Issue using MINUS clause in SQL - sql

While using minus clause in between two statements giving some error. Can someone help me with this?
Error is Msg 102, Level 15, State 1, Line 101
Incorrect syntax near 'MINUS'.
SELECT a from (SELECT DISTINCT(name) as a FROM hack WHERE name LIKE '%') a
MINUS
SELECT b from (SELECT DISTINCT(name) as b FROM hack WHERE name LIKE '[aeiou]%[aeiou]') b

MINUS is exist in Oracle. By seeing your error message, I hope you are looking in SQL Server.
In SQL Server, EXCEPT is the correct replacement for MINUS.
SELECT DISTINCT name
FROM hack
WHERE name LIKE '%'
EXCEPT
SELECT DISTINCT name
FROM hack
WHERE name LIKE '[aeiou]%[aeiou]'

You can simplify the logic to:
SELECT DISTINCT name
FROM hac
WHERE name NOT LIKE '[aeiou]%[aeiou]'
A simple comparison should be much more efficient that multiple comparisons along with set operators.

Related

REPLACE with JOIN - SQL

I need help to understand what I did wrong ... I'm a beginner so excuse me the simple question!
I have two tables in which I want to do a JOIN where, in one of the columns I had to use REPLACE to remove the text 'RIxRE' that does not interest me.
In table 1, this is the original text of the column id_notification: RIxRE-1787216-BSB and this is the text that returns when using REPLACE: 1787216-BSB
In column 2, this is the text that exists: 1787216-BSB
However, I get the following error:
# 1054 - Unknown column 'a.id_not' in 'on clause'
SELECT *, REPLACE(a.id_notificacao,'RIxRE','') AS id_not
FROM robo_qualinet_cadastro_remedy a
JOIN (SELECT * FROM painel_monitoracao) b ON a.id_not = b.id_notificacao
You cannot use a column alias again in the FROM clause or the WHERE clause after the SELECT (and possibly not other clauses as well, depending on the database).
So, repeat the expression:
SELECT *, REPLACE(a.id_notificacao, 'RIxRE', '') AS id_not
FROM robo_qualinet_cadastro_remedy rqcr JOIN
painel_monitoracao pm
ON REPLACE(rqcr.id_notificacao, 'RIxRE', '') = pm.id_notificacao;
Notes:
Use table aliases the mean something, such as abbreviations for the able names.
The subquery is not necessary in the FROM clause.
I suspect that you have a problem with your data model if you need a REPLACE() for the JOIN condition, but that is a different issue from this question.

Sql - Error with expression of non-boolean

Can anyone help me find this issue?
This is my code
SELECT
MSC_Customer.cust_number, cust_name,
COUNT(ord_number) AS number_of_orders
FROM
MSC_Customer, MSC_Order
WHERE
MSC_Customer.cust_number = MSC_Order.cust_number
HAVING
MSC_Customer.cust_number
GROUP BY
cust_city LIKE 'Pennsylvania';
I get this error
Msg 4145, Level 15, State 1, Line 5
An expression of non-boolean type specified in a context where a condition is expected, near 'GROUP'.
I am trying to join the two tables, and use a COUNT aggregate and a GROUP BY clause in the SELECT statement
I'm going to suggest the following corrected query:
SELECT
c.cust_number,
c.cust_name,
COUNT(ord_number) AS number_of_orders
FROM MSC_Customer c
INNER JOIN MSC_Order o
ON c.MSC_Customer = o.cust_number
WHERE
cust_city LIKE '%Pennsylvania%' -- or maybe just cust_city = 'Pennsylvania'
GROUP BY
c.cust_number,
c.cust_name;
I am assuming that you want to aggregate by customer name/number. The check on the customer city would seem to belong in a WHERE clause, not in the GROUP BY clause. Of note, I rephrased your query to use an explicit inner join, instead of an old school implicit join. This is the preferred way of writing joins now.
Use condition in Where not Group By. Try below Script
SELECT MSC_Customer.cust_number, cust_name, count(ord_number) AS
number_of_orders
FROM MSC_Customer
JOIN MSC_Order ON
MSC_Customer.cust_number = MSC_Order.cust_number
WHERE cust_city like '%Pennsylvania%'
GROUP BY cust_city;
This type of error occurs generally when you write keyword which is used in expression or condition but you have not passed the value of the condition. For example -
select * from table where
this will give the same error as you have not passed here the value for where
You have missed to write the condition in having clause. You need to write the value with operator in having clause which may be one of the following.
HAVING
MSC_Customer.cust_number = '0120008024'
OR
HAVING
MSC_Customer.cust_number <> '0120008024'
OR
HAVING
MSC_Customer.cust_number like '%0120008024%'
You have to only specify the values in having clause you have missed as per your requirement.

