table ta having four columns ( SQL server and D column is date)
A | B | C|D
1 |11| 0|10-MAY-2019
1 |12| 0|10-MAY-2019
1 |13| 0|null
2 |33| 5|null
2 |34| 10|null
2 |35| 78|null
5 |45| 0|10-MAY-2019
5 |49| 0|10-MAY-2019
5 |51| 0|10-MAY-2019
8 |10| 0|1-MAY-2018
8 |14| 0|1-MAY-2018
8 |34| 0|1-MAY-2018
I am looking the SQL query to fetch the distinct A value which is having C value ZERO for all the B (ie. SUM(ABS(C))=0) and all D value for that will not be null and should be > GETDATE() - 90 (i.e any day between current date and 90 days)
From above table I would only get the value of A as '5'
Try this-
SELECT * FROM
(
SELECT A
FROM your_table
WHERE D > CAST(DATEADD(DD,-90,GETDATE()) AS DATE)
GROUP BY A
HAVING COUNT(A) = SUM(CASE WHEN C= 0 THEN 1 ELSE 0 END)
)A
WHERE NOT EXISTS
(
SELECT 1 FROM your_table B WHERE A.A = B.A
AND D IS NULL
)
You can use aggregation. I think this is the logic you describe:
select a
from t
where d > dateadd(day, -90, getdate()) or d is null
group by a
having max(c) = 0 and
count(*) = count(d); -- no NULL d values
Related
Table 1
ID
Grp
Qty
1
A
5
2
A
4
3
B
5
4
B
3
5
B
2
6
C
14
7
D
1
8
D
1
9
E
2
10
E
2
11
E
1
12
E
1
Table 2
ID
Grp
Qty
1
A
7
2
B
9
3
C
13
4
D
1
5
E
4
Select/Output
ID
Grp
Qty
1
A
0
2
A
2
3
B
0
4
B
0
5
B
1
6
C
1
7
D
0
8
D
1
9
E
0
10
E
0
11
E
1
12
E
1
I want to select a row on a 1st table with a specific quantity based on the total quantity of the 2nd table. The result is on the 3rd table. Please see sample tables above, I really appreciate a help, thank you so much and sorry it was my first time asking a question here.
I have tried this code on both 2 tables
WITH tbl AS(
SELECT ID,
Qty,
Grp,
ROW_NUMBER() OVER (PARTITION BY Grp)AS Rown,
SUM(Qty) OVER (PARTITION BY Grp)AS Total
FROM Table1
)
SELECT * FROM tbl WHERE Rown = 1
But I am not able to select the specific rows on Table 1 because it only select the 1st row and total the quantity. Every row on table 1 has its own quantity.
You could use a cumulative windowed aggregates and then a CASE expression to achieve this:
--Saple Data
WITH Table1 AS(
SELECT *
FROM (VALUES(1,'A',5),
(2,'A',4),
(3,'B',5),
(4,'B',3),
(5,'B',2),
(6,'C',14))V(ID,Grp,Qty)),
Table2 AS(
SELECT *
FROM (VALUES(1,'A',7),
(2,'B',9),
(3,'C',13))V(ID,Grp,Qty)),
--Solution
CTE AS(
SELECT T1.ID,
T1.Grp,
T1.Qty,
SUM(T1.Qty) OVER (PARTITION BY T1.Grp ORDER BY T1.Id
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS RunningQty,
T2.Qty AS T2Qty
FROM Table1 T1
JOIN Table2 T2 ON T1.Grp = T2.Grp)
SELECT C.ID,
C.Grp,
CASE WHEN C.RunningQty <= C.T2Qty THEN C.Qty
ELSE C.T2Qty - LAG(C.RunningQty,1,0) OVER (PARTITION BY C.Grp ORDER BY C.ID)
END AS Qty
FROM CTE C;
I have a table A:
entity_id name
------------------
1 Test1
2 Test2
3 Test3
4 Test4
5 Test5
6 Test6
I have a table B:
entity_id value1 value2
-----------------------------
1 10 20
1 15 30
2 10 25
1 9 45
3 null 1
2 45 50
3 20 null
I need to write a single query to select the entity_id and name from Table A and count the total occurrences for an entity_id of columns value1 and value2 from Table B and then the total of those column counts (null doesn't count).
