Example: http://sqlfiddle.com/#!18/7f3df/2
CREATE TABLE Table1 (
Reg uniqueidentifier
);
INSERT INTO Table1 (Reg)
Values
('DF215E10-8BD4-4401-B2DC-99BB03135F2E'),
('93015E10-8BD4-4401-B2DC-99BB03135F2E'),
('21215E10-8BD4-4401-B2DC-99BB03135F2E');
Query:
select * from Table1
WHERE left(CAST(Reg AS CHAR(36)),1) > 8
I need to create a query that finds all results that start with either a number 8 or higher or starts with a letter but i am getting a conversion error i cant find a fix for. The column is a uniqueidentifier. How can i cast this to something i can filter on?
Can anyone give some advice on a solution to this?
Thanks
You need to do the comparison using strings:
convert(varchar(36), newid()) like '[89ABCDEF]%'
You may use SQL Server's enhanced LIKE here, which has some basic regex support:
SELECT *
FROM table1
WHERE Reg LIKE '[89A-Z]%';
The pattern [89A-Z]% says to match a starting 8 or 9, or any letter.
Related
I am trying to run a select statement on a table acct id. My account ID's can have the following pattern which is the one I am having issues with: 2733R9087813964
How do I run a SELECT Statement on this column and extract only the numeric portion after the "R"?
So the result in this scenario would be: 9087813964
Any help would be appreciated.
try
SELECT Substr(ACC_ID, Position('R' IN ACC_ID) +1 )
FROM ACCOUNT
Table contains data as below
Table Name is REGISTER
Column Name is EXAM_CODE
Values like ('S6TJ','S7','S26','S24')
I want answer like below
Result set - > (6,7,26,24)
Please suggest solution - since regexp_replace is not recognized built in function name in SQL.
The complexity of the answer depends on two things: the RDBMS used and whether the numbers in the EXAM_CODE are contiguous.
I have assumed that the RDBMS is SQL Server and the numbers in EXAM_CODE are always contiguous. If not, please advise and I can revise the answer.
The following SQL shows a way of accomplishing the above using PATINDEX.:
CREATE TABLE #REGISTER (EXAM_CODE VARCHAR(10));
INSERT INTO #REGISTER VALUES ('S6TJ'),('S7'),('S26'),('S24');
SELECT LEFT(EXAM_CODE, PATINDEX('%[^0-9]%', EXAM_CODE) - 1)
FROM (
SELECT RIGHT(EXAM_CODE, LEN(EXAM_CODE) - PATINDEX('%[0-9]%', EXAM_CODE) + 1) + 'A' AS EXAM_CODE
FROM #REGISTER
) a
DROP TABLE #REGISTER
This outputs:
6
7
26
24
PATINDEX matches a specified pattern against a string (or returns 0 if there is no match).
Using this, the inner query fetches all of the string AFTER the first occurence of a number. The outer query then strips any text that may appear on the end of the string.
Note: The character A is appended to the result of the inner query in order to ensure that the PATINDEX check in the outer query will make a match. Otherwise, PATINDEX would return 0 and an error would occur.
I'm using the following code:
SELECT * FROM table
WHERE Col IN (123,123,222,....)
However, if I put more than ~3000 numbers in the IN clause, SQL throws an error.
Does anyone know if there's a size limit or anything similar?!!
Depending on the database engine you are using, there can be limits on the length of an instruction.
SQL Server has a very large limit:
http://msdn.microsoft.com/en-us/library/ms143432.aspx
ORACLE has a very easy to reach limit on the other side.
So, for large IN clauses, it's better to create a temp table, insert the values and do a JOIN. It works faster also.
There is a limit, but you can split your values into separate blocks of in()
Select *
From table
Where Col IN (123,123,222,....)
or Col IN (456,878,888,....)
Parameterize the query and pass the ids in using a Table Valued Parameter.
For example, define the following type:
CREATE TYPE IdTable AS TABLE (Id INT NOT NULL PRIMARY KEY)
Along with the following stored procedure:
CREATE PROCEDURE sp__Procedure_Name
#OrderIDs IdTable READONLY,
AS
SELECT *
FROM table
WHERE Col IN (SELECT Id FROM #OrderIDs)
Why not do a where IN a sub-select...
Pre-query into a temp table or something...
CREATE TABLE SomeTempTable AS
SELECT YourColumn
FROM SomeTable
WHERE UserPickedMultipleRecordsFromSomeListOrSomething
then...
