Find all rows where date column has timestamp = 00:00:00.000 - sql

I have a table in which one column as registrationDate whose type is datetime. I need to find all the rows where registrationDate as timestamp as 00:00:00.000.
for example :
registrationDate: '2019-03-20 00:00:00.000'
I need to query something similar as below :
select * from table where registrationDate like '%00:00:00.000';


You can cast datetime as time:
WHERE CAST(registrationDate AS TIME) = '00:00'


WHERE registrationDate = CONVERT(date, registrationDate);


See UPDATE below
Create Table #tbl
(
registrationDate Datetime
)
Insert Into #tbl Values
('2019-03-20 00:00:00.000'),
('2019-03-20 00:00:25.000')
Query
Select * From #tbl
Where Cast(registrationDate As Time) = '00:00:00.0000000'
Result:
registrationDate
2019-03-20 00:00:00.000
Update: If you really need to use "Like"
Select * From #tbl
Where convert(VarChar(50), registrationDate, 121) Like '%00:00:00.000'


select * from table where FORMAT(registrationDate, 'HH:mm:ss:ms') ='00:00:00.000'


The following expression gets for every datetime value the corresponding date with time portion:
dateadd(day, datediff(day, 0, '<date_time>'), 0)
Hence, the following will do the job:
create table foo (id int, registrationDate datetime)
insert foo values
(1, '2019-04-04T03:22:48.00'),
(2, '2019-04-04T00:00:00.00')
select * from foo
where registrationDate =
dateadd(day, datediff(day, 0, registrationDate), 0)

Related

SQL Column Concatenation whilst keeping the datatype of first column [duplicate]

In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown.
How can I query the table to combine these two fields into 1 column of type datetime?
Dates
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
Times
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000

You can simply add the two.
if the Time part of your Date column is always zero
and the Date part of your Time column is also always zero (base date: January 1, 1900)
Adding them returns the correct result.
SELECT Combined = MyDate + MyTime FROM MyTable
Rationale (kudos to ErikE/dnolan)
It works like this due to the way the date is stored as two 4-byte
Integers with the left 4-bytes being the date and the right
4-bytes being the time. Its like doing $0001 0000 + $0000 0001 =
$0001 0001
Edit regarding new SQL Server 2008 types
Date and Time are types introduced in SQL Server 2008. If you insist on adding, you can use Combined = CAST(MyDate AS DATETIME) + CAST(MyTime AS DATETIME)
Edit2 regarding loss of precision in SQL Server 2008 and up (kudos to Martin Smith)
Have a look at How to combine date and time to datetime2 in SQL Server? to prevent loss of precision using SQL Server 2008 and up.

If the time element of your date column and the date element of your time column are both zero then Lieven's answer is what you need. If you can't guarantee that will always be the case then it becomes slightly more complicated:
SELECT DATEADD(day, 0, DATEDIFF(day, 0, your_date_column)) +
DATEADD(day, 0 - DATEDIFF(day, 0, your_time_column), your_time_column)
FROM your_table

This is an alternative solution without any char conversions:
DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
You will only get milliseconds accuracy this way, but that would normally be OK. I have tested this in SQL Server 2008.

This worked for me
CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)
(on SQL 2008 R2)

If you're not using SQL Server 2008 (i.e. you only have a DateTime data type), you can use the following (admittedly rough and ready) TSQL to achieve what you want:
DECLARE #DateOnly AS datetime
DECLARE #TimeOnly AS datetime
SET #DateOnly = '07 aug 2009 00:00:00'
SET #TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
as datetime)
It's rough and ready, but it works!

