Using standard SQL in bigquery:
Given a table such as: Where the values have been counted so only appear once
| id | key | value |
--------------------
| 1 | read | aa |
| 1 | read | bb |
| 1 | name | abc |
| 2 | read | bb |
| 2 | read | cc |
| 2 | name | def |
| 2 | value| some |
| 3 | read | aa |
How can I make it so each row is one user and their respective values? e.g. NEST
So the table would look like:
| id | key | value |
--------------------
| 1 | read | aa |
| | read | bb |
| | name | abc |
| 2 | read | bb |
| | read | cc |
| | name | def |
| | value| some |
| 3 | read | aa |
I've tried using ARRAY_AGG on the column, which ends up listing all the values of that column.
I just need to have each row as a single user with multiple values, as shown above.
Like BigQuery does here, this is what I want it to look like:
Below is for BigQuery Standard SQL
#standardSQL
SELECT id, ARRAY_AGG(STRUCT(key AS key, value AS value)) params
FROM `project.dataset.table`
GROUP BY id
if to apply to your sample data - result is
Related
In PostgreSQL, I have a table that looks like,
| id | json |
| -- | ------------------------------- |
| 1 | {"id":1,"customer":"BANK"} |
| 1 | {"id":1,"customer":"BANK"} |
| 2 | {"id":2,"customer":"GOVT"} |
| 3 | {"id":3,"customer":"BANK"} |
| 4 | {"id":4,"customer":"ASSET MGR"} |
| 4 | {"id":4,"customer":"ASSET MGR"} |
I need the output of counting the occurrences of customers with unique ids, such as
| customer | count |
| ----------- | ----- |
| "BANK" | 2 |
| "GOVT" | 1 |
| "ASSET MGR" | 1 |
Is there a good way to achieve using PostgreSQL & json? I currently am able to extract the customer and IDs, but am having difficulty counting the unique json objects.
select count(distinct id), jsondata ->> 'customer' customer
from data
group by customer
count | customer
----: | :--------
1 | ASSET MGR
2 | BANK
1 | GOVT
db<>fiddle here
I have a table like this:
+----+-------+-----------------+
| ID | Name | Email |
+----+-------+-----------------+
| 1 | Jane | Jane#doe.com |
| 2 | Will | Will#gmail.com |
| 3 | Will | wsj#example.com |
| 4 | Jerry | jj2#test.com |
+----+-------+-----------------+
Unfortunately I have records that are duplicates due to multiple emails. I would like to run a sql query to generate this:
+----+-------+---------------------------------+
| ID | Name | Email |
+----+-------+---------------------------------+
| 1 | Jane | Jane#doe.com |
| 2 | Will | Will#gmail.com, wsj#example.com |
| 4 | Jerry | jj2#test.com |
+----+-------+---------------------------------+
I know with numbers you'd do something like this, but I don't know how to 'sum' text fields:
SELECT *,
SUM(Number_Field) AS Number_Field,
FROM table
Thanks!
Edit: I am using MS Access
Here is what I want to do:
I have this table
+----+-------------+
| id | data |
+----+-------------+
| 1 | max |
| 2 | linda |
| 3 | sam |
| 4 | henry |
+----+-------------+
and I want to Update the data with concatenating Id column with data, which will look like this:
+----+-------------+
| id | data |
+----+-------------+
| 1 | max1 |
| 2 | linda2 |
| 3 | sam3 |
| 4 | henry4 |
+----+-------------+
Sounds like this is basically what you want (T-SQL, Other platforms may have different methods for type conversion and concatenation):
update myTable
set data=data+convert(varchar(50),id)
I have a table which represents the hierarchy of departments:
+-----------+--------------+--------------+--------------+-----------+-------+
| Top Dept. | 2-tier Dept. | 3-tire Dept. | 4-tier Dept. | name | tier |
+-----------+--------------+--------------+--------------+-----------+-------+
| 00 | | | | abc | 0 |
| | 00-01 | | | bcd | 1 |
| | | 00-01-01 | | cde | 2 |
| | | 00-01-02 | | abc | 2 |
| | 00-02 | | | aef | 1 |
| | | 00-02-01 | | qwe | 2 |
| | | 00-02-03 | | abc | 2 |
| | | | 00-02-03-01 | abc | 3 |
+-----------+--------------+--------------+--------------+-----------+-------+
now I want to sort the rows which are in the same tier by their names while keeping the hierarchy overall, That's what I expect:
+-----------+--------------+--------------+--------------+-----------+-------+
| Top Dept. | 2-tier Dept. | 3-tire Dept. | 4-tier Dept. | name | tier |
+-----------+--------------+--------------+--------------+-----------+-------+
| 00 | | | | abc | 0 |
| | 00-02 | | | aef | 1 |
| | | 00-02-03 | | abc | 2 |
| | | 00-02-01 | | qwe | 2 |
| | 00-01 | | | def | 1 |
| | | 00-01-02 | | abc | 2 |
| | | 00-01-01 | | cde | 2 |
| | | | 00-02-03-01 | abc | 3 |
+-----------+--------------+--------------+--------------+-----------+-------+
the missing data means null, I'm using Oracle DB, can anyone help me?
