I have a code that imports chatterbot.
I run
python -m spacy download en
python terminal1.py.
terminal1.py
''''
import spacy
from chatterbot import ChatBot
# Uncomment the following lines to enable verbose logging
# import logging
# logging.basicConfig(level=logging.INFO)
# Create a new instance of a ChatBot
bot = ChatBot(
'Terminal',
storage_adapter='chatterbot.storage.SQLStorageAdapter',
logic_adapters=[
'chatterbot.logic.MathematicalEvaluation',
'chatterbot.logic.TimeLogicAdapter',
'chatterbot.logic.BestMatch'
],
database_uri='sqlite:///database.db'
)
print('Type something to begin...')
# The following loop will execute each time the user enters input
while True:
try:
user_input = input()
bot_response = bot.get_response(user_input)
print(bot_response)
# Press ctrl-c or ctrl-d on the keyboard to exit
except (KeyboardInterrupt, EOFError, SystemExit):
break
''''
I get the error
OSErrror: [E050] Can't find model 'en'. It doesn't seem to be a shortcut link, a Python package or a valid path to a data directory.
Can some one help me fix this problem and in the process run the code. I will be much thankful.
try to run this command pip install spacy && python -m spacy download en this will link en model.
Related
i want to use TreeTagger module to tag POS-information on the raw corpus.
As it seems to be faster to use GPU via Google Colab, I installed TreeTagger module, but Colab codes cannot locate TreeTagger directory.
The error type is like this:
TreeTaggerError: Can't locate TreeTagger directory (and no TAGDIR specified)
Please tell me where I should uplaod the treetagger folder.
You have to specify directory:
treetaggerwrapper.TreeTagger(TAGLANG='en', TAGDIR='treetagger/') # treetagger is the installation dir
Installation in Colab.
Follow the instructions on the website.
In one cell in Colab you have to put the following (for other (not English) languages put other link for parameter files):
%%bash
mkdir treetagger
cd treetagger
# Download the tagger package for your system (PC-Linux, Mac OS-X, ARM64, ARMHF, ARM-Android, PPC64le-Linux).
wget https://cis.lmu.de/~schmid/tools/TreeTagger/data/tree-tagger-linux-3.2.4.tar.gz
tar -xzvf tree-tagger-linux-3.2.4.tar.gz
# Download the tagging scripts into the same directory.
wget https://cis.lmu.de/~schmid/tools/TreeTagger/data/tagger-scripts.tar.gz
gunzip tagger-scripts.tar.gz
# Download the installation script install-tagger.sh.
wget https://cis.lmu.de/~schmid/tools/TreeTagger/data/install-tagger.sh
# Download the parameter files for the languages you want to process.
# list of all files (parameter files) https://cis.lmu.de/~schmid/tools/TreeTagger/#parfiles
wget https://cis.lmu.de/~schmid/tools/TreeTagger/data/english.par.gz
sh install-tagger.sh
cd ..
sudo pip install treetaggerwrapper
And in the other following cell you can check the installation:
>>> import pprint # For proper print of sequences.
>>> import treetaggerwrapper
>>> #1) build a TreeTagger wrapper:
>>> tagger = treetaggerwrapper.TreeTagger(TAGLANG='en', TAGDIR='treetagger/')
>>> #2) tag your text.
>>> tags = tagger.tag_text("This is a very short text to tag.")
>>> #3) use the tags list... (list of string output from TreeTagger).
>>> pprint.pprint(tags)
I have a Centos 7 server with cPanel and I'm working on a Telegram bot for my business needs. The bot should be able to run a terminal command with os.system or subprocess.Popen, however both options do not work when configured through a webhook + wsgi process.
I tested both with bot.polling method and they worked as a charm, however after I switched to webhook method served by flask and wsgi, both stopped working for me. I have tried the following:
mycommand = "python3.6 GoReport.py --id 31-33 --format word"
os.chdir('dir_to_run_command_from')
os.system(mycommand)
and the following one:
mycommand = "python3.6 GoReport.py --id 31-33 --format word"
subprocess.Popen(mycommand, cwd="dir_to_run_command_from", shell=True)
Both options simply do nothing right now. I tried to print them both and received 0 as a response. I wonder if the issue is caused by permissions or something.
I expect both options to work through webhook + wsgi as good as they work through bot.polling method.
I think I got it wrong. Your script writes a report to a specific directory. You do not need a result in your application route.
I wrote a small test application called tryout. It runs in a virtual environment.
$ mkdir tryout
$ cd tryout
$ python3 -m venv tryout
$ source tryout/bin/activate
$ export FLASK_APP=tryout/app
$ export FLASK_ENV=development
$ flask run
Directory structure:
/tryout
/app/*
/bin/*
/include/*
/lib/*
/subdir/*
Application:
# /tryout/app/__init__.py
import sys, os
from flask import Flask
def create_app(env=os.getenv('FLASK_ENV', 'development')):
app = Flask(__name__)
#app.route('/run-script')
def run_script():
import subprocess
cmd = 'python script.py'
cwd = 'subdir'
ret = subprocess.check_output(cmd, cwd=cwd, shell=True)
print(ret)
return ret, 200
return app
app = create_app()
Script:
# /subdir/script.py
import os, sys
def main():
with open('report.txt', 'w+') as fp:
fp.write('Info\n')
sys.stdout.write('It works!')
if __name__ == '__main__':
main()
It works!
A new file named "report.log" is written into the "subdir"-directory.
In Browser appears "It works!".
Hope I could help you or I have no real idea of what you want to do.
If you want to run an external script from inside flask, you could use subprocess to run the script from the command line. This is the right solution.