So my output table would be:
entity_id name value1_count value2_count total_count
----------------------------------------------------------------------
1 Test1 3 3 6
2 Test2 1 2 3
3 Test3 1 1 2
4 Test4 0 0 0
5 Test5 0 0 0
6 Test6 0 0 0
I am having trouble summing the count of value1 and count of value2 and outputting that value in the total_count per unique entity_it.
This is the query I have so far:
SELECT DISTINCT a.entity_id, a.name
, count(b.value1) AS value1_count, count(b.value2) AS value2_count, sum(2) AS total_count
FROM a
LEFT JOIN b ON a.entity_id = b.entity_id
GROUP BY a.entity_id, a.name
I know that the sum(2) as total_count is incorrect and doesn't get me what I want.
SELECT entity_id, a.name
, COALESCE(b.v1_ct, 0) AS value1_count
, COALESCE(b.v2_ct, 0) AS value2_count
, COALESCE(b.v1_ct + b.v2_ct, 0) AS total_count
FROM a
LEFT JOIN (
SELECT entity_id, count(value1) AS v1_ct, count(value2) AS v2_ct
FROM b
GROUP BY 1
) b USING (entity_id);
db<>fiddle here
Aggregate first, join later. That's simpler and faster. See:
Query with LEFT JOIN not returning rows for count of 0
count() never produces NULL. Only the LEFT JOIN can introduce NULL values for counts in this query, so v1_ct and v2_ct are either both NULL or both NOT NULL. Hence COALESCE(v1_ct + v2_ct, 0) is ok. (Else, one NULL would nullify the other summand in the addition.)
try this :
WITH list AS
(
SELECT b.entity_id
, count(*) FILTER (WHERE b.value1 IS NOT NULL) OVER () AS value1_count
, count(*) FILTER (WHERE b.value2 IS NOT NULL) OVER () AS value2_count
FROM Table_B AS b
GROUP BY b.entity_id
)
SELECT a.entity_id, a.name
, COALESCE(l.value1_count, 0)
, COALESCE(l.value2_count,0)
, COALESCE(l.value1_count + l.value2_count, 0) AS total_count
FROM Table_A AS a
LEFT JOIN list AS l
ON a.entity_id = l.entity_id
I have two tables; table A and table B. Table A has StoreNumber, MatNumber and Date. Table B has StoreNumber, MatNumber, Date and ShipmentValue. I have to get the Shipment value from table B for StoreNumber and MatNumber given that the Maximum Date in Table B for the StoreNumber and MatNumber should be less than the Date for the same StoreNumber and MatNumber in Table A (each row in Table A) . Please see the output table.
Table A:
StoreNumber MatNumber Date
A 9 3/30/2020
A 9 3/30/2020
B 10 3/18/2020
B 10 3/18/2020
A 9 3/13/2020
Table B:
StoreNumber MatNumber Date ShipmentValue
A 9 3/10/2020 2
A 9 3/12/2020 3
A 9 3/18/2020 4
B 10 3/4/2020 7
B 10 3/7/2020 9
B 10 3/16/2020 10
Output:
StoreNumber MatNumber A.Date B.Date ShipmentValue
A 9 3/30/2020 3/18/2020 4
A 9 3/30/2020 3/18/2020 4
B 10 3/18/2020 3/16/2020 10
B 10 3/18/2020 3/16/2020 10
A 9 3/13/2020 3/12/2020 3
Tried with ROW_NUMBER and selecting 1st row after ordering date by desc.
