
WITH cte AS (
SELECT DATE '2019-01-01' + rownum -1 dt FROM DUAL CONNECT BY ROWNUM < 366
)
SELECT DISTINCT
SUM(CASE WHEN COUNT(DISTINCT GUESTTYPE)=2 THEN 1 END) OVER() AS both,
SUM(CASE WHEN COUNT(DISTINCT GUESTTYPE)=1 AND MIN(GUESTTYPE)='Cat' THEN 1 END) OVER() AS cats_only,
SUM(CASE WHEN COUNT(DISTINCT GUESTTYPE)=1 AND MIN(GUESTTYPE)='Dog' THEN 1 END) OVER() AS dogs_only
FROM cte c
LEFT JOIN "ANIMALGUESTS" a ON c.dt BETWEEN a.CHECKIN AND a.CHECKOUT
GROUP BY dt;
db<>fiddle demo
Oracle 12c supports recursive CTEs, so you can expand the data and then aggregate:
with cte as (
select checkin as dt, checkout, guesttype
from ANIMALGUESTS
union all
select dt + 1, checkout, guesttype
from cte
where dt < checkout
)
select sum(case when cats > 0 and dogs > 0 then 1 else 0 end) as both,
sum(case when cats > 0 and dogs = 0 then 1 else 0 end) as cats_only,
sum(case when cats = 0 and dogs > 0 then 1 else 0 end) as dogs_only
from (select dt, sum(case when guesttype = 'Cat' then 1 else 0 end) as cats,
sum(case when guesttype = 'Dog' then 1 else 0 end) as dogs
from cte
group by dt
) cte;
This generates the result set as columns in a row, rather than separate rows.
Related
I'm trying to figure out if what I'm trying to do is possible. Instead of resorting to multiple queries on a table, I wanted to group the records by business date and id then group by the id and select one date for a field and another date for the other field.
SELECT
*
{AMOUNT FROM DATE}
{AMOUNT FROM OTHER DATE}
FROM (
SELECT
date,
id,
SUM(amount) AS amount
FROM
table
GROUP BY id, date
AS subquery
GROUP BY id
It seems that you're looking to do a pivot query. I usually use cross tabs for this. Based on the query you posted, it could look like:
SELECT
id,
SUM(CASE WHEN date = '20190901' THEN amount ELSE 0 END) AmountFromSept01,
SUM(CASE WHEN date = '20191001' THEN amount ELSE 0 END) AmountFromOct01
FROM (
SELECT
date,
id,
SUM(amount) AS amount
FROM
table
GROUP BY id, date
)AS subquery
GROUP BY id;
You could also use a CTE.
WITH CTE AS(
SELECT
date,
id,
SUM(amount) AS amount
FROM
table
GROUP BY id, date
)
SELECT
id,
SUM(CASE WHEN date = '20190901' THEN amount ELSE 0 END) AmountFromSept01,
SUM(CASE WHEN date = '20191001' THEN amount ELSE 0 END) AmountFromOct01
FROM CTE
GROUP BY id;
Or even be a rebel and do the operation directly.
SELECT
id,
SUM(CASE WHEN date = '20190901' THEN amount ELSE 0 END) AmountFromSept01,
SUM(CASE WHEN date = '20191001' THEN amount ELSE 0 END) AmountFromOct01
FROM CTE
GROUP BY id;
However, some people have tested for performance and found that pre-aggregating can improve performance.
If I understand you correctly, then you're just trying to pivot, but only with two particular dates:
select id,
date1 = sum(iif(date = '2000-01-01', amount, null)),
date2 = sum(iif(date = '2000-01-02', amount, null))
from [table]
group by id
I have the following code which gives me production dates and production volumes for a thirty day period.
select
(case when trunc(so.revised_due_date) <= trunc(sysdate)
then trunc(sysdate) else trunc(so.revised_due_date) end) due_date,
(case
when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD')
then 'CD' end) = 'CD'
and (case when so.tec_criteria in ('PI','MC')
then 'XX' else so.tec_criteria end) = 'OF'
then sum(so.revised_qty_due)
end) CD_OF_VOLUME
from shop_order so
left join scm_prodtyp sp
on so.prodtyp = sp.prodtyp
where so.order_type = 'MD'
and so.plant = 'W'
and so.status_code between '4' and '8'
and trunc(so.revised_due_date) <= trunc(sysdate)+30
group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
order by trunc(so.revised_due_date)
The problem I have is where there is a date with no production planned, the date wont appear on the report. Is there a way of filling in the missing dates.
i.e. the current report shows the following ...
