How many customers upgraded from Product A to Product B? - sql

I have a "daily changes" table that records when a customer "upgrades" or "downgrades" their membership level. In the table, let's say field 1 is customer ID, field 2 is membership type and field 3 is the date of change. Customers 123 and ABC each have two rows in the table. Values in field 1 (ID) are the same, but values in field 2 (TYPE) and 3 (DATE) are different. I'd like to write a SQL query to tell me how many customers "upgraded" from membership type 1 to membership type 2 how many customers "downgraded" from membership type 2 to membership type 1 in any given time frame.
The table also shows other types of changes. To identify the records with changes in the membership type field, I've created the following code:
SELECT *
FROM member_detail_daily_changes_new
WHERE customer IN (
SELECT customer
FROM member_detail_daily_changes_new
GROUP BY customer
HAVING COUNT(distinct member_type_cd) > 1)
I'd like to see an end report which tells me:
For Fiscal 2018,
X,XXX customers moved from Member Type 1 to Member Type 2 and
X,XXX customers moved from Member Type 2 to Member type 1

Sounds like a good time to use a LEAD() analytical function to look ahead for a given customer's member_Type; compare it to current record and then evaluate if thats an upgrade/downgrade then sum results.
DEMO
CTE AS (SELECT case when lead(Member_Type_Code) over (partition by Customer order by date asc) > member_Type_Code then 1 else 0 end as Upgrade
, case when lead(Member_Type_Code) over (partition by Customer order by date asc) < member_Type_Code then 1 else 0 end as DownGrade
FROM member_detail_daily_changes_new
WHERE Date between '20190101' and '20190201')
SELECT sum(Upgrade) upgrades, sum(downgrade) downgrades
FROM CTE
Giving us: using my sample data
+----+----------+------------+
| | upgrades | downgrades |
+----+----------+------------+
| 1 | 3 | 2 |
+----+----------+------------+
I'm not sure if SQL express on rex tester just doesn't support the sum() on the analytic itself which is why I had to add the CTE or if that's a rule in non-SQL express versions too.
Some other notes:
I let the system implicitly cast the dates in the where clause
I assume the member_Type_Code itself tells me if it's an upgrade or downgrade which long term probably isn't right. Say we add membership type 3 and it goes between 1 and 2... now what... So maybe we need a decimal number outside of the Member_Type_Code so we can handle future memberships and if it's an upgrade/downgrade or a lateral...
I assumed all upgrades/downgrades are counted and a user can be counted multiple times if membership changed that often in time period desired.
I assume an upgrade/downgrade can't occur on the same date/time. Otherwise the sorting for lead may not work right. (but if it's a timestamp field we shouldn't have an issue)
So how does this work?
We use a Common table expression (CTE) to generate the desired evaluations of downgrade/upgrade per customer. This could be done in a derived table as well in-line but I find CTE's easier to read; and then we sum it up.
Lead(Member_Type_Code) over (partition by customer order by date asc) does the following
It organizes the data by customer and then sorts it by date in ascending order.
So we end up getting all the same customers records in subsequent rows ordered by date. Lead(field) then starts on record 1 and Looks ahead to record 2 for the same customer and returns the Member_Type_Code of record 2 on record 1. We then can compare those type codes and determine if an upgrade or downgrade occurred. We then are able to sum the results of the comparison and provide the desired totals.
And now we have a long winded explanation for a very small query :P

You want to use lag() for this, but you need to be careful about the date filtering. So, I think you want:
SELECT prev_membership_type, membership_type,
COUNT(*) as num_changes,
COUNT(DISTINCT member) as num_members
FROM (SELECT mddc.*,
LAG(mddc.membership_type) OVER (PARTITION BY mddc.customer_id ORDER BY mddc.date) as prev_membership_type
FROM member_detail_daily_changes_new mddc
) mddc
WHERE prev_membership_type <> membership_type AND
date >= '2018-01-01' AND
date < '2019-01-01'
GROUP BY membership_type, prev_membership_type;
Notes:
The filtering on date needs to occur after the calculation of lag().
This takes into account that members may have a certain type in 2017 and then change to a new type in 2018.
The date filtering is compatible with indexes.
Two values are calculated. One is the overall number of changes. The other counts each member only once for each type of change.

