Select *
from tbl
where id = '1fa3bcdc9a1cf60f02a2ae774e2cf166'
or matching_id = 'ea74c270-65fd-46d0-898b-faf1a7bf7e16'
My id column below comes back with a NULL for one of my events. They are related using the matching_id key. Is there a way I can write a case statement to populate that id field so its not NULL?
You can use coalesce() and in case of null id fetch a value (any value?) for the id matching the matching_id like this:
Select
coalesce(
id,
(select max(id) from tbl where matching_id = 'ea74c270-65fd-46d0-898b-faf1a7bf7e16')
) as id,
matching_id,
event_name
from tbl
where
id = '1fa3bcdc9a1cf60f02a2ae774e2cf166'
or
matching_id = 'ea74c270-65fd-46d0-898b-faf1a7bf7e16'
Edit.
Try this in case of unknown values:
Select
coalesce(
t.id,
(select max(id) from tbl where matching_id = t.matching_id)
) as id,
coalesce(
t.matching_id,
(select max(matching_id) from tbl where id = t.id)
) as matching_id,
t.event_name
from tbl t
Ended up writing something like this..
[snapshot 1
with find_event AS (
Select tbl1. id, tbl1.matching_id
from tbl1
where tbl1.id IS NOT NULL
)
Select
CASE WHEN find_event. id IS NOT NULL
THEN find_event. id
WHEN find_event.id IS NULL
THEN tbl2. id
ELSE tbl2. id
END as final_id,
tbl2.matching_id,
tbl2. id,
tbl2.event_name,
find _event. id as find_canonical_id
from tbl2
left JOIN find_event on find_event.matching_id = tbl2.matching_id
where
tbl2.transaction_canonical_id = '1fa3bcdc9a1cf60f02a2ae774e2cf166'
or
tbl2.matching_id = 'ea74c270-65fd-46d0-898b-faf1a7bf7e16'
If you want to replace the column values with the values from your parameters, you could use something like this:
with ids (id, mid) as (
values
('1fa3bcdc9a1cf60f02a2ae774e2cf166', 'ea74c270-65fd-46d0-898b-faf1a7bf7e16')
)
Select coalesce(tbl.id, ids.id),
tbl.matching_id,
tbl.event_name
from tbl
join ids on ids.id = tbl.id or ids.mid = tbl.matching_id;
You may be able to utilize the ISNULL() function for this. Maybe something like:
Select
ISNULL(id, matching_id) AS [myid],
matching_id,
event_name
from tbl
where id = '1fa3bcdc9a1cf60f02a2ae774e2cf166'
or matching_id = 'ea74c270-65fd-46d0-898b-faf1a7bf7e16'
Related
I'm trying to get a number of count for exist and non-exist for my validation to insert my data. As refer to the image below, I'm inserting 3 data in which 1 data consist of same ID number as destination table, 1 data consist of same quotation number as destination table and the last data is a new entry.
Okay here's my requirement. I am sending my source table data to insert into the dest table. So before inserting, I want to do validation by mapping the entire dest table like this:
SELECT COUNT(*) FROM sourceTable WHERE exists(
SELECT * FROM sourceTable WHERE QuotationId IN
(SELECT A.QuotationId FROM sourceTable A
JOIN DestTable B ON A.QuotationId = B.QuotationId
JOIN DestTable C ON A.QuotationNum = C.QuotationNum)
Without further details on table structure and so on it's difficult to tell, but something like the following might do the trick:
WITH cteMatch AS(
SELECT s.QuotationID AS src, d.QuotationID as dst
FROM sourceTable s
LEFT JOIN destTable d
)
SELECT CASE WHEN dst IS NULL THEN N'NonExist' ELSE N'Exist' END AS ValExist, COUNT(*) cnt
FROM cteMatch
GROUP BY CASE WHEN dst IS NULL THEN N'NonExist' ELSE N'Exist' END
You seem to want:
select count(*)
from sourcetable s
where exists(
select 1
from desttable d
where d.quotationid = s.quotationid or d.quotationnum = s.quotationnum
)
This counts how many rows in the source table have a quotation id or num that exists in the target table. If you want the count of both existing and non-existing rows, I would recommend:
select sum(flag) as cnt_exists, sum(1 - flag) as cnt_not_exists
from (
select
case when exists (
select 1
from desttable d
where d.quotationid = s.quotationid or d.quotationnum = s.quotationnum
) then 1 else 0 end as flag
from sourcetable s
) t
Following are the two tables in SQL Server: TABLE_A and TABLE_B
I need to get the output as follows:
Get IDs from TABLE_A where Exist = 0
We would get 100, 101 & 102
Now, among 100, 101 & 102, no other rows (in the same table) with the same ID value should have Exist = 1
Hence, 100 can't be selected as it has Exist = 1 in the 2nd row.
So, only 101 & 102 remain
With the remaining ID values (101 & 102), check against the ID column in TABLE_B where 'Exist' column value should not be equal to '1' in any of the rows
In TABLE_B, 4th row has Exist = 1 for 102. So, that can't be selected
We have only 101 now. This is required output and that should be selected.
