I am trying to count over two tables and by union to take the results. How can i take the SUM of the rows afterwards?
select count(PARTNER_ID) from Administrator.PARTNERS
union
select count(RECORD_ID) from Administrator.DELETED_RECORDS WHERE RECORD_BASE_TYPE = 'PARTNER'
use subquery
select sum(val)
from
(
select count(PARTNER_ID) as val from Administrator.PARTNERS
union all
select count(RECORD_ID) from Administrator.DELETED_RECORDS WHERE RECORD_BASE_TYPE = 'PARTNER'
)A
Related
I have a query with union all functionality each giving me count(*) return from respective queries and another count query like below. I want an outer query that gives the total.
1st query
select count(*) from a
union all
select count(*) from b;
Sample result for 1st query:
COUNT
10
40
2nd query
select count(*) from xy;
Sample result for 2nd query:
COUNT
20
I want output like this in 2 rows:
TABLES
COUNT
xy
20
ab
50
something like above. How can I achieve this in oracle? please suggest the best way to do this.
I wrote a select and union all but not sure how to proceed further.
One option is to sum counts returned by the 1st query and then union it with the 2nd; also, add constants which show the source:
select 'ab' what, (select count(*) from a) + (select count(*) from b) cnt from dual
union all
select 'xy', count(*) from xy;
You can use:
SELECT 'ab' AS type,
COUNT(*) AS total
FROM ( SELECT 1 FROM a UNION ALL
SELECT 1 from b );
UNION ALL
SELECT 'xy', COUNT(*)
FROM xy;
You can sum counts from your three unioned Select statements and group the result by combination of sources:
WITH
a AS
( Select LEVEL "A_ID", 'some column a' "COL_A" From Dual Connect By LEVEL <= 30 ),
b AS
( Select LEVEL "B_ID", 'some column b' "COL_B" From Dual Connect By LEVEL <= 20 ),
xy AS
( Select LEVEL "XY_ID", 'some column xy' "COL_XY" From Dual Connect By LEVEL <= 20 )
with above sample data it is like here:
SELECT
CASE WHEN SOURCE IN('a', 'b') THEN 'ab' ELSE SOURCE END "SOURCE",
Sum(CNT) "CNT"
FROM
( Select 'a' "SOURCE", Count(*) "CNT" From a Union All
Select 'b', Count(*) From b Union All
Select 'xy', Count(*) From xy
)
GROUP BY
CASE WHEN SOURCE IN('a', 'b') THEN 'ab' ELSE SOURCE END
--
-- R e s u l t :
-- SOURCE CNT
-- ------ ----------
-- ab 50
-- xy 20
Assuming that your real queries can be a lot more complex, I take it as a given that we shall not try to change them and somehow merge or split them.
Your first query returns two rows. You want to get their sum, so you must aggregate the result and use SUM.
Below query uses CTEs (subqueries in the WITH clause) for your two queries, and then a query that gets this sum. It then uses these CTEs for the final UNION ALL query.
with query1 (cnt) as (select count(*) from a union all select count(*) from b)
, query2 (cnt) as (select count(*) from xy)
, sumquery1 (total) as (select sum(cnt) from query1)
select 'ab' as tables, total from sumquery1
union all
select 'xy' as tables, cnt from query2
order by tables desc;
I want to return the number of rows with columns from two Tables related by UNION.
I wrote this query
SELECT(
(SELECT * FROM(
(SELECT
ID_COMPTE,
TITLE,
LINK,
DATE_CREAT,
DATE_MODIF,
'TF1' AS "TYPE_FICHIER",
case when DATE_MODIF is null then DATE_CREAT else DATE_MODIF end as LAST_UPDATE FROM FIRST_TABLE FFF where ID_COMPTE= 11111111)
UNION
(SELECT
ID_COMPTE,
TITLE,
LINK,
DATE_CREAT,
DATE_MODIF,
'TF2' AS "TYPE_FICHIER",
case when DATE_MODIF is null then DATE_CREAT else DATE_MODIF end as LAST_UPDATE FROM SECOND_TABLE SSS where ID_COMPTE= 11111111)
order by LAST_UPDATE desc
) parentSelect WHERE ROWNUM BETWEEN 0 AND 2)), count(firstSelect) FROM firstSelect;
The purpose is to return the the last two rows with the count of all the rows of Table 1 and Table 2.
The query without the count works fine it's just the count that cause problem, I don't know how to insert it.
I tried also to use count() for each SELECT and SUM in the parent SELECT but it doesn't work.
This concept should work for you. Basically you select the data you want in the with clause. Then in the main select, you select your data, and the count.
WITH
base AS
(
SELECT 'TEST1' DATA FROM DUAL
UNION ALL
SELECT 'TEST2' DATA FROM DUAL
UNION ALL
SELECT 'TEST3' DATA FROM DUAL
)
SELECT (SELECT COUNT(*) FROM base) AS KOUNT, base.*
FROM base
;
You can use #Temp ( TempTable ).
Insert or manupulate the rows in it which you want to have and finally return it from stored procedure.
I want to select a third column based on two distant columns within the same table.
I could only think of this:
select tl.thirdcolumn
from table1 t1
WHERE
EXISTS
(
Select distinct tl.firstcolumn , t1.secondcolumn
From t1
)
This:
select distinct tl.thirdcolumn
from table t1
won't work as I don't want the distinct thirdrow. I want the thirdrow to be based on the first two rows being distinct.