If both of your fields are datetime then simply adding those will work.
eg:
Declare #d datetime, #t datetime
set #d = '2009-03-12 00:00:00.000';
set #t = '1899-12-30 12:30:00.000';
select #d + #t
If you used Date & Time datatype then just cast the time to datetime
eg:
Declare #d date, #t time
set #d = '2009-03-12';
set #t = '12:30:00.000';
select #d + cast(#t as datetime)

This was my solution which ignores the date value of the time column
CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)
Hope this helps others

Convert the first date stored in a datetime field to a string, then convert the time stored in a datetime field to string, append the two and convert back to a datetime field all using known conversion formats.
Convert(datetime, Convert(char(10), MYDATETIMEFIELD, 103) + ' ' + Convert(char(8), MYTIMEFIELD, 108), 103)

Convert both field into DATETIME :
SELECT CAST(#DateField as DATETIME) + CAST(#TimeField AS DATETIME)
and if you're using Getdate() use this first:
DECLARE #FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(#FechaActual as DATETIME) + CAST(#HoraInicioTurno AS DATETIME)

I had many errors as stated above so I did it like this
try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime
It worked for me.

Finding this works for two dates where you want time from one and date from the other:
declare #Time as datetime = '2021-11-19 12:34'
declare #Date as datetime = '2021-10-10'
SELECT #time + datediff(day, #Time, #Date)

DECLARE #Dates table ([Date] datetime);
DECLARE #Times table ([Time] datetime);
INSERT INTO #Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-30 00:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
WITH Dates (ID, [Date])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM #Dates
), Times (ID, [Time])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM #Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
JOIN Times ON Times.ID = Dates.ID
Prints:
2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000

To combine date from a datetime column and time from another datetime column this is the best fastest solution for you:
select cast(cast(DateColumn as date) as datetime) + cast(TimeColumn as datetime) from YourTable

SELECT CAST(CAST(#DateField As Date) As DateTime) + CAST(CAST(#TimeField As Time) As DateTime)

Another way is to use CONCATand CAST, be aware, that you need to use DATETIME2(x) to make it work. You can set x to anything between 0-7 7 meaning no precision loss.
DECLARE #date date = '2018-03-12'
DECLARE #time time = '07:00:00.0000000'
SELECT CAST(CONCAT(#date, ' ', #time) AS DATETIME2(7))
Returns 2018-03-12 07:00:00.0000000
Tested on SQL Server 14

simply concatenate both , but cast them first as below
select cast(concat(Cast(DateField as varchar), ' ', Cast(TimeField as varchar)) as datetime) as DateWithTime from TableName;

select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between #FromDate and #ToDate

The existing answers do not address the datetime2 datatype so I will add mine:
Assuming that you want to add a time value to a datetime2 value where:
The datetime2 value could contain non-zero time component and/or fractional seconds
The time value could contain the value 23:59:59.9999999 which is 86,399.9999999 seconds, 86,399,999,999.9 microseconds or 86,399,999,999,900 nanoseconds¹
Due to the limitations of dateadd function¹ you must add them in two steps:
Convert the time value to seconds and use dateadd(second, ...)
Extract the nanoseconds from the time value and use dateadd(nanosecond, ...) to add them to the date calculated above
declare #dv datetime2 = '2000-01-01 12:34:56.7890123';
declare #tv time = '23:59:59.9999999';
select dateadd(
nanosecond,
datepart(nanosecond, #tv),
dateadd(
second,
datepart(hour, #tv) * 60 * 60 + datepart(minute, #tv) * 60 + datepart(second, #tv),
#dv
)
);
-- 2000-01-02 12:34:56.7890122
¹ Nanosecond values might not fit in int datatype which dateadd function expects.

SELECT CAST(your_date_column AS date) + CAST(your_time_column AS datetime) FROM your_table
Works like a charm

I ran into similar situation where I had to merge Date and Time fields to DateTime field. None of the above mentioned solution work, specially adding two fields as the data type for addition of these 2 fields is not same.
I created below solution, where I added hour and then minute part to the date. This worked beautifully for me. Please check it out and do let me know if you get into any issues.
;with tbl
as
(
select StatusTime = '12/30/1899 5:17:00 PM', StatusDate = '7/24/2019 12:00:00 AM'
)
select DATEADD(MI, DATEPART(MINUTE,CAST(tbl.StatusTime AS TIME)),DATEADD(HH, DATEPART(HOUR,CAST(tbl.StatusTime AS TIME)), CAST(tbl.StatusDate as DATETIME)))
from tbl
Result: 2019-07-24 17:17:00.000

How to cast and convert to datetime in where condition in t-sql?

