I have 2 tables :
tab_1 :
ID VAL
1 Y
2 N
3 Y
tab_2 :
ID VAL
2 N
3 X
4 Y
I want to get the final output like
ID Operation
1 INSERT
2 EQUAL
3 DIFF
4 DEL
I am in very basic level in joins so need some help in explanation/understanding this type of functionalities.Thanks in advance.
It appears that you want a full outer join between the two tables; and then a case expression to compare the val columns (both their existence and values) in both tables. Maybe something like:
-- CTEs for sample data
with tab_1 (ID, VAL) as (
select 1, 'Y' from dual
union all select 2, 'N' from dual
union all select 3, 'Y' from dual
),
tab_2 (ID, VAL) as (
select 2, 'N' from dual
union all select 3, 'X' from dual
union all select 4, 'Y' from dual
)
-- actual query
select coalesce(t1.id, t2.id) as id,
case
when t1.id is null then 'DEL'
when t2.id is null then 'INSERT'
when t2.val = t1.val then 'EQUAL'
else 'DIFF'
end as operation
from tab_1 t1
full outer join tab_2 t2 on t2.id = t1.id
order by id;
ID OPERATION
---------- ---------
1 INSERT
2 EQUAL
3 DIFF
4 DEL
Related
Hi I am trying to filter data with dates between but it insert null 0 rows created its cross joining table I am not aware is there problem due to cross joining or something else. There is no error message
without dates it works fine any solution Please
insert into PAY_IN_OUT2 (EMP_CODE, DATE_IN, DATE_OUT, ATT_DATE, DATE_INA, DATE_OUTA, DATE_INB, DATE_OUTB, DATE_INC, DATE_OUTC, ATT_PRESENT)
select a.EMPLOYEE_ID1, b.DT, b.DT1, B.ATT_DT, B.DT3, B.DT4, B.DT4, B.DT5, B.DT5, B.DT3, 'P'
from CALENDAR_DATES4 b cross join EMPLOYEES a
WHERE A.EMPLOYEE_ID1 BETWEEN 70001 AND 70009
AND B.ATT_DT BETWEEN TO_DATE('10/02/2021', 'DD/MM/YYYY') AND TO_DATE('20/02/2021', 'DD/MM/YYYY') ;
without this its working fine but I have to filter this with dates AND B.ATT_DT BETWEEN TO_DATE('10/02/2021', 'DD/MM/YYYY') AND TO_DATE('20/02/2021', 'DD/MM/YYYY')
If you're cross joining two tables and filtering on each table, and you end up selecting 0 rows, then at least one of your predicates is causing no rows to be returned.
For example, here's a set of queries demonstrating some different results, depending on what the predicates cause to be returned:
WITH t1 AS (SELECT 1 ID, 10 val FROM dual UNION ALL
SELECT 2 ID, 20 val FROM dual UNION ALL
SELECT 3 ID, 30 val FROM dual UNION ALL
SELECT 4 ID, 40 val FROM dual UNION ALL
SELECT 5 ID, 50 val FROM dual),
t2 AS (SELECT 'A' col1, 'AA' col2 FROM dual UNION ALL
SELECT 'B' col1, 'BA' col2 FROM dual UNION ALL
SELECT 'C' col1, 'AC' col2 FROM dual UNION ALL
SELECT 'D' col1, 'DD' col2 FROM dual)
SELECT 1 case_no, -- case 1: no rows expected to be returned (no t1 rows with an id between 6 and 10)
t1.*,
t2.*
FROM t1
CROSS JOIN t2
WHERE t1.id BETWEEN 6 AND 10
AND t2.col2 LIKE 'A%'
UNION ALL
SELECT 2 case_no, -- case 2: no rows expected to be returned (no t2 rows with a col2 starting with "C")
t1.*,
t2.*
FROM t1
CROSS JOIN t2
WHERE t1.id BETWEEN 2 AND 4
AND t2.col2 LIKE 'C%'
UNION ALL
SELECT 3 case_no, -- case 3: no rows expected to be returned (no t1 rows with an id between 6 and 10, and no t2 rows with a col2 starting with "C")
t1.*,
t2.*
FROM t1
CROSS JOIN t2
WHERE t1.id BETWEEN 6 AND 10
AND t2.col2 LIKE 'C%'
UNION ALL
SELECT 4 case_no, -- case 4: 6 rows expected to be returned (3 t1 rows with an id between 2 and 4, and 2 t2 rows with a col2 starting with "A"; 3 x 2 = 6)
t1.*,
t2.*
FROM t1
CROSS JOIN t2
WHERE t1.id BETWEEN 2 AND 4
AND t2.col2 LIKE 'A%';
CASE_NO ID VAL COL1 COL2
---------- ---------- ---------- ---- ----
4 2 20 A AA
4 3 30 A AA
4 4 40 A AA
4 2 20 C AC
4 3 30 C AC
4 4 40 C AC
You can see that only case 4 (rows in both tables match the predicates) has any rows returned by the cross join.