#app.route('/run-script')
def run_script():
cmd = '<your command here!>'
result = subprocess.check_output(cmd, cwd='<your wordir>', shell=True)
return render_template('results.html', **locals())
Have fun!
#Bogdan Kozlowskyi
Is it possible to pipe on the command line? Do you need to return a result to the user?
cmd = 'first_cmd | tee report.log'
result = subprocess.check_output(cmd, cwd='<your wordir>', shell=True)
Perhaps you should look for shell commands like '>>', '>' and 'tee'.
Seems to be a user-groups permission problem (execute and write).
I have installed TensorFlow in virtual environment on Ubunut 16.04. when I enter in virtualen by using command "source ~/tensorflow/bin/activate" it enters in virtualen. but after that when I enter the command " import tensorflow as tf" it gives me the following error
"import: not authorized 'tf' # error/constitute.c/WriteImages/1028."
how to solve this..
Maybe you forgot about telling which interpreter to use. Two variants:
Add shebang #!/usr/bin/env python3 at the beginning of you script
OR
Run script like python3 my_scripy.py
In windows power shell ,I can run scrapy shell 'http://www.hao123.com',
scrapy shell 'http://www.hao123.com
I can run ipython
I can run ipython but not scrapy shell 'http://www.hao123.com'
ipython then scrapy shell 'http://www.hao123.com
In ipython notebook,I can't run scrapy shell 'http://www.hao123.com'also
scrapy shell 'http://www.hao123.com'
File "<ipython-input-3-be4048c8f90b>", line 1
scrapy shell 'http://www.hao123.com'
^
SyntaxError: invalid syntax
Ipython is installed by anaconda,scrapy is installed by pip,anaconda and pip is in different file.
Please help me!
That's not a feature you can have in ipython. scrapy shell is a command, it's own application completely separate from ipython.
However, there are two things you can do:
If you have a Spider and Response objects from somewhere you can simply use scrapy.shell.inspect_repsonse
from scrapy.shell import inspect_response
# You need a scrapy spider object that has crawler instance attached to it
some_spider = Spider()
# you need response object
some_response = Response()
inspect_response(some_spider, some_response)
# new ipython shell will be embedded, like one from scrapy shell command
Otherwise you can spawn a subprocess:
import subprocess
subprocess.call('scrapy shell http://stackoverflow.com', shell=True)
# new ipython shell will be embedded, like one from scrapy shell command
if you are using Anaconda on windows 7 .
Follow: environment --> root --> Open terminal. Then you can write:
scrapy shell 'http://www.hao123.com'
Environment:
Mac OS X 10.8.5
Apache2 (version that came with the OS)
Python2 (version that came with the OS)
Python3 (installed via Homebrew)
This code returns "testing" in the web browser:
#!/usr/bin/env python
# -*- coding: UTF-8 -*-
from __future__ import print_function, division
print("Content-Type: text/html") # HTML is following.
print() # Blank line, end of headers.
print("testing")
But this code returns "Internal Server Error" in the web browser (using python3 this time):
#!/usr/bin/env python3
# -*- coding: UTF-8 -*-
print("Content-Type: text/html") # HTML is following.
print() # Blank line, end of headers.
print("testing")
...and in the Apache2 error log:
env: python3: No such file or directory
Premature end of script headers: test_cgi.py
In echo $PATH:
/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin
Looking deeper, ls -al /usr/bin/python*:
/usr/bin/python
/usr/bin/python-config
/usr/bin/python2.5 -> ../../System/Library/Frameworks/Python.framework/Versions/2.5/bin/python2.5
/usr/bin/python2.5-config -> ../../System/Library/Frameworks/Python.framework/Versions/2.5/bin/python2.5-config
/usr/bin/python2.6 -> ../../System/Library/Frameworks/Python.framework/Versions/2.6/bin/python2.6
/usr/bin/python2.6-config -> ../../System/Library/Frameworks/Python.framework/Versions/2.6/bin/python2.6-config
/usr/bin/python2.7 -> ../../System/Library/Frameworks/Python.framework/Versions/2.7/bin/python2.7
/usr/bin/python2.7-config -> ../../System/Library/Frameworks/Python.framework/Versions/2.7/bin/python2.7-config
/usr/bin/pythonw
/usr/bin/pythonw2.5 -> ../../System/Library/Frameworks/Python.framework/Versions/2.5/bin/pythonw2.5
/usr/bin/pythonw2.6 -> ../../System/Library/Frameworks/Python.framework/Versions/2.6/bin/pythonw2.6
/usr/bin/pythonw2.7 -> ../../System/Library/Frameworks/Python.framework/Versions/2.7/bin/pythonw2.7
And in ls -al /usr/local/bin/python*:
/usr/local/bin/python3 -> ../Cellar/python3/3.3.3/bin/python3
/usr/local/bin/python3.3 -> ../Cellar/python3/3.3.3/bin/python3.3
/usr/local/bin/python3.3-config -> ../Cellar/python3/3.3.3/bin/python3.3-config
/usr/local/bin/pythonw3.3 -> ../Cellar/python3/3.3.3/bin/pythonw3.3
Questions:
Since the first item in my PATH is /usr/local/bin, why can't Apache find Python3 ?
How can I tell Apache to use Python3 ?
Thank you for your help :)
I have the exact same problem; I cannot figure out how to get apache to recognize python3. Furthermore, if you specify the interpreter manually:
#!/usr/bin/python
Works, however:
#!/usr/local/bin/python3
Complains about a "malformed header from script" in the apache error log... I have no idea why this is an issue as it should just be running an arbitrary interpreter.
EDIT
Okay, so my problem was actually just me not outputting header information. Your issue is that no python3 environment variable has been set. Try changing the first line to:
#!/usr/local/bin/python3