DUE_DATE CD_OF_VOLUME
14/04/2015 35,267.00
15/04/2015 71,744.00
16/04/2015 20,268.00
17/04/2015 35,156.00
18/04/2015 74,395.00
19/04/2015 3,636.00
21/04/2015 5,522.00
22/04/2015 15,502.00
04/05/2015 10,082.00
Note: missing dates (20/04/2015, 23/04/2015 to 03/05/2015)
Range is always for a thirty day period from sysdate.
How do you fill in the missing dates?
Do you need some kind of calendar table?
Thanks
You can get the 30-day period from SYSDATE as follows (I assume you want to include SYSDATE?):
WITH mydates AS (
SELECT TRUNC(SYSDATE) - 1 + LEVEL AS due_date FROM dual
CONNECT BY LEVEL <= 31
)
Then use the above to do a LEFT JOIN with your query (perhaps not a bad idea to put your query in a CTE as well):
WITH mydates AS (
SELECT TRUNC(SYSDATE) - 1 + LEVEL AS due_date FROM dual
CONNECT BY LEVEL <= 31
), myorders AS (
select
(case when trunc(so.revised_due_date) <= trunc(sysdate)
then trunc(sysdate) else trunc(so.revised_due_date) end) due_date,
(case
when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD')
then 'CD' end) = 'CD'
and (case when so.tec_criteria in ('PI','MC')
then 'XX' else so.tec_criteria end) = 'OF'
then sum(so.revised_qty_due)
end) CD_OF_VOLUME
from shop_order so
left join scm_prodtyp sp
on so.prodtyp = sp.prodtyp
where so.order_type = 'MD'
and so.plant = 'W'
and so.status_code between '4' and '8'
and trunc(so.revised_due_date) <= trunc(sysdate)+30
group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
order by trunc(so.revised_due_date)
)
SELECT mydates.due_date, myorders.cd_of_volume
FROM mydates LEFT JOIN myorders
ON mydates.due_date = myorders.due_date;
If you want to show a zero on "missing" dates instead of a NULL, use COALESCE(myorders.cd_of_volume, 0) AS cd_of_volume above.
what you can do is this :
creating a new table with all the days you need .
WITH DAYS AS
(SELECT TRUNC(SYSDATE) - ROWNUM DDD
FROM ALL_OBJECTS
WHERE ROWNUM < 365)
SELECT
DAYS.DDD
FROM
DAYS;
then full outer join between thoes table :
select DUE_DATE , CD_OF_VOLUME , DDD
from (
select
(case when trunc(so.revised_due_date) <= trunc(sysdate)
then trunc(sysdate) else trunc(so.revised_due_date) end) due_date,
(case
when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD')
then 'CD' end) = 'CD'
and (case when so.tec_criteria in ('PI','MC')
then 'XX' else so.tec_criteria end) = 'OF'
then sum(so.revised_qty_due)
end) CD_OF_VOLUME
from shop_order so
left join scm_prodtyp sp
on so.prodtyp = sp.prodtyp
where so.order_type = 'MD'
and so.plant = 'W'
and so.status_code between '4' and '8'
and trunc(so.revised_due_date) <= trunc(sysdate)+30
group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
order by trunc(so.revised_due_date)
) full outer join NEW_TABLE new on ( new .DDD = DUE_DATE )
where new .DDD between /* */ AND /* */ /* pick your own limit) */
you can get the gaps by using connect by and a left join:
assuming your schema is:
create table tbl(DUE_DATE date, CD_OF_VOLUME float);
insert into tbl values(to_date('14/04/2015','DD/MM/YYYY'),35267.00);
insert into tbl values(to_date('15/04/2015','DD/MM/YYYY'),71744.00);
insert into tbl values(to_date('16/04/2015','DD/MM/YYYY'),20268.00);
insert into tbl values(to_date('17/04/2015','DD/MM/YYYY'),35156.00);
insert into tbl values(to_date('18/04/2015','DD/MM/YYYY'),74395.00);
insert into tbl values(to_date('19/04/2015','DD/MM/YYYY'),3636.00);
insert into tbl values(to_date('21/04/2015','DD/MM/YYYY'),5522.00);
insert into tbl values(to_date('22/04/2015','DD/MM/YYYY'),15502.00);
insert into tbl values(to_date('04/05/2015','DD/MM/YYYY'),10082.00);
you can say:
with cte as
(
select (select min(DUE_DATE)-1 from tbl)+ level as dt
from dual
connect by level <= (select max(DUE_DATE)-min(DUE_DATE) from tbl)
)
select to_char(c.dt,'DD/MM/YYYY') gap,null volume
from cte c
left join tbl t on c.dt=t.DUE_DATE
where t.DUE_DATE is null
order by c.dt
Result:
GAP VOLUME
20/04/2015 (null)
23/04/2015 (null)
24/04/2015 (null)
25/04/2015 (null)
26/04/2015 (null)
27/04/2015 (null)
28/04/2015 (null)
29/04/2015 (null)
30/04/2015 (null)
01/05/2015 (null)
02/05/2015 (null)
03/05/2015 (null)
Notice: you can implement this in your original query, one simplest way is to wrap your query and use it as a subquery instead of tbl in above code snippet.
