I have the below query
Select sum (ABC) as ecr from table1
Where a<>'y' or b is null and c<>'g'
Union all
Select sum(bcd) as ech from table2
Note: I am getting results under one column but I want to be displayed under two columns
Please try this.
SELECT sum (A.ABC) as ecr,SUM(B.bcd) as ech
FROM table1 AS A
LEFT JOIN table2 AS B
ON B.Id = A.Id
Where A.a<>'y' or A.b is null and A.c<>'g'
I think you just need a cross join
Select sum(ABC) as ecr,
sum(bcd) as ech
from table1 t1
cross join table2
Where t1.a <> 'y'
or t1.b is null
and t1.c <> 'g'
In MS Access, you use , for CROSS JOIN:
select t1.ecr, t2.ech
from (select sum(ABC) as ecr
from table1
where a <> 'y' or b is null and c <> 'g'
) t1,
(select sum(bcd) as ech
from table2
) t2;
In any other database, you would use CROSS JOIN.
Related
I have written the query:
Select distinct a,b from t1 minus Select distinct a,b from t2.
Here t1 and t2 are two tables. I want distinct values of a and b that occur in t1 but not in t2. So I'm using minus operator. I want values of both a and b but I know that in some cases the value of b in t1 and t2 maybe different. This would result in values of a and b that are present in both t1 and t2 as minus would not happen if values of b do not match in both the tables. How can I do this successfully?
How can I get values of a and b that are present in table t1 but not in table t2 even though in some cases values of b might not match in both the tables?
table1: table2:
column1 column2 column1 column2
1 a 1 c
2 b 3 d
In this case I would want values (2,b) only. I would not want (1,a) as 1 is also present in table2.
Start with not exists:
select distinct. . .
from t1
where not exists (select 1 from t2 where t2.a = t1.a and t2.b = t1.b);
From you describe, you might want the comparison only on a:
select distinct a, b
from t1
where not exists (select 1 from t2 where t2.a = t1.a);
Another option is to use sub query in the WHERE condition as below-
SELECT A.*
FROM table1 A
WHERE A.column1 NOT IN
(SELECT DISTINCT column1 FROM table2)
You can also use LEFT JOIN as below which will provide you the same output as below-
SELECT A.*
FROM table1 A
LEFT JOIN table2 B ON A.column1 = B.column1
WHERE B.column1 IS NULL
For the data not include in t2, you can either go for the NOT EXISTS or LEFT OUTER JOIN.
Here is the solution.
Using NOT EXISTS
SELECT DISTINCT A,B FROM T1 WHERE NOT EXISTS (SELECT 1 FROM T2 WHERE T2.A = T1.A AND T2.B = T1.B);
Using Left Join
SELECT DISTINCT a,b,c FROM T1 LEFT JOIN T2 ON T1.a = T2.a and T1.b = T2.b WHERE T2.a IS NULL AND T2.b IS NULL
Hope it helps.
I have two table a and b
table a
ID
a
b
c
table b
ID Value
a 1
b 2
default 0
So I want to join two tables on ID when exactly matching, otherwise use default value
The desired results
ID Value
a 1
b 2
c 0
Use a LEFT OUTER JOIN for that purpose like
select t1.ID, COALESCE(t2.Value, 0) as Value
from tablea t1
left join tableb t2 on t1.ID = t2.ID;
Try this:
SELECT a.ID, b.Value
FROM a
INNER JOIN b
ON a.ID = b.ID
UNION ALL
SELECT a.ID, b.Value
FROM a
CROSS JOIN b
WHERE
a.id <> b.id
This will provide you with all matching IDs, then the UNION of the CROSS JOIN query should provide the default value for non-matching IDs.
Try this:
SELECT t1.ID,
COALESCE(t2.Value, (SELECT Value FROM tableb t3 WHERE ID ='default')) AS Value
FROM tablea t1
LEFT JOIN tableb t2 on t1.ID = t2.ID;
I want the use 2 SELECT statements and an INNER JOIN from different queries BUT also want to show the two different results, from different tables in the same query. Like this..
SELECT column1 FROM earth e1 that is null
+
SELECT chair5 FROM space s1 that is not null
INNER JOIN space s1 ON e1.car = s1.truck
ORDER BY e1.column,s1.chair5
How do I show the results of two different queries while using an INNER JOIN?
Assume the table T1 contains values 'A','B','C' and table T2 contains values 'A','B','D'
You may query
select 'T1' as source, col from t1
union all
select 'T2' as source, col from t2
union all
select 'join T1,T2' as source, t1.col from t1 inner join t2
on t1.col= t2.col
order by 1,2
;
getting
SOURCE COL
---------- -----
T1 A
T1 B
T1 C
T2 A
T2 B
T2 D
join T1,T2 A
join T1,T2 B
The first column identifies the source: single query or a join
Alternatively, which I'll prefer you may get the same information (more compressed) using FULL OUTER JOIN
with fj as (
select t1.col t1_col, t2.col t2_col
from t1 full outer join t2
on t1.col= t2.col
)
select
case when t1_col is not null and t2_col is not null then 'both'
when t1_col is not null then 'T1 only'
when t2_col is not null then 'T2 only' end as source,
nvl(t1_col, t2_col) col
from fj
order by 1,2
.
SOURCE COL
------- ----------
T1 only C
T2 only D
both A
both B
I have two table say T1 and T2 and one column C is common to both. I need an SQL query in which if C is null in T1 it will select from other table.
I tried writing SELECT statement in THEN clause but not running. Don't know is there any IF ELSE clause in SQL.
Select C, case when c = null Then Select c from T2
from T1
Even better, most RDBMSs support COALESCE, which lets you check multiple values and return the first non-null value.
SELECT COALESCE(T1.C, T2.C) AS C
FROM T1
LEFT OUTER JOIN T2 ON T1.[Primary Key] = T2.[Primary Key]
Is this in TransactSQL?
I like the first answer, however you could also do it this way...
select case t1.C
when null then t2.C
else t1.C
end as [testC]
from t1
inner join t2
on t1.PKID = t2.PKID
What you seem to need is a union
select c from t1
where c is not null
union
select c from t2
where c is not null
Now you get all the columns C from T1and T2 in one result set but only if not null.
Well of course if this has simplified your problem too much you need to work with a join
select coalesce(t1.c,t2.c) as c
from t1
left join t2 on (t2.id = t1.foreign_id)
This assumed that T2.ID is the primary key and related to T1 with T1.FOREIGN_ID
It is important that you do a left join because otherwise you only get T1 rows when the row also exists in T2.
Is it possible to write a sql query where you know you have to use the left outer join..but cannot or are not allowed to use the "outer join" Key Word
I have two table sand want to get rows with null vaues from the left table ...this is pretty simple ...but am not supposed to use the key word....outer join....I need to right the logic for