Could you let me know how to write the simplest query to achieve this please? Let me know if the question needs to be improved.
You can use exists & not exists :
with t as (
select t1.*
from t1
where exists (select 1 from t1 t11 where t11.id = t1.id and t11.exists = 0) and
not exists (select 1 from t1 t11 where t11.id = t1.id and t11.exists = 1)
)
select t.*
from t
where not exists (select 1 from t2 where t.id = t2.id and t2.exists = 1);
Try:
SELECT
ID,
SUM(CAST(Exist AS int)) AS [Exists]
FROM
TABLE_A
GROUP BY ID
HAVING SUM(CAST(Exist AS bit)) = 0
will give you the answer to the first part. You can then JOIN this to a similar query for TABLE_B. That is a "simple" way to show how this works. You can write more complex queries as that from #Yogest Sharma
Like #Peter Smith mentioned, you can use the aggregate function SUM. Note that you would need a cast since you cannot use the aggregate function on a field that has a BIT datatype
;WITH CTE AS
(
SELECT ID, SUM(CAST(Exist AS INT)) AS AggExist FROM TABLE_A GROUP BY ID
UNION
SELECT ID, SUM(CAST(Exist AS INT)) As AggExist FROM TABLE_B GROUP BY ID
)
SELECT ID, SUM(AggExist) FROM CTE GROUP BY ID
HAVING SUM(AggExist) = 0
Here is the demo
I have a table that contains comma-separated values in a column In Postgres.
ID PRODS
--------------------------------------
1 ,142,10,75,
2 ,142,87,63,
3 ,75,73,2,58,
4 ,142,2,
Now I want a query where I can give a comma-separated string and it will tell me the number of matches between the input string and the string present in the row.
For instance, for input value ',142,87,', I want the output like
ID PRODS No. of Match
------------------------------------------------------------------------
1 ,142,10,75, 1
2 ,142,87,63, 2
3 ,75,73,2,58, 0
4 ,142,2, 1
Try this:
SELECT
*,
ARRAY(
SELECT
*
FROM
unnest(string_to_array(trim(both ',' from prods), ','))
WHERE
unnest = ANY(string_to_array(',142,87,', ','))
)
FROM
prods_table;
Output is:
1 ,142,10,75, {142}
2 ,142,87,63, {142,87}
3 ,75,73,2,58, {}
4 ,142,2, {142}
Add the cardinality(anyarray) function to the last column to get just a number of matches.
And consider changing your database design.
Check This.
select T.*,
COALESCE(No_of_Match,'0')
from TT T Left join
(
select ID,count(ID) No_of_Match
from (
select ID,unnest(string_to_array(trim(t.prods, ','), ',')) A
from TT t)a
Where A in ('142','87')
group by ID
)B
On T.Id=b.id
Demo Here
OutPut
If you install the intarray extension, this gets quite easy:
select id, prods, cardinality(string_to_array(trim(prods, ','), ',')::int[] & array[142,87])
from bad_design;
Otherwise it's a bit more complicated:
select bd.id, bd.prods, m.matches
from bad_design bd
join lateral (
select bd.id, count(v.p) as matches
from unnest(string_to_array(trim(bd.prods, ','), ',')) as l(p)
left join (
values ('142'),('87') --<< these are your input values
) v(p) on l.p = v.p
group by bd.id
) m on m.id = bd.id
order by bd.id;
Online example: http://rextester.com/ZIYS97736
But you should really fix your data model.
with data as
(
select *,
unnest(string_to_array(trim(both ',' from prods), ',') ) as v
from myTable
),
counts as
(
select id, count(t) as c from data
left join
( select unnest(string_to_array(',142,87,', ',') ) as t) tmp on tmp.t = data.v
group by id
order by id
)
select t1.id, t1.prods, t2.c as "No. of Match"
from myTable t1
inner join counts t2 on t1.id = t2.id;
In the below SQL:
I need to add two columns in the result
1) Local_code
2)Local_CPTY_SYS_ID,
which are in HSBC_LOCAL_INVOL_PARTY table.
