I have 2 input tables, and I need output in string format.
I tried following query, but it does not work. How can I get the above output?
with
cte1 as --table 1
(select 1 as id , 'A' as abc from dual
union
select 2 as id , 'B' as abc from dual
union
select 3 as id , 'C' as abc from dual
union
select 4 as id , 'D' as abc from dual
union
select 5 as id , 'E' as abc from dual
union
select 6 as id , 'F' as abc from dual
),
cte2 as --table2
(select 1 as id, 3 as name from dual
union
select 1 as id, 5 as name from dual
union
select 1 as id, 4 as name from dual
union
select 2 as id, 3 as name from dual
union
select 2 as id, 6 as name from dual
)
SELECT e.id, e.abc, m.id as mgr, e.abc, c.*
FROM
cte1 e, cte2 m, cte2 c
WHERE e.id = m.id
and
e.id=c.name;
You are trying to join each row in table 1 to two rows in table 2, and the conditions can never both be true.
You want to join each row in table 2 to two rows in table 1:
SELECT e.abc, m.abc
FROM cte2 c, cte1 e, cte1 m
WHERE e.id = c.id
AND m.id = c.name
ORDER BY c.id, c.name;
A A
- -
A C
A D
A E
B C
B F
or with 'modern' join syntax, which you should really be using:
SELECT e.abc, m.abc
FROM cte2 c
JOIN cte1 e ON e.id = c.id
JOIN cte1 m ON m.id = c.name
ORDER BY c.id, c.name;
A A
- -
A C
A D
A E
B C
B F
Related
Will the following 2 SQL statements give same result?
SQL1-
A inner join B on (condition1)
union
A inner join B on (condition2)
union
A inner join B on (condition3)
SQL2-
A inner join B on (condition1) OR (condition2) OR (condition3)
At least it depends on A or B originally having doubles. For example
with A(c) as (
select 1 union all
select 1 union all
select 2
),
B(c) as (
select 1 union all
select 2 union all
select 3
)
select *
from A join B on A.c=B.c
union
select *
from A join B on A.c>B.c
returns 3 rows (distinct).
with A(c) as (
select 1 union all
select 1 union all
select 2
),
B(c) as (
select 1 union all
select 2 union all
select 3
)
select *
from A join B on A.c=B.c or A.c>B.c
returns 4 rows due to A having doubles.
I want to combine 5 multiple tables, that have the same reference ID as the basic table containing all IDs. The "joined" tables are not containing a value for every reference, but sometimes they have multiple values for one reference. The output should be a sum of each value of the ID.
Example:
Basic Table:
Reference
Basic.Value
1
a
2
b
3
c
4
d
5
e
6
f
7
g
8
h
Table 1:
Reference
T1.Value
1
i
2
j
2
x
3
k
4
l
Table 2
Reference
T2.Value
1
m
5
n
7
o
7
y
8
p
Table 3
Reference
T3.Value
2
q
4
r
6
s
8
t
8
z
Result that should be the output:
Reference
Basic.Value
SUM(T1.Value)
SUM(T2.Value)
SUM(T3.Value)
1
a
i
m
2
b
(j+x)
q
3
c
k
4
d
l
r
5
e
n
6
f
s
7
g
(o+y)
8
h
p
(t+z)
I tried the following code:
SELECT
T0."STATUS",
T0."DocNum" AS "ProjectNumber",
T0."NAME", T0."CARDNAME" AS "Client",
T0."FINISHED" AS "Project Finished",
T1."PoPhAmt" AS "Project Value",
T1."PhBudget" AS "Budget",
(T1."PoPhAmt"-T1."PhBudget") AS "Planned Gross Profit",
T1."TotalAP" AS "Ordered",
SUM(T2."PaidSys") AS "Paid Downpayments(Client)",
COUNT(T2."PaidSys"),
