Query SQL with similar values - sql

Question

I have to make a query to a base using as a comparison a string like this 12345678, but the value to compare is this way12.345.678, if I do the following query it does not return anything.
SELECT * FROM TABLA WHERE CAMPO = '12345678'
Where CAMPO would have the value of (12.345.678), if I replace = with a like, it does not return the data either
SELECT * FROM TABLA WHERE CAMPO like '12345678%'
SELECT * FROM TABLA WHERE CAMPO like '%12345678'
SELECT * FROM TABLA WHERE CAMPO like '%12345678%'
None of the 3 previous consultations works for me, how can I make this query?
The value can be of either 7, 8 or 9 numbers and the. It has to be every 3 from the end to the beginning

Answer 1

Use REPLACE() function to replace all the dots '.' as
SELECT *
FROM(
VALUES ('12.345.678'),
('23.456.789')
) T(CAMPO)
WHERE REPLACE(CAMPO, '.', '') = '12345678';
Your query should be
SELECT * FROM TABLA WHERE REPLACE(CAMPO, '.', '') = '12345678';

Answer 2

You can compare the string without the dots to a REPLACE(StringWithDots, '.','')

Answer 3

I recommend you to convert the number to numeric
So you can use < and > operators and all functions that require you to have a number...
the best way to achieve this is to make sure you remove any unecessary dots and convert the commas to dots. like this
CONVERT(NUMERIC(10, 2),
REPLACE(
REPLACE('7.000,45', '.', ''),
',', '.'
)
)
I hope this will help you out.

Answer 4

A SARGABLE solution would be to write a function that takes your target value ('12345678') and inserts the separators ('.') every third character from right to left. The result ('12.345.678') can then be used in a where clause and benefit from an index on CAMPO.
The following code demonstrates an approach without creating a user-defined function (UDF). Instead, a recursive common table expression (CTE) is used to process the input string three characters at a time to build the dotted target string. The result is used in a query against a sample table.
To see the results from the recursive CTE replace the final select statement with the commented select immediately above it.
-- Sample data.
declare #Samples as Table ( SampleId Int Identity, DottedDigits VarChar(20) );
insert into #Samples ( DottedDigits ) values
( '1' ), ( '12' ), ( '123' ), ( '1.234' ), ( '12.345' ),
( '123.456' ), ( '1.234.567' ), ( '12.345.678' ), ( '123.456.789' );
select * from #Samples;
-- Query the data.
declare #Target as VarChar(15) = '12345678';
with
Target as (
-- Get the first group of up to three characters from the tail of the string ...
select
Cast( Right( #Target, 3 ) as VarChar(20) ) as TargetString,
Cast( Left( #Target, case when Len( #Target ) > 3 then Len( #Target ) - 3 else 0 end ) as VarChar(20) ) as Remainder
union all
-- ... and concatenate the next group with a dot in between.
select
Cast( Right( Remainder, 3 ) + '.' + TargetString as VarChar(20) ),
Cast( Left( Remainder, case when Len( Remainder ) > 3 then Len( Remainder ) - 3 else 0 end ) as VarChar(20) )
from Target
where Remainder != ''
)
-- To see the intermediate results replace the final select with the line commented out below:
--select TargetString from Target;
select SampleId, DottedDigits
from #Samples
where DottedDigits = ( select TargetString from Target where Remainder = '' );
An alternative approach would be to add a indexed computed column to the table that contains Replace( CAMPO, '.', '' ).

Answer 5

If the table containing IDs like 12.345.678 is big (contains many records), I would add a computed field that removes the dots (and if this ID does never contain any alphanumeric characters other than dots and has no significant leading zeros then also cast it in an INT or BIGINT) and persist it and lay an index over it. That way you loose a little time when inserting the record but are querying it with maximum speed and therefore saving processor power.