So far I have tried to add
select local_code from HSBC_LOCAL_INVOL_PARTY
h join t_cdr T2
on T2.counterparty_new = h.entity_code
but that doesn't work. It needs an explicit outer join in the end. Please help
SELECT
T2.counterparty_new,
T2.bis_entity_type_original,
T2.counterparty_new_desc,
T2.counterparty_new_attribute_6,
T2.method_original,
T2.netting_agreement_reference,
T2.internal_rating_new,
T2.counterparty_type_original,
T2.obligor_grade_new,
T2.pd_pre_floor_new,
T2.pd_new,
T2.lgd,
T2.rwa
from t_cdr T2,
(
SELECT * FROM (
SELECT
FINAL.FILTER_MARKER,
FINAL.entity_code
FROM (
SELECT
FILTER_POP.entity_code,
FILTER_POP.FILTER_MARKER
FROM (
SELECT
CASE
WHEN CONCAT(Dlgd,unfloored_lgd) IS NOT NULL
THEN 'EXCLUDE'
WHEN CONCAT(Dlgd,unfloored_lgd) IS NULL
THEN 'INCLUDE'
END AS FILTER_MARKER,
entity_code,
Dlgd,
unfloored_lgd
FROM
HSBC_LOCAL_INVOL_PARTY
WHERE
((HSBC_LOCAL_INVOL_PARTY.entity_code) NOT LIKE '%DUM%')
AND
((HSBC_LOCAL_INVOL_PARTY.entity_code) NOT LIKE '%HSBC%')
) FILTER_POP
GROUP BY
FILTER_POP.entity_code,
FILTER_POP.FILTER_MARKER) FINAL
GROUP BY
FINAL.FILTER_MARKER,
FINAL.entity_code
ORDER BY
FINAL.entity_code)
PIVOT
(
COUNT(FILTER_MARKER)
FOR FILTER_MARKER IN ('INCLUDE' AS INCLUDE,'EXCLUDE' AS EXCLUDE)
)
WHERE INCLUDE = 1 AND EXCLUDE = 0
) ENTITY_FILTER
WHERE ENTITY_FILTER.entity_code = T2.counterparty_new
AND T2.method_original = 'ADV'
ORDER BY T2.rwa DESC
Solved it: Look at the last few lines. Took a while but optimized it as well for performance.
SELECT
T2.counterparty_new,
T2.bis_entity_type_original,
T2.counterparty_new_desc,
T2.counterparty_new_attribute_6,
T2.method_original,
T2.netting_agreement_reference,
T2.internal_rating_new,
T2.counterparty_type_original,
T2.obligor_grade_new,
T2.pd_pre_floor_new,
T2.pd_new,
T2.lgd,
HSBC_LOCAL_INVOL_PARTY.local_code,
T2.rwa
from t_cdr T2,
(
SELECT * FROM (
SELECT
FINAL.FILTER_MARKER,
FINAL.entity_code
FROM (
SELECT
FILTER_POP.entity_code,
FILTER_POP.FILTER_MARKER
FROM (
SELECT
CASE
WHEN CONCAT(Dlgd,unfloored_lgd) IS NOT NULL
THEN 'EXCLUDE'
WHEN CONCAT(Dlgd,unfloored_lgd) IS NULL
THEN 'INCLUDE'
END AS FILTER_MARKER,
entity_code,
Dlgd,
unfloored_lgd
FROM
HSBC_LOCAL_INVOL_PARTY
WHERE
((HSBC_LOCAL_INVOL_PARTY.entity_code) NOT LIKE '%DUM%')
AND
((HSBC_LOCAL_INVOL_PARTY.entity_code) NOT LIKE '%HSBC%')
) FILTER_POP
GROUP BY
FILTER_POP.entity_code,
FILTER_POP.FILTER_MARKER) FINAL
GROUP BY
FINAL.FILTER_MARKER,
FINAL.entity_code
ORDER BY
FINAL.entity_code)
PIVOT
(
COUNT(FILTER_MARKER)
FOR FILTER_MARKER IN ('INCLUDE' AS INCLUDE,'EXCLUDE' AS EXCLUDE)
)
WHERE INCLUDE = 1 AND EXCLUDE = 0
) ENTITY_FILTER,HSBC_LOCAL_INVOL_PARTY
WHERE ENTITY_FILTER.entity_code = T2.counterparty_new
AND ENTITY_FILTER.entity_code = HSBC_LOCAL_INVOL_PARTY.entity_code(+)
AND T2.method_original = 'ADV'
ORDER BY T2.rwa DESC
Hi there I am trying to execute a query but cannot seem to get it right.
SELECT *
FROM table
WHERE id IN (SELECT *
FROM table
WHERE description = 'A')
AND description = 'B'
Above is the query that I have got, the select * from table where description = A works as expected when ran alone I just need to make the where clause to work so I can see any id that has a description of A and B.
You will be getting multiple columns from the sub query when I assume you only want the id column:
SELECT *
FROM table
WHERE id IN (SELECT id
FROM table
WHERE description = 'A')
AND description = 'B'
No need for the select in the where clause
SELECT *
FROM table
WHERE id IN ('A', 'B')
Try this:
SELECT *
FROM table
WHERE description IN ('A', 'B')
it should be:
select * from table where id in (select id from table where description = 'A') and description = 'B'
but this query will give you zero result as you select records with description = 'A' and description = 'B', if you want to get records with either description of A or B, then you should write as
select * from table where description = 'A' or description = 'B'
or
select * from table where description in ('A','B')
SELECT distinct AnaTablo.Id , AnaTablo.FirmaAdi , AnaTablo.FirmaId , AnaTablo.KayitTarihi ,
users.Email Personel, (SELECT top 1 sabitler.Ayar from tblSabitAyarlar sabitler WHERE sabitler.Tur = 29 and sabitler.Deger in
(SELECT top 1 IslemId from tblEFaturaTakipIslem Islem WHERE AnaTablo.Id = Islem.EFaturaTakipId order by KayitTarihi desc))YapilanIslem,
AnaTablo.Eposta , AnaTablo.Aciklama
from tblEFaturaTakip AnaTablo left join AspNetUsers users on AnaTablo.PersonelId = users.Id