I have data in a column with values such as 4w4d, 1w0d, 2w5d, 0w6d.
How could I use this data to get the number of days out?
Create Table #temp
(
Data char(4),
ExpectedResult int
)
insert into #temp
(
Data,
ExpectedResult
)
select '4w4d','32'
union all
select '1w0d','7'
union all
select '2w5d','19'
union all
select '0w6d','6'
union all
select '0w5d','5'
union all
select '0w1d','1'
union all
select '0w3d','3'
union all
select '1w6d','13'
You need to parse out the week component and the day component and then convert into the number of days. The following is one way to do this:
-- Find the weeks, multiple by 7
convert(int, substring([Data], 1, charindex('w',[Data])-1))*7
-- Find the days and add on
+ convert(int, substring([Data], charindex('w',[Data])+1, charindex('d',[Data])-charindex('w',[Data])-1))
You can parse the string using string operations:
select convert(int, left(data, 1)) * 7 + convert(int, substring(data, 3, 1))
Here is a db<>fiddle with your sample data.
Related
I have a table with 2628 rows in it. I want to get a count per hour. I have a completion_time column which tells the date time of per record.
I can find only one-hour count.
select count(*)
from billing b
where b.completion_time >= '2019-04-16 23:50:23'
and b.completion_time <='2019-04-17 00:50:22'
The date time is up to 9 hours. i.e. the process was started at 2016-04-16 23:50:23 and it ends on 2019-04-17 08:16:49. So I want total counts per hour.
Update 1
I want output like below
How can I achieve it? Any help would be highly appreciated.
Try this:
select datepart(hour,b.completion_time) Hour, count(*) NumberOfRecords
from billing b
group by datepart(hour,b.completion_time)
Edit:
select row_number() over (order by min(b.completion_time)) RowNumber, count(*) NumberOfRecords
from billing b
group by datepart(hour,b.completion_time)
order by min(b.completion_time)
try this.
Declare #StartTime DATETIME = '2016-04-16 23:50:23'
Declare #EndTime DateTime = '2019-04-17 08:16:49'
Declare #Tab Table(id int, Completion_Time DateTime)
Insert into #Tab
SELECT 1, '2016-04-16 23:50:23' Union All
SELECT 2,'2016-04-17 00:50:24' Union All
SELECT 3,'2016-04-17 01:50:26' Union All
SELECT 4,'2016-04-17 01:50:32' Union All
SELECT 5,'2016-04-17 01:50:55' Union All
SELECT 6,'2016-04-17 02:50:28' Union All
SELECT 7,'2016-04-17 02:50:30' Union All
SELECT 8,'2016-04-17 02:50:45' Union All
SELECT 9,'2016-04-17 04:50:32' Union All
SELECT 10,'2016-04-17 04:50:52'
--Select Id, DATEDIFF(HH,#StartTime,Completion_Time) Diff from #Tab
;with cte
As
(
SELECT CONVERT(VARCHAR(5),DATEDIFF(HH,#StartTime,Completion_Time)+1) as [Hour] , COUNT(*) As [Records]
From #Tab
Group by DATEDIFF(HH,#StartTime,Completion_Time)+1
)
Select [Hour] + CASE
WHEN [Hour] % 100 IN (11,12,13) THEN 'th'
WHEN [Hour] % 10 = 1 THEN 'st'
WHEN [Hour] % 10 = 2 THEN 'nd'
WHEN [Hour] % 10 = 3 THEN 'rd'
ELSE 'th'
END + ' hour',
Records
from cte
This will do just what you need :
SELECT HOUR(b.completion_time) hourOfDay, COUNT(*) NumberOfRecords
FROM billing b
GROUP BY hourOfDay
HOUR is a predefined function to calculate hour from a DateTime.
I have a table where 2 columns are called Month and Year and are both INT. I need to return all the records that are less than the date provided.
So if I pass the following parameters #Month = 8 and #Year = 2017, I would like to return all records before August 2017. What is the best way to achieve this?
