Loop SQL by month - sql

In Oracle SQL Developer I need to calculate some figures (count for instance) since first day till today monthly. How can I create a loop by changing month in a date field? Now I have a time range on WHERE clause like (date >= '2017-01-01' and date < '2019-01-01'). So what I need is a table that counts for months and inserts results in two columns: month (2019_01, 2019_02, etc) and count

Here's an example which might help you do what need. It is based on Scott's sample schema, its EMP table that contains the HIREDATE column which will be joined to a CTE named months; it utilizes hierarchical query to create "calendar" of 12 months (that's what the CONNECT BY clause does). It will have to be changed in your case, I presume.
Current data:
SQL> select empno, ename, hiredate
2 from emp
3 order by hiredate;
EMPNO ENAME HIREDATE
---------- ---------- ----------
7369 SMITH 17.12.1980
7499 ALLEN 20.02.1981
7521 WARD 22.02.1981
7566 JONES 02.04.1981
7698 BLAKE 01.05.1981
7782 CLARK 09.06.1981
7844 TURNER 08.09.1981
7654 MARTIN 28.09.1981
7839 KING 17.11.1981
7900 JAMES 03.12.1981
7902 FORD 03.12.1981
7934 MILLER 23.01.1982
7788 SCOTT 09.12.1982
7876 ADAMS 12.01.1983
14 rows selected.
SQL>
Query you might need:
SQL> with months as
2 (select add_months(date '1980-12-01', level - 1) mon
3 from dual
4 connect by level <= 12
5 )
6 select to_char(m.mon, 'mm.yyyy') mon,
7 count(e.empno)
8 from months m left join emp e on m.mon = trunc(e.hiredate, 'mm')
9 group by m.mon
10 order by m.mon;
MON COUNT(E.EMPNO)
------- --------------
12.1980 1 --> Smith
01.1981 0
02.1981 2 --> Allen, Ward
03.1981 0
04.1981 1 --> Jones
05.1981 1 --> Blake
06.1981 1 --> Clark
07.1981 0
08.1981 0
09.1981 2 --> Turner, Martin
10.1981 0
11.1981 1 --> King
12 rows selected.
SQL>

Related

Get data starting from the middle of the table

I have a question. I want to get data from the middle of the table. But the problem is I can't start from the middle. I have read that rownum can't be used for this. But i dont know how to do this with another method. Anyone have any clue how to do this? Thank you.
Below is an example.
select count(1) --9857
from time_day_dm
where rownum between 5000 and 9857
The output would be 0.
What i expect would be 4857.
rownum won't help here (as you already know).
What you might do, is to use a couple of analytic functions (count, to find number of rows in the table; row_number, to sort them).
Here's an example based on Scott's emp table. This is its contents:
SQL> select empno, ename, job, sal
2 from emp
3 order by ename;
EMPNO ENAME JOB SAL
---------- ---------- --------- ----------
7876 ADAMS CLERK 1100
7499 ALLEN SALESMAN 1600
7698 BLAKE MANAGER 2850
7782 CLARK MANAGER 2450
7902 FORD ANALYST 3000
7900 JAMES CLERK 950
7566 JONES MANAGER 2975
7839 KING PRESIDENT 5000
7654 MARTIN SALESMAN 1250
7934 MILLER CLERK 1300
7788 SCOTT ANALYST 3000
7369 SMITH CLERK 800
7844 TURNER SALESMAN 1500
7521 WARD SALESMAN 1250
14 rows selected.
Query you might be interested in looks like this:
SQL> with temp as
2 (select empno, ename, job, sal,
3 row_number() over (order by ename) rn,
4 count(*) over () cnt
5 from emp
6 )
7 select *
8 from temp
9 where rn between cnt/2 and cnt;
EMPNO ENAME JOB SAL RN CNT
---------- ---------- --------- ---------- ---------- ----------
7566 JONES MANAGER 2975 7 14
7839 KING PRESIDENT 5000 8 14
7654 MARTIN SALESMAN 1250 9 14
7934 MILLER CLERK 1300 10 14
7788 SCOTT ANALYST 3000 11 14
7369 SMITH CLERK 800 12 14
7844 TURNER SALESMAN 1500 13 14
7521 WARD SALESMAN 1250 14 14
8 rows selected.
SQL>

