Please I want to count total consecutive days for an event record and order by this record grouping by actor id . for instance we have. For sqlite
event_id| created_at |actor_id
1 | 2018-07-01| 40 /* this is a consecutive days
1 | 2018-07-02| 40 */
1 | 2018-07-04| 40
1 | 2018-07-05| 40
1 | 2018-07-09| 40
2 | 2018-07-11| 40
2 | 2018-07-12| 40
1 | 2018-07-13| 41
should give me something like
actor_id|streak
40 | 3
41 | 0
You can group by actor_id and sum conditionally if there exists a consecutive day:
select
t.actor_id,
sum(case when exists (
select 1 from tablename
where
actor_id = t.actor_id and
julianday(created_at) - julianday(t.created_at) = 1
) then 1 else 0 end) streak
from tablename t
group by t.actor_id
See the demo.
Or with a self join:
select
t.actor_id,
sum(tt.created_at is not null) streak
from tablename t left join tablename tt
on tt.actor_id = t.actor_id and julianday(tt.created_at) - julianday(t.created_at) = 1
group by t.actor_id
See the demo.
Results:
| actor_id | streak |
| -------- | ------ |
| 40 | 3 |
| 41 | 0 |
Related
I have a table:
| id | Number |Address
| -----| ------------|-----------
| 1 | 0 | NULL
| 1 | 1 | NULL
| 1 | 2 | 50
| 1 | 3 | NULL
| 2 | 0 | 10
| 3 | 1 | 30
| 3 | 2 | 20
| 3 | 3 | 20
| 4 | 0 | 75
| 4 | 1 | 22
| 4 | 2 | 30
| 5 | 0 | NULL
I need to get: the NUMBER of the last ADDRESS change for each ID.
I wrote this select:
select dh.id, dh.number from table dh where dh =
(select max(min(t.history)) from table t where t.id = dh.id group by t.address)
But this select not correctly handling the case when the address first changed, and then changed to the previous value. For example id=1: group by return:
| Number |
| -------- |
| NULL |
| 50 |
I have been thinking about this select for several days, and I will be happy to receive any help.
You can do this using row_number() -- twice:
select t.id, min(number)
from (select t.*,
row_number() over (partition by id order by number desc) as seqnum1,
row_number() over (partition by id, address order by number desc) as seqnum2
from t
) t
where seqnum1 = seqnum2
group by id;
What this does is enumerate the rows by number in descending order:
Once per id.
Once per id and address.
These values are the same only when the value is 1, which is the most recent address in the data. Then aggregation pulls back the earliest row in this group.
I answered my question myself, if anyone needs it, my solution:
select * from table dh1 where dh1.number = (
select max(x.number)
from (
select
dh2.id, dh2.number, dh2.address, lag(dh2.address) over(order by dh2.number asc) as prev
from table dh2 where dh1.id=dh2.id
) x
where NVL(x.address, 0) <> NVL(x.prev, 0)
);
I'm trying to find an efficient way to derive the column Expected below from only Id and State. What I want is for the number Expected to increase each time State is 0 (ordered by Id).
+----+-------+----------+
| Id | State | Expected |
+----+-------+----------+
| 1 | 0 | 1 |
| 2 | 1 | 1 |
| 3 | 0 | 2 |
| 4 | 1 | 2 |
| 5 | 4 | 2 |
| 6 | 2 | 2 |
| 7 | 3 | 2 |
| 8 | 0 | 3 |
| 9 | 5 | 3 |
| 10 | 3 | 3 |
| 11 | 1 | 3 |
+----+-------+----------+
I have managed to accomplish this with the following SQL, but the execution time is very poor when the data set is large:
WITH Groups AS
(
SELECT Id, ROW_NUMBER() OVER (ORDER BY Id) AS GroupId FROM tblState WHERE State=0
)
SELECT S.Id, S.[State], S.Expected, G.GroupId FROM tblState S
OUTER APPLY (SELECT TOP 1 GroupId FROM Groups WHERE Groups.Id <= S.Id ORDER BY Id DESC) G
Is there a simpler and more efficient way to produce this result? (In SQL Server 2012 or later)
Just use a cumulative sum:
select s.*,
sum(case when state = 0 then 1 else 0 end) over (order by id) as expected
from tblState s;
Other method uses subquery :
select *,
(select count(*)
from table t1
where t1.id < t.id and state = 0
) as expected
from table t;
select top 20 *
from dbo.DUTs D
inner join dbo.Statuses S on d.StatusID = s.StatusID
where s.Description = 'Active'
Above SQL Query returns the top 20 rows, how can I get a nth row from the result of the above query? I looked at previous posts on finding the nth row and was not clear to use it for my purpose.