SELECT * FROM testTable
WHERE year <= #Year AND
month < #Month
is my current SQL. This won't work if I need to display the record that is November 2014
Compare them as dates. Like this:
SELECT * FROM testTable
WHERE DATEFROMPARTS(year, month, 1) <= DATEFROMPARTS(#Year, #Month, 1)
Pass The Parameter as Date. Like
DECLARE #MyDate DATE = '08-01-2014'
Now you can go for either of the below
SELECT
*
FROM YourTable
WHERE CAST(ConCAT([Monnth],'-01-',[Year]) AS DATE) = #MyDate
Or
SELECT
*
FROM YourTable
WHERE [Year] = YEAR(#MyDate)
AND [Month] = MONTH(#MyDate)
You can use DATEPART function of SQL Server
SELECT * FROM testTable
WHERE YEAR<= DATEPART(yy,yourdate) AND
MONTH < DATEPART(mm,yourdate)
It would be better to convert data types and query further.
DECLARE #testtable TABLE (id INT identity(1, 1), name VARCHAR(100), year INT, month INT)
INSERT INTO #testtable (name, year, month)
SELECT 'me', '2014', 10
UNION
SELECT 'you', '2017', 08
UNION
SELECT 'us', '2015', 10
UNION
SELECT 'Him', '2017', 10
UNION
SELECT 'Her', '2018', 1
SELECT *
FROM #testtable
WHERE CONCAT (year, '-', right('00' + cast(Month AS VARCHAR(2)), 2), '-', '01')
< = '2017-08-01'
I have a flat file that I am importing into a SQL Server 2005 staging table as character data.
I need to convert the birthday field to datetime format when copying it to the final destination table. I was doing so using the following:
BIRTHDAY = case when isdate(DOB)=1 then convert(datetime, '19'+right(DOB, 2)+left(DOB, 2)+substring(DOB,3,2)) else null end
The problem is only 100+ of the birthdays from the 32k+ file are identified as dates.
I cannot see a difference between the ones that are dates and the ones that aren't. I have included a sampling below.
good date bad date
41129 100465
10531 122467
10429 20252
81030 62661
31231 20959
11028 91965
80928 60665
Looks like the raw data is in MMDDYY, but the months are not 0-padded.
Building on this assumption, you can parse the date parts like below and rebuild a datetime:
declare #raw table (dob varchar(100));
insert into #raw
select '41129' union all
select '10531' union all
select '10429' union all
select '81030' union all
select '31231' union all
select '11028' union all
select '80928' union all
select '100465' union all
select '122467' union all
select '20252' union all
select '62661' union all
select '20959' union all
select '91965' union all
select '60665'
select *,
[asDate] = dateadd(day, dd - 1, dateadd(month, mm - 1, dateadd(year, ('19' + yy)-1900, 0)))
from ( select dob,
substring(right('0' + dob, 6), 1, 2),
substring(right('0' + dob, 6), 3, 2),
substring(right('0' + dob, 6), 5, 2)
from #raw
) as stage (string, mm, dd, yy);
I got the following code from the following question I asked:
Passing in Week Day name to get nearest date in SQL
I need to find next 4 Weekdays based on today's date for corresponding Day-Of-Week in my table ie, if today is 2015-01-24 the result should be 1/24, 1/31, 2/7, 2/14 for Saturdays.
TABLE
SAMPLE QUERY
create table #t
(
jobId int,
personId int,
frequencyVal varchar(10)
);
insert into #t values (1,100,'Mondays'),(2,101,'Saturdays');
WITH cte(n) AS
(
SELECT 0
UNION ALL
SELECT n+1 FROM cte WHERE n < 3
)
select #t.jobId, #t.personId, #t.frequencyVal, STUFF(a.d, 1, 1, '') AS FutureDates
from #t
cross apply (SELECT CASE #t.frequencyVal
WHEN 'SUNDAYS' THEN 1
WHEN 'MONDAYS' THEN 2
WHEN 'TUESDAYS' THEN 3
WHEN 'WEDNESDAYS' THEN 4
WHEN 'THURSDAYS' THEN 5
WHEN 'FRIDAYS' THEN 6
WHEN 'SATURDAYS' THEN 7
END)tranlationWeekdays(n)
cross apply (select ',' + CONVERT(varchar(10), CONVERT(date,dateadd(WEEK, cte.n,CONVERT(DATE, DATEADD(DAY, (DATEPART(WEEKDAY, GETDATE()) + tranlationWeekdays.n) % 7, GETDATE()))))) from cte FOR XML PATH('')) a(d);
drop table #t;
EXPECTED RESULT
Gets the first day of current month.
