I have full name that contains blank or null value and cause an error when I split into first name,lastname.
here is the error:
ERROR [22011] [IBM][DB2/AIX64] The statement was not executed because a numeric argument of a scalar function is out of range.
here is my original code:
UPPER(right(AGENT_NM, (char_length (AGENT_NM) - position( ' ', AGENT_NM))))|| ', ' || UPPER(left(AGENT_NM, position( ' ', AGENT_NM) - 1)) AS AGENT_NAME,
here is what I have tried:
1-
CASE when REGEXP_COUNT(AGENT_NM,',')> 0 then left (AGENT_NM, position( ' ', AGENT_NM) - 1) END AS FNAME,
2-
CASE when(AGENT_NM= ' ') then Null Else left (AGENT_NM, position( '
> ', AGENT_NM) - 1) END AS FNAME,
However it returns blank.
Concatenate a space onto the end of your name first:
SELECT
TRIM(UPPER(RIGHT(AGENT_NMs, char_length (AGENT_NMs) - position( ' ', AGENT_NMs))))||
', ' ||
TRIM(UPPER(left(AGENT_NMs, position( ' ', AGENT_NMs) - 1)))
AS AGENT_NAME
FROM
(
SELECT
a.*,
COALESCE(agent_nm, '')||' ' as agent_nms
FROM
yourtable a
) x
Here we use coalesce to ensure the name is not null, and we then add a space on as something for the position function to find
The top bit is just your code tweaked to refer to the new name agent_nms and add an extra trim command for removing any extraneous spaces. It did look like it had one too many brackets in by the way
name=str(input("your name here"))
split_name=name.split(" ")
Related
I have a query that returns some demographics like firstName, lastName, MiddleName and i need to use LEFT function on each to filter the First Letter of each column like LEFt(firstName, 1).This is working fine when each column is not a null value. when it is null value
select otherColumns, LEFT(sub.LastName, 1) + ',' + LEFT(sub.FirstName, 1) + ' ' + LEFT(sub.MiddleName, 1) as patientInitials from <table> <inner joins> <some where conditions>;
But when one of demographics like middleName is null and other firstName, lastName are not null , patientInitials are evaulating to NULL, not sure why?
I resolved my issue by adding COALESCE
LEFT(sub.LastName, 1) + ',' + LEFT(sub.FirstName, 1) + ' ' + COALESCE((LEFT(sub.MiddleName, 1)),'') as patientInitials
But is there any other good way to check for notNull on the LEFT function ??
Help Appreciated!
But is there any other good way to check for notNull on the LEFT function ??
CONCAT function ignores NULLs:
SELECT CONCAT(LEFT(sub.LastName, 1), ',' ,
LEFT(sub.FirstName, 1),
' ' + LEFT(sub.MiddleName, 1)) patientInitials
FROM tab;
' ' + LEFT(sub.MiddleName, 1)) using ' ' will remove leading space in case if Middle Name is NULL.
The CONCAT_WS function also has a similar function：CONCAT_WS (Transact-SQL)
I am trying to separate a name field into the appropriate fields. The name field is not consistently the same. It can show up as Doe III,John w or Doe,John, or Doe III,John, or Doe,John W or it may be lacking the suffix and or middle initial. Any ideas would be greatly appreciated.
SELECT (
CASE LEN(REPLACE(FirstName, ' ', ''))
WHEN LEN(FirstName + ' ') - 1
THEN PARSENAME(REPLACE(FirstName, ' ', '.'), 2)
ELSE PARSENAME(REPLACE(FirstName, ' ', '.'), 3)
END
) AS LastName
,(
CASE LEN(REPLACE(FirstName, ' ', ''))
WHEN LEN(FirstName + ',') - 1
THEN NULL
ELSE PARSENAME(REPLACE(FirstName, ' ', '.'), 2)
END
) AS Suffix
,PARSENAME(REPLACE(FirstName, ' ', '.'), 1) AS FirstName
FROM Trusts.dbo.tblMember
I need the name regardless of the format, as stated above, to parse into the appropriate fields of LastName,Suffix,FirstName,MiddleInitial, regardless of whether it has a suffix or a middle initial
If the given 4 names are the only type of cases, then you can use something like below.
Note: I used a CTE table tbl2 to separate comma_pos,first_space,second_space for better understanding in the main query. You can replace these value in main query with their corresponding function in CTE, to make the main query faster. I mean replace comma_pos in main query with charindex(',',name) an so on.
Also I am assuming that there are no leading/trailing or extra whitespaces or any junk character in name column. If you have, then sanitize your data first before proceeding.
Rexter Sample
with tbl2 as (
select tbl.*,
charindex(',',name) as comma_pos,
charindex(' ',name,1) first_space,
charindex(' ',name,charindex(' ',name,1)+1) second_space
from tbl)
select tbl2.name
,case when second_space <> 0
then substring(name,comma_pos+1,second_space-comma_pos-1)
when first_space > comma_pos
then substring(name,comma_pos+1,first_space-comma_pos-1)
else substring(name,comma_pos+1,len(name)-comma_pos)
end as first_name
,case when second_space <> 0
then substring(name,second_space+1,len(name)-second_space)
when first_space > comma_pos
then substring(name,first_space+1,len(name)-first_space)
end as middle_name
,case when first_space=0 or first_space>comma_pos
then substring(name,1,comma_pos-1)
else substring(name,1,first_space-1)
end as last_name
,case when first_space=0 or first_space>comma_pos
then null
else substring(name,first_space,comma_pos-first_space)
end as suffix
from tbl2;
My SELECT statement reads something like this:
SELECT JKLL.LKJJ, LKJF.ASLKD, TRIM (ADDR.UNNBR) || ' ' || TRIM(ADDR.PREDIR) || ' ' ||, TRIM(ADDR.STREET)....