SUM(T3."PaidSys") AS "Paid Invoices(Client)",
COUNT(T3."PaidSys"),
SUM(T4."PaidSys") AS "Creditnotes(Client)",
COUNT(T4."PaidSys")
FROM
(OPMG T0 INNER JOIN PMG8 T1 ON T0."AbsEntry" = T1."AbsEntry")
LEFT JOIN ODPI T2 ON T0."FIPROJECT" = T2."Project"
LEFT JOIN OINV T3 ON T0."FIPROJECT" = T3."Project"
LEFT JOIN ORIN T4 ON T0."FIPROJECT" = T4."Project"
WHERE
T0."FINISHED" < '100' AND T0."STATUS" <> 'N' AND T0."STATUS" <> 'P'
GROUP BY
T0."STATUS",
T0."DocNum",
T0."NAME",
T0."CARDNAME",
T0."FINISHED" ,
T1."PoPhAmt",
T1."PhBudget",
T1."TotalAP"
ORDER BY
T0."DocNum"
Aggregate before joining:
select *
from basic_table t left join
(select t1.project, count(*) as cnt1, sum(value) as value1
from t1
group by t1.project
) t1
on t.FIPROJECT = T1.Project left join
(select t2.project, count(*) as cnt2, sum(value) as value2
from t2
group by t2.project
) t2
on t.FIPROJECT = T2.Project left join
(select t3.project, count(*) as cnt3, sum(value) as value3
from t3
group by t3.project
) t3
on t.FIPROJECT = T3.Project;
SELECT T.ID,T.VALUE,T1.VALUE T_1_VALUE,T2.VALUE T_2_VALUE,T3.VALUE T_3_VALUE
FROM BASIC_TABLE T
LEFT JOIN TABLE_1 T1 ON T.ID=T1.ID
LEFT JOIN TABLE_2 T2 ON T.ID=T2.ID
LEFT JOIN TABLE_3 T3 ON T.ID=T3.ID
WITH BASIC_TABLE(REFERENCE,BASIC_VALUE) AS
(
SELECT 1, 'a' UNION ALL
SELECT 2 , 'b' UNION ALL
SELECT 3 , 'c' UNION ALL
SELECT 4 , 'd' UNION ALL
SELECT 5 , 'e' UNION ALL
SELECT 6 , 'f' UNION ALL
SELECT 7 , 'g' UNION ALL
SELECT 8 , 'h'
),
TABLE_1(REFERENCE,T1_VALUE) AS
(
SELECT 1, 'i' UNION ALL
SELECT 2, 'j' UNION ALL
SELECT 2, 'x' UNION ALL
SELECT 3, 'k' UNION ALL
SELECT 4, 'l'
),
TABLE_2(REFERENCE,T2_VALUE)AS
(
SELECT 1, 'm' UNION ALL
SELECT 5, 'n' UNION ALL
SELECT 7, 'o' UNION ALL
SELECT 7, 'y' UNION ALL
SELECT 8 , 'p'
),
TABLE_3(REFERENCE,T3_VALUE)AS
(
SELECT 2, 'q' UNION ALL
SELECT 4, 'r' UNION ALL
SELECT 6, 's' UNION ALL
SELECT 8, 't' UNION ALL
SELECT 8, 'z'
)
SELECT B.REFERENCE,B.BASIC_VALUE,ISNULL(T1.R,'')AS SUM_T_1_VALUE,ISNULL(T2.R,'')AS SUM_T_2_VALUE,
ISNULL(T3.R,'')AS SUM_T_3_VALUE
FROM BASIC_TABLE AS B
LEFT JOIN
(
SELECT T.REFERENCE,STRING_AGG(T.T1_VALUE,'+')R
FROM TABLE_1 AS T
GROUP BY T.REFERENCE
)T1 ON B.REFERENCE=T1.REFERENCE
LEFT JOIN
(
SELECT T.REFERENCE,STRING_AGG(T.T2_VALUE,'+')R
FROM TABLE_2 AS T
GROUP BY T.REFERENCE
)T2 ON B.REFERENCE=T2.REFERENCE
LEFT JOIN
(
SELECT T.REFERENCE,STRING_AGG(T.T3_VALUE,'+')R
FROM TABLE_3 AS T
GROUP BY T.REFERENCE
)T3 ON B.REFERENCE=T3.REFERENCE
Not sure about SAP HANA, but in MS SQL Server 2017 this code produces more or less the required output
use following query STRING_AGG function with group by Basic_Table.Reference
SELECT
T.Reference,
MAX(T.Basic_Value) AS Basic_Value,
SUM(T1.T1_Value) AS T1_Value,
SUM(T2.T2_Value) AS T2_Value,
SUM(T3.T3_Value) AS T3_Value
FROM BASIC_TABLE T
LEFT JOIN TABLE_1 T1 ON T.Reference=T1.Reference
LEFT JOIN TABLE_2 T2 ON T.Reference=T2.Reference
LEFT JOIN TABLE_3 T3 ON T.Reference=T3.Reference
GROUP BY T.Reference
I have a table with id, name and parent_id where parent_id is a parent hierarchy relating to id, see below.