DECLARE #FIRSTDAY DATE=DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0)
Create the table and insert values
create table #t
(
jobId int,
personId int,
frequencyVal varchar(10)
);
insert into #t values (1,100,'Mondays'),(2,101,'Saturdays');
You can use either of the below queries for your situation.
QUERY 1 : Select the first 4 week of days in current month for particular week day
-- Gets the first day of current month
DECLARE #FIRSTDAY DATE=DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0)
;WITH CTE as
(
-- Will find all dates in current month
SELECT #FIRSTDAY as DATES
UNION ALL
SELECT DATEADD(DAY,1,DATES)
FROM CTE
WHERE DATES < DATEADD(MONTH,1,#FIRSTDAY)
)
,CTE2 AS
(
-- Join the #t table with CTE on the datename+'s'
SELECT jobId,personId,frequencyVal, DATES,
ROW_NUMBER() OVER(PARTITION BY DATENAME(WEEKDAY,CTE.DATES) ORDER BY CTE.DATES) DATECNT
FROM CTE
JOIN #t ON DATENAME(WEEKDAY,CTE.DATES)+'s' = #t.frequencyVal
WHERE MONTH(DATES)= MONTH(GETDATE())
)
-- Converts to CSV and make sure that only 4 days are generated for month
SELECT DISTINCT C2.jobId,C2.personId,frequencyVal,
SUBSTRING(
(SELECT ', ' + CAST(DATEPART(MONTH,DATES) AS VARCHAR(2)) + '/' +
CAST(DATEPART(DAY,DATES) AS VARCHAR(2))
FROM CTE2
WHERE C2.jobId=jobId AND C2.personId=personId AND DATECNT<5
ORDER BY CTE2.DATES
FOR XML PATH('')),2,200000) futureDates
FROM CTE2 C2
SQL FIDDLE
For example, in Query1 the nearest date(here we take example as Saturday) of
2015-Jan-10 will be 01/03,01/10,01/17,01/24
2015-Jan-24 will be 01/03,01/10,01/17,01/24
QUERY 2 : Select nearest 4 week of days in current month for particular week day
-- Gets the first day in current month
DECLARE #FIRSTDAY DATE=DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0)
;WITH CTE as
(
-- Will find all dates in current
SELECT CAST(#FIRSTDAY AS DATE) as DATES
UNION ALL
SELECT DATEADD(DAY,1,DATES)
FROM CTE
WHERE DATES < DATEADD(MONTH,1,#FIRSTDAY)
)
,CTE2 AS
(
-- Join the #t table with CTE on the datename+'s'
SELECT jobId,personId,frequencyVal,DATES,
-- Get week difference for each weekday
DATEDIFF(WEEK,DATES,GETDATE()) WEEKDIFF,
-- Count the number of weekdays in a month
COUNT(DATES) OVER(PARTITION BY DATENAME(WEEKDAY,CTE.DATES)) WEEKCOUNT
FROM CTE
JOIN #t ON DATENAME(WEEKDAY,CTE.DATES)+'s' = #t.frequencyVal
WHERE MONTH(DATES)= MONTH(GETDATE())
)
-- Converts to CSV and make sure that only nearest 4 week of days are generated for month
SELECT DISTINCT C2.jobId,C2.personId,frequencyVal,
SUBSTRING(
(SELECT ', ' + CAST(DATEPART(MONTH,DATES) AS VARCHAR(2)) + '/' +
CAST(DATEPART(DAY,DATES) AS VARCHAR(2))
FROM CTE2
WHERE C2.jobId=jobId AND C2.personId=personId AND C2.frequencyVal=frequencyVal AND
((WEEKDIFF<3 AND WEEKDIFF>-3 AND WEEKCOUNT = 5) OR WEEKCOUNT <= 4)
ORDER BY CTE2.DATES
FOR XML PATH('')),2,200000) futureDates
FROM CTE2 C2
SQL FIDDLE
For example, in Query2 the nearest date(here we take example as Saturday) of
2015-Jan-10 will be 01/03,01/10,01/17,01/24
2015-Jan-24 will be 01/10,01/17,01/24,01/31
QUERY 3 : Select next 4 week's dates for particular week day irrelevant of month
;WITH CTE as
(
-- Will find all dates in current month
SELECT CAST(GETDATE() AS DATE) as DATES
UNION ALL
SELECT DATEADD(DAY,1,DATES)
FROM CTE
WHERE DATES < DATEADD(DAY,28,GETDATE())
)
,CTE2 AS
(
-- Join the #t table with CTE on the datename+'s'
SELECT jobId,personId,frequencyVal, DATES,
