How to SUM column 1 and select column 2 by condition? - sql

Question

I've stuck with how to sum column A and select column B with a condition if column B >= 50 select this row id.
Example Table Like this
+----+-----------+---------+
| ID | PRICE | PERCENT |
+----+-----------+---------+
| 1 | 5 | 5 |
| 2 | 18 | 20 |
| 3 | 7 | 50 |
| 4 | 16 | 56 |
| 5 | 50 | 87 |
| 6 | 17 | 95 |
| 7 | 40 | 107 |
+----+-----------+---------+
SELECT ID, SUM(PRICE) AS PRICE, PERCENT FROM Table
Column ID and PERCENT, I want to select from a row with PERCENT >= 50
The result should be
Any suggestions?

Answer 1

Try below query:
declare #tbl table(ID int, PRICE int, [PERCENT] int);
insert into #tbl values
(1, 5, 5),
(2, 18, 20),
(3, 7, 50),
(4, 16, 56),
(5, 50, 87),
(6, 17, 95),
(7, 40, 107);
select top 1 ID,
(select sum(PRICE) from #tbl) PRICE,
[PERCENT]
from #tbl
where [PERCENT] > 50

Answer 2

You could include the total in a subquery in the SELECT clause of your query like this:
SELECT
[ID],
(SELECT SUM([PRICE]) FROM T) AS [PRICE],
[PERCENT]
FROM
T
WHERE
[PRICE] >= 50
However, it remains unclear which of the five valid records should be picked. You indicated it should be the record where PERCENT has value 56, but IMHO value 50 would be possible too, just like 87, 95, and 107 (?). It is unclear why you pick value 56 as the correct one. If it doesn't matter, you could use TOP (1) in the SELECT clause, but if it does matter, you should extend the WHERE clause with appropriate conditions/filters.
Mixing aggregate data from groups back with individual elements/records like this is often fuzzy. I consider it to be a "code smell" and here in your question on StackOverflow, it might indicate an XY-problem. Anyway, these query results might get misinterpreted quite easily if you are not careful. Always remember that such aggregated data in the result (in this case the PRICE field) has practically nothing to do with the detail data in the result (in this case the ID and PERCENT fields). Unless you want to combine your aggregate data with your detail data (in a calculation for example), but you do not indicate you want anything like that in your question...

Answer 3

you can do this Trick to have a result of 2 queries in 1 query:
select ID as ID,T.[PERCENT] AS B, 0 as sumA
from Table_1 as T
where T.[PERCENT]>=50
union All
select 0 as ID,0 AS B, sum(t.[PRICE]) as sumA
from Table_1 as T

Answer 4

Am not sure why you need this but certainly, You can Archive Above Output using below query
Sample Data
declare #data table
(Id int, Price int, [Percent] int)
insert #data
VALUES (1,5,5),
(2,18,20),
(3,7,50),
(4,16,56),
(5,50,87),
(6,17,95),
(7,40,107)
Query
select top 1 ID, (select sum(price) from #data) as Price, [Percent ]
from #data
where [Percent ] >50

Answer 5

You can try the following code:
SELECT TOP (1) [ID], SUM(PRICE) OVER (), [PERCENT]
FROM #tbl
ORDER BY CASE WHEN [PERCENT] > 50 THEN 0 ELSE 1 END, [ID];
I am using OVER clause in order to extract/read data from the table only once - one table scan.