SQL: Update and Insert with condition - sql

Question

I would like to know if this is possible. I would like to update a record only if the typeId equal my value and add a record in table B if that's the case.
TableA:
id (PK, int)
typeId (int)
TableB:
id (PK, int)
tableAId (FK, int)
note (nvarchar)
My SQL script:
UPDATE [dbo].[TableA]
SET [TypeId] = CASE
WHEN [TypeId] = 4 THEN 6 AND
(INSERT INTO [dbo].[TableB] ([tableAId],[note])
VALUES ([dbo].[TableA].Id,'type has changed'))
ELSE [Id]
END
The script above looks like I want to achieve but obviously it's incorrect. How can I do multiple things in my case condition? Update a value and insert a record with the current id?
Data sample:
Table A (id, typeId)
1, 4
2, 5
3, 2
Table B (id, tableAid, note)
1, 1, 'note1'
2, 1, 'note2'
3, 2, 'note1'
Should become:
Table A (id, typeId)
1, 6
2, 5
3, 2
Table B (id, tableAid, note)
1, 1, 'note1'
2, 1, 'note2'
3, 2, 'note1'
4, 1, 'type has changed'

Answer 1

Try to use OUTPUT clause.
Test tables and data:
CREATE TABLE A(
id int NOT NULL PRIMARY KEY,
typeId int NOT NULL
)
INSERT A(id,typeId)VALUES(1, 4),(2, 5),(3, 2)
CREATE TABLE B(
id int NOT NULL IDENTITY PRIMARY KEY,
tableAid int NOT NULL REFERENCES A(id),
note varchar(50) NOT NULL
)
SET IDENTITY_INSERT B ON
INSERT B(id,tableAid,note)VALUES(1, 1, 'note1'),(2, 1, 'note2'),(3, 2, 'note1')
SET IDENTITY_INSERT B OFF
Using OUTPUT demo:
DECLARE #LogTable TABLE(tableAid int,note varchar(50))
UPDATE A
SET
typeId=6
OUTPUT inserted.id,'type has changed'
INTO #LogTable(tableAid,note)
WHERE typeID=4
INSERT B(tableAid,note)
SELECT tableAid,note
FROM #LogTable
If you drop the foreign key in the table B then you can use OUTPUT directly into table B without #LogTable:
-- table B without FOREIGN KEY
CREATE TABLE B(
id int NOT NULL IDENTITY PRIMARY KEY,
tableAid int NOT NULL, --REFERENCES A(id),
note varchar(50) NOT NULL
)
-- only one UPDATE with OUTPUT
UPDATE A
SET
typeId=6
OUTPUT inserted.id,'type has changed'
INTO B(tableAid,note)
WHERE typeID=4