I have a column that includes strings that are separated by space and commas. It looks like:
Column1
----------------------------
T1234, C1234, D1234, C1234
E1234, C1234
I need a SQL query to extract anything that starts with C. So the result would look like:
Column1
--------------
C1234, C1234
C1234
This is also an opportunity to use a recursive CTE:
with t as (
select 'T1234, C1234, D1234, C1234' as col1 union all
select 'E1234, C1234'
),
cte as (
select col1,
convert(varchar(max), (case when col1 like 'C%' then ', ' + left(col1, charindex(',', col1 + ',') - 1 ) else '' end)) as c_list,
convert(varchar(max), stuff(col1, 1, charindex(',', col1 + ',') + 1, '')) as rest,
1 as lev
from t
union all
select col1,
c_list + (case when rest like 'C%' then ', ' + left(rest, charindex(',', rest + ',') - 1 ) else '' end) ,
convert(varchar(max), stuff(rest, 1, charindex(',', rest + ',') + 1, '')) as rest,
lev + 1
from cte
where rest > '' and lev < 10
)
select stuff(c_list, 1, 2, '') as c_list
from (select cte.*, row_number() over (partition by col1 order by lev desc) as seqnum
from cte
) cte
where seqnum = 1;
This approach does not require extracting strings and then reaggregating. It also guarantees that the values remain in the original order as in the original data.
Here is a db<>fiddle.
declare #t table (c varchar(200) PRIMARY KEY)
insert into #t values ('T1234, C1234, D1234, C1234'), ('E1234, C1234')
;with cte1 as ( -- cte1 - number the rows. Order by PK
select row_number() over(order by c) rn, *
from #t
), cte2 as ( -- cte2 - turn comma delimited lists into rows of trimmed values
select rn, replace(ca.value, ' ', '') val
from cte1
cross apply (
select value from string_split((select c from cte1 cte1_inner where cte1_inner.rn = cte1.rn), N',')
)ca
), cte3 as ( -- cte3 - get distinct row numbers and re-concat vals in a subquery
select distinct rn, (
SELECT STUFF(
(
select ', ' + val
from cte2 cte2_inner
where val like 'c%' and cte2_inner.rn = cte2.rn
for xml path('')
), 1, 2, '')
)concatenated
from cte2
)
select concatenated
from cte3
Returns:
concatenated
C1234
C1234, C1234
Here's what each CTE returns:
cte1:
rn c
1 E1234, C1234
2 T1234, C1234, D1234, C1234
cte2:
rn val
1 E1234
1 C1234
2 T1234
2 C1234
2 D1234
2 C1234
cte3:
rn concatenated
1 C1234
2 C1234, C1234
Related
I have a table with the following columns 'ID, LIST_OF_VALUES'.
Example data is:
ID| LIST_OF_VALUES
--+----------------------------
1 | firstval-secondval-thirdval
2 | val1-val2
3 | val10-val20-val30
4 | singleval
I would like to select the data like this:
ID| VAL1 | VAL2 | VAL3
--+----------+-----------+-------
1 | firstval | secondval | thirdval
2 | val1 | val2 | NULL
3 | val10 | val20 | val30
4 | singlval | NULL | NULL
I am aware of the STRING_SPLIT function. I have tried using it in various ways with Cross Apply, but I can't seem to get the result I want.
I know I can do this using a mess of SUBSTR/INDEX, but I am just curious if STRING_SPLIT offers a more elegant solution.
Just another option
Example of XML Option
Select A.ID
,Val1 = tmpXML.value('/x[1]','varchar(100)')
,Val2 = tmpXML.value('/x[2]','varchar(100)')
,Val3 = tmpXML.value('/x[3]','varchar(100)')
from YourTable A
Cross Apply ( values ( Cast('<x>' + replace([LIST_OF_VALUES],'-','</x><x>')+'</x>' as xml) ) ) B(tmpXML)
Returns
ID Val1 Val2 Val3
1 firstval secondval thirdval
2 val1 val2 NULL
3 val10 val20 val30
4 singleval NULL NULL
Example of JSON Option - as suggested by #PanagiotisKanavos if 2016+
Select A.ID
,Val1 = JSON_VALUE(S,'$[0]')
,Val2 = JSON_VALUE(S,'$[1]')
,Val3 = JSON_VALUE(S,'$[2]')
from #YourTable A
Cross Apply ( values ( '["'+replace(replace([LIST_OF_VALUES],'"','\"'),'-','","')+'"]' ) ) B(S)
Assuming you don't have duplicates, you can use it . . . but it is not trivial:
select t.*, s.*
from t cross apply
(select max(case when seqnum = 1 then value end) as val1,
max(case when seqnum = 2 then value end) as val2,
max(case when seqnum = 3 then value end) as val3
from (select s.value,
row_number() over (order by charindex('-' + value + '-', '-' + t.list_of_values + '-') as seqnum
from string_split(t.list_of_values, '-') s
) s
) s;
Unfortunately, string_split() doesn't provide the ordering. This recreates it using charindex().