ROW_NUMBER() OVER(PARTITION BY DATENAME(WEEKDAY,CTE.DATES) ORDER BY CTE.DATES) DATECNT
FROM CTE
JOIN #t ON DATENAME(WEEKDAY,CTE.DATES)+'s' = #t.frequencyVal
)
-- Converts to CSV and make sure that only 4 days are generated for month
SELECT DISTINCT C2.jobId,C2.personId,frequencyVal,
SUBSTRING(
(SELECT ', ' + CAST(DATEPART(MONTH,DATES) AS VARCHAR(2)) + '/' +
CAST(DATEPART(DAY,DATES) AS VARCHAR(2))
FROM CTE2
WHERE C2.jobId=jobId AND C2.personId=personId AND C2.frequencyVal=frequencyVal
AND DATECNT < 5
ORDER BY CTE2.DATES
FOR XML PATH('')),2,200000) futureDates
FROM CTE2 C2
SQL FIDDLE
The following would be the output if the GETDATE() (if its Saturday) is
2015-01-05 - 1/10, 1/17, 1/24, 1/31
2015-01-24 - 1/24, 1/31, 2/7, 2/14
This is a simpler way I think, and I think it fits your requirements
Note that I have changed your frequency_val column to an integer that represents the day of the week from SQL servers perspective and added a calculated column to illustrate how you can easily derive the day name from that.
/*************************************************/
--Set up our sample table
/*************************************************/
declare #t table
(
jobId int,
personId int,
--frequencyVal varchar(10) -- why store a string when a tiny int will do.
frequency_val tinyint,
frequency_day as datename(weekday,frequency_val -1) + 's'
)
insert into #t
values
(1,100,1),--'Mondays'),
(2,101,6),--'Saturdays');
(3,101,7),--'Sundays');
(4,100,2)--'Tuesdays'),
--select * from #t
/*************************************************/
--Declare & initialise variables
/*************************************************/
declare #num_occurances int = 4
declare #from_date date = dateadd(dd,3,getdate()) -- this will allow you to play with the date simply by changing the increment value
/*************************************************/
-- To get a row for each occurance
/*************************************************/
;with r_cte (days_ahead, occurance_date)
as (select 0, convert(date,#from_date,121)
union all
select r_cte.days_ahead +1, convert(date,dateadd(DD, r_cte.days_ahead+1, #from_date),121)
from r_cte
where r_cte.days_ahead < (7 * #num_occurances) -1
)
select t.*, r_cte.occurance_date
from
#t t
inner join r_cte
on DATEPART(WEEKDAY, dateadd(dd,##DATEFIRST - 1 ,r_cte.occurance_date)) = t.frequency_val
/*************************************************/
--To get a single row with a CSV of every occurance
/*************************************************/
;with r_cte (days_ahead, occurance_date)
as (select 0, convert(date,#from_date,121)
union all
select r_cte.days_ahead +1, convert(date,dateadd(DD, r_cte.days_ahead+1, #from_date),121)
from r_cte
where r_cte.days_ahead < (7 * #num_occurances) -1
)
select
t.*,
STUFF( (select ', '
+ convert(varchar(2),datepart(month,occurance_date),0) + '/'
+ convert(varchar(2),datepart(day,occurance_date),0) as occurance
from r_cte
where DATEPART(WEEKDAY, dateadd(dd,##DATEFIRST - 1 ,r_cte.occurance_date)) = t.frequency_val
FOR XML PATH (''),TYPE).value('.','varchar(30)')
,1,2,'') occurance_date -- rest of STUFF() function
from
#t t
I want to make a SQL query that gets todays date and the most recent date from a date column. So if I have three records in my database that have the following dates:
March 8, 2012
March 2, 2012
December 8, 2011
I want the SQL query to return all records for March 8, 2012 and March 2, 2012 (most recent date). How can I do this?