ETA: if you were wanting to see employee rows regardless of whether there are matching date rows or not, you would need to use an outer join, e.g. using my earlier example, case 2 would become:
WITH t1 AS (SELECT 1 ID, 10 val FROM dual UNION ALL
SELECT 2 ID, 20 val FROM dual UNION ALL
SELECT 3 ID, 30 val FROM dual UNION ALL
SELECT 4 ID, 40 val FROM dual UNION ALL
SELECT 5 ID, 50 val FROM dual),
t2 AS (SELECT 'A' col1, 'AA' col2 FROM dual UNION ALL
SELECT 'B' col1, 'BA' col2 FROM dual UNION ALL
SELECT 'C' col1, 'AC' col2 FROM dual UNION ALL
SELECT 'D' col1, 'DD' col2 FROM dual)
SELECT t1.*,
t2.*
FROM t1
LEFT OUTER JOIN t2 ON t2.col2 LIKE 'C%'
WHERE t1.id BETWEEN 2 AND 4;
ID VAL COL1 COL2
---------- ---------- ---- ----
2 20
3 30
4 40
Table 1
no name col1
1 a a_1
2 b b_1
Table 2
id name parent
a_1 zz c_1
b_1 yy d_1
c_1 aa null
d_1 bb e_1
e_1 dd1 null
what i want to show is showing the all list name. for example table 1 name a has col1 name a_1 it will show the name on table 2, and then check the parent in the table 2 and show it and keep checking until it found null. the example is like below.. im sorry for my bad explanation
t1_name t2_name t2_name t2_name
a zz aa
b yy bb dd1
or shows like below
t1_name t2_name
a aa/zz
b dd1/bb/yy
what I've done is this query
select t1.name,t2.name as folder from table1 as t1 inner join table2 as t2 on t1.col1=t2.id
and I don't know how to check again in query... I am using oracle version 12.2.0.1.0 in SQL developer any help?
You want to get the rows from the first table and then recursively fetch all the rows from the second table until you reach a null parent, so you do:
with cte(NAME,
PARENT,
CURRENTPATH) as
(select t1.NAME,
t2.PARENT,
t2.NAME as CURRENTPATH
from TABLE1 t1
join TABLE2 t2 on t1.COL1 = t2.ID
union all
select t1.NAME,
t2.PARENT,
t1.CURRENTPATH || '/' || t2.NAME as CURRENTPATH
from cte t1
join TABLE2 t2 on t2.ID = t1.PARENT)
select NAME,
CURRENTPATH
from cte
where PARENT is null;
You can use the hierarchical query as following:
SQL> -- Your data
SQL> with table1(no,name,col1) as
2 (SELECT 1, 'a','a_1' FROM DUAL UNION ALL
3 SELECT 2, 'b','b_1' FROM DUAL
4 ),
5 table2 (id, name, parent) as
6 (select 'a_1', 'zz', 'c_1' from dual union all
7 select 'b_1', 'yy', 'd_1' from dual union all
8 select 'c_1', 'aa', null from dual union all
9 select 'd_1', 'bb', 'e_1' from dual union all
10 select 'e_1', 'dd1', null from dual)
11 -- Your query starts from here
12 SELECT
13 T1.NAME AS T1_NAME,
14 T2.NAMES AS T2_NAMES
15 FROM TABLE1 T1
16 JOIN (
17 SELECT
18 T2.ID,
19 SYS_CONNECT_BY_PATH(T2.NAME, '/') AS NAMES,
20 ROW_NUMBER() OVER(PARTITION BY ID ORDER BY LEVEL DESC) AS L
21 FROM TABLE2 T2
22 CONNECT BY T2.PARENT = PRIOR T2.ID
23 ) T2 ON T1.COL1 = T2.ID
24 WHERE L = 1;
T1_NAME T2_NAMES
------- ---------------
a /aa/zz
b /dd1/bb/yy
SQL>
Cheers!!
