In big query how do I get the yesterday date with the time part 00:00:00?
DATE Doesn't have time part
if you want yesterday DateTime with 00:00 as time use:
SELECT DATETIME_TRUNC(DATETIME_SUB(CURRENT_DATETIME(), INTERVAL 1 DAY), DAY) as yesterday;
if you want yesterday date use:
SELECT DATE_SUB(CURRENT_DATE(), INTERVAL 1 DAY) as yesterday;
If you want a time part, then you want either a TIMESTAMP or DATETIME column.
So, either:
SELECT DATETIME(DATE_ADD(CURRENT_DATE(), INTERVAL -1 DAY)) as yesterday_dt,
TIMESTAMP(DATE_ADD(CURRENT_DATE(), INTERVAL -1 DAY)) as yesterday_ts
This code gets you date
SELECT DATEADD(dd, -1, DATEDIFF(dd, 0, GETDATE()));
For different methods check this link
MS SQL Server - How to get Date only from the datetime value?
Below is yet another option for BigQuery standard SQL
#standardSQL
SELECT
TIMESTAMP_SECONDS(86400 * (UNIX_DATE(CURRENT_DATE()) - 1)) yesterday_as_timestamp,
DATETIME(TIMESTAMP_SECONDS(86400 * (UNIX_DATE(CURRENT_DATE()) - 1))) yesterday_as_datetime
with result (as of answer day - April 02, 2019)
Row yesterday_as_timestamp yesterday_as_datetime
1 2019-04-01 00:00:00 UTC 2019-04-01T00:00:00
Note:
DATETIME Represents a year, month, day, hour, minute, second, and subsecond. Range: 0001-01-01 00:00:00 to 9999-12-31 23:59:59.999999.
TIMESTAMP Represents an absolute point in time, with microsecond precision. Range: 0001-01-01 00:00:00 to 9999-12-31 23:59:59.999999 UTC.
A timestamp represents an absolute point in time, independent of any time zone or convention such as Daylight Savings Time.
TIMESTAMP provides microsecond precision.
Unlike Timestamps, a DATETIME object does not refer to an absolute instance in time. Instead, it is the civil time, or the time that a user would see on a watch or calendar.
You can see more details about DATETIME and TIMESTAMP in Data Types doc
Related
I'm working with BigQuery and have a table that looks like:
YEAR
MONTH
DAY
timezone
local time
2015
6
24
America/Los Angeles
1930
Where local time is given by hhmm. I'm wondering if I can format this information into a timestamp column in SQL that yields time in UTC.
I know I can use `TO_TIMESTAMP` but that would involve concatenating all these columns as strings first. Is there any better way to do this? If I were to concatenate, I'm not sure how I would use timezone and then back out UTC.
You might consider below.
WITH sample_table AS (
SELECT 2015 year, 6 month, 24 day, 'America/Los_Angeles' timezone, 1930 local_time UNION ALL
SELECT 2015 year, 6 month, 24 day, 'America/Los_Angeles' timezone, 2400 local_time
)
SELECT TIMESTAMP_SECONDS(
UNIX_SECONDS(TIMESTAMP(DATE(year, month, day), timezone))
+ DIV(local_time, 100) * 3600 + MOD(local_time, 100) * 60
) utc
FROM sample_table;
Since TIME(24, 0, 0) is not a valid time format, the query converts datetime into unix seconds and get back to UTC with the time calculation in seconds.
Input calculates to invalid time: 24:00:00
Query results
I am trying to include, in my where clause, a way to automatically pull data for the previous day based on my current timezone. All of my data is stored with a UTC timestamp.
I can change my timestamp from UTC to my timezone ("America/Chicago") and I can automatically pull data for the last X days; for example, for the prior week, without having to manually enter a date. But I cannot figure out how to do both simultaneously in my where clause.
SELECT *
FROM `my-data-set`
WHERE
event_time >= CAST(DATE_SUB(CURRENT_DATE(), INTERVAL 7 DAY) AS TIMESTAMP)
AND event_time < CAST(DATE_SUB(CURRENT_DATE(), INTERVAL 0 DAY) AS TIMESTAMP)
I would like to be able to look at the previous week or day in my timezone, not the previous UTC day.