One simple and very efficient and scalable way would be to use an ordinal splitter such as dbo.DelimitedSplit8K (or dbo.DelimitedSplitN4K (for nchar/nvarchar). Then the query would be something like this
dbo.DelimitedSplit8K tvf
CREATE FUNCTION dbo.DelimitedSplit8K
--===== Define I/O parameters
(#pString VARCHAR(8000), #pDelimiter CHAR(1))
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE!
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000...
-- enough to cover VARCHAR(8000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(#pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(#pString,t.N,1) = #pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(#pDelimiter,#pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(#pString, l.N1, l.L1)
FROM cteLen l;
Query
select t.id,
max(case when ds.ItemNumber=1 then ds.Item end) as val1,
max(case when ds.ItemNumber=2 then ds.Item end) as val2,
max(case when ds.ItemNumber=3 then ds.Item end) as val3
from tTable t
cross apply
dbo.DelimitedSplit8K(t.LIST_OF_VALUES, '-') ds
group by t.id
order by t.id;
[EDIT] Here is an alternate method which produces the same output but does not use the DelimitedSplit8K function. This is the same approach as Gordon's but with an outer GROUP BY clause.
;with charindex_split_cte(id, Item, ItemNumber) as (
select t.id, sp.value,
row_number() over (order by charindex('-' + sp.value + '-', '-' + t.list_of_values + '-'))
from tTable t
cross apply string_split(t.list_of_values, '-') sp)
select id,
max(case when ItemNumber=1 then Item end) as val1,
max(case when ItemNumber=2 then Item end) as val2,
max(case when ItemNumber=3 then Item end) as val3
from charindex_split_cte
group by id
order by id;
I need to be able to split one string by the delimiter * into separate columns without including *
The column y from table x looks like this:
column y
*1HS*AB*GXX*123*02*PA45*2013-08-10*
*1R1*B*GX*123*02*PA45*2013-08-10*
*1HS*B*GX*13*01*PA45*2013-08-01*
*1P*C*GXX*123*02*PA45*2013-08-10*
STRING_SPLIT is not avalible
The outcome should be this:
Column1 Column2 Column3 Column4 Column5 Column6 Column7
1HS AB GXX 123 2 PA45 10-08-2013
1R1 B GX 123 2 PA45 10-08-2013
1HS B GX 13 1 PA45 01-08-2013
1P C GXX 123 2 PA45 10-08-2013
will you use the below query..
select RTRIM (REGEXP_SUBSTR (column y, '[^,]*,', 1, 1), ',') AS column 1
, RTRIM (REGEXP_SUBSTR (column y, '[^,]*,', 1, 2), ',') AS column 2
, RTRIM (REGEXP_SUBSTR (column y, '[^,]*,', 1, 3), ',') AS column 3
, LTRIM (REGEXP_SUBSTR (column y, ',[^,]*', 1, 3), ',') AS column 4
from YOUR_TABLE
Unfortunately, string_split() does not guarantee that it preserves the ordering of the values. And, SQL Server does not offer other useful string functions.
So, I recommend using recursive CTEs for this purpose:
with t as (
select *
from (values ('*1HS*AB*GXX*123*02*PA45*2013-08-10*'), ('1HSB*GX*13*01*PA45*2013-08-01*')) v(str)
),
cte as (
select convert(varchar(max), null) as val, 0 as lev, convert(varchar(max), str) as rest,
row_number() over (order by (select null)) as id
from t
union all
select left(rest, charindex('*', rest) - 1), lev + 1, stuff(rest, 1, charindex('*', rest) + 1, ''), id
from cte
where rest <> '' and lev < 10
)
select max(case when lev = 1 then val end) as col1,
max(case when lev = 2 then val end) as col2,
max(case when lev = 3 then val end) as col3,
max(case when lev = 4 then val end) as col4,
max(case when lev = 5 then val end) as col5,
max(case when lev = 6 then val end) as col6,
max(case when lev = 7 then val end) as col7
from cte
where lev > 0
group by cte.id;
Here is a db<>fiddle.