I am trying to get last months worth of data from the table vis_p_activities_final and tried the query below:
SELECT * FROM DPICD.vis_p_activities_final
WHERE DPICD.vis_p_activities_final.current_activity_code IN (
'SDBPR', 'SDBPU', 'XSDBPU', 'SDBPUX' )
AND CAST((DPICD.vis_p_activities_final.raised_date_time) AS DATETIME) >=
Dateadd(month, -1, CURRENT_TIMESTAMP)`
the raised_date_time column is VARCHAR and I want to convert it to datetime for the filter. How can I do that?

you can use temp table as
declare #lastmonth datetime
set #lastmonth = Dateadd(month, -1, CURRENT_TIMESTAMP)`
SELECT *, CAST((DPICD.vis_p_activities_final.raised_date_time) AS DATETIME) as
'revised_date' into #tmp FROM DPICD.vis_p_activities_final
WHERE DPICD.vis_p_activities_final.current_activity_code IN (
'SDBPR', 'SDBPU', 'XSDBPU', 'SDBPUX' )
`
select * from #tmp where revised_date >= #lastmonth

Datetime fetch incorrect data for second iteration

I have this query :
Declare #t table ( StartDate datetime , ENDDate datetime)
Insert into #t values ('2020-02-05 15:00:00.000','2020-02-05 15:30:00.000')
Insert into #t values ('2020-02-05 15:10:00.000','2020-02-05 15:20:00.000')
Declare #time datetime ='2020-02-05 15:11:00.000'
select top 1 * from #t
where StartDate <= #time
order by StartDate desc
It gives me 2nd row as an output which is correct. Because time is 15:11:00.000.
Now If I pass
Declare #time datetime ='2020-02-05 15:31:00.000'
And I run the above query it still gives me the same output, But I want to show the 1st row as an output. What changes do I need to make to satisfy both the requirement with 1 query?
The reason I want to show the 1st row as an output: Because the enddate which is being passed is near to the end date of the 1st row, I can write the second query to fetch the data, But I need just 1 query wherin both the condition should be satisfied.
I tried this as well:
Declare #t table ( StartDate datetime , ENDDate datetime)
Insert into #t values ('2020-02-05 15:00:00.000','2020-02-05 15:30:00.000')
Insert into #t values ('2020-02-05 15:10:00.000','2020-02-05 15:20:00.000')
Declare #time datetime ='2020-02-05 15:11:00.000'
select *,DATEDIFF(MINUTE,ENDDate,#time) DTB from (
select top 1 * from #t
where StartDate <= #time
order by StartDate desc
) a
order by dtb
But I am still getting the same output.

Can you please try this below logic-
DEMO HERE
Declare #t table ( StartDate datetime , ENDDate datetime)
Insert into #t values ('2020-02-05 15:00:00.000','2020-02-05 15:30:00.000')
Insert into #t values ('2020-02-05 15:10:00.000','2020-02-05 15:20:00.000')
--Declare #time datetime ='2020-02-05 15:11:00.000'
Declare #time datetime ='2020-02-05 15:31:00.000'
select TOP 1 *
from #t
where StartDate <= #time
ORDER BY ABS(datediff(mi,ENDDate,#time))

** Your query only checking one condition StartDate <= #time, if you wanted to fetch the 1st record from your table which matches the condition then remove desc from your query.
select top 1 * from #t
where StartDate <= #time
order by StartDate
** if you want to sort the date and fetch based on date difference between StartDate and passing date #t the use DATEDIFF
select *,DATEDIFF(MINUTE, StartDate, #time) as dif from #t
where cast(StartDate as datetime) <= cast(#time as datetime)
ORDER BY DATEDIFF(MINUTE, StartDate, #time)
select top 1 * from #t
where cast(StartDate as datetime) <= cast(#time as datetime)
ORDER BY DATEDIFF(MINUTE, StartDate, #time)