You can do specify the timezone:
where date(event_time, 'America/Chicago') = date_add(current_date, interval -1 day)
Note that the parentheses are not needed for current_date.
The key to the logic is converting the UTC timestamp to a date in your local time.
I am working with time data that is currently stores in UTC but I want it to be in PST, which is 8 hours behind. I have a pretty lengthy and involved query, but the only thing I am interested in is the time right now so I have included those parts. I want to convert the times to PST and then group by the date for the last week of data. The query has the following structure:
select
date_trunc('day', time1) AT TIME ZONE 'US/Pacific'
...
where
time1 AT TIME ZONE 'US/Pacific' > now() AT TIME ZONE current_setting('TimeZone') - INTERVAL '168 HOURS'
...
group by date_trunc('day', time1)
This results in the following time groupings. From my understanding, it groups from the 0:00 UTC, which is 16:00 in PST. However, I want the groupby to start at 0:00 PST. How do I do this? Right now, the counts in each group are misleading for each day because they go from 4 pm to 4 pm instead of 12 am to 12 am. For example, Sundays have uncharacteristically high counts because Sunday includes part of Monday's data in the groupby. I would appreciate any input to fix this issue. Thank you.
The answer depends on whether it is a timestamp with time zone or one without:
If it's a timestamp with time zone, you can convert to PST with select time1 AT TIME ZONE 'US/Pacific' and get the date with select date_trunc('day', time1 AT TIME ZONE 'US/Pacific')
If it's a timestamp without time zone stored in UTC that you want to convert, you first have to tell PostgreSQL to interpret it as UTC, then convert it, like so: select (time1 AT TIME ZONE 'Z') AT TIME ZONE 'US/Pacific' and of course you can get the date with select date_trunc('day', (time1 AT TIME ZONE 'Z') AT TIME ZONE 'US/Pacific')
In either case you have to convert time zones before truncating to the day level or you may end up with inaccurate results.
Using Standard SQL in BQ - as part of a task I want to search for records created between 2pm the previous day & 2pm on current day
I have found
SELECT DATETIME_SUB(DATETIME_TRUNC(CURRENT_DATETIME(), DAY), INTERVAL 10 hour) Gives me 2PM yesterday
SELECT DATETIME_ADD(DATETIME_TRUNC(CURRENT_DATETIME(), DAY), INTERVAL 14 hour)
Gives me 2pm today
So, i assumed i could use this in my query
Select * from
TableA
where CreatedDate Between
DATETIME_SUB(DATETIME_TRUNC(CURRENT_DATETIME(), DAY), INTERVAL 10 hour) and DATETIME_ADD(DATETIME_TRUNC(CURRENT_DATETIME(), DAY), INTERVAL 14 hour)
However I get the following
No matching signature for operator BETWEEN for argument types:
TIMESTAMP, DATETIME, DATETIME. Supported signature: (ANY) BETWEEN
(ANY) AND (ANY)
Where am i going wrong?
Your issue is that CreatedDate is TIMESTAMP and you need to convert into a DATETIME
It could be like:
where DATETIME(CreatedDate) Between ...
But you could easily write your own statements for TIMESTAMP
SELECT timestamp_sub(timestamp_trunc(current_timestamp() ,
DAY),interval 10 hour)
I have a oracle table for maintaining cutoff time. here we are storing cutoff time for various securities.. currently we are defaulting date portion of cutoff to 1st Jan 1970. The requirement is to replace this date portion with current date without changing time and timezone portion of cutoff.
You could calculate the number of days between today and 1970-01-01, and then add that as a day-to-second interval to your cutoff timestamp value:
create table my_table (cutoff timestamp with time zone);
insert into my_table values (timestamp '1970-01-01 18:00:00 -5:00');
select cutoff + numtodsinterval(trunc(sysdate) - date '1970-01-01', 'DAY') as adjusted
from my_table;
ADJUSTED
-----------------------------------
05-JUN-17 18.00.00.000000000 -05:00
or if you prefer, you can generate an interval directly (as #mathguy pointed out):
select cutoff + (trunc(sysdate) - timestamp '1970-01-01 00:00:00') as adjusted
from my_table;
ADJUSTED
-------------------------
06-JUN-17 18:00:00 -05:00
The -05:00 time zone offset ignores daylight savings time, of course, but that seems to be what you intended.