compare count columns not recognized - sql

Question

I have some Columns whose values depend on sums for the row info. However, when I get to the where statement, it won't let me compare those values so I can just display the ones with issues. See comment *** in query for issue.
This is what my query looks like:
SELECT
DISTINCT
p.ID
,p.Last
,p.First
,SUM(distinct CASE WHEN pf.facility in ('S','H','E') then 1 ELSE 0 END) as facility_count
,SUM(distinct CASE WHEN (fs.ques_id = 59 AND pf.facility in ('S','H','E') ) THEN 1 ELSE 0 END) AS sum_qst_59
FROM person p
inner JOIN person_facilities pf ON p.ID = pf.ID
LEFT JOIN dbo.ADD_ANSW fs ON p.id = fs.id
WHERE
pf.Facility in ('s', 'h', 'e')
AND
pf.status in ('Active')
AND
facility_count != sum_qst_59 ***--this doesn't work. Says no such columns***
group by p.id, Last, First
order by Last
I saw compare counts, but I can't figure out how to get that to work for my query and output. Any help would be appreciated.
In other words, there are people that belong in multiple facilities (which I'm counting their facilities for each person). Plus I'm counting how many times they have answer 59 for those same facilities. Then I'm comparing the counts because they should be the same if they answered it for all facilities. Then I'm finding where the counts don't match so we can fix it.
*Update -
I'm trying what was suggested but it has the error
Incorrect syntax near keyword 'having'
SELECT
DISTINCT
p.ID
,p.Last
,p.First
--change in having and sum line below
,having SUM(distinct CASE WHEN pf.facility in ('S','H','E') then 1 ELSE 0 END) as facility_count
<>
SUM(distinct CASE WHEN (fs.ques_id = 59 AND pf.facility in ('S','H','E') ) THEN 1 ELSE 0 END) AS sum_qst_59
FROM person p
inner JOIN person_facilities pf ON p.ID = pf.ID
LEFT JOIN dbo.ADD_ANSW fs ON p.id = fs.id
WHERE
pf.Facility in ('s', 'h', 'e')
AND
pf.status in ('Active')
group by p.id, Last, First
order by Last
Update 2: Also tried the following but still incorrect syntax near having -
SELECT
DISTINCT
p.ID
,p.Last
,p.First
,SUM(distinct CASE WHEN pf.facility in ('S','H','E') then 1 ELSE 0 END) as facility_count
,SUM(distinct CASE WHEN (fs.ques_id = 59 AND pf.facility in ('S','H','E') ) THEN 1 ELSE 0 END) AS sum_qst_59
FROM person p
inner JOIN person_facilities pf ON p.ID = pf.ID
LEFT JOIN dbo.ADD_ANSW fs ON p.id = fs.id
WHERE
pf.Facility in ('s', 'h', 'e')
AND
pf.status in ('Active')
--change in having and sum line below
AND --this has incorrect syntax near having
having SUM(distinct CASE WHEN pf.facility in ('S','H','E') then 1 ELSE 0 END)
<>
SUM(distinct CASE WHEN (fs.ques_id = 59 AND pf.facility in ('S','H','E') ) THEN 1 ELSE 0 END)
group by p.id, Last, First
order by Last

Answer 1

Column aliases cannot be used to reference expressions in a WHERE clause. But even if they could you'd be wrong as filters that should take place after aggregation have to be put in a HAVING clause.
Try:
...
HAVING sum(CASE
WHEN pf.facility IN ('S','H','E') THEN
1
ELSE
0
END)
<>
sum(CASE
WHEN fs.ques_id = 59
AND pf.facility IN ('S','H','E') THEN
1
ELSE
0
END)
...
sum(DISTINCT ...) also doesn't seem to make sense. And the DISTINCT in the outer SELECT also could be useless.