sql searching multiple words in a string

What is the most efficient and elegant SQL query looking for a string containing the words "David", "Moses" and "Robi". Assume the table is named T and the column C.
Select * from table where
columnname like'%David%' and
columnname like '%Moses%' and columnname like'%Robi%'
In SQL Server 2005+ with Full-Text indexing switched on, I'd do the following:
SELECT *
FROM T
WHERE CONTAINS(C, '"David" OR "Robi" OR "Moses"');
If you wanted your search to bring back results where the result is prefixed with David, Robi or Moses you could do:
SELECT *
FROM T
WHERE CONTAINS(C, '"David*" OR "Robi*" OR "Moses*"');
Here is what I uses to search for multiple words in multiple columns - SQL server
Hope my answer help someone :) Thanks
declare #searchTrm varchar(MAX)='one two three ddd 20 30 comment';
--select value from STRING_SPLIT(#searchTrm, ' ') where trim(value)<>''
select * from Bols
WHERE EXISTS (SELECT value
FROM STRING_SPLIT(#searchTrm, ' ')
WHERE
trim(value)<>''
and(
BolNumber like '%'+ value+'%'
or UserComment like '%'+ value+'%'
or RequesterId like '%'+ value+'%' )
)
If you care about the sequence of the terms, you may consider using a syntax like
select * from T where C like'%David%Moses%Robi%'
Oracle SQL :
select *
from MY_TABLE
where REGEXP_LIKE (company , 'Microsodt industry | goglge auto car | oracles database')
company - is the database column name.
results - this SQL will show you if company column rows contain one of those companies (OR phrase)
please note that : no wild characters are needed, it's built in.
more info at : http://www.techonthenet.com/oracle/regexp_like.php
if you put all the searched words in a temporaray table say #tmp and column col1, then you could try this:
Select * from T where C like (Select '%'+col1+'%' from #temp);
Maybe EXISTS can help.
and exists (select 1 from #DocumentNames where pcd.Name like DocName+'%' or CD.DocumentName like DocName+'%')
Oracle SQL:
There is the "IN" Operator in Oracle SQL which can be used for that:
select
namet.customerfirstname, addrt.city, addrt.postalcode
from schemax.nametable namet
join schemax.addresstable addrt on addrt.adtid = namet.natadtid
where namet.customerfirstname in ('David', 'Moses', 'Robi');

How do I execute different SELECT statements based on a CASE

I am facing a problem in executing queries with CASE statement.
Based on my condition,(for eg. length), I want to execute different SQL statement.
Problematic sample query is as follows:
select case
when char_length('19480821') = 8
then select count(1) from Patient
when char_length('19480821')=10
then select count(1) from Doctor
end
Exception:
[Error] Script lines: 1-5 --------------------------
Incorrect syntax near the keyword 'select'.
Msg: 156, Level: 15, State: 2
Server: sunsrv4z7, Line: 2
I am not able to correct the syntax. I am getting the string for char_length as input from the user.
How can I fire queries based on certain condition?
Is CASE the right choice ? Or do I have to use any other thing.
Just put opening and closing bracket around select statement resolve you problem
select
case when
char_length('19480821')=8 then
(select count(1) from Patient )
when
char_length('19480821')=10 then
(select count(1) from Doctor )
end
select
case when char_length('19480821')=8 then (select count(1) from Patient)
when char_length('19480821')=10 then (select count(1) from Doctor)
end
The problem is that you are missing opening and closing brackets in your nested 'Select' statements :)
Please do note that it is not a case STATEMENT, it is a case EXPRESSION. By enclosing the queries in parentheses, you are converting them (syntactically) to values.
This is similar in principle to a subquery, such as
" select name from Doctor where salary = (select max(salary) from Doctor)"
select
case when
LEN('1948082100')=8 then
(select 'HELLO' )
when
LEN('194808210')=10 then
(select 'GOODBYE')
end
Change the values to test results.