how to query a table using name from another column from another table

I am trying to get data from a table where the table name is stored in another table.
I am trying for select query but not able to get the data.
example
t1
table name | some data
t2 - table name is same coming from t1
t2
id | some data
I need to fetch the t2 name first from t1 that I am able to do. but using that query response I am not sure how to fetch the second query as the result is coming from first query.
Any help is appreciated.
Thanks
It'll have to be some kind of "dynamic" SQL. One option is to create a function that returns ref cursor. Here's an example.
This is your t1 table; it contains some table names.
SQL> select * from tname;
ID TABLE_NAME
---------- ---------------
1 emp
2 dept
Function:
SQL> create or replace function f_tab (par_table_name in varchar2)
2 return sys_refcursor
3 is
4 rc sys_refcursor;
5 begin
6 open rc for 'select * from ' || dbms_assert.sql_object_name(par_table_name);
7 return rc;
8 end;
9 /
Function created.
Testing: query selects table names from the tname table and returns their contents:
SQL> select f_tab(t.table_name) result
2 from tname t
3 order by t.id;
RESULT
--------------------
CURSOR STATEMENT : 1
CURSOR STATEMENT : 1
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- ------------------- ---------- ---------- ----------
7369 SMITH CLERK 7902 17.12.1980 00:00:00 800 20
7499 ALLEN SALESMAN 7698 20.02.1981 00:00:00 1600 300 30
7521 WARD SALESMAN 7698 22.02.1981 00:00:00 1250 500 30
7566 JONES MANAGER 7839 02.04.1981 00:00:00 2975 20
7654 MARTIN SALESMAN 7698 28.09.1981 00:00:00 1250 1400 30
7698 BLAKE MANAGER 7839 01.05.1981 00:00:00 2850 30
7782 CLARK MANAGER 7839 09.06.1981 00:00:00 2450 10
7788 SCOTT ANALYST 7566 09.12.1982 00:00:00 3000 20
7839 KING PRESIDENT 17.11.1981 00:00:00 5000 10
7844 TURNER SALESMAN 7698 08.09.1981 00:00:00 1500 0 30
7876 ADAMS CLERK 7788 12.01.1983 00:00:00 1100 20
7900 JAMES CLERK 7698 03.12.1981 00:00:00 950 30
7902 FORD ANALYST 7566 03.12.1981 00:00:00 3000 20
7934 MILLER CLERK 7782 23.01.1982 00:00:00 1300 10
14 rows selected.
CURSOR STATEMENT : 1
CURSOR STATEMENT : 1
DEPTNO DNAME LOC
---------- -------------- -------------
10 ACCOUNTING NEW YORK
20 RESEARCH DALLAS
30 SALES CHICAGO
40 OPERATIONS BOSTON
SQL>

How to select middle 80% rows in Oracle SQL with order by (top % is not working)

I tried top % but that is not working in Oracle SQL. Offset and fetch next are working but I am not able to give percentage.
What will be the best way to fetch middle 80% rows?
Any help will be appreciated, thanks!
Middle 80%? That's between 10 and 90%, then? Let's suppose it is.
Sample data (Scott's EMP table), sorted by salary:
SQL> select ename, job, sal,
2 rank() over (order by sal) rnk
3 from emp order by sal;
ENAME JOB SAL RNK
---------- --------- ---------- ----------
SMITH CLERK 800 1
JAMES CLERK 950 2
ADAMS CLERK 1100 3
WARD SALESMAN 1250 4
MARTIN SALESMAN 1250 4
MILLER CLERK 1300 6
TURNER SALESMAN 1500 7
ALLEN SALESMAN 1600 8
CLARK MANAGER 2450 9
BLAKE MANAGER 2850 10
JONES MANAGER 2975 11
SCOTT ANALYST 3000 12
FORD ANALYST 3000 12
KING PRESIDENT 5000 14
14 rows selected.
CTE ranks employees by their salaries; the final where clause returns rows for those of them who fall into that "middle" 80% (the pct column).
SQL> with temp as
2 (select ename, job, sal,
3 rank() over (order by sal) rnk, -- rank rows by salary
4 count(*) over (order by null) cnt -- total number of rows
5 from emp
6 )
7 select t.*,
8 round(rnk / cnt * 100) pct -- percentage
9 from temp t
10 where round(rnk / cnt * 100) between 10 and 90;
ENAME JOB SAL RNK CNT PCT
---------- --------- ---------- ---------- ---------- ----------
JAMES CLERK 950 2 14 14
ADAMS CLERK 1100 3 14 21
WARD SALESMAN 1250 4 14 29
MARTIN SALESMAN 1250 4 14 29
MILLER CLERK 1300 6 14 43
TURNER SALESMAN 1500 7 14 50
ALLEN SALESMAN 1600 8 14 57
CLARK MANAGER 2450 9 14 64
BLAKE MANAGER 2850 10 14 71
JONES MANAGER 2975 11 14 79
SCOTT ANALYST 3000 12 14 86
FORD ANALYST 3000 12 14 86
12 rows selected.
SQL>