id
name
parent_id
0
A
null
1
B
0
2
C
1
3
D
1
4
E
2
I'm trying to create a nicer looking table with each id and its parent_id, including multiple levels up in the hierarchy. I use UNION and self-join to accomplish this, but I have a feeling there should be a nicer way of querying it with BigQuery's Standard SQL.
In the query below I go two levels, but you can imagine I want to go 5-6 levels.
WITH T1 as (
select 0 as id, 'A' as name, null as parent_id union all
select 1 as id, 'B' as name, 0 as parent_id union all
select 2 as id, 'C' as name, 1 as parent_id union all
select 3 as id, 'D' as name, 1 as parent_id union all
select 4 as id, 'E' as name, 2 as parent_id
)
SELECT
a.id as id,
a.name as req_name,
FROM T1 as a
UNION ALL
SELECT
a.id as id,
b.name as req_name,
FROM T1 as a
JOIN T1 as b ON a.parent_id = b.id
UNION ALL
SELECT
a.id as id,
c.name as req_name,
FROM T1 as a
JOIN T1 as b on a.parent_id = b.id
JOIN T1 as c on b.parent_id = c.id
resulting in the table
id
req_name
0
A
1
B
2
C
3
D
4
E
2
A
3
A
4
B
1
A
2
B
3
B
4
C
I would be thankful for any insights!
BigQuery does not (yet) support recursive or hierarchical queries. So your approach is actually fine. You can condense it, if you like, using left joins:
with t as (
select 0 as id, 'A' as name, null as parent_id union all
select 1 as id, 'B' as name, 0 as parent_id union all
select 2 as id, 'C' as name, 1 as parent_id union all
select 3 as id, 'D' as name, 1 as parent_id union all
select 4 as id, 'E' as name, 2 as parent_id
)
select distinct id, t1.name
from t t1 left join
t t2
on t2.parent_id = t1.id left join
t t3
on t3.parent_id = t2.id cross join
unnest(array[t1.id, t2.id, t3.id]) id
where id is not null;
You still need explicit joins to the maximum depth of the data.
The other alternative is to use a looping construct, which is available in the scripting language.
I got 2 tables "Records" and "Char". With 1 -> N relation
I need to make a select, with a subquery/join where the value to present on the join column is a fixed string like "Multiple Chars" or the content Char.char_val
Let me illustrate:
Records:
R_ID | Name Char: C_ID | R_ID | Char_Val
1 A 1 3 c1
2 B 2 1 c2
3 C 3 1 c3
4 2 c3
Expected Result:
R_ID | Name | Char_Val
1 A Multiple Records
2 B c3
3 C c1
I guess my query would be something like:
Select r.R_ID, r.Name, (conditional select) Char_Val
From Records r, Char c
where r.R_ID = c.R_ID
Suggestions for the (conditional select)?