I am trying to count events (which are rows in the event_table) in the year before and the year after a particular target date for each person. For example, say I have a person 100 and target date is 10/01/2012. I would like to count events in 9/30/2011-9/30/2012 and in 10/02/2012-9/30/2013.
My query looks like:
select *
from (
select id, target_date
from subsample_table
) as i
left join (
select id, event_date, count(*) as N
, case when event_date between target_date-365 and target_date-1 then 0
when event_date between target_date+1 and target_date+365 then 1
else 2 end as after
from event_table
group by id, target_date, period
) as h
on i.id = h.id
and i.target_date = h.event_date
The output should look something like:
id target_date after N
100 10/01/2012 0 1000
100 10/01/2012 1 0
It's possible that some people do not have any events in the before or after periods (or both), and it would be nice to have zeros in that case. I don't care about the events outside the 730 days.
Any suggestions would be greatly appreciated.
I think the following may approach what you are trying to accomplish.
select id
, target_date
, event_date
, count(*) as N
, SUM(case when event_date between target_date-365 and target_date-1
then 1
else 0
end) AS Prior_
, SUM(case when event_date between target_date+1 and target_date+365
then 1
else 0
end) as After_
from subsample_table i
left join
event_table h
on i.id = h.id
and i.target_date = h.event_date
group by id, target_date, period
This is a generic answer. I don't know what date functions teradata has, so I will use sql server syntax.
select id, target_date, sum(before) before, sum(after) after, sum(righton) righton
from yourtable t
join (
select id, target_date td
, case when yourdate >= dateadd(year, -1, target_date)
and yourdate < target_date then 1 else 0 end before
, case when yourdate <= dateadd(year, 1, target_date)
and yourdate > target_date then 1 else 0 end after
, case when yourdate = target_date then 1 else 0 end righton
from yourtable
where whatever
group by id, target_date) sq on t.id = sq.id and target_date = dt
where whatever
group by id, target_date
This answer assumes that an id can have more than one target date.
(Also posted here.)
So I have two tables, one is invalid table and the other is valid table.
valid table:
id
status
date
invalid table:
id
status
date
I have to produce a report with this output:
date on-time late total valid invalid1 invalid2 total rate
--------- ------- ---- ----- ----- -------- -------- ----- ----
9/10/2011 4 10 14 3 3 3 6
date: common fields on the 2 tables, field to group by, how many records on that day has
on-time: count of all the id on the valid table
late: count of all the records(id) on the invalid table
total: total of on-time and late
valid: count of id on the valid table with the "valid" status
invalid1: count of id on the invalid table with "invalid1" status
invalid2: count of id on the invalid table with "invalid2" status
total: total of valid, invalid1, invalid2
rate: average of totals
It's basically multiple queries with different table. How can I achieve it?
Someting like this?
SELECT
*,
(result.total + result._total) / 2 AS rate
FROM (
SELECT
date,
SUM(CASE WHEN data.valid = 1 THEN 1 ELSE 0 END) AS ontime,
SUM(CASE WHEN data.valid = 0 THEN 1 ELSE 0 END) AS late,
COUNT(*) AS total,
SUM(CASE WHEN data.valid = 1 AND data.status = 'valid' THEN 1 ELSE 0 END) AS valid,
SUM(CASE WHEN data.valid = 0 AND data.status = 'invalid1' THEN 1 ELSE 0 END) AS invalid1,
SUM(CASE WHEN data.valid = 0 AND data.status = 'invalid2' THEN 1 ELSE 0 END) AS invalid2,
SUM(CASE WHEN data.status IN ('valid', 'invalid', 'invalid2') THEN 1 ELSE 0 END) AS _total
FROM (
SELECT
date,
status,
valid = 1
FROM
Valid
UNION ALL
SELECT
date,
status,
valid = 0
FROM
InValid ) AS data
GROUP BY
date) AS result
SELECT date, ontime, late, ontime+late total, valid, invalid1, invalid2, valid+invalid1+invalid2 total
FROM
(SELECT date,
COUNT(*) late,
COUNT(IIF(status = 'invalid1', 1, NULL)) invalid1,
COUNT(IIF(status = 'invalid2', 1, NULL)) invalid2,
FROM invalid
GROUP BY date
) JOIN (
SELECT date,
COUNT(*) ontime,
COUNT(IIF(status = 'valud', 1, NULL)) valid,
FROM valid
GROUP BY date
) USING (date)
First of all, it seems that you are holding exactly the same information in 2 tables - I would recommend merging those tables together and add an additional boolean column called valid to hold the info related to validity of the record.