Assuming you can add a table valued function to your database then Jeff Moden's string split function is the best approach I've encountered. It will allow you to maintain order as well.
Find details here
I'm looking for a way to get table below:
CREATE TABLE [dbo].[#temp]
(
[ID_TASK] [NVARCHAR](300) NULL,
[CHNAME_NAME] [NVARCHAR](300) NULL,
[CHNAME_PHONE] [NVARCHAR](300) NULL
) ON [PRIMARY]
INSERT INTO [dbo].[#temp]
VALUES ('ID005', 'Anderson Abreu Oliveira', '68157120'),
('ID006', 'Gonzalez-IV', '64106929'),
('ID009', 'Parker W.H.', '60994308')
I'm using this SQL query:
SELECT
ID_TASK, CHNAME_NAME,
RTRIM(LTRIM(SUBSTRING(CHNAME_NAME, 1, CHARINDEX(' ', CHNAME_NAME)))) AS SURNAME,
RTRIM(LTRIM(SUBSTRING(CHNAME_NAME, CHARINDEX(' ', CHNAME_NAME) + 1, LEN(CHNAME_NAME) - (CHARINDEX(' ', CHNAME_NAME) - 1)))) AS FIRSTNAME,
REPLACE((RTRIM(LTRIM(CHNAME_PHONE))), '8-', '') AS CHNAME_PHONE
FROM
[dbo].[#temp]
but I get this result:
How do I fix this SQL query to get the desired result? Thank you
You might try to use case..when structure
with CHARINDEX('-', CHNAME_NAME) and CHARINDEX(' ', CHNAME_NAME)
as in the following statement :
SELECT
ID_TASK, CHNAME_NAME,
RTRIM(LTRIM(SUBSTRING(CHNAME_NAME, 1,
(Case CHARINDEX(' ', CHNAME_NAME) When 0 Then CHARINDEX('-', CHNAME_NAME)-1
Else CHARINDEX(' ', CHNAME_NAME) End)))) AS SURNAME,
RTRIM(LTRIM(SUBSTRING(CHNAME_NAME,
(Case CHARINDEX(' ', CHNAME_NAME) When 0 Then CHARINDEX('-', CHNAME_NAME)
Else CHARINDEX(' ', CHNAME_NAME) End) + 1,
LEN(CHNAME_NAME) - (CHARINDEX(' ', CHNAME_NAME) - 1)))) AS FIRSTNAME,
REPLACE((RTRIM(LTRIM(CHNAME_PHONE))), '8-', '') AS CHNAME_PHONE
FROM
[dbo].[#temp]
This is quite an advanced thing to achieve I've done some SQL to get you there, but not tidied it up...
DECLARE #temp TABLE (
[ID_TASK] [nvarchar](300) NULL,
[CHNAME_NAME] [nvarchar](300) NULL,
[CHNAME_PHONE] [nvarchar](300) NULL
)
INSERT INTO #temp
SELECT 'ID005','Anderson Abreu Oliveira','68157120' UNION ALL
SELECT 'ID006','Gonzalez-IV','64106929' UNION ALL
SELECT 'ID009','Parker W.H.','60994308'
select ID_TASK, col1, col2, col3
from
(
select a.ID_TASK, Item , 'col' + CONVERT(NVARCHAR(10), ItemNumber) ItemNumber
from #temp a
CROSS APPLY [dbo].[DelimitedSplit] ( REPLACE(a.CHNAME_NAME, '-', ' '), ' ' ) b
) d
pivot
(
MAX(item)
for itemNumber in (col1, col2, col3)
) piv
GROUP BY ID_TASK, col1, col2, col3
Helper function:
CREATE FUNCTION [dbo].[DelimitedSplit] (
#pString VARCHAR(MAX),
#pDelimiter CHAR(1)
)
RETURNS TABLE WITH SCHEMABINDING
AS
RETURN
WITH E1(N) AS ( -- 10
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
),
E2(N) AS (SELECT 1 FROM E1 a, E1 b),
E3(N) AS (SELECT 1 FROM E2 a, E2 b, E2 c),
E4(N) AS (SELECT 1 FROM E3 a, E3 b, E3 c, E3 d),
cteTally(N) AS (
SELECT 0 UNION ALL
SELECT TOP ( DATALENGTH( ISNULL( #pString, 1 ) ) ) ROW_NUMBER() OVER ( ORDER BY ( SELECT NULL ) ) FROM E4
),
cteStart(N1) AS (
SELECT t.N + 1
FROM cteTally t
WHERE ( SUBSTRING( #pString, t.N, 1 ) = #pDelimiter OR t.N = 0 )
)
-- ------
SELECT
ItemNumber = ROW_NUMBER() OVER( ORDER BY s.N1 ),
Item = SUBSTRING( #pString, s.N1, ISNULL( NULLIF( CHARINDEX( #pDelimiter, #pString, s.N1 ), 0) - s.N1, 1000000 ) )
FROM cteStart s
GO
Here you go:
CREATE TABLE [dbo].[#temp]
(
[ID_TASK] [NVARCHAR](300) NULL,
[CHNAME_NAME] [NVARCHAR](300) NULL,
[CHNAME_PHONE] [NVARCHAR](300) NULL