You can use a case statement and aggregation to get a fixed string:
case when count(c.c_id) > 1 then 'Multiple Records' else max(c.char_val) end
and you need to group by r_id and name:
select r.r_id, r.name,
case when count(c.c_id) > 1 then 'Multiple Records'
else max(c.char_val) end as char_val
from records r
join char c on r.r_id = c.r_id
group by r.r_id, r.name
order by r.r_id;
I've also switched to use ANSI joins instead of the old syntax (as #Thorsten suggested).
This is a demo using CTE to generate your data, giving them slightly different names because char is a reserved word:
with t_records (r_id, name) as (
select 1, 'A' from dual
union all select 2, 'B' from dual
union all select 3, 'C' from dual
),
t_char (c_id, r_id, char_val) as (
select 1, 3, 'c1' from dual
union all select 2, 1, 'c2' from dual
union all select 3, 1, 'c3' from dual
union all select 4, 2, 'c3' from dual
)
select r.r_id, r.name,
case when count(c.c_id) > 1 then 'Multiple Records'
else max(c.char_val) end as char_val
from t_records r
join t_char c on r.r_id = c.r_id
group by r.r_id, r.name
order by r.r_id;
R_ID N CHAR_VAL
---------- - ----------------
1 A Multiple Records
2 B c3
3 C c1
Group by r_id. Either MIN = MAX or you want 'Multiple Records':
select r_id, r.name, c.char_vals
from
(
select
r_id,
case when min(char_val) = max(char_val) then min(char_val) else 'Multiple Records' end
as char_vals
from char
group by r_id
) c
join records r using(r_id)
order by r_id;
Following query gives the result (with Char_val separated by comma) you expected:
Select r.R_ID, r.Name, listagg(c.char_val,',') WITHIN GROUP(ORDER BY c.char_val) AS Char_Val
From Records r, Char c
where r.R_ID = c.R_ID
GROUP BY r.R_ID, r.Name
in need Help with oracle SQL.
I have a table with
from to
F B
B R
R D
E X
X Q
and I need the list
F
B
R
D
E
X
Q
so my problem is the jump from R-->D to E-->X
Edit: It's a big list with from and to, seperatet with a annother column as citerium. Normaly there is every from in the to column, so i used
SELECT from,snr as Nr FROM list where StrAbsNr = 1
union all
SELECT to,snr + 1 as Nr FROM list
to create a ordered list. But there are gaps in some parts, in the example there is D-->E missing
has anybody an idea ?
for your example this work:
WITH ft AS
(SELECT 'f' vfrom, 'b' AS vto FROM dual UNION ALL
SELECT 'b' , 'r' FROM dual UNION ALL
SELECT 'r','d' FROM dual UNION ALL
SELECT 'e','x' FROM dual UNION ALL
SELECT 'x','q' FROM dual )
SELECT a.a, MAX(rn), MIN(ob)
FROM
( SELECT vfrom a , rownum rn, 1 ob FROM ft
UNION ALL
SELECT vto , rownum rn, 2 ob FROM ft
) a
GROUP BY a
ORDER BY MAX(rn), MIN(ob)
A MAX(RN) MIN(OB)
- ---------- ----------
f 1 1
b 2 1
r 3 1
d 3 2
e 4 1
x 5 1
q 5 2
7 rows selected
or analityc func row_number:
SELECT *
FROM
(SELECT a.a,
row_number() over (partition BY a order by rn, ob) rna,
ob,
rn
FROM
( SELECT vfrom a, rownum rn, 1 ob FROM ft
UNION ALL
SELECT vto , rownum rn, 2 ob FROM ft
) a
)
WHERE rna=1
ORDER BY rn,
ob
A RNA OB RN
- ---------- ---------- ----------
f 1 1 1
b 1 2 1
r 1 2 2
d 1 2 3
e 1 1 4
x 1 2 4
q 1 2 5
7 rows selected
select "from" as val from table
union
select to from table
And if you want to keep the order:
select distinct val
from (select "from" as val, rownum, 1 as valOrder from table
union
select to, rownum, 2 as valOrder from table)
order by rownum,valOrder