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Here is the "Customers" table
ID Name Country
1 A UK
2 B CN
3 C IN
4 D GB
5 E CN
6 F GB
7 H UK
8 I IN
Need a query to show number of customers for each country. GB and UK should be considered as single country.
Use a CASE expression:
SELECT (CASE WHEN country = 'GB' THEN 'UK' ELSE country END) as country,
COUNT(*), Country
FROM Customer
GROUP BY (CASE WHEN country = 'GB' THEN 'UK' ELSE country END);
Related
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I have data of the following form:
ID
Category
Amount
1
A
100
1
B
200
1
B
150
1
C
500
2
B
20
3
A
100
1
B
100
I wish to GROUP BY the column ID, find out the DISTINCT types of Category present for each ID group and create a new column where I can create the following classification labels for each grouped ID based on the unique or distinct categories present and also calculate the corresponding sum of amount for each grouped ID. So the output should be the follows:
ID
Classification
Sum of Amount
1
ALL
950
1
B only
20
1
A and B only
200
I tried the following SQL code but it doesn't work, most likely because DISTINCT() command within a CASE WHEN statement cannot consider multiple values.
My query:
SELECT
ID,
(CASE WHEN DISTINCT(CATEGORY) IN ("A") then "A Only" WHEN WHEN DISTINCT(CATEGORY) IN ("B") THEN "B only"..........)
SUM(AMOUNT)
FROM Table
GROUP BY 1,2
I have tried multiple ways of using the DISTINCT statement with CASE WHEN but none of them works.
Hmmm . . . How about this?
select id,
(case when min(category) = max(category)
then min(category) || ' only'
when count(distinct category) = 3
then 'All'
when min(category) is NULL
then 'None'
else min(category) || ' and ' || max(category)
end)
from t
group by id;
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Please find below Tables.
How to show all departments where in March 2014 there were sales of goods with a price of less than 400?
CREATE TABLE dep
(
id NUMBER (10) NOT NULL,
city VARCHAR2 (100) NOT NULL,
name VARCHAR2 (100) NOT NULL,
CONSTRAINT dep_pk PRIMARY KEY (id)
);
I guess you need below query -
SELECT D.name, SUM(cost)
FROM sales S
JOIN dep D ON S.dep_id = D.id
WHERE EXTRACT(YEAR FROM time) = 2014
AND EXTRACT(MONTH FROM time) = 3
GROUP BY D.name
HAVING SUM(cost) < 400
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select * from (
select distinct nationality,gender,regplacetype,count(gender) as total from population
where date_part('year',age(to_date(dateofbirth,'DDMMYYYY'))) BETWEEN 16 and 67 and gender = 'Man'
group by nationality,gender,regplacetype
) as man,
(
select distinct nationality,gender,regplacetype,count(nationality) as total from population
where date_part('year',age(to_date(dateofbirth,'DDMMYYYY'))) BETWEEN 16 and 57 and gender = 'female'
group by xnationality,gender,regplacetype) as female
with man as (
select distinct nationality,gender,regplacetype,count(gender) as total from population
where date_part('year',age(to_date(dateofbirth,'DDMMYYYY'))) BETWEEN 16 and 67 and gender = 'Man'
group by nationality,gender,regplacetype
) select * from man,
union
select distinct nationality,gender,regplacetype,count(nationality) as total from population
where date_part('year',age(to_date(dateofbirth,'DDMMYYYY'))) BETWEEN 16 and 57 and gender = 'female'
group by xnationality,gender,regplacetype
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The table is called PEOPLE and has the columns: id, fname, lname, state, jobtitle, salary, cat
I want to display the 50 states, the number of people in the state with a Cat value of Y, the number of people in the state with a Cat value of N and the total number of people in the state. The four column headings should be State, Yes, No and Total.
I know that we are supposed to use sub queries but not sure how to begin.
SELECT State
, SUM(CASE WHEN Cat = 'Y' THEN 1 ELSE 0 END) as Yes
, SUM(CASE WHEN Cat = 'N' THEN 1 ELSE 0 END) No
, COUNT(*) as Total
FROM PEOPLE
GROUP BY STATE
Here:
SELECT upper(p.state) State,
(SELECT count(*) from PEOPLE p2 where p2.state = p.state and p2.cat = 'Y') Yes,
(SELECT count(*) from PEOPLE p3 where p3.state = p.state and p3.cat = 'N') No,
count(*) Total
FROM PEOPLE p
GROUP BY upper(state)
If you have any doubt about it, fell free to ask.
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I have a table with column name "Val" which contains following values:
Val
1
2
3
4
My desired output is as follows:
1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
Thanks!
Ajaysharma2061
You can do this with a self join:
select t.val, t2.val
from t join
t t2
on t2.val <= t.val
order by t.val;
You can join the table on itself as if its a two different tables using the SQL join keyword. Following your attached image your SQL query is expected to be like this
SELECT t.Val, c.Val
FROM Table t, Table c
WHERE t.id <= c.id
Here is a link on
tutorial point
that can help you as well