How to convert round number to data and time format

Two Column in table tblpress
Date Time
20160307 120949
20160307 133427
Need to be select below the format:
07-03-2016 12:09:49
07-03-2016 13:34 27
or
03-March-2016 12:09: 49 PM
03-March-2016 01:34: 27 PM

You can try below
select format(cast([Date] as date),'dd-MMMM-yyyy') as [Date],
TIMEFROMPARTS(LEFT([Time],2), SUBSTRING([Time],3,2), RIGHT([Time],2), 0,0) as [Time]

I think CAST/CONVERT will help you:
SELECT
CAST('20160307' AS date),
CAST(STUFF(STUFF('120949',3,0,':'),6,0,':') AS time)
And convert for out:
SELECT
CONVERT(varchar(20),NormalDate,105) OutDate, -- Italian style
CONVERT(varchar(20),NormalTime,108) OutTime -- hh:mi:ss
FROM
(
SELECT
CAST([Date] AS date) NormalDate,
CAST(STUFF(STUFF([Time],3,0,':'),6,0,':') AS time) NormalTime
FROM YourTable
) q
CAST and CONVERT (Transact-SQL)
And you can use FORMAT (Transact-SQL)
SELECT
FORMAT(GETDATE(),'dd-MM-yyyy'),
FORMAT(GETDATE(),'HH:mm:ss')

Best way to do it is to create a function :
create FUNCTION [dbo].[udfGetDateTimeFromInteger]
(
#intDate int,
#intTime int
)
RETURNS datetime
AS BEGIN
-- Declare the return variable here
DECLARE #DT_datetime datetime = NULL,
#str_date varchar(11),
#str_time varchar(8)
if(#intDate is not null and #intDate > 0)
begin
select #str_date = CAST( cast(#intDate as varchar(8)) AS date)
if #intTime=0
select #str_time ='000000'
else
select #str_time = right('0'+CONVERT(varchar(11),#intTime),6)
select #str_time =
SUBSTRING(#str_time,1,2)+':'+SUBSTRING(#str_time,3,2)+':'+SUBSTRING(#str_time,5,2)
select #DT_datetime = CAST(#str_date+' '+#str_time as datetime)
end
-- Return the result of the function
RETURN #DT_datetime
END
and then call it in select like :
declare #next_run_date int, #next_run_time int
select #next_run_date = 20160307
select #next_run_time = 130949
SELECT #next_run_date inputdate,
#next_run_time inputtime,
dbo.udfGetDateTimeFromInteger(#next_run_date, #next_run_time) outputdatetime
Output will be like :
inputdate inputtime outputdatetime
20160307 130949 2016-03-07 13:09:49.000

You said those are numbers, right? You can use datetimefromparts (or datetime2fromparts). ie:
select
datetimefromparts(
[date]/10000,
[date]%10000/100,
[date]%100,
[time]/10000,
[time]%10000/100,
[time]%100,0)
from tblpress;
DB Fiddle demo
Note that naming fields like that and also storing date and time like that is a bad idea.
I later noticed it was char fields:
select
cast([date] as datetime) +
cast(stuff(stuff([time],5,0,':'),3,0,':') as datetime)
from tblpress;

How to combine date from one field with time from another field - MS SQL Server

In an extract I am dealing with, I have 2 datetime columns. One column stores the dates and another the times as shown.
How can I query the table to combine these two fields into 1 column of type datetime?
Dates
2009-03-12 00:00:00.000
2009-03-26 00:00:00.000
2009-03-26 00:00:00.000
Times
1899-12-30 12:30:00.000
1899-12-30 10:00:00.000
1899-12-30 10:00:00.000