I guess its a kind of nested sql statment with a select top 1... idk
CATEGORY NAME Query
---------------------------------------------------
STUDENTS NUMBER_OF_CHAPTERS QueryA
STUDENTS NUMBER_OF_STUDENT_MEMBERS QueryB
STUDENTS NUMBER_OF_STUDENT_MEMBERS QueryB
MEMBERS NUMBER_OF_MEMBERS_WORLDWIDE QueryC
MEMBERS NUMBER_OF_MEMBERS_WORLDWIDE QueryC
Your question is rather hard to follow, but I think you might simply want group by:
select tl.firstcolumn , t1.secondcolumn, max(tl.thirdcolumn)
from table1 t1
group by tl.firstcolumn , t1.secondcolumn;
If you want rows where the pair of values only appears once, then add having count(*) = 1:
select tl.firstcolumn , t1.secondcolumn, max(tl.thirdcolumn)
from table1 t1
group by tl.firstcolumn , t1.secondcolumn
having count(*) = 1;
Query -
SELECT
CATEGORY,NAME,QUERY
FROM
(
WITH TAB AS (
SELECT
'STUDENTS' AS CATEGORY,
'NUMBER_OF_CHAPTERS' AS NAME,
'QUERYA' AS QUERY
FROM
DUAL
UNION ALL
SELECT
'STUDENTS' AS CATEGORY,
'NUMBER_OF_STUDENT_MEMBERS' AS NAME,
'QUERYB' AS QUERY
FROM
DUAL
UNION ALL
SELECT
'STUDENTS' AS CATEGORY,
'NUMBER_OF_STUDENT_MEMBERS' AS NAME,
'QUERYB' AS QUERY
FROM
DUAL
UNION ALL
SELECT
'MEMBERS' AS CATEGORY,
'NUMBER_OF_MEMBERS_WORLDWIDE' AS NAME,
'QUERYC' AS QUERY
FROM
DUAL
UNION ALL
SELECT
'MEMBERS' AS CATEGORY,
'NUMBER_OF_MEMBERS_WORLDWIDE' AS NAME,
'QUERYC' AS QUERY
FROM
DUAL
) SELECT
CATEGORY,
NAME,
QUERY,
COUNT(*) OVER(PARTITION BY
CATEGORY,
NAME
ORDER BY
CATEGORY,
NAME,
QUERY
) AS RNK
FROM
TAB
)
WHERE
RNK = 1;
Output -
"CATEGORY","NAME","QUERY"
"STUDENTS","NUMBER_OF_CHAPTERS","QueryA"
How would I join the following tables to give a total count from all the tables.
select (BatchIdentifier),
Count(distinct BatchIdentifier) as ERTBatchCheckIdentifier
from ERTBatchChecks
Group By BatchIdentifier
select (ERTBatchNumber),
Count(distinct ERTBatchNumber) as ERTBatchNumber
from ERTClaims
Group By ERTBatchNumber
select (BatchIdentifier),
Count(distinct BatchIdentifier) as ERTBatchesIdentifier
from ERTBatches
Group By BatchIdentifier
If you simply want a SUM() then use a derived table and union all:
SELECT Batch, SUM(Cnt) AS TotalCount
FROM (
select (BatchIdentifier) AS Batch,
Count(distinct BatchIdentifier) as Cnt
from ERTBatchChecks
Group By BatchIdentifier
union all
select (ERTBatchNumber),
Count(distinct ERTBatchNumber)
from ERTClaims
Group By ERTBatchNumber
union all
select (BatchIdentifier),
Count(distinct BatchIdentifier)
from ERTBatches
Group By BatchIdentifier
) SubCounts
GROUP BY Batch
If you want a total count of the distinct 'batches' then use union and COUNT():
SELECT Count(Batch) AS TotalDistinctBatches
FROM (
select distinct BatchIdentifier as Batch
from ERTBatchChecks
union
select distinct ERTBatchNumber
from ERTClaims
union
select distinct BatchIdentifier
from ERTBatches
) DistinctBatches
Note: Union all will keep duplicates, Union will not. Hence for adding the counts, we want to use Union all in case two of the counts are the same. But for counting the distinct batches, we want Union so we don't count the same batch more than once.
I'm trying to do multiple select from diff tables and just have a result in one column.
SELECT COUNT(*) FROM tb1 union
SELECT COUNT(*) FROM tb2 union
SELECT COUNT(*) FROM tb3;
output should be like:
593643
18103600
0
Problem with this is that the result is being arranged on desc order.
Like below:
0
593643
18103600
I would want the result to be as I put the select statement.
Please advise. Btw, I'm using teradata.
Thank you.
SQL result sets are inherently unordered, unless you explicitly specify an order by clause. You can do this with a subquery:
select cnt
from ((SELECT COUNT(*) as cnt, 1 as ord FROM tb1)
union all
(SELECT COUNT(*), 2 FROM tb2)
union all
(SELECT COUNT(*), 3 FROM tb3)
) t
order by ord
If you want specific order, add ORDER BY clause. It would also be good to use UNION ALL so you always get 3 rows, even with duplicate results (two tables having the same number of rows):
SELECT 'tbl1' AS tablename, COUNT(*) AS cnt, 1 AS ord FROM tb1 UNION ALL
SELECT 'tbl2', COUNT(*), 2 FROM tb2 UNION ALL
SELECT 'tbl3', COUNT(*), 3 FROM tb3
ORDER BY ord ;