Oracle randomly shuffling entire rows

have a locations table that contains 3 types of records (see below). I only need to SELECT record_type = 'G' rows.
I want to wrap the data in a loop ( ie 5 times) but how can I randomly shuffle the ENTIRE rows, by location_id, so they appear in a different order with each iteration of the loop? Perhaps, sticking the rows into an array and shuffling the array?
Note, I don't want to shuffle the columns, I want the row kept in tact. In the future more locations maybe added.
CREATE TABLE locations AS
SELECT level AS location_id,
'Door ' || level AS location_name,
CASE round(dbms_random.value(1,3))
WHEN 1 THEN 'A'
WHEN 2 THEN 'T'
WHEN 3 THEN 'G'
END AS location_type
FROM dual
CONNECT BY level <= 25;
SELECT * from tour_detail
Order by tour_id, tour_time
TOUR_ID TOUR_TIME LOCATION_ID
1 06212020 00:10:25 2
1 06212020 00:21:05 18
1 06212020 00:30:33 11
1 06212020 00:40:51 17
1 06212020 00:52:13 4
1 06212020 01:01:42 2
1 06212020 01:07:52 11
We have an access control system when you slide your card it records card_num, location_id, access_date in MMDDYYY HH24:MI:SS format.
Some wanted to create a guard tour system. That compares the access_date to the tour_detail detail date. If within a certain criteria say + or - 2 minutes that means the guard was on time, if GT or LT 2 minutes we log an early or late, if GT Or LT 5 minutes or no access_history record we log a no show.
I was asked to throw together some testing data. As you can see the tour_detail records contain MMDDYYYY HH24:MI:SS so I'm thinking about changing the tour_detail records to interval hour to minute but I have little experience working with that.
so they appear in a different order with each iteration of the loop
This is pointless. You are inserting rows into a table. Rows (in a RDBMS table) aren't stored in any particular order.
But, you can sort them when selecting from that table and - in order to do that - you have to use the order by clause.
As of selecting, see if this helps:
SQL> with data as
2 (select empno, ename, job, sal
3 from emp
4 where deptno = 20
5 order by round(dbms_random.value(0, 15))
6 )
7 select column_value, d.*
8 from data d cross join table(cast(multiset(select level from dual
9 connect by level <= 5
10 ) as sys.odcinumberlist));
COLUMN_VALUE EMPNO ENAME JOB SAL
------------ ---------- ---------- --------- ----------
4 7902 FORD ANALYST 3000
4 7788 SCOTT ANALYST 3000
2 7369 SMITH CLERK 1000
4 7369 SMITH CLERK 1000
1 7369 SMITH CLERK 1000
5 7566 JONES MANAGER 2975
1 7876 ADAMS CLERK 1100
1 7788 SCOTT ANALYST 3000
5 7788 SCOTT ANALYST 3000
3 7876 ADAMS CLERK 1100
1 7902 FORD ANALYST 3000
2 7876 ADAMS CLERK 1100
5 7902 FORD ANALYST 3000
3 7902 FORD ANALYST 3000
3 7566 JONES MANAGER 2975
1 7566 JONES MANAGER 2975
3 7788 SCOTT ANALYST 3000
2 7902 FORD ANALYST 3000
4 7566 JONES MANAGER 2975
5 7876 ADAMS CLERK 1100
2 7788 SCOTT ANALYST 3000
3 7369 SMITH CLERK 1000
4 7876 ADAMS CLERK 1100
2 7566 JONES MANAGER 2975
5 7369 SMITH CLERK 1000
25 rows selected.
SQL>
Let's say you have a table with 5 IDs
create table tab as
select rownum id from dual connect by level <= 5;
THis produce a random order output of the rows
select * from tab order by dbms_random.value;
ID
----------
2
4
5
1
3
If you repeat the statment you get a different (random) result
ID
----------
5
4
2
1
3
So simple repaet the query in the loop or make something like this
with data as (
select 1 pass_id, id from tab
union all
select 2 pass_id, id from tab
union all
select 3 pass_id, id from tab )
select * from data
order by 1,dbms_random.value

sql-oHow can I achieve the following in oracle without creating a stored procedure?group by using

how can ı get this result with using employees table?for salary< average 0
for salary >avg 1
employee_id salary
a 1
b 1
c 0
d 0
e 0
f 1
You could simply calculate the AVERAGE of the salary and compare it with the SALARY for each employee in the CASE expression itself.
For example,
SQL> SELECT empno,
2 ename,
3 CASE
4 WHEN sal >
5 (SELECT AVG(sal) FROM emp
6 )
7 THEN 1
8 ELSE 0
9 END flag
10 FROM emp;
EMPNO ENAME FLAG
---------- ---------- ----------
7369 SMITH 0
7499 ALLEN 0
7521 WARD 0
7566 JONES 1
7654 MARTIN 0
7698 BLAKE 1
7782 CLARK 1
7788 SCOTT 1
7839 KING 1
7844 TURNER 0
7876 ADAMS 0
7900 JAMES 0
7902 FORD 1
7934 MILLER 0
14 rows selected.
SQL>
Alternate solution You could use AVG() analytic function.
For example,
SQL> SELECT empno,
2 ename,
3 CASE
4 WHEN sal > avg(sal) OVER(ORDER BY NULL) THEN
5 1
6 ELSE
7 0
8 END flag
9 FROM emp;
EMPNO ENAME FLAG
---------- ---------- ----------
7369 SMITH 0
7499 ALLEN 0
7521 WARD 0
7566 JONES 1
7654 MARTIN 0
7698 BLAKE 1
7782 CLARK 1
7788 SCOTT 1
7839 KING 1
7844 TURNER 0
7876 ADAMS 0
7900 JAMES 0
7902 FORD 1
7934 MILLER 0
14 rows selected.
SQL>
You could cross join on the average salary:
SELECT employee_id,
CASE WHEN salary > avg_salary THEN 1 ELSE 0 END AS salary
FROM employee
CROSS JOIN (SELECT AVG(salary)
FROM employee)