The query on your existent DB structure might look something like this:
SELECT unioned.* FROM (
( SELECT v.date AS date, v.status AS status, v.id AS id, COUNT(id) AS valid, 0 AS invalid1, 0 AS invalid2 FROM valid v GROUP BY v.date)
UNION
( SELECT i1.date AS date, i1.status AS status, i1.id AS id, 0 AS valid, COUNT(i1.id) AS invalid1, 0 AS invalid2 FROM invalid1 i1 GROUP BY i1.date)
UNION
( SELECT i2.date AS date, i2.status AS status, i2.id AS id, 0 AS valid, 0 AS invalid1, COUNT(i.id) AS invalid2 FROM invalid1 i1 GROUP BY i1.date)
) AS unioned GROUP BY unioned.date
how to calculate count based on rows?
SOURCE TABLE
each employee can take 2 days off
Employee-----First_Day_Off-----Second_Day_Off
1------------10/21/2009--------12/6/2009
2------------09/3/2009--------12/6/2009
3------------09/3/2009--------NULL
4
5
.
.
.
Now i need a table that shows the dates and number of people taking off on that day
Date---------First_Day_Off-------Second_Day_Off
10/21/2009---1-------------------0
12/06/2009---1--------------------1
09/3/2009----2--------------------0
Any ideas?
Oracle 9i+, using Subquery Factoring (WITH):
WITH sample AS (
SELECT a.employee,
a.first_day_off AS day_off,
1 AS day_number
FROM YOUR_TABLE a
WHERE a.first_day_off IS NOT NULL
UNION ALL
SELECT b.employee,
b.second_day_off,
2 AS day_number
FROM YOUR_TABLE b
WHERE b.second_day_off IS NOT NULL)
SELECT s.day_off AS date,
SUM(CASE WHEN s.day_number = 1 THEN 1 ELSE 0 END) AS first_day_off,
SUM(CASE WHEN s.day_number = 2 THEN 1 ELSE 0 END) AS second_day_off
FROM sample s
GROUP BY s.day_off
Non Subquery Version
SELECT s.day_off AS date,
SUM(CASE WHEN s.day_number = 1 THEN 1 ELSE 0 END) AS first_day_off,
SUM(CASE WHEN s.day_number = 2 THEN 1 ELSE 0 END) AS second_day_off
FROM (SELECT a.employee,
a.first_day_off AS day_off,
1 AS day_number
FROM YOUR_TABLE a
WHERE a.first_day_off IS NOT NULL
UNION ALL
SELECT b.employee,
b.second_day_off,
2 AS day_number
FROM YOUR_TABLE b
WHERE b.second_day_off IS NOT NULL) s
GROUP BY s.day_off
It is a bit awkward to handle these queries, since you have days off stored in different columns. A better layout would be to have something like
EMPLOYEE_ID DAY_OFF
Then you would have multiple rows if an employee took multiple days off
EMPLOYEE_ID DAY_OFF
1 10/21/2009
1 12/6/2009
2 09/3/2009
2 12/6/2009
3 09/3/2009
...
In that case, you could find out how many days off each person took by using the following query:
SELECT EMPLOYEE_ID, COUNT(*) AS NUM_DAYS_OFF FROM DAYS_OFF_TABLE GROUP BY EMPLOYEE_ID
And the number of people who took days off on each date like this:
SELECT DAY_OFF, COUNT(*) AS NUM_PEOPLE FROM DAYS_OFF_TABLE GROUP BY DAY_OFF
But I digress...
You can try to use an SQL CASE statement to help with this:
SELECT Employee, CASE
WHEN First_Day_Off is NULL AND Second_Day_Off is NULL THEN 0
WHEN First_Day_Off is NOT NULL AND Second_Day_Off is NULL THEN 1
WHEN First_Day_Off is NULL AND Second_Day_Off is NOT NULL THEN 1
ELSE 2
END AS NUM_DAYS_OFF
FROM DAYS_OFF_TABLE
(note that you may need to change around the syntax slightly depending on your database.
Getting dates and number of people who took off on that day might be more complicated.
I don't know if this would work, but you can try it:
SELECT
Date_Off,
COUNT(*) AS Num_People
FROM
(SELECT
First_Day_Off, COUNT(*) AS Num_People FROM DAYS_OFF_TABLE WHERE First_Day_Off IS NOT NULL GROUP BY First_Day_Off
UNION
SELECT Second_Day_Off, COUNT(*) AS Num_People FROM DAYS_OFF_TABLE WHERE Second_Day_Off IS NOT NULL GROUP BY Second_Day_Off)
GROUP BY
Num_People