I need all value from JSON array - sql

Question

I have a table in which I have JSON data and the field type is NVARCHAR(4000)
[
{"number":1,"booked":0},
{"number":2,"booked":0},
{"number":3,"booked":0},
{"number":4,"booked":1},
{"number":5,"booked":0},
{"number":6,"booked":0},
{"number":7,"booked":0},
{"number":8,"booked":0}
]
I want to query on this field of array, and want the output that Number of booked is 1 and not booked are 7.
I have used JSON_VALUE(), JSON_QUERY() functions but not getting at the point.
I also want that Number:4 is booked.
I am using SQL Server 2016

Answer 1

Hi if i understand all what your're trying todo, thoses example can respond :
DECLARE #json NVARCHAR(MAX)
SET #json =
N'[
{"number":1,"booked":0},
{"number":2,"booked":0},
{"number":3,"booked":0},
{"number":4,"booked":1},
{"number":5,"booked":0},
{"number":6,"booked":0},
{"number":7,"booked":0},
{"number":8,"booked":0}
]'
SELECT number, booked
FROM OPENJSON(#json)
WITH (number int 'strict $.number', booked int 'strict $.booked')
WHERE booked = 1
In futur propose please provide some data and excepted output and query what your're trying .

Answer 2

[
{"number":1,"booked":0},
{"number":2,"booked":0},
{"number":3,"booked":0},
{"number":4,"booked":1},
{"number":5,"booked":0},
{"number":6,"booked":0},
{"number":7,"booked":0},
{"number":8,"booked":0}
]
Select query:
SELECT
COUNT(JSON_VALUE(jsonInfo,'$.booked'))
OVER(PARTITION BY JSON_VALUE(jsonInfo,'$.booked'))
FROM table
GROUP BY JSON_VALUE(jsonInfo,'$.booked')
ORDER BY JSON_VALUE(jsonInfo,'$.booked')