Thanks.
The row order is arbitrary, so I would add an ORDER BY expression. Then, you can do something like this:
SELECT TOP 1 * FROM (SELECT TOP 20 * FROM ... ORDER BY d.StatusID) AS d ORDER BY d.StatusID DESC
to get the 20th row.
You can also use OFFSET like:
SELECT * FROM ... ORDER BY d.StatusID OFFSET 19 ROWS FETCH NEXT 1 ROWS ONLY
And a third option:
SELECT * FROM (SELECT *, rownum = ROW_NUMBER() OVER (ORDER BY d.StatusID) FROM ...) AS a WHERE rownum = 20
I tend to use CTEs with the ROW_NUMBER() function to get my lists numbered in order. As #zambonee said, you'll need an ORDER BY clause either way or SQL can put them in a different order every time. It doesn't usually, but without ordering it yourself, you're not guaranteed to get the same thing twice. Here I'm assuming there's a [DateCreated] field (DATETIME NOT NULL DEFAULT GETDATE()), which is usually a good idea so you know when that record was entered. This says "give me everything in that table and add a row number with the most recent record as #1":
; WITH AllDUTs
AS (
SELECT *
, DateCreatedRank = ROW_NUMBER() OVER(ORDER BY [DateCreated] DESC)
FROM dbo.DUTs D
INNER JOIN dbo.Statuses S ON D.StatusID = S.StatusID
WHERE S.Description = 'Active'
)
SELECT *
FROM AllDUTs
WHERE AllDUTs.DateCreatedRank = 20;
SELECT * FROM (SELECT * FROM EMP ORDER BY ROWID DESC) WHERE ROWNUM<11
It's another sample:
SELECT * ,CASE WHEN COUNT(0)OVER() =ROW_NUMBER()OVER(ORDER BY number) THEN 1 ELSE 0 END IsNth
FROM (
select top 10 *
from master.dbo.spt_values AS d
where d.type='P'
) AS t
+------+--------+------+-----+------+--------+-------+
| name | number | type | low | high | status | IsNth |
+------+--------+------+-----+------+--------+-------+
| NULL | 0 | P | 1 | 1 | 0 | 0 |
| NULL | 1 | P | 1 | 2 | 0 | 0 |
| NULL | 2 | P | 1 | 4 | 0 | 0 |
| NULL | 3 | P | 1 | 8 | 0 | 0 |
| NULL | 4 | P | 1 | 16 | 0 | 0 |
| NULL | 5 | P | 1 | 32 | 0 | 0 |
| NULL | 6 | P | 1 | 64 | 0 | 0 |
| NULL | 7 | P | 1 | 128 | 0 | 0 |
| NULL | 8 | P | 2 | 1 | 0 | 0 |
| NULL | 9 | P | 2 | 2 | 0 | 1 |
+------+--------+------+-----+------+--------+-------+
I am trying to use union for merging two output but these rows value are different.I need different rows value are zero.like output(third) table.I was struggle with pass two days please help me.
Select t1.round,
t1.SC,
t1.ST,
t1.OTHERS,
t2.round_up,
t2.SC_up,
t2.ST_up,
t2.OTHERS_up
From
(Select round as round,
Sum (non_slsc_qty) as SC,
Sum (non_slst_qty) as ST,
Sum (non_slot_qty) as OTHERS
FROM vhn_issue
where (date between '2015-08-01' and '2015-08-31')AND
dvn_cd='15' AND phc_cd='012' AND hsc_cd='05' GROUP BY round) t1
,
(Select round as round_up,
Sum (non_slsc_qty) as SC_up,
Sum (non_slst_qty) as ST_up,
Sum (non_slot_qty) as OTHERS_up,
FROM vhn_issue
where (date between '2015-04-01' and '2015-08-31')AND
dvn_cd='15' AND phc_cd='012' AND hsc_cd='05' GROUP BY round) t2
This first table result
+-----------------------------------+------------+--------+--------
| round | SC | ST | OTHERS |
+-----------------------------------+------------+--------+--------
| 1 | 20 | 30 | 50 |
| | | | |
| | | | |
+-----------------------------------+------------+--------+--------+
This is second table result
+-----------------------------------+------------+--------+----------
| round_up | SC_up | ST_up | OTHERS_up |
+-----------------------------------+------------+--------+-----------
| 1 | 21 | 31 | 51 |
| 3 | 10 | 5 | 2 |
| | | | |
+-----------------------------------+------------+--------+--------+---
I need output like this
+------------+--------+----------------------------------------------
| round_up | SC | ST |OTHERS | SC_up | ST_up |OTHERS_up |
+------------+--------+-----------------------------------------------
| 1 | 20 | 30 | 50 | 21 | 31 | 51 |
| | | | | | | |
| 3 | 0 | 0 | 0 | 10 | 5 | 2 |
+------------+--------+--------+---------------------------------------
You can use WITH Queries (Common Table Expressions) to wrap the two selects and use RIGHT JOIN to get the desired output,COALESCE is used to print 0 instead of NULL.