You can simply add the two.
if the Time part of your Date column is always zero
and the Date part of your Time column is also always zero (base date: January 1, 1900)
Adding them returns the correct result.
SELECT Combined = MyDate + MyTime FROM MyTable
Rationale (kudos to ErikE/dnolan)
It works like this due to the way the date is stored as two 4-byte
Integers with the left 4-bytes being the date and the right
4-bytes being the time. Its like doing $0001 0000 + $0000 0001 =
$0001 0001
Edit regarding new SQL Server 2008 types
Date and Time are types introduced in SQL Server 2008. If you insist on adding, you can use Combined = CAST(MyDate AS DATETIME) + CAST(MyTime AS DATETIME)
Edit2 regarding loss of precision in SQL Server 2008 and up (kudos to Martin Smith)
Have a look at How to combine date and time to datetime2 in SQL Server? to prevent loss of precision using SQL Server 2008 and up.

If the time element of your date column and the date element of your time column are both zero then Lieven's answer is what you need. If you can't guarantee that will always be the case then it becomes slightly more complicated:
SELECT DATEADD(day, 0, DATEDIFF(day, 0, your_date_column)) +
DATEADD(day, 0 - DATEDIFF(day, 0, your_time_column), your_time_column)
FROM your_table

This is an alternative solution without any char conversions:
DATEADD(ms, DATEDIFF(ms, '00:00:00', [Time]), CONVERT(DATETIME, [Date]))
You will only get milliseconds accuracy this way, but that would normally be OK. I have tested this in SQL Server 2008.

This worked for me
CAST(Tbl.date as DATETIME) + CAST(Tbl.TimeFrom AS TIME)
(on SQL 2008 R2)

If you're not using SQL Server 2008 (i.e. you only have a DateTime data type), you can use the following (admittedly rough and ready) TSQL to achieve what you want:
DECLARE #DateOnly AS datetime
DECLARE #TimeOnly AS datetime
SET #DateOnly = '07 aug 2009 00:00:00'
SET #TimeOnly = '01 jan 1899 10:11:23'
-- Gives Date Only.
SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly))
-- Gives Time Only.
SELECT DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
-- Concatenates Date and Time parts.
SELECT
CAST(
DATEADD(dd, 0, DATEDIFF(dd, 0, #DateOnly)) + ' ' +
DATEADD(Day, -DATEDIFF(Day, 0, #TimeOnly), #TimeOnly)
as datetime)
It's rough and ready, but it works!

If both of your fields are datetime then simply adding those will work.
eg:
Declare #d datetime, #t datetime
set #d = '2009-03-12 00:00:00.000';
set #t = '1899-12-30 12:30:00.000';
select #d + #t
If you used Date & Time datatype then just cast the time to datetime
eg:
Declare #d date, #t time
set #d = '2009-03-12';
set #t = '12:30:00.000';
select #d + cast(#t as datetime)

This was my solution which ignores the date value of the time column
CAST(Tbl.date as DATETIME) + CAST(CAST(Tbl.TimeFrom AS TIME) as DATETIME)
Hope this helps others

Convert the first date stored in a datetime field to a string, then convert the time stored in a datetime field to string, append the two and convert back to a datetime field all using known conversion formats.
Convert(datetime, Convert(char(10), MYDATETIMEFIELD, 103) + ' ' + Convert(char(8), MYTIMEFIELD, 108), 103)

Convert both field into DATETIME :
SELECT CAST(#DateField as DATETIME) + CAST(#TimeField AS DATETIME)
and if you're using Getdate() use this first:
DECLARE #FechaActual DATETIME = CONVERT(DATE, GETDATE());
SELECT CAST(#FechaActual as DATETIME) + CAST(#HoraInicioTurno AS DATETIME)

I had many errors as stated above so I did it like this
try_parse(concat(convert(date,Arrival_date),' ',arrival_time) as datetime) AS ArrivalDateTime
It worked for me.