Where UNNBR is the address number and PREDIR is the predirection (NSEW).
When concatenating into the same column, if predir is null, I get two spaces between UNNBR and STREET, obviously.
Can I use a case statement to eliminate this space when PREDIR is null? If so, what would that syntax look like?
I sometimes do something like this for these situations:
(TSQL syntax)
SELECT
CASE WHEN ADDR.UNNBRIS IS NOT NULL THEN ADDR.UNNBR + ' ' ELSE '' END +
CASE WHEN ADDR.PREDIR IS NOT NULL THEN ADDR.PREDIR + ' ' ELSE '' END +
...
This way you only get the space if the field isn't null.
I would use ISNULL
SELECT JKLL.LKJJ, LKJF.ASLKD, TRIM(ADDR.UNNBR) + ISNULL(' ' + TRIM(ADDR.PREDIR),'') ...
A NULL value concatenated to anything yields a NULL. So something like this will work:
WITH ex as
(SELECT 'Pants' as item, null as other, 'George' as name)
SELECT COALESCE(item + ' ', '')
+ COALESCE(other + ' ', '')
+ COALESCE(name + ' ', '')
FROM ex
I am able to extract the first word from a string, using ANSI SQL, like this:
SELECT SUBSTRING(name FROM 1 FOR POSITION(' ' IN name)) AS first_name
However, if the original string is only one word long (ie, if there is no space), it returns an empty substring.
How can the above query be adapted to solve this problem?
Thanks in advance.
I'm sure there is a cleaner way to do it, but this works.
DECLARE #tbl TABLE (i varchar(100));
INSERT INTO #tbl ( i )
VALUES ('hello'), ('hello space here');
SELECT *,
SUBSTRING(i, 0, CASE CHARINDEX(' ', i)
WHEN 0 THEN LEN(i) + 1
ELSE CHARINDEX(' ', i)
END)
FROM #tbl
Simply but messy solution - add a space on the end:
SELECT SUBSTRING((name || ' ') FROM 1 FOR POSITION(' ' IN (name || ' '))) AS first_name
Use a conditional if statement.
For a MySQL/SQL Server answer:
SELECT IF(INSTR(name, ' ') >0, LEFT(name, INSTR(name, ' ') - 1), name) AS firstname
For Oracle:
SELECT IF(INSTRB(name, ' ', 1, 1) >0, SUBSTR(name, 1, INSTRB(name, ' ', 1, 1) - 1), name) AS firstname
I personally prefer the Regexp query for this, but below query also works.
You basically append a space at the end of the string and search for the position of the space using INSTR.
ORACLE:
select substr(Var1, 0,INSTR(Var1||' ',' ')) from table-name;
Replace Var1 with the column-name or string you are evaluating.
Put Column Name in place of #foo
DECLARE #Foo VARCHAR(50) = 'One Two Three'
SELECT
CASE
--For One Word
WHEN CHARINDEX(' ', #Foo, 1) = 0 THEN #Foo
--For multi word
ELSE SUBSTRING(#Foo, 1, CHARINDEX(' ', #Foo, 1) - 1)
END
DECLARE #test VARCHAR(50) = 'One Two Three'
SELECT SUBSTRING(LTRIM(#test),1,(CHARINDEX(' ',LTRIM(#test) + ' ')-1))
you can use this to get the first word of a string.initcap
will get you the first letter capital.
SELECT SUBSTR(column_1, 1, INSTR(column_1, ' ', 1,1) ) FROM table_name WHERE column_1= initcap('your string');
I need to concatenate the City, State and Country columns into something like City, State, Country.
This is my code:
Select City + ', ' + State + ', ' + Country as outputText from Places
However, because City and State allow null (or empty) value, what happen is, (for example) if the City is null/empty, my output will look like , Iowa, USA; or say the State is empty, then the output will look like Seattle, , USA
Is there anyway I can format the output and remove "unnecessary" commas?
Edited: Because of the requirements, I should not use any other mean (such as PL/SQL, Store Procedure) etc., so it has to be plain SQL statement
select
isnull(City, '') +
case when isnull(City, '') != '' then ', ' else '' end +
isnull(State, '') +
case when isnull(State, '') != '' then ', ' else '' end +
isnull(Country, '') as outputText
from
Places
Since adding a string with null will result null so if they are null (not empty string) this will give you teh desired result
Select isnull(City + ', ','') + isnull(State + ', ' ,'') + isnull(Country,'') as outputText from Places
Use the COALESCE (Transact-SQL) function.
SELECT COALESCE(City + ', ', '') + COALESCE(State + ', ', '')...
In SQL Server 2012 you can use CONCAT function:
select concat(City,', ',State,', ',Country ) as outputText from Places
Not elegant by any means...
first changes city, state,country to null values if blank
then interprets that value for null and adds a space before a comma
then replaces any space comma space ( , ) with empty set.
Query:
SELECT replace(coalesce(Replace(City,'',Null),' ') + ', ' +
coalesce(Replace(State,'',Null), ' ' + ', ' +
coalesce(replace(Country,''Null),''), ' , ','') as outputText
FROM Places
Assumes no city state or country will contain space comma space.