SQL Order of Operations - GROUP BY using field created in SELECT - sql

I'm having trouble wrapping my head around a fairly elementary concept. Any help appreciated!
I have learned from resources like this that the processing order of SQL operations is:
1) from
2) where
3) group by
4) having
5) select
6) order by
7) limit
However, I am perplexed when looking at this below query taken from DataCamp. If SQL is processing GROUP BY before SELECT, how can I use a field that was created within the SELECT statement (home_team) in the GROUP BY clause?
Thank you!
-- Identify the home team as Bayern Munich, Schalke 04, or neither
SELECT
CASE WHEN hometeam_id = 10189 THEN 'FC Schalke 04'
WHEN hometeam_id = 9823 THEN 'FC Bayern Munich'
ELSE 'Other' END AS home_team,
COUNT(id) AS total_matches
FROM matches_germany
-- Group by the CASE statement alias
GROUP BY home_team;

Your particular query has:
GROUP BY hometeam_id
---------^
This is a column in the original data, not in the SELECT. The data is aggregated at the hometeam_id level. Then the CASE expression is applied after the aggregation.
Your question supposed that the query is written using:
GROUP BY home_team
And this might or might not work, depending on the database.
SQL does not have an "order of processing". The SQL engine analyzes the query and develops a directed-acyclic graph (DAG) representing the operations that need to be performed on the data.
What you are thinking of are rules for the scoping of identifiers in SQL. The big question is where an alias defined in a SELECT can be used.
Basically no databases allow column aliases to be used in the following clauses:
SELECT
FROM
WHERE
All databases allow column aliases in the following clauses:
ORDER BY.
Some databases allow column aliases in the GROUP BY and HAVING clauses.
Your database appears to be one that allows such usage in the GROUP BY.

Related

SQL - Difference between .* and * in aggregate function query

SELECT reviews.*, COUNT(comments.review_id)
AS comment_count
FROM reviews
LEFT JOIN comments ON comments.review_id = reviews.review_id
GROUP BY reviews.review_id
ORDER BY reviews.review_id ASC;
When I run this code I get exactly what I want from my SQL query, however if I run the following
SELECT *, COUNT(comments.review_id)
AS comment_count
FROM reviews
LEFT JOIN comments ON comments.review_id = reviews.review_id
GROUP BY reviews.review_id
ORDER BY reviews.review_id ASC;
then I get an error "column must appear in GROUP BY clause or be used in an aggregate function
Just wondered what the difference was and why the behaviour is different.
Thanks
In the first example, the column are taken only from the reviews table. Although not databases allow the use of SELECT * with GROUP BY, it is allowed by Standard SQL, assuming that review_id is the primary key.
The issue is that that you are including columns in the SELECT that are not included in the GROUP BY. This is only allowed -- in certain databases -- under very special circumstances, where the columns in the GROUP BY are declared to uniquely identify each row (which a primary key does).
The second example has columns from comments that do not meet this condition. Hence it is not allowed.
In the select part of the query with group by, you can chose only those columns which you used in group by.
Since you did group by reviews.review_id, you can get the output for the first case. In the second query you are try to get all the records and that is not possible with group by.
You can use window function if you need to select columns which are not present in your group by clause. Hope it makes sense.
https://www.windowfunctions.com/

In SQL, does groupby on an ordered query behave the same as doing both in the same query?