EDIT: Actually, it's a simple version of this sql, I've tried to add a new column which concats the values of the first four columns and then order by it and by name, but it did't work.
Update: This appears to be working... SQL Fiddle
All that was really needed from my original comment was to amend name to department in that order in both selects. This allows the engine to sort by name first, while maintaining the hierarchy.
WITH cte(Dept, superiorDept, name, depth, sort)AS (
SELECT
Dept,
superiorDept,
name,
0,
name|| dept
FROM hierarchy h
WHERE superiorDept IS NULL
UNION ALL
SELECT
h2.Dept,
h2.superiorDept,
h2.name,
cte.depth + 1,
cte.sort || h2.name ||h2.dept
FROM hierarchy h2
INNER JOIN cte ON h2.superiorDept = cte.Dept
)
SELECT
CASE WHEN depth = 0 THEN Dept END AS 一级部门,
CASE WHEN depth = 1 THEN Dept END AS 二级部门,
CASE WHEN depth = 2 THEN Dept END AS 三级部门,
CASE WHEN depth = 3 THEN Dept END AS 四级部门,
name,
depth,
sort
FROM cte
ORDER BY sort, name
I have a master table (Project List) along with several sub tables that are joined on one common field (RecNum). I need to get totals for all of the sub tables, by column and am not sure how to do it. This is a sample of the table design. There are more columns in each table (I need to pull * from "Project List") but I'm showing a sampling of the column names and values to get an idea of what to do.
Project List
| RecNum | Project Description |
| 6 | Sample description |
| 7 | Another sample |
WeekA
| RecNum | UserName | Day1Reg | Day1OT | Day2Reg | Day2OT | Day3Reg | Day3OT |
| 6 | JustMe | 1 | 2 | 3 | 4 | 5 | 6 |
| 6 | NotMe | 1 | 2 | 3 | 4 | 5 | 6 |
| 7 | JustMe | | | | | | |
| 7 | NotMe | | | | | | |
WeekB
| RecNum | UserName | Day1Reg | Day1OT | Day2Reg | Day2OT | Day3Reg | Day3OT |
| 6 | JustMe | 7 | 8 | 1 | 2 | 3 | 4 |
| 6 | NotMe | 7 | 8 | 1 | 2 | 3 | 4 |
| 7 | JustMe | | | | | | |
| 7 | NotMe | | | | | | |
So the first query should return the complete totals for both users, like this:
| RecNum | Project Description | sumReg | sumOT |
| 6 | Sample description | 40 | 52 |
| 7 | Another sample | 0 | 0 |
The second query should return the totals for just a specified user, (WHERE UserName = 'JustMe') like this:
| RecNum | Project Description | sumReg | sumOT |
| 6 | Sample description | 20 | 26 |
| 7 | Another sample | 0 | 0 |
Multiple parallel tables with the same structure is usually a sign of poor database design. The data should really be all in one table, with additional columns specifying the week.
You can, however, use union all to bring the data together. The following is an example of a query:
select pl.recNum, pl.ProjectDescription,
sum(Day1Reg + Day2Reg + Day3Reg) as reg,
sum(Day1OT + Day2OT + Day3OT) as ot
from ProjectList pl join
(select * from weekA union all
select * from weekB
) w
on pl.recNum = w.recNum
group by l.recNum, pl.ProjectDescription,;
In practice, you should use select * with union all. You should list the columns out explicitly. You can add appropraite where clauses or conditional aggregation to get the results you want in any particular case.