how to join 2 tables in SQL oracle - sql

Question

please help me, I want to join from skyteam1 (ID 1, comno 1, ename Boeing737, country USA)
into comm1 (id 1, comno (all), ename (all), ddate(all), SUM (total price) of the aircraft
SQL> SELECT * FROM SKYTEAM1;
ID; COMNO; ENAME; COUNTRY;
1 1 Boeing737 USA
2 2 Boeing777 USA
3 3 AirBus320 RUSSIA
SQL> SELECT * FROM COMM1;
ID; COMNO; ENAME; DDATE; SAL; DEPTNO;
1 1 Engine 20.02.81 900 20
1 2 Wings 22.02.81 35000 30
1 3 Battery 09.06.81 84800 20
1 4 APU 17.11.81 8400 10
1 5 EECU 03.12.81 8400 20
1 6 Generator 23.01.82 40000 20
EXAMPLE;
I need this ANSWER
ID; COMNO; ENAME; ENAME; DDATE; SAL; SUM_TOTAL;
1 1 Boeing737 Engine 20.02.81 900
2 Wings 22.02.81 35000
3 Battery 09.06.81 84800
4 APU 17.11.81 8400
5 EECU 03.12.81 8400
6 Generator 23.01.82 40000 17750;

Answer 1

Here's an example:
SQL> with skyteam1 (id, comno, ename) as
2 (select 1, 1, 'boeing 737' from dual union all
3 select 2, 2, 'boeing 777' from dual union all
4 select 3, 3, 'airbus 320' from dual
5 ),
6 comm1 (id, comno, ename, ddate, sal) as
7 (select 1, 1, 'engine', '20.02.81', 900 from dual union all
8 select 1, 2, 'wings', '22.02.81', 35000 from dual union all
9 select 1, 3, 'battery', '09.06.81', 84800 from dual union all
10 select 1, 4, 'apu', '17.11.81', 8400 from dual union all
11 select 1, 5, 'eecu', '03.12.81', 8400 from dual union all
12 select 1, 6, 'generator', '23.01.81', 40000 from dual
13 )
14 select c.id,
15 c.comno,
16 s.ename,
17 c.ename,
18 c.ddate,
19 c.sal,
20 sum(c.sal) over (order by null) total
21 from skyteam1 s join comm1 c on c.id = s.id
22 where s.id = 1
23 order by c.comno;
ID COMNO ENAME ENAME DDATE SAL TOTAL
---------- ---------- ---------- --------- -------- ---------- ----------
1 1 boeing 737 engine 20.02.81 900 177500
1 2 boeing 737 wings 22.02.81 35000 177500
1 3 boeing 737 battery 09.06.81 84800 177500
1 4 boeing 737 apu 17.11.81 8400 177500
1 5 boeing 737 eecu 03.12.81 8400 177500
1 6 boeing 737 generator 23.01.81 40000 177500
6 rows selected.
SQL>
Depending on a tool you use, it can be made prettier. For example, in SQL*Plus:
SQL> break on id on s_ename
SQL> compute sum of sal on id
SQL>
SQL> with skyteam1 (id, comno, ename) as
2 (select 1, 1, 'boeing 737' from dual union all
3 select 2, 2, 'boeing 777' from dual union all
4 select 3, 3, 'airbus 320' from dual
5 ),
6 comm1 (id, comno, ename, ddate, sal) as
7 (select 1, 1, 'engine', '20.02.81', 900 from dual union all
8 select 1, 2, 'wings', '22.02.81', 35000 from dual union all
9 select 1, 3, 'battery', '09.06.81', 84800 from dual union all
10 select 1, 4, 'apu', '17.11.81', 8400 from dual union all
11 select 1, 5, 'eecu', '03.12.81', 8400 from dual union all
12 select 1, 6, 'generator', '23.01.81', 40000 from dual
13 )
14 select c.id,
15 c.comno,
16 s.ename s_ename,
17 c.ename c_ename,
18 c.ddate,
19 c.sal
20 from skyteam1 s join comm1 c on c.id = s.id
21 where s.id = 1
22 order by c.comno;
ID COMNO S_ENAME C_ENAME DDATE SAL
---------- ---------- ---------- --------- -------- ----------
1 1 boeing 737 engine 20.02.81 900
2 wings 22.02.81 35000
3 battery 09.06.81 84800
4 apu 17.11.81 8400
5 eecu 03.12.81 8400
6 generator 23.01.81 40000
********** ********** ----------
sum 177500
6 rows selected.
SQL>