With conditional aggregation after self joining the table:
select
2018 fiscal,
sum(case when m.member_type_cd > t.member_type_cd then 1 else 0 end) upgrades,
sum(case when m.member_type_cd < t.member_type_cd then 1 else 0 end) downgrades
from member_detail_daily_changes_new m inner join member_detail_daily_changes_new t
on
t.customer = m.customer
and
t.changedate = (
select max(changedate) from member_detail_daily_changes_new
where customer = m.customer and changedate < m.changedate
)
where year(m.changedate) = 2018
This will work even if there are more than 2 types of membership level.

Related

SQLite - Output count of all records per day including days with 0 records

I have a sqlite3 database maintained on an AWS exchange that is regularly updated by a Python script. One of the things it tracks is when any team generates a new post for a given topic. The entries look something like this:
id
client
team
date
industry
city
895
acme industries
blueteam
2022-06-30
construction
springfield
I'm trying to create a table that shows me how many entries for construction occur each day. Right now, the entries with data populate, but they exclude dates with no entries. For example, if I search for just
SELECT date, count(id) as num_records
from mytable
WHERE industry = "construction"
group by date
order by date asc
I'll get results that looks like this:
date
num_records
2022-04-01
3
2022-04-04
1
How can I make sqlite output like this:
date
num_records
2022-04-02
3
2022-04-02
0
2022-04-03
0
2022-04-04
1
I'm trying to generate some graphs from this data and need to be able to include all dates for the target timeframe.
EDIT/UPDATE:
The table does not already include every date; it only includes dates relevant to an entry. If no team posts work on a day, the date column will jump from day 1 (e.g. 2022-04-01) to day 3 (2022-04-03).
Given that your "mytable" table contains all dates you need as an assumption, you can first select all of your dates, then apply a LEFT JOIN to your own query, and map all resulting NULL values for the "num_records" field to "0" using the COALESCE function.
WITH cte AS (
SELECT date,
COUNT(id) AS num_records
FROM mytable
WHERE industry = "construction"
GROUP BY date
ORDER BY date
)
SELECT dates.date,
COALESCE(cte.num_records, 0) AS num_records
FROM (SELECT date FROM mytable) dates
LEFT JOIN cte
ON dates.date = cte.date

Executing a Aggregate function within a case without Group by

I am trying to assign a specific code to a client based on the number of gifts that they have given in the past 6 months using a CASE. I am unable to use WITH (screenshot) due to the limitations of the software that I am creating the query in. It only allows for select functions. I am unsure how to get a distinct count from another table (transaction data) and use that as parameters in the CASE I have currently built (based on my client information table). Does anyone know of any workarounds for this? I am unable to GROUP BY clientID at the end of my query because not all of my columns are aggregate, and I only need to GROUP BY clientID for this particular WHEN statement in the CASE. I have looked into the OVER() clause, but I am needing my date range that I am evaluating to be dynamic (counting transactions over the last six months), and the amount of rows that I would be including is variable, as the transaction count month to month varies. Also, the software that I am building this in does not recognize the PARTITIONED BY parameter of the over clause.
Any help would be great!
EDIT:
it is not letting me attach an image... -____- I have added the two sections of code that I am looking for assistance with!
WITH "6MonthGIftCount" (
"ConstituentID"
,"GiftCount"
)
AS (
SELECT COUNT(DISTINCT "GiftView"."GiftID" FROM "GiftView" WHERE MONTHS_BETWEEN("GiftView"."GiftDate", getdate()) <= 6 GROUP BY "GiftView"."ConstituentID")
SELECT...CASE
WHEN "6MonthGiftCount"."GiftCount" >= 4
THEN 'A010'
)
Perform your grouping/COUNT(1) in a subquery to obtain the total # of donations by ConstituentID, then JOIN this total into your main query that uses this new column to perform its CASE statement.
select
hist.*,
case when timesDonated > 5 then 'gracious donor'
when timesDonated > 3 then 'repeated donor'
when timesDonated >= 1 then 'donor'
else null end as donorCode
from gifthistory hist
left join ( /* your grouping subquery here, pretending to be a new table */
select
personID,
count(1) as timesDonated
from gifthistory i
WHERE abs(months_between(giftDate, sysdate)) <= 6
group by personid ) grp on hist.personid = grp.personID
order by 1;
*Naturally, syntax changes will vary by DB; you didn't specify which it was based on, but you should be able to use this template with whichever you utilize. This works in both Oracle and SQL Server after tweaking the month calculation appropriately.