Finding this works for two dates where you want time from one and date from the other:
declare #Time as datetime = '2021-11-19 12:34'
declare #Date as datetime = '2021-10-10'
SELECT #time + datediff(day, #Time, #Date)

DECLARE #Dates table ([Date] datetime);
DECLARE #Times table ([Time] datetime);
INSERT INTO #Dates VALUES('2009-03-12 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-26 00:00:00.000');
INSERT INTO #Dates VALUES('2009-03-30 00:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 12:30:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
INSERT INTO #Times VALUES('1899-12-30 10:00:00.000');
WITH Dates (ID, [Date])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Date]), [Date] FROM #Dates
), Times (ID, [Time])
AS (
SELECT ROW_NUMBER() OVER (ORDER BY [Time]), [Time] FROM #Times
)
SELECT Dates.[Date] + Times.[Time] FROM Dates
JOIN Times ON Times.ID = Dates.ID
Prints:
2009-03-12 10:00:00.000
2009-03-26 10:00:00.000
2009-03-30 12:30:00.000

To combine date from a datetime column and time from another datetime column this is the best fastest solution for you:
select cast(cast(DateColumn as date) as datetime) + cast(TimeColumn as datetime) from YourTable

SELECT CAST(CAST(#DateField As Date) As DateTime) + CAST(CAST(#TimeField As Time) As DateTime)

Another way is to use CONCATand CAST, be aware, that you need to use DATETIME2(x) to make it work. You can set x to anything between 0-7 7 meaning no precision loss.
DECLARE #date date = '2018-03-12'
DECLARE #time time = '07:00:00.0000000'
SELECT CAST(CONCAT(#date, ' ', #time) AS DATETIME2(7))
Returns 2018-03-12 07:00:00.0000000
Tested on SQL Server 14

simply concatenate both , but cast them first as below
select cast(concat(Cast(DateField as varchar), ' ', Cast(TimeField as varchar)) as datetime) as DateWithTime from TableName;

select s.SalesID from SalesTbl s
where cast(cast(s.SaleDate as date) as datetime) + cast(cast(s.SaleCreatedDate as time) as datetime) between #FromDate and #ToDate

The existing answers do not address the datetime2 datatype so I will add mine:
Assuming that you want to add a time value to a datetime2 value where:
The datetime2 value could contain non-zero time component and/or fractional seconds
The time value could contain the value 23:59:59.9999999 which is 86,399.9999999 seconds, 86,399,999,999.9 microseconds or 86,399,999,999,900 nanoseconds¹
Due to the limitations of dateadd function¹ you must add them in two steps:
Convert the time value to seconds and use dateadd(second, ...)
Extract the nanoseconds from the time value and use dateadd(nanosecond, ...) to add them to the date calculated above
declare #dv datetime2 = '2000-01-01 12:34:56.7890123';
declare #tv time = '23:59:59.9999999';
select dateadd(
nanosecond,
datepart(nanosecond, #tv),
dateadd(
second,
datepart(hour, #tv) * 60 * 60 + datepart(minute, #tv) * 60 + datepart(second, #tv),
#dv
)
);
-- 2000-01-02 12:34:56.7890122
¹ Nanosecond values might not fit in int datatype which dateadd function expects.

SELECT CAST(your_date_column AS date) + CAST(your_time_column AS datetime) FROM your_table
Works like a charm

I ran into similar situation where I had to merge Date and Time fields to DateTime field. None of the above mentioned solution work, specially adding two fields as the data type for addition of these 2 fields is not same.
I created below solution, where I added hour and then minute part to the date. This worked beautifully for me. Please check it out and do let me know if you get into any issues.
;with tbl
as
(
select StatusTime = '12/30/1899 5:17:00 PM', StatusDate = '7/24/2019 12:00:00 AM'
)
select DATEADD(MI, DATEPART(MINUTE,CAST(tbl.StatusTime AS TIME)),DATEADD(HH, DATEPART(HOUR,CAST(tbl.StatusTime AS TIME)), CAST(tbl.StatusDate as DATETIME)))
from tbl
Result: 2019-07-24 17:17:00.000