Are the following queries identical, or might I get different results (in any major DB system, e.g. MSSQL, MySQL, Postgres, SQLite):
Doing both in the same query:
SELECT group, some_agg_func(some_value)
FROM my_table
GROUP BY group
ORDER BY some_other_value
vs. ordering in a subquery:
SELECT group, some_agg_func(some_value)
FROM (
SELECT group, some_value
FROM my_table
ORDER BY some_other_value
) as alias
GROUP BY group
Looking at the first sample:
SELECT group, some_agg_func(some_value)
FROM my_table
GROUP BY group
ORDER BY some_other_value
Let's think about what GROUP BY does by looking at this imaginary sample data:
A B
- -
1 1
1 2
Then think about this query:
SELECT A
FROM SampleData
GROUP BY A
ORDER BY B
The GROUP BY clause puts the two rows into a single group. Then we want to order by B... but the two rows in the group have different values for B. Which should it use?
Obviously in this situation it doesn't really matter: there's only one row in the results, so the order is not relevant. But generally, how does the database know what to do?
The database could guess which one you want, or just take the first value, or the last — whatever those mean in a setting where the data is unordered by definition. And in fact this is what MySql will try to do for you: it will try to guess are your meaning. But this response is really inappropriate. You specified an in-exact query; the only correct thing to do is throw an error, which is what most databases will do.
Now let's look at the second sample:
SELECT group, some_agg_func(some_value)
FROM (
SELECT group, some_value
FROM my_table
ORDER BY some_other_value
) as alias
GROUP BY group
Here it is important to remember databases have their roots in relational set theory, and what we think of as "tables" are more formally described as Unordered Relations. Again: the idea of being "unordered" is baked into the very nature of a table at the deepest level.
In this case the inner query can run and create results in the specified order, and then the outer query can use that with GROUP BY to create a new set... but just like tables, query results are unordered relations. Without an ORDER BY clause the final result is also unordered by definition.
Now you might tend to get results in the order you want, but the reality is all bets are off. In fact, the databases that run this query will tend to give you results in the order in which they first encountered each group, which will not tend to match the ORDER BY because the GROUP BY expression is looking at completely different columns. Other databases (Sql Server is in this group) will not even allow the query to run, though I might prefer a warning here.
So now we come to the final section, where we must re-think the question, like this:
How can I use GROUP BY on the one group column, while also ordering by some_other_column not in the group?
The answer is each group can contain multiple rows, and so you must tell the database which row to look at to get the correct (specific) some_other_column value. The typical way to do this is with another aggregate function, which might look like this:
SELECT group, some_agg_func(some_value)
FROM my_table
GROUP BY group
ORDER BY some_other_agg_func(some_other_column)
That code will run without error on pretty much any database.
Just be careful here. On one hand, when people want to do this it's often for the common case where they know every record for some_other_column in each group will have the same value. For example, you might GROUP BY UserID, but ORDER BY Email, where of course every record with the same UserID should have the same Email address. As humans, we have the ability to make that kind of inference. Computers, however, don't handle that kind of thinking as well, and so we help it out with an extra aggregate function like MIN() or MAX().
On the other hand, if you're not careful sometimes the two different aggregate functions don't match up, and you end up showing the value from one row in the group, while using a completely different row from the group for the ORDER BY expression in a way that is not good.
Tables are unordered sets of data. A query result is a table. So if you select from a subquery that contains an ORDER BY clause, that clause means nothing; the data set is unordered by definition. The DBMS is free to ignore the ORDER BY clause. Some DBMS may even issue a warning or error, but I suppose it's more common that the ORDER BY clause just has no effect - at least not guaranteed.
In this query
SELECT group, some_agg_func(some_value)
FROM my_table
GROUP BY group
ORDER BY some_other_value
you try to order your results by some_other_value. If this is meant to be a column, you can't, because that other column is no part of your results. You'll get a syntax error. If some_other_value is a fixed value, then there is nothing ordered, because you'd have the same sort key for every row. But it can be an expression based on your result data (group key and aggreation results) and you can order your result rows by that.
In this query
SELECT group, some_agg_func(some_value)
FROM (
SELECT group, some_value
FROM my_table
ORDER BY some_other_value
) as alias
GROUP BY group
the ORDER BY clause has no effect. You could just as well just select FROM my_table directly:
SELECT group, some_agg_func(some_value)
FROM my_table as alias
GROUP BY group
This gets the results unordered (or at least the order you see is not guaranteed to be thus every time you run that query), because your query doesn't have an ORDER BY clause.

Refer to aggregate result in Amazon Redshift query?