SELECT A.StoreNumber
,A.MatNumber
,A.Date
,B.Date AS B_Date
,B.ShipmentValue
FROM TableA A
LEFT JOIN
(
SELECT StoreNumber ,MatNumber , Date , ShipmentValue
FROM
(
SELECT ROW_NUMBER() OVER (PARTITION BY StoreNumber, MatNumber ORDER BY DATE DESC ) AS ID,*
FROM TableB
) A
WHERE ID = 1
) B
ON A.StoreNumber = B.StoreNumber
AND A.MatNumber = B.MatNumber
This is a place where a lateral join is handy:
select a.*, b.date, b.shipmentvalue
from a left join lateral
(select b.*
from b
where b.storenumber = a.storenumber and
b.matnumber = a.matnumber and
b.date <= a.date
order by b.date desc
fetch first 1 row only
) b
on 1=1; -- returns rows in a even when there are no matches
EDIT:
Wow. Snowflake implements lateral joins and then limits them in a fundamental way. Another method is more expensive but should work:
select ab.*, b.shipmentValue
from (select a.StoreNumber, a.MatNumber, a.Date, max(b.date) as b_date, b.shipmentvalue
from a left join
b
on b.storenumber = a.storenumber and
b.matnumber = a.matnumber and
b.date <= a.date
group by a.StoreNumber, a.MatNumber, a.Date
) ab join
b
on b.storenumber = ab.storenumber and
b.matnumber = ab.matnumber and
b.date <= ab.b_date
I have the following table on my database which contains some transactions for which I need to calc points and rewards.
Every time a TxType A occurs I should record 10 points.
Then I have to subtract from these points the value of the PP column every time a TxType B occurs.
When the calculation goes to zero a reward is reached.
ID TxType PP
1 A 0
2 B 2
3 B 1
4 B 1
5 B 1
6 B 3
7 B 1
8 B 1
9 A 0
10 B 4
11 B 3
12 B 2
13 B 1
14 A 0
15 B 2
I have created the sql query to calc points as follow
SELECT SUM(
CASE
WHEN TxType = 'A' THEN 10
WHEN TxType = 'B' THEN (PP * -1)
END)
FROM myTable
This query return the value of 8, which is exactly the number of points based on the sample data.
How do I calculate the rewards occurred (2 in the given example)?
thanks for helping
One way to do the calculation (in SQL Server 2008) using a correlated subquery:
select t.*,
(select sum(case when TxType = 'A' then 10
when TxType = 'B' then PP * -1
end)
from mytable t2
where t2.id <= t.id
) as TheSum
from mytable t;
You can then apply the logic of what happens when the value is 0. In SQL Server 2012, you could just use a cumulative sum.
To complete Gordon Linoff's the answer, you just need to count the records where TheSum is 0 to get how many rewards occurred:
SELECT COUNT(1)
FROM (
SELECT ID,
TxType,
PP,
( SELECT SUM(CASE TxType WHEN 'A' THEN 10 WHEN 'B' THEN -PP END)
FROM #myTable t2
WHERE t2.id <= t1.id
) AS TheSum
FROM #myTable t1
) Result
WHERE TheSum = 0
I have a problem with a select in sql server, i have this table with 2 columns:
a 2
b 1
c 100
d 1
a 100
b 1
c 2
d 1
I want ordered it based on the first column,in this way:
a 2
a 100
b 1
b 1
c 2
c 100
d 1
d 1
But then j want the rows with secondcolumn=100 be moved at the bottom,so:
a 2
b 1
b 1
c 2
d 1
d 1
a 100
c 100
I have tried with clause ORDER BY column1 ASC, (column2=100) ASC,but it didnt work!
Thankyou and greetings.
Actually, you want the rows with 100 in the second column moved to the bottom first, and then ordered by the first column:
order by (case when col2 = 100 then 1 else 0 end),
col1
Use the CASE expression as below
SELECT *
FROM tab
ORDER BY CASE
WHEN column2 = 100 THEN 1
ELSE 0
END ASC,
column1 asc
SELECT *
FROM table1
ORDER BY
CASE
WHEN col2>=100 THEN 1
ELSE 0
END,
col1,
col2
SQLFiddle Example