Which Oracle version are you using?
ID | Type | total
1 Purchase 12
1 Return 2
1 Exchange 5
2 Purchase null
2 Return 5
2 Exchange 1
3 Purchase 34
3 Return 4
3 Exchange 2
4 Purchase 12
4 Exchange 2
Above is sample data. What I want to return is:
ID | Type | total
1 Purchase 12
1 Return 2
1 Exchange 5
3 Purchase 34
3 Return 4
3 Exchange 2
So if a field is null in total or the values of Purchase, Return and Exchange are not all present for that ID, ignore that ID completely. How can I go about doing this?
You can use exists. I think you intend:
select t.*
from t
where exists (select 1
from t t2
where t2.id = t.id and t2.type = 'Purchase' and t2.total is not null
) and
exists (select 1
from t t2
where t2.id = t.id and t2.type = 'Exchange' and t2.total is not null
) and
exists (select 1
from t t2
where t2.id = t.id and t2.type = 'Return' and t2.total is not null
);
There are ways to "simplify" this:
select t.*
from t
where 3 = (select count(distinct t2.type)
from t t2
where t2.id = t.id and
t2.type in ('Purchase', 'Exchange', 'Return') and
t2.total is not null
);
I would write this as a join, without subqueries:
SELECT pur.id, pur.total AS Purchase, exc.total AS Exchange, ret.total AS Return
FROM MyTable as pur
INNER JOIN MyTable AS exc ON exc.id=pur.id AND exc.type='Exchange'
INNER JOIN MyTable AS ret ON ret.id=pur.id AND ret.type='Return'
WHERE pur.type='Purchase'
The inner join means that if any of the three rows with different values are not found for a given id, then no row is included in the result.
Analytic functions are a good way to solve this kind of problems. The base table is read just once, and no joins (explicit or implicit, as in EXISTS conditions or correlated subqueries) are needed.
In the solution below, we count distinct values of 'Purchase', 'Exchange' and 'Return' for each id while ignoring other values (assuming that is indeed the requirement), and separately count total nulls in the total column for each id. Then it becomes a trivial matter to select just the "desired" rows in an outer query.
with
test_data ( id, type, total ) as (
select 1, 'Purchase', 12 from dual union all
select 1, 'Return' , 2 from dual union all
select 1, 'Exchange', 5 from dual union all
select 2, 'Purchase', null from dual union all
select 2, 'Return' , 5 from dual union all
select 2, 'Exchange', 1 from dual union all
select 3, 'Purchase', 34 from dual union all
select 3, 'Return' , 4 from dual union all
select 3, 'Exchange', 2 from dual union all
select 4, 'Purchase', 12 from dual union all
select 4, 'Exchange', 2 from dual
)
-- end of test data; actual solution (SQL query) begins below this line
select id, type, total
from ( select id, type, total,
count( distinct case when type in ('Purchase', 'Return', 'Exchange')
then type end
) over (partition by id) as ct_type,
count( case when total is null then 1 end
) over (partition by id) as ct_total
from test_data
)
where ct_type = 3 and ct_total = 0
;
Output:
ID TYPE TOTAL
-- -------- -----
1 Exchange 5
1 Purchase 12
1 Return 2
3 Exchange 2
3 Purchase 34
3 Return 4
This also should work fine even if new values are added to type column
select * from t where
ID not in(select ID from t where
t.total is null or t.[Type] is null)
I have to join 2 tables with SQL in a special way:
TABLE1 has the fields GROUP and MEMBER, TABLE2 has the fields GROUP and MASTER.