) ON [PRIMARY]
INSERT INTO [dbo].[#temp]
VALUES ('ID005', 'Anderson Abreu Oliveira', '68157120'),
('ID006', 'Gonzalez-IV', '64106929'),
('ID009', 'Parker W.H.', '60994308');
WITH CTE AS
(
SELECT [ID_TASK],
LEFT([CHNAME_NAME], IIF( CHARINDEX(' ', [CHNAME_NAME]) = 0 , CHARINDEX('-', [CHNAME_NAME])-1, CHARINDEX(' ', [CHNAME_NAME]))) AS T,
[CHNAME_NAME],
[CHNAME_PHONE]
FROM #Temp
)
SELECT [ID_TASK],
[CHNAME_NAME],
T AS SURNAME,
LTRIM(REPLACE(CASE WHEN (T IS NULL) OR (T = '') THEN [CHNAME_NAME] ELSE SUBSTRING([CHNAME_NAME], LEN(T)+1, LEN([CHNAME_NAME])) END, '-', '')) FirstName,
[CHNAME_PHONE]
FROM CTE;
Results:
+---+---------+-------------------------+-----------+-----------------+--------------+
| | ID_TASK | CHNAME_NAME | SURNAME | FirstName | CHNAME_PHONE |
+---+---------+-------------------------+-----------+-----------------+--------------+
| 1 | ID005 | Anderson Abreu Oliveira | Anderson | Abreu Oliveira | 68157120 |
| 2 | ID006 | Gonzalez-IV | Gonzalez | IV | 64106929 |
| 3 | ID009 | Parker W.H. | Parker | W.H. | 60994308 |
+---+---------+-------------------------+-----------+-----------------+--------------+
Demo
I have a table contains IDs in field. It looks like:
FieldName
-------------------------
1,8,2,3,4,10,5,9,6,7
-------------------------
1,8
-------------------------
1,8
I need to count these IDs to get result:
ID | Count
---|------
1 | 3
8 | 3
2 | 1
3 | 1
Any ideas?
Thanks!
Try this :
Declare #demo table(FieldName varchar(100))
insert into #demo values('1,8,2,3,4,10,5,9,6,7')
insert into #demo values('1,8')
insert into #demo values('1,8')
select ID, COUNT(id) ID_count from
(SELECT
CAST(Split.a.value('.', 'VARCHAR(100)') AS INT) AS ID
FROM
(
SELECT CAST ('<M>' + REPLACE(FieldName, ',', '</M><M>') + '</M>' AS XML) AS ID
FROM #demo
) AS A CROSS APPLY ID.nodes ('/M') AS Split(a)) q1
group by ID
I like Devart's answer because of the faster execution. Here is a modified earlier answer to suite your need :
Declare #col varchar(200)
SELECT
#col=(
SELECT FieldName + ','
FROM #demo c
FOR XML PATH('')
);
;with demo as(
select cast(substring(#col,1,charindex(',',#col,1)-1) AS INT) cou,charindex(',',#col,1) pos
union all
select cast(substring(#col,pos+1,charindex(',',#col,pos+1)-pos-1)AS INT) cou,charindex(',',#col,pos+1) pos
from demo where pos<LEN(#col))
select cou ID, COUNT(cou) id_count from demo
group by cou
Try this one -
Query:
SET NOCOUNT ON;
DECLARE #temp TABLE (txt VARCHAR(8000))
INSERT INTO #temp (txt)
VALUES ('1,8,2,3,4,10,5,9,6,7'), ('1,8'), ('1,8')
SELECT
t.ID
, [Count] = COUNT(1)
FROM (
SELECT
ID =
SUBSTRING(
t.string
, number + 1
, ABS(CHARINDEX(',', t.string, number + 1) - number - 1)
)
FROM (
SELECT string = (
SELECT ',' + txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)')
) t
CROSS JOIN [master].dbo.spt_values n
WHERE [type] = 'p'
AND number <= LEN(t.string) - 1
AND SUBSTRING(t.string, number, 1) = ','
) t
GROUP BY t.ID
ORDER BY [Count] DESC
Output:
ID Count
----- -----------
1 3
8 3
9 1
10 1
2 1
3 1
4 1
5 1
6 1
7 1
Query cost:
Input:
ID groupId RowID Data
1 1 1 W
2 1 1 NULL
3 1 1 NULL
4 1 1 Z
5 1 2 NULL
6 1 2 NULL
7 1 2 X
8 1 2 NULL
9 1 3 NULL
10 1 3 NULL
11 1 3 Y
12 1 3 NULL
Expected Output
GroupId NewData
1 2Y1,2X1,W2Z
For every Null there will be a numeric count. That is if there are two nulls then the numeric value will be 2.