Is there any way to combine IN with LIKE in an SQL statement?

I am trying to find a way, if possible, to use IN and LIKE together. What I want to accomplish is putting a subquery that pulls up a list of data into an IN statement. The problem is the list of data contains wildcards. Is there any way to do this?
Just something I was curious on.
Example of data in the 2 tables
Parent table
ID Office_Code Employee_Name
1 GG234 Tom
2 GG654 Bill
3 PQ123 Chris
Second table
ID Code_Wildcard
1 GG%
2 PQ%
Clarifying note (via third-party)
Since I'm seeing several responses which don't seems to address what Ziltoid asks, I thought I try clarifying what I think he means.
In SQL, "WHERE col IN (1,2,3)" is roughly the equivalent of "WHERE col = 1 OR col = 2 OR col = 3".
He's looking for something which I'll pseudo-code as
WHERE col IN_LIKE ('A%', 'TH%E', '%C')
which would be roughly the equivalent of
WHERE col LIKE 'A%' OR col LIKE 'TH%E' OR col LIKE '%C'
The Regex answers seem to come closest; the rest seem way off the mark.
I'm not sure which database you're using, but with Oracle you could accomplish something equivalent by aliasing your subquery in the FROM clause rather than using it in an IN clause. Using your example:
select p.*
from
(select code_wildcard
from second
where id = 1) s
join parent p
on p.office_code like s.code_wildcard
In MySQL, use REGEXP:
WHERE field1 REGEXP('(value1)|(value2)|(value3)')
Same in Oracle:
WHERE REGEXP_LIKE(field1, '(value1)|(value2)|(value3)')
Do you mean somethign like:
select * FROM table where column IN (
SELECT column from table where column like '%%'
)
Really this should be written like:
SELECT * FROM table where column like '%%'
Using a sub select query is really beneficial when you have to pull records based on a set of logic that you won't want in the main query.
something like:
SELECT * FROM TableA WHERE TableA_IdColumn IN
(
SELECT TableA_IdColumn FROM TableB WHERE TableA_IDColumn like '%%'
)
update to question:
You can't combine an IN statement with a like statement:
You'll have to do three different like statements to search on the various wildcards.
You could use a LIKE statement to obtain a list of IDs and then use that in the IN statement.
But you can't directly combine IN and LIKE.
Perhaps something like this?
SELECT DISTINCT
my_column
FROM
My_Table T
INNER JOIN My_List_Of_Value V ON
T.my_column LIKE '%' + V.search_value + '%'
In this example I've used a table with the values for simplicity, but you could easily change that to a subquery. If you have a large list (like tens of thousands) then performance might be rough.
select *
from parent
where exists( select *
from second
where office_code like trim( code_wildcard ) );
Trim code_wildcard just in case it has trailing blanks.
You could do the Like part in a subquery perhaps?
Select * From TableA Where X in (Select A from TableB where B Like '%123%')
tsql has the contains statement for a full-text-search enabled table.
CONTAINS(Description, '"sea*" OR "bread*"')
If I'm reading the question correctly, we want all Parent rows that have an Office_code that matches any Code_Wildcard in the "Second" table.
In Oracle, at least, this query achieves that:
SELECT *
FROM parent, second
WHERE office_code LIKE code_wildcard;
Am I missing something?