SELECT * FROM OtherTable
WHERE YourColumn IN ( SELECT YourColumn FROM SomeTempTable )
Depending on your version, use a table valued parameter in 2008, or some approach described here:
Arrays and Lists in SQL Server 2005
For MS SQL 2016, passing ints into the in, it looks like it can handle close to 38,000 records.
select * from user where userId in (1,2,3,etc)
I solved this by simply using ranges
WHERE Col >= 123 AND Col <= 10000
then removed unwanted records in the specified range by looping in the application code. It worked well for me because I was looping the record anyway and ignoring couple of thousand records didn't make any difference.
Of course, this is not a universal solution but it could work for situation if most values within min and max are required.
You did not specify the database engine in question; in Oracle, an option is to use tuples like this:
SELECT * FROM table
WHERE (Col, 1) IN ((123,1),(123,1),(222,1),....)
This ugly hack only works in Oracle SQL, see https://asktom.oracle.com/pls/asktom/asktom.search?tag=limit-and-conversion-very-long-in-list-where-x-in#9538075800346844400
However, a much better option is to use stored procedures and pass the values as an array.
You can use tuples like this:
SELECT * FROM table
WHERE (Col, 1) IN ((123,1),(123,1),(222,1),....)
There are no restrictions on number of these. It compares pairs.
I'm trying to perform some selects in DB2 SQL, using the LIKE command, specifically looking for values that start with certain multiple digits. I thought I was using the expression correctly, but I keep getting syntax errors and I'm not sure where I'm going wrong.
Right now I've been trying:
Select ID, NAME
From Table1
Where ID LIKE '888%'
Or ID LIKE '999%';
Am I just using the wrong SQL for the environment? (This is polling DB2 for Zo/s) LIKE doesn't seem to work when I just try a single 8% or 9% either.
I appreciate any shared experience, thank you!
Be sure the id is not a number and if is a number then cast as char
Select ID, NAME
From Table1
Where cast(ID as char(10)) LIKE '888%'
Or cast(ID as char(10)) LIKE '999%';
If the data type is number then you can try the following
Select ID, NAME
From Table1
Where to_char(ID) LIKE '888%'
Or to_char(ID) LIKE '999%';
I'm using the following code:
SELECT * FROM table
WHERE Col IN (123,123,222,....)
However, if I put more than ~3000 numbers in the IN clause, SQL throws an error.
Does anyone know if there's a size limit or anything similar?!!
Depending on the database engine you are using, there can be limits on the length of an instruction.
SQL Server has a very large limit:
http://msdn.microsoft.com/en-us/library/ms143432.aspx
ORACLE has a very easy to reach limit on the other side.
So, for large IN clauses, it's better to create a temp table, insert the values and do a JOIN. It works faster also.
There is a limit, but you can split your values into separate blocks of in()
Select *
From table
Where Col IN (123,123,222,....)
or Col IN (456,878,888,....)
Parameterize the query and pass the ids in using a Table Valued Parameter.
For example, define the following type:
CREATE TYPE IdTable AS TABLE (Id INT NOT NULL PRIMARY KEY)
Along with the following stored procedure:
CREATE PROCEDURE sp__Procedure_Name
#OrderIDs IdTable READONLY,
AS
SELECT *
FROM table
WHERE Col IN (SELECT Id FROM #OrderIDs)
Why not do a where IN a sub-select...
Pre-query into a temp table or something...
CREATE TABLE SomeTempTable AS
SELECT YourColumn
FROM SomeTable
WHERE UserPickedMultipleRecordsFromSomeListOrSomething
then...
SELECT * FROM OtherTable
WHERE YourColumn IN ( SELECT YourColumn FROM SomeTempTable )
Depending on your version, use a table valued parameter in 2008, or some approach described here:
Arrays and Lists in SQL Server 2005
For MS SQL 2016, passing ints into the in, it looks like it can handle close to 38,000 records.
select * from user where userId in (1,2,3,etc)
I solved this by simply using ranges
WHERE Col >= 123 AND Col <= 10000
then removed unwanted records in the specified range by looping in the application code. It worked well for me because I was looping the record anyway and ignoring couple of thousand records didn't make any difference.
Of course, this is not a universal solution but it could work for situation if most values within min and max are required.
You did not specify the database engine in question; in Oracle, an option is to use tuples like this:
SELECT * FROM table
WHERE (Col, 1) IN ((123,1),(123,1),(222,1),....)
This ugly hack only works in Oracle SQL, see https://asktom.oracle.com/pls/asktom/asktom.search?tag=limit-and-conversion-very-long-in-list-where-x-in#9538075800346844400
However, a much better option is to use stored procedures and pass the values as an array.
You can use tuples like this:
SELECT * FROM table
WHERE (Col, 1) IN ((123,1),(123,1),(222,1),....)
There are no restrictions on number of these. It compares pairs.