I can date today's date using:
CONVERT( varchar(100), DATEADD( DAY, 0, getdate() ), 111)
Thank You
Edit:
Thanks everyone. I just have one more question. I have created two views:
create view with top dates
CREATE VIEW topDates AS
select DISTINCT TOP 3 replace(CONVERT(VARCHAR(20),date,111),'-','/') AS dates from CSAResults.dbo.Details
create view dateTwo
select *
from (select ROW_NUMBER() over (order by dates desc) as srNo, dates
from topDates)
AS employee
WHERE srNo=2
And now I want to select * from my DB where a column is equal to the 'dates' column from the view 'dateTwo'
select buildNumber
from CSAResults.dbo.Details
where buildNumber LIKE '%Main '+ (SELECT dates FROM dateTwo) + '%'
But this returns nothing.
Thanks
You can do the following:
select date
from yourtable
where
(
date = Convert(varchar(10), getdate(), 101)
OR
date IN (SELECT Max(date)
FROM yourtable
WHERE date!= Convert(varchar(10), getdate(), 101))
)
Here is an example script that does what you are asking. It uses a sub-query to select all records with MAX on the date. You would just add an OR to also select items for the current date.
DECLARE #A TABLE
(
part_no VARCHAR(5),
rev CHAR,
on_hand TINYINT,
safety_stock TINYINT,
so_no VARCHAR(5),
so_date DATETIME
)
INSERT #A
SELECT '12345', 'A', 10, 15, 'S1234', '12/14/2009' UNION ALL
SELECT '12345', 'A', 10, 15, 'S1233', '10/01/2009' UNION ALL
SELECT '12345', 'A', 10, 15, 'S1232', '08/02/2009' UNION ALL
SELECT '12346', '', 5, 0, 'S1231', '08/01/2009' UNION ALL
SELECT '12347', '-', 0, 0, 'S1230', '10/20/2009' UNION ALL
SELECT '12347', '-', 0, 0, 'S1229', '07/15/2009'
SELECT * FROM #A AS A
WHERE so_date =
(
SELECT MAX(so_date)
FROM #A AS B
WHERE B.part_no = A.part_no AND B.Rev = A.Rev
)
SELECT *
INTO #TEMP
FROM
(
SELECT GETDATE() DATE_FIELD, 'Blah1...' OTHER_FIELDS
UNION SELECT GETDATE() DATE_FIELD, 'Blah2...' OTHER_FIELDS
UNION SELECT DATEADD(d,-1,GETDATE()) DATE_FIELD, 'Blah3...' OTHER_FIELDS
UNION SELECT DATEADD(d,-1,GETDATE()) DATE_FIELD, 'Blah4...' OTHER_FIELDS
UNION SELECT DATEADD(d,-3,GETDATE()) DATE_FIELD, 'Blah5...' OTHER_FIELDS
) A
SELECT * FROM #TEMP
SELECT * FROM
(
SELECT DATE_FIELD, OTHER_FIELDS,
DENSE_RANK() OVER (ORDER BY DATE_FIELD DESC) _RANK
FROM #TEMP
) A
WHERE A._RANK < 3
For your second question:
select buildNumber
from CSAResults.dbo.Details
inner join dateTwo
on buildNumber LIKE '%Main '+ dateTwo.dates + '%'