In other postgresql DBMSes (e.g., Netezza) I can do something like this without errors:
select store_id
,sum(sales) as total_sales
,count(distinct(txn_id)) as d_txns
,total_sales/d_txns as avg_basket
from my_tlog
group by 1
I.e., I can use aggregate values within the same SQL query that defined them.
However, when I go to do the same sort of thing on Amazon Redshift, I get the error "Column total_sales does not exist..." Which it doesn't, that's correct; it's not really a column. But is there a way to preserve this idiom, rather than restructuring the query? I ask because there would be a lot of code to change.
Thanks.
You simply need to repeat the expressions (or use a subquery or CTE):
select store_id,
sum(sales) as total_sales,
count(distinct txn_id) as d_txns,
sum(sales)/count(distinct txn_id) as avg_basket
from my_tlog
group by store_id;
Most databases do not support the re-use of column aliases in the select. The reason is twofold (at least):
The designers of the database engine do not want to specify the order of processing of expressions in the select.
There is ambiguity when a column alias is also a valid column in a table in the from clause.
Personally I loove the construct in netezza. This is compact and the syntax is not ambiguous: any 'dublicate' column names will default to (new) alias in the current query, and if you need to reference the column of the underlying tables, simply put the tablename in front of the column. The above example would become:
select store_id
,sum(sales) as sales ---- dublicate name
,count(distinct(txn_id)) as d_txns
,my_tlog.sales/d_txns as avg_basket --- this illustrates but may not make sense
from my_tlog
group by 1
I recently moved away from sql server, and on that database I used a construct like this to avoid repeating the expressions:
Select *, total_sales/d_txns as avg_basket
From (
select store_id
,sum(sales) as total_sales
,count(distinct(txn_id)) as d_txns
from my_tlog
group by 1
)x
Most (if not all) databases will support this construct, and have done so for 10 years or more

Why can't I GROUP BY 1 when it's OK to ORDER BY 1?

Why are column ordinals legal for ORDER BY but not for GROUP BY? That is, can anyone tell me why this query
SELECT OrgUnitID, COUNT(*) FROM Employee AS e GROUP BY OrgUnitID
cannot be written as
SELECT OrgUnitID, COUNT(*) FROM Employee AS e GROUP BY 1
When it's perfectly legal to write a query like
SELECT OrgUnitID FROM Employee AS e ORDER BY 1
?
I'm really wondering if there's something subtle about the relational calculus, or something, that would prevent the grouping from working right.
The thing is, my example is pretty trivial. It's common that the column that I want to group by is actually a calculation, and having to repeat the exact same calculation in the GROUP BY is (a) annoying and (b) makes errors during maintenance much more likely. Here's a simple example:
SELECT DATEPART(YEAR,LastSeenOn), COUNT(*)
FROM Employee AS e
GROUP BY DATEPART(YEAR,LastSeenOn)
I would think that SQL's rule of normalize to only represent data once in the database ought to extend to code as well. I'd want to only right that calculation expression once (in the SELECT column list), and be able to refer to it by ordinal in the GROUP BY.
Clarification: I'm specifically working on SQL Server 2008, but I wonder about an overall answer nonetheless.
One of the reasons is because ORDER BY is the last thing that runs in a SQL Query, here is the order of operations
FROM clause
WHERE clause
GROUP BY clause
HAVING clause
SELECT clause
ORDER BY clause
so once you have the columns from the SELECT clause you can use ordinal positioning
EDIT, added this based on the comment
Take this for example
create table test (a int, b int)
insert test values(1,2)
go
The query below will parse without a problem, it won't run
select a as b, b as a
from test
order by 6
here is the error
Msg 108, Level 16, State 1, Line 3
The ORDER BY position number 6 is out of range of the number of items in the select list.
This also parses fine
select a as b, b as a
from test
group by 1
But it blows up with this error
Msg 164, Level 15, State 1, Line 3
Each GROUP BY expression must contain at least one column that is not an outer reference.
There is a lot of elementary inconsistencies in SQL, and use of scalars is one of them. For example, anyone might expect
select * from countries
order by 1
and
select * from countries
order by 1.00001
to be a similar queries (the difference between the two can be made infinitesimally small, after all), which are not.
I'm not sure if the standard specifies if it is valid, but I believe it is implementation-dependent. I just tried your first example with one SQL engine, and it worked fine.
use aliasses :
SELECT DATEPART(YEAR,LastSeenOn) as 'seen_year', COUNT(*) as 'count'
FROM Employee AS e
GROUP BY 'seen_year'
** EDIT **
if GROUP BY alias is not allowed for you, here's a solution / workaround:
SELECT seen_year
, COUNT(*) AS Total
FROM (
SELECT DATEPART(YEAR,LastSeenOn) as seen_year, *
FROM Employee AS e
) AS inline_view
GROUP
BY seen_year
databases that don't support this basically are choosing not to. understand the order of the processing of the various steps, but it is very easy (as many databases have shown) to parse the sql, understand it, and apply the translation for you. Where its really a pain is when a column is a long case statement. having to repeat that in the group by clause is super annoying. yes, you can do the nested query work around as someone demonstrated above, but at this point it is just lack of care about your users to not support group by column numbers.

