how to query daily cost of specific product in bigQuery? - google-bigquery

Question

I exported billing to bigquery and I want to get the translations total cost in specific date from bigQuery monthly or specific date. like April 1, 2019.
google docs sample query get monthly.
SELECT
invoice.month,
SUM(cost)
+ SUM(IFNULL((SELECT SUM(c.amount)
FROM UNNEST(credits) c), 0))
AS total,
(SUM(CAST(cost * 1000000 AS int64))
+ SUM(IFNULL((SELECT SUM(CAST(c.amount * 1000000 as int64))
FROM UNNEST(credits) c), 0))) / 1000000
AS total_exact
FROM `project.dataset.gcp_billing_export_v1_XXXXXX_XXXXXX_XXXXXX`
GROUP BY 1
ORDER BY 1 ASC
;
but I created my query this way:
$myVariable=
"SELECT
COUNT(*) total_times,
SUM(cost) total_cost
FROM
`project.dataset.gcp_billing_export_v1_XXXXXX_XXXXXX_XXXXXX`
WHERE
service.description = 'Translate' AND (usage_end_time >= timestamp('2019-04-04 00:00:00') AND usage_end_time <= timestamp('2019-04-04 23:59:59'))";
I want to get the total cost of the current day and the total cost from the first day of the month to the current day.
sample:
1. 2019/04/04: 4223.05 - (882 Times)
2. 2019/04/Total: 16505.43 - (3882 Times)

Answer 1

You can further add details to your working query:
SELECT
service.description,
timestamp_trunc(usage_start_time,DAY) as time_fragment,
ROUND(SUM(cost)
+ SUM(IFNULL((SELECT SUM(c.amount)
FROM UNNEST(credits) c), 0)),3)
AS total,
round((SUM(CAST(cost * 1000000 AS int64))
+ SUM(IFNULL((SELECT SUM(CAST(c.amount * 1000000 as int64))
FROM UNNEST(credits) c), 0))) / 1000000,3)
AS total_exact
FROM `project.dataset.gcp_billing_export_v1_XXXXXX_XXXXXX_XXXXXX`
WHERE service.description='Translate'
GROUP BY 1,2
ORDER BY 2 desc;
which displays:
you can further to into HOURly granularity if you edit line 3.