Avoiding roundtrips in the database caused by looping

I am using postgres and, I recently encountered that the code I am using has too many roundtrips.
What I am doing is basically getting data from a table on a daily basis because I have to look for changes on a daily basis, but the whole function that does this job is called once a month.
An example of my table
Amount
Id | Itemid | Amount | Date
1 | 2 | 50 | 20-5-20
Now this table can be updated to add items at any point in time and I have to see the total amount that is SUM(Amount) every day.
But here's the catch, I have to add interest to the amount of each day at the rate of 5%.
So I can't just once call the function, I have to look at its value every day.
For example if I add an item of 50$ on the 1st of may then the interest on that day is 5/100*50
I add another item on the 5th of may worth 50$ and now the interest on the 5th day is 5/100*50.
But prior to 5th, the interest was on only 50$ so If I just simply use SUM(Amount)*5/100. It is wrong.
Also, another issue is the fact that dates are stored as timestamps and I need to group it by date of the timestamp because if I group it on the basis of timestamp then it will create multiple rows for the same date which I want to avoid while taking the sum.
So if there are two entries on the same date but different hours ideally the query should sum it up as one single date.
Example
Amount Table
Date | Amount
2020-5-5 20:8:8 100
2020-5-5 7:8:8 | 100
Result should be
Amount Table
Date | Amount
2020-5-5 200
My current code.
for i in numberofdaysinthemonth:
amount = amount + session.query(func.sum(Amount.Amount)).filter(Amount.date<current_date).scalar() * 5/100
I want a query that gets all these values according to dates, for example
date | Sum of amount till that date
20-5-20 | 50
20-6-20 | 100
Any ideas about what I should do to avoid a loop that runs 30 times since the function is called once in a month.
I am supposed to get all this data in a table daywise and aggregated as the sum of amount for each day
That is a simple "running total"
select "date",
sum(amount) over (order by "date") as amount_til_date
from the_table
order by "date";
If you need the amount per itemid
select "date",
sum(amount) over (partition by itemid order by "date") as amount_til_date
from the_table
order by "date";
If you also need to calculate the "compound interest rate" up to that day, you can do that as well:
select item_id,
"date",
sum(amount) over (partition by itemid order by "date") as amount_til_date,
sum(amount) over (partition by item_id order by "date") * power(1.05, count(*) over (partition by item_id order by "date")) as compound_interest
from the_table
order by "date";
To get that for a specific month, add a WHERE clause:
where "date" >= date '2020-06-01'
and "date" < date '2020-07-01'
In general to avoid round trips between application and database, application code must be moved from application to database in stored code (stored procedures an stored functions) using a procedural language. This approach is sometimes called "thick database" in commercial databases like Oracle Database.
PostgreSQL default procedural language is pl/pgsql but you can use Java, Perl, Python, Javascript using PostgreSQL extensions that you would need to install in PostgreSQL.

