I have a table that save personnel code.
When I select from this table I get 3 rows result such as:
2129,3394,3508,3534
2129,3508
4056
I want when create select result combine in one row such as:
2129,3394,3508,3534,2129,3508,4056
or distinct value such as:
2129,3394,3508,3534,4056
You should ideally avoid storing CSV data at all in your tables. That being said, for your first result set we can try using STRING_AGG:
SELECT STRING_AGG(col, ',') AS output
FROM yourTable;
Your second requirement is more tricky, and we can try going through a table to remove duplicates:
WITH cte AS (
SELECT DISTINCT VALUE AS col
FROM yourTable t
CROSS APPLY STRING_SPLIT(t.col, ',')
)
SELECT STRING_AGG(col, ',') WITHIN GROUP (ORDER BY CAST(col AS INT)) AS output
FROM cte;
Demo
I solved this by using STUFF and FOR XML PATH:
SELECT
STUFF((SELECT ',' + US.remain_uncompleted
FROM Table_request US
WHERE exclusive = 0 AND reqact = 1 AND reqend = 0
FOR XML PATH('')), 1, 1, '')
Thank you Tim
Related
I need to extract a comma separated list from the following:
Return should gives something like
1 : Route#1, Route#2
2 : Route#3, Route#4
3 : Route#5
4 : Route#6
I'm struggling with the STUFF function. So far I have:SELECT STUFF( (SELECT DISTINCT ';' + T4.[Outbound Trucks] FROM #TEMP4 T4 FOR XML PATH('') ),1,1,'') AS MasterRoutes
Result gives me
any help would be really appreciated.
thanks a lof for your time
If your sql server is 2017 or more :
SELECT dorno, STRING_AGG ([Outbound Trucks], ',') as CSV
FROM #TEMP4
GROUP BY dorno
Explanation Here
In you case you can eliminate doublon to like this:
with tmp as (
select distinct dorno, [Outbound Trucks] Truck from #TEMP4
)
SELECT dorno, STRING_AGG (Truck, ',') as CSV
FROM tmp
GROUP BY dorno
I have two comma-separated string which needs to be converted into a temptable with two columns synchronized based on the index.
If the input string as below
a = 'abc,def,ghi'
b = 'aaa,bbb,ccc'
then output should be
column1 | column2
------------------
abc | aaa
def | bbb
ghi | ccc
Let us say I have function fnConvertCommaSeparatedStringToColumn which takes in comma-separated string and delimiter as a parameter and returns a column with values. I use this on both strings and get two columns to verify if the count is the same on both sides. But it would be nice two have them in a single temp table. How can i do that?
Let us say I have function which ... returns a column with values.
At that point, the basic idea is to select the column and use the row_number() function with both of your strings. Then you can JOIN the two together using the row_number() result as the matching field for the join.
One method is a recursive CTE:
with cte as (
select convert(varchar(max), null) as a_part, convert(varchar(max), null) as b_part,
convert(varchar(max), 'abc,def,ghi') + ',' as a,
convert(varchar(max), 'aaa,bbb,ccc') + ',' as b,
0 as lev
union all
select convert(varchar(max), left(a, charindex(',', a) - 1)),
convert(varchar(max), left(b, charindex(',', b) - 1)),
stuff(a, 1, charindex(',', a), ''),
stuff(b, 1, charindex(',', b), ''),
lev + 1
from cte
where a <> '' and lev < 10
)
select a_part, b_part
from cte
where lev > 0;
Here is a db<>fiddle.
Here's something a bit sneaky you can try.
I don't have your bespoke function so have used the built-in string_split function (SQL2016+) - for quickly testing, but assuming the parameters are the same. Ideally, your bespoke function should return its own row number in which case you'd use that instead of a rownumber function.
declare #a varchar(20)='abc,def,ghi', #b varchar(20)='aaa,bbb,ccc';
with v as (
select a.value A,b.value B,
row_number() over(partition by a.value order by (select 1/0))Arn,
row_number() over(partition by b.value order by (select 1/0))Brn
from fnConvertCommaSeparatedStringToColumn (#a,',')a
cross apply fnConvertCommaSeparatedStringToColumn (#b,',')b
)
select A,B from v
where Arn=Brn
I would suggest getting a (set based) function that can split a string, based on a delimiter, that returns the ordinal position as well. For example DelimitedSplit8k_LEAD. Then you can trivially split the value, and JOIN on the ordinal position:
DECLARE #a varchar(100) = 'abc,def,ghi';
DECLARE #b varchar(100) = 'aaa,bbb,ccc';
SELECT A.Item AS A,
B.Item AS B
FROM dbo.delimitedsplit8k_lead(#a,',') A
FULL OUTER JOIN dbo.delimitedsplit8k_lead(#a,',') B ON A.ItemNumber = B.ItemNumber;
db<>fiddle
I use a FULL OUTER JOIN and then if either column has a NULL value you know that the 2 delimited lists don't have the same number of delimited values.
I need to transpose one of the columns in the data date to a row of string and group by 2 other columns. My sample data consists of the following data:
I need the result to look like this:
That is all the LNs in one row per Employee code, per day.
I tried the below code -
DECLARE #Process_Conditions_Loans VARCHAR(500)
SELECT
t1.EmplCode,
t1.LogDate,
#Process_Conditions_Loans = CONCAT(COALESCE(#Process_Conditions_Loans + ',', ''),PS2)
FROM
#temp t1
WHERE
LN IS NOT NULL
GROUP BY
EmplCode, LogDate
But I am getting an error
A SELECT statement that assigns a value to a variable must not be combined with data-retrieval operations.