I have to build a new TABLE3 with the fields GROUP and ID by copying TABLE1 to TABLE3 and search TABLE2 if there is a GROUP from TABLE1 and if, copy GROUP and MASTER to TABLE3.
Example:
table1:
group member
1 a
1 b
1 c
2 x
3 y
table2:
group master
3 n
3 z
1 k
9 v
2 m
7 o
8 p
Expected result, table3:
group id
1 a from table1
1 b from table1
1 c from table1
1 k from table2
2 x from table1
2 m from table2
3 y from table1
3 z from table2
3 n from table2
I hope everything's clear.
So what is the SQL query?
Thanks, Hein
The first part (copy members) should be easy:
INSERT INTO table3 (group, id) SELECT group, member FROM table1;
Then You just copy the masters, that are in groups, that are already present in table1:
INSERT INTO table3 (group, id) SELECT group, master FROM table2 WHERE group IN (SELECT DISTINCT group FROM table1);
Try this out. Of course you need to INSERT the whole selection to your new table named Table3.
WITH TABLE1(GRP,MMBR) AS
(SELECT 1, 'a' FROM DUAL UNION ALL
SELECT 1, 'b' FROM DUAL UNION ALL
SELECT 1, 'c' FROM DUAL UNION ALL
SELECT 2, 'x' FROM DUAL UNION ALL
SELECT 3, 'y' FROM DUAL),
TABLE2(GRP,MSTR) AS
(SELECT 3, 'n' FROM DUAL UNION ALL
SELECT 3, 'z' FROM DUAL UNION ALL
SELECT 1, 'k' FROM DUAL UNION ALL
SELECT 9, 'v' FROM DUAL UNION ALL
SELECT 2, 'm' FROM DUAL UNION ALL
SELECT 7, 'o' FROM DUAL UNION ALL
SELECT 8, 'p' FROM DUAL)
SELECT * FROM (
SELECT GRP, MMBR ID FROM TABLE1
UNION --UNION ALL if you need duplicates
SELECT GRP, MSTR ID FROM TABLE2
WHERE TABLE2.GRP IN (SELECT GRP FROM TABLE1)
)
ORDER BY GRP, ID
You can do it using UNION ALL and 2 simple SELECT in an INSERT as follows:
INSERT INTO table3(group,id)
SELECT group,id FROM table1
UNION ALL
SELECT group,id FROM table2
SELECT * FROM table3;
And if you don't want duplicate values,try this using UNION instead of UNION ALL:
INSERT INTO table3(group,id)
SELECT group,id FROM table1
UNION
SELECT group,id FROM table2
SELECT * FROM table3;
I want to categorize data into two types based on:
If a value exists in T2, display "A", else display "B" as "Type". Is there a way to implement this in case when or decode?
T1 is the parent of T2.
T1
1
2
3
4
5
T2
1
1
3
3
3
4
Ideally my output would be
Type
A
B
A
A
B
edit: I want to add that A and B are text values I want to display based on my above condition, this is not coming from the db. Also, T2 will not have a corresponding record at all for 2 & 5. so I cannot really check for null.
Try this:
SELECT T1.Col,
CASE WHEN T2.Col IS NOT NULL THEN 'A' ELSE 'B' END AS Type
FROM T1
LEFT JOIN (
SELECT DISTINCT Col FROM T2
) AS T2 ON T1.Col = T2.Col
Oracle Setup:
CREATE TABLE T1 ( column_name ) AS
SELECT LEVEL FROM DUAL CONNECT BY LEVEL < 6;
CREATE TABLE t2 ( column_name ) AS
SELECT 1 FROM DUAL UNION ALL
SELECT 1 FROM DUAL UNION ALL
SELECT 3 FROM DUAL UNION ALL
SELECT 3 FROM DUAL UNION ALL
SELECT 4 FROM DUAL;
Query:
SELECT NVL2( T2.column_name, 'A', 'B' ) AS Type
FROM T1
LEFT OUTER JOIN
( SELECT DISTINCT column_name FROM T2 ) T2
ON T1.column_name = T2.column_name
ORDER BY T1.column_name;
Output:
TYPE
----
A
B
A
A
B