SQL Find latest record only if COMPLETE field is 0

I have a table with multiple records submitted by a user. In each record is a field called COMPLETE to indicate if a record is fully completed or not.
I need a way to get the latest records of the user where COMPLETE is 0, LOCATION, DATE are the same and no additional record exist where COMPLETE is 1. In each record there are additional fields such as Type, AMOUNT, Total, etc. These can be different, even though the USER, LOCATION, and DATE are the same.
There is a SUB_DATE field and ID field that denote the day the submission was made and auto incremented ID number. Here is the table:
ID NAME LOCATION DATE COMPLETE SUB_DATE TYPE1 AMOUNT1 TYPE2 AMOUNT2 TOTAL
1 user1 loc1 2017-09-15 1 2017-09-10 Food 12.25 Hotel 65.54 77.79
2 user1 loc1 2017-09-15 0 2017-09-11 Food 12.25 NULL 0 12.25
3 user1 loc2 2017-08-13 0 2017-09-05 Flight 140 Food 5 145.00
4 user1 loc2 2017-08-13 0 2017-09-10 Flight 140 NULL 0 140
5 user1 loc3 2017-07-14 0 2017-07-15 Taxi 25 NULL 0 25
6 user1 loc3 2017-08-25 1 2017-08-26 Food 45 NULL 0 45
The results I would like is to retrieve are ID 4, because the SUB_DATE is later that ID 3. Which it has the same Name, Location, and Date information and there is no COMPLETE with a 1 value.
I would also like to retrieve ID 5, since it is the latest record for the User, Location, Date, and Complete is 0.
I would also appreciate it if you could explain your answer to help me understand what is happening in the solution.
Not sure if I fully understood but try this
SELECT *
FROM (
SELECT *,
MAX(CONVERT(INT,COMPLETE)) OVER (PARTITION BY NAME,LOCATION,DATE) AS CompleteForNameLocationAndDate,
MAX(SUB_DATE) OVER (PARTITION BY NAME, LOCATION, DATE) AS LastSubDate
FROM your_table t
) a
WHERE CompleteForNameLocationAndDate = 0 AND
SUB_DATE = LastSubDate
So what we have done here:
First, if you run just the inner query in Management Studio, you will see what that does:
The first max function will partition the data in the table by each unique Name,Location,Date set.
In the case of your data, ID 1 & 2 are the first partition, 3&4 are the second partition, 5 is the 3rd partition and 6 is the 4th partition.
So for each of these partitions it will get the max value in the complete column. Therefore any partition with a 1 as it's max value has been completed.
Note also, the convert function. This is because COMPLETE is of datatype BIT (1 or 0) and the max function does not work with that datatype. We therefore convert to INT. If your COMPLETE column is type INT, you can take the convert out.
The second max function partitions by unique Name, Location and Date again but we are getting the max_sub date this time which give us the date of the latest record for the Name,Location,Date
So we take that query and add it to a derived table which for simplicity we call a. We need to do this because SQL Server doesn't allowed windowed functions in the WHERE clause of queries. A windowed function is one that makes use of the OVER keyword as we have done. In an ideal world, SQL would let us do
SELECT *,
MAX(CONVERT(INT,COMPLETE)) OVER (PARTITION BY NAME,LOCATION,DATE) AS CompleteForNameLocationAndDate,
MAX(SUB_DATE) OVER (PARTITION BY NAME, LOCATION, DATE) AS LastSubDate
FROM your)table t
WHERE MAX(CONVERT(INT,COMPLETE)) OVER (PARTITION BY NAME,LOCATION,DATE) = 0 AND
SUB_DATE = MAX(SUB_DATE) OVER (PARTITION BY NAME, LOCATION, DATE)
But it doesn't allow it so we have to use the derived table.
So then we basically SELECT everything from our derived table Where
CompleteForNameLocationAndDate = 0
Which are Name,Location, Date partitions which do not have a record marked as complete.
Then we filter further asking for only the latest record for each partition
SUB_DATE = LastSubDate
Hope that makes sense, not sure what level of detail you need?
As a side, I would look at restructuring your tables (unless of course you have simplified to better explain this problem) as follows:
(Assuming the table in your examples is called Booking)
tblBooking
BookingID
PersonID
LocationID
Date
Complete
SubDate
tblPerson
PersonID
PersonName
tblLocation
LocationID
LocationName
tblType
TypeID
TypeName
tblBookingType
BookingTypeID
BookingID
TypeID
Amount
This way if you ever want to add Type3 or Type4 to your booking information, you don't need to alter your table layout

SQL statement to match dates that are the closest?

I have the following table, let's call it Names:
Name Id Date
Dirk 1 27-01-2015
Jan 2 31-01-2015
Thomas 3 21-02-2015
Next I have the another table called Consumption:
Id Date Consumption
1 26-01-2015 30
1 01-01-2015 20
2 01-01-2015 10
2 05-05-2015 20
Now the problem is, that I think that doing this using SQL is the fastest, since the table contains about 1.5 million rows.
So the problem is as follows, I would like to match each Id from the Names table with the Consumption table provided that the difference between the dates are the lowest, so we have: Dirk consumes on 27-01-2015 about 30. In case there are two dates that have the same "difference", I would like to calculate the average consumption on those two dates.
While I know how to join, I do not know how to code the difference part.
Thanks.
DBMS is Microsoft SQL Server 2012.
I believe that my question differs from the one mentioned in the comments, because it is much more complicated since it involves comparison of dates between two tables rather than having one date and comparing it with the rest of the dates in the table.
This is how you could it in SQL Server:
SELECT Id, Name, AVG(Consumption)
FROM (
SELECT n.Id, Name, Consumption,
RANK() OVER (PARTITION BY n.Id
ORDER BY ABS(DATEDIFF(d, n.[Date], c.[Date]))) AS rnk
FROM Names AS n
INNER JOIN Consumption AS c ON n.Id = c.Id ) t
WHERE t.rnk = 1
GROUP BY Id, Name
Using RANK with PARTITION BY n.Id and ORDER BY ABS(DATEDIFF(d, n.[Date], c.[Date])) you can locate all matching records per Id: all records with the smallest difference in days are going to have rnk = 1.
Then, using AVG in the outer query, you are calculating the average value of Consumption between all matching records.
SQL Fiddle Demo