WITH a
AS (
SELECT round AS round
,Sum(non_slsc_qty) AS SC
,Sum(non_slst_qty) AS ST
,Sum(non_slot_qty) AS OTHERS
FROM vhn_issue
WHERE (
DATE BETWEEN '2015-08-01'
AND '2015-08-31'
)
AND dvn_cd = '15'
AND phc_cd = '012'
AND hsc_cd = '05'
GROUP BY round
)
,b
AS (
SELECT round AS round_up
,Sum(non_slsc_qty) AS SC_up
,Sum(non_slst_qty) AS ST_up
,Sum(non_slot_qty) AS OTHERS_up
,
FROM vhn_issue
WHERE (
DATE BETWEEN '2015-04-01'
AND '2015-08-31'
)
AND dvn_cd = '15'
AND phc_cd = '012'
AND hsc_cd = '05'
GROUP BY round
)
SELECT coalesce(b.round_up, 0) round_up
,coalesce(a.sc, 0) sc
,coalesce(a.st, 0) st
,coalesce(a.others, 0) others
,coalesce(b.sc_up, 0) sc_up
,coalesce(b.st_up, 0) st_up
,coalesce(b.others_up, 0) others_up
FROM a
RIGHT JOIN b ON a.round = b.round_up
WITH Results_CTE AS
(
Select t1.round as round_up ,
t1.SC as SC,
t1.ST as ST,
t1.OTHERS as OTHERS,
0 as SC_up,
0 as ST_up,
0 as OTHERS_up
from round t1
union all
t2.round_up as round_up ,
0 as SC,
0 as ST,
0 as OTHERS,
t2.SC_up,
t2.ST_up,
t2.OTHERS_up from round t2
)
select round_up , sum(SC) as SC,sum (ST) as ST, sum(OTHERS) as OTHERS, sum(SC_up) as SC_up, sum(ST_up) as ST_up, sum(OTHERS_up) as OTHERS_ up
from Results_CTE group by round_up
I'm using Oracle SQL, and i need some help with a query. I have no idea how to do that.
I have the following table (table_a):
Mortgage_ID (int)
Doc_ID (int)
Status (varchar)
Each document can be sent many times for the same mortgage.
From the table above i've made the following table (table_b):
Rank (int)
Document_type (int)
Count (int)
This table is containing the global count of the top 40 popular documents from table_a (regardless the status). For example:
Rank | Doc_ID | count
--------------------------
1 | 212121 | 90
2 | 555111 | 82
3 | 4567654 | 76
. | . | .
. | . | .
. | . | .
40 | 54321 | 22
Now i need to create the following table: For each mortgage from table_a, I need the count of the documents that has been sent for each one of the top 40 documents with the status "OK".
For example:
Mortgage_id | Pop1 | Pop2 | Pop3 | ... | Pop40
-------------------------------------------------
123 | 50 | 21 | 30 | ... | 6
555 | 70 | 0 | 21 | ... | 40
654 | 100 | 96 | 58 | ... | 0
Pop1 doc (the most popular document) has been sent 50 times with the status "OK" for Mortgage_ID 123. Pop2 has been sent 21 times with status "OK" for Mortgage_id 123 and so on.
I hope the description is clear enough. Is anyone knows how to do that?
Basically, this is a join to combine the two tables and then a pivot. In this case, I would use conditional aggregation. So, I think this is what you are looking for:
select a.mortgage_id,
sum(case when b.rank = 1 then 1 else 0 end) as pop1,
sum(case when b.rank = 2 then 1 else 0 end) as pop2,
. . .
sum(case when b.rank = 40 then 1 else 0 end) as pop40
from table_b b join
table_a a
on b.doc_id = a.doc_id
group by a.mortgage_id;
Try this:
select *
from (select ta.Mortgage_ID, rank, cnt
from table_a ta, table_b tb
where ta.doc_id = tb.doc_id
)
pivot (
sum(cnt)
for rank in (1 pop1,2 pop2,3 pop3,4 pop4,5 pop5)
)
MORTGAGE_ID POP1 POP2 POP3 POP4 POP5
----------- ---------- ---------- ---------- ---------- ----------
1 20
2 40
5 10
4 5
3 30
SQLFiddle