I can not use group_concat since I am using SQL Server 2016.
Any help would be great appreciated.
Thanks,
JH
You can use the older form of string aggregation:
select emplcode, logdate,
stuff( (select concat(', ', ln)
from t
where t.emplcode = el.emplcode and t.logdate = el.logdate
order by ln
for xml path ('')
), 1, 2, ''
)
from (select distinct emplcode, logdate
from t
) el
I was testing a query in SQL in which I need to concatenate values in the form of a comma-separated list, and it works, I just have the problem of duplicate values.
This is the query:
SELECT t0.id_marcas AS CodMarca,
t0.nombremarcas AS NombreMarca,
t0.imagenmarcas,
(SELECT String_agg((t2.name), ', ')
FROM exlcartu_devcit.store_to_cuisine t1
INNER JOIN exlcartu_devcit.cuisine t2
ON t1.cuisine_id = t2.cuisine_id
WHERE store_id = (SELECT TOP 1 store_id
FROM exlcartu_devcit.store
WHERE id_marcas = t0.id_marcas
AND status = 1)) AS Descripcion,
t0.logo,
t0.imagen,
(SELECT TOP 1 preparing_time
FROM exlcartu_devcit.store
WHERE id_marcas = t0.id_marcas
AND status = 1) AS Tiempo,
t0.orden,
(SELECT TOP 1 Avg(minimum_amount)
FROM exlcartu_devcit.store_delivery_zone
WHERE id_marcas = t0.id_marcas) AS MontoMinimo
FROM exlcartu_devcit.[marcas] t0
I thought the solution could be just adding a DISTINCT to the query to avoid repeated values in this way ...
(SELECT STRING_AGG(DISTINCT (t2.name), ', ') AS Descripcion
But apparently the STRING_AGG() function does not support it, any idea how to avoid repeated values?
Simplest way is just select from select, like this:
with dups as (select 1 as one union all select 1 as one)
select string_agg(one, ', ') from (select distinct one from dups) q;
vs original
with dups as (select 1 as one union all select 1 as one)
select string_agg(one, ', ') from dups;
Table has a column with values
ColA
------
a.b.c.d.e (car.make.model, car.la, kg)
ab.cd.ef (car.make.model)
a1.b2.c3.d4.e5(car.make.model, car.la, kg, av.vc.de)
I want to write a sql query to split the ColA by delimiter "." and pick last but one.
Expected output
Result
------
d
cd
d4
I have tried ParseName but dont see option to pick last but one.
Thank you
Using Jeff Moden's DelimitedSplit8K:
USE Sandbox;
GO
CREATE TABLE #Sample (ColA varchar(500));
GO
INSERT INTO #Sample
VALUES ('a.b.c.d.e'),
('ab.cd.ef'),
('a1.b2.c3.d4.e5');
GO
SELECT *
FROM #Sample;
WITH Split AS(
SELECT S.ColA,
DS.*,
MAX(DS.ItemNumber) OVER (PARTITION BY S.ColA) AS Items
FROM #Sample S
CROSS APPLY DelimitedSplit8K(S.ColA,'.') DS)
SELECT Item
FROM Split
WHERE ItemNumber = Items - 1;
GO
DROP TABLE #Sample
Ideally, though, don't store your data in a delimited format. :)
Just to play around using STRING_SPLIT:
SELECT ColA, t.value
FROM table1
CROSS APPLY(SELECT value,
COUNT(*) OVER () as cnt,
ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS rn
FROM STRING_SPLIT(ColA, '.')) AS t
WHERE t.rn = t.cnt - 1
Note: The function is available from SQL Server 2016.
Note 2: The query works provided that the function returns each value in the same order as the one it appears inside the string.
Why not simply using substring?
DECLARE #ColA NVARCHAR(100) = 'a1.b2.c3.d4.e5(car.make.model, car.la, kg, av.vc.de)';
SELECT REVERSE(LEFT(RIGHT(REVERSE(LEFT(#ColA, CHARINDEX('(', #ColA)-1)), LEN(LEFT(#ColA, CHARINDEX('(', #ColA)-1))-CHARINDEX('.',REVERSE(LEFT(#ColA, CHARINDEX('(', #ColA)-1)))), CHARINDEX('.',RIGHT(REVERSE(LEFT(#ColA, CHARINDEX('(', #ColA)-1)), LEN(LEFT(#ColA, CHARINDEX('(', #ColA)-1))-CHARINDEX('.',REVERSE(LEFT(#ColA, CHARINDEX('(', #ColA)-1)))))-1))
However, this last edit does NOT handle the case when there is no . or no ( in the string - feel free t o extend the query accordingly
Try This
;WITH CTE(ColA)
AS
(
SELECT 'a.b.c.d.e' UNION ALL
SELECT 'ab.cd.ef' UNION ALL
SELECT 'a1.b2.c3.d4.e5'
)
SELECT ColA,REVERSE(SUBSTRING(ReqColA,0,CHARINDEX('.',(ColA)))) AS ReqColA
FROM
(
SELECT ColA ,SUBSTRING(REVERSE(ColA),CHARINDEX('.',REVERSE(ColA))+1,LEN(REVERSE(ColA))) AS ReqColA FROM CTE
)dt
Result
ColA ReqColA
-----------------------
a.b.c.d.e d
ab.cd.ef cd
a1.b2.c3.d4.e5 d4