What is the difference between HAVING and WHERE in SQL?

What is the difference between HAVING and WHERE in an SQL SELECT statement?
EDIT: I have marked Steven's answer as the correct one as it contained the key bit of information on the link:
When GROUP BY is not used, HAVING behaves like a WHERE clause
The situation I had seen the WHERE in did not have GROUP BY and is where my confusion started. Of course, until you know this you can't specify it in the question.
HAVING: is used to check conditions after the aggregation takes place.
WHERE: is used to check conditions before the aggregation takes place.
This code:
select City, CNT=Count(1)
From Address
Where State = 'MA'
Group By City
Gives you a table of all cities in MA and the number of addresses in each city.
This code:
select City, CNT=Count(1)
From Address
Where State = 'MA'
Group By City
Having Count(1)>5
Gives you a table of cities in MA with more than 5 addresses and the number of addresses in each city.
HAVING specifies a search condition for a
group or an aggregate function used in SELECT statement.
Source
Number one difference for me: if HAVING was removed from the SQL language then life would go on more or less as before. Certainly, a minority queries would need to be rewritten using a derived table, CTE, etc but they would arguably be easier to understand and maintain as a result. Maybe vendors' optimizer code would need to be rewritten to account for this, again an opportunity for improvement within the industry.
Now consider for a moment removing WHERE from the language. This time the majority of queries in existence would need to be rewritten without an obvious alternative construct. Coders would have to get creative e.g. inner join to a table known to contain exactly one row (e.g. DUAL in Oracle) using the ON clause to simulate the prior WHERE clause. Such constructions would be contrived; it would be obvious there was something was missing from the language and the situation would be worse as a result.
TL;DR we could lose HAVING tomorrow and things would be no worse, possibly better, but the same cannot be said of WHERE.
From the answers here, it seems that many folk don't realize that a HAVING clause may be used without a GROUP BY clause. In this case, the HAVING clause is applied to the entire table expression and requires that only constants appear in the SELECT clause. Typically the HAVING clause will involve aggregates.
This is more useful than it sounds. For example, consider this query to test whether the name column is unique for all values in T:
SELECT 1 AS result
FROM T
HAVING COUNT( DISTINCT name ) = COUNT( name );
There are only two possible results: if the HAVING clause is true then the result with be a single row containing the value 1, otherwise the result will be the empty set.
The HAVING clause was added to SQL because the WHERE keyword could not be used with aggregate functions.
Check out this w3schools link for more information
Syntax:
SELECT column_name, aggregate_function(column_name)
FROM table_name
WHERE column_name operator value
GROUP BY column_name
HAVING aggregate_function(column_name) operator value
A query such as this:
SELECT column_name, COUNT( column_name ) AS column_name_tally
FROM table_name
WHERE column_name < 3
GROUP
BY column_name
HAVING COUNT( column_name ) >= 3;
...may be rewritten using a derived table (and omitting the HAVING) like this:
SELECT column_name, column_name_tally
FROM (
SELECT column_name, COUNT(column_name) AS column_name_tally
FROM table_name
WHERE column_name < 3
GROUP
BY column_name
) pointless_range_variable_required_here
WHERE column_name_tally >= 3;
The difference between the two is in the relationship to the GROUP BY clause:
WHERE comes before GROUP BY; SQL evaluates the WHERE clause before it groups records.
HAVING comes after GROUP BY; SQL evaluates HAVING after it groups records.
References
SQLite SELECT Statement Syntax/Railroad Diagram
Informix SELECT Statement Syntax/Railroad Diagram
HAVING is used when you are using an aggregate such as GROUP BY.
SELECT edc_country, COUNT(*)
FROM Ed_Centers
GROUP BY edc_country
HAVING COUNT(*) > 1
ORDER BY edc_country;
WHERE is applied as a limitation on the set returned by SQL; it uses SQL's built-in set oeprations and indexes and therefore is the fastest way to filter result sets. Always use WHERE whenever possible.