The ddl is as under
DECLARE #t TABLE(ID INT IDENTITY(1,1) , GroupId INT, RowID INT, Data VARCHAR(10))
INSERT INTO #t (GroupId, RowID,DATA)
SELECT 1,1,'W' UNION ALL SELECT 1,1,NULL UNION ALL SELECT 1,1,NULL UNION ALL SELECT 1,1,'Z' UNION ALL SELECT 1,2,NULL UNION ALL
SELECT 1,2,NULL UNION ALL SELECT 1,2,'X' UNION ALL SELECT 1,2,NULL UNION ALL SELECT 1,3,NULL UNION ALL SELECT 1,3,NULL UNION ALL
SELECT 1,3,'Y' UNION ALL SELECT 1,3,NULL
select * from #t
My version is as under but not the correct output
;with t as (
select GroupID, id, RowID, convert(varchar(25), case when Data is null then '' else Data end) Val,
case when Data is null then 1 else 0 end NullCount from #t where id = 1
union all
select t.GroupID, a.id,a.RowID, convert(varchar(25), Val +
case when Data is not null or (t.RowID <> a.RowID and NullCount > 0) then ltrim(NullCount) else '' end +
case when t.RowID <> a.RowID then ',' else '' end + isnull(Data, '')),
case when Data is null then NullCount + 1 else 0 end NullCount
from t inner join #t a on t.GroupID = a.GroupID and t.id + 1 = a.id
)
select GroupID, Data = Val + case when NullCount > 0 then ltrim(NullCount) else '' end from t
where id = (select max(id) from #t where GroupID = t.GroupId)
Is yielding the below output
GroupID Data
1 W2Z,2X1,3Y1
Please help me out
Thanks in advance
Kind of messy and most likely can be improved
;With RawData AS
(
select * from #t
)
,Ranked1 as
(
select *, RANK() OVER (PARTITION BY GroupId, RowID ORDER BY ID, GroupId, RowID) R from #t
)
,Ranked2 as
(
select *, R - RANK() OVER (PARTITION BY GroupId, RowID ORDER BY ID, GroupId, RowID) R2 from Ranked1
where Data is null
)
,Ranked3 as
(
select MIN(ID) as MinID, GroupId, RowID, R2, COUNT(*) C2 from Ranked2
group by GroupId, RowID, R2
)
,Ranked4 as
(
select RD.ID, RD.GroupId, RD.RowID, ISNULL(Data, C2) as C3 from RawData RD
left join Ranked3 R3 on RD.ID = R3.MinID and RD.GroupId = R3.GroupId and RD.RowID = R3.RowID
where ISNULL(Data, C2) is not null
)
,Grouped as
(
select GroupId, RowID,
(
select isnull(C3, '') from Ranked4 as R41
where R41.GroupId = R42.GroupId and R41.RowID = R42.RowID
order by GroupId, RowID for xml path('')
) as C4
from Ranked4 as R42
group by GroupId, RowID
)
select GroupId,
stuff((
select ',' + C4 from Grouped as G1
where G1.GroupId = G2.GroupId
order by GroupId for xml path('')
), 1, 1, '')
from Grouped G2
group by GroupId