HAVING is necessary for some aggregate filters. It filters the query AFTER sql has retrieved, assembled, and sorted the results. Therefore, it is much slower than WHERE and should be avoided except in those situations that require it.
SQL Server will let you get away with using HAVING even when WHERE would be much faster. Don't do it.
WHERE clause does not work for aggregate functions
means : you should not use like this
bonus : table name
SELECT name
FROM bonus
GROUP BY name
WHERE sum(salary) > 200
HERE Instead of using WHERE clause you have to use HAVING..
without using GROUP BY clause, HAVING clause just works as WHERE clause
SELECT name
FROM bonus
GROUP BY name
HAVING sum(salary) > 200
Difference b/w WHERE and HAVING clause:
The main difference between WHERE and HAVING clause is, WHERE is used for row operations and HAVING is used for column operations.
Why we need HAVING clause?
As we know, aggregate functions can only be performed on columns, so we can not use aggregate functions in WHERE clause. Therefore, we use aggregate functions in HAVING clause.
One way to think of it is that the having clause is an additional filter to the where clause.
A WHERE clause is used filters records from a result. The filter occurs before any groupings are made. A HAVING clause is used to filter values from a group
In an Aggregate query, (Any query Where an aggregate function is used) Predicates in a where clause are evaluated before the aggregated intermediate result set is generated,
Predicates in a Having clause are applied to the aggregate result set AFTER it has been generated. That's why predicate conditions on aggregate values must be placed in Having clause, not in the Where clause, and why you can use aliases defined in the Select clause in a Having Clause, but not in a Where Clause.
I had a problem and found out another difference between WHERE and HAVING. It does not act the same way on indexed columns.
WHERE my_indexed_row = 123 will show rows and automatically perform a "ORDER ASC" on other indexed rows.
HAVING my_indexed_row = 123 shows everything from the oldest "inserted" row to the newest one, no ordering.
When GROUP BY is not used, the WHERE and HAVING clauses are essentially equivalent.
However, when GROUP BY is used:
The WHERE clause is used to filter records from a result. The
filtering occurs before any groupings are made.
The HAVING clause is used to filter values from a group (i.e., to
check conditions after aggregation into groups has been performed).
Resource from Here
From here.
the SQL standard requires that HAVING
must reference only columns in the
GROUP BY clause or columns used in
aggregate functions
as opposed to the WHERE clause which is applied to database rows
While working on a project, this was also my question. As stated above, the HAVING checks the condition on the query result already found. But WHERE is for checking condition while query runs.
Let me give an example to illustrate this. Suppose you have a database table like this.
usertable{ int userid, date datefield, int dailyincome }
Suppose, the following rows are in table:
1, 2011-05-20, 100
1, 2011-05-21, 50
1, 2011-05-30, 10
2, 2011-05-30, 10
2, 2011-05-20, 20
Now, we want to get the userids and sum(dailyincome) whose sum(dailyincome)>100
If we write:
SELECT userid, sum(dailyincome) FROM usertable WHERE
sum(dailyincome)>100 GROUP BY userid
This will be an error. The correct query would be:
SELECT userid, sum(dailyincome) FROM usertable GROUP BY userid HAVING
sum(dailyincome)>100
WHERE clause is used for comparing values in the base table, whereas the HAVING clause can be used for filtering the results of aggregate functions in the result set of the query
Click here!
When GROUP BY is not used, the WHERE and HAVING clauses are essentially equivalent.
However, when GROUP BY is used:
The WHERE clause is used to filter records from a result. The
filtering occurs before any groupings are made.
The HAVING clause is
used to filter values from a group (i.e., to check conditions after
aggregation into groups has been performed).
I use HAVING for constraining a query based on the results of an aggregate function. E.G. select * in blahblahblah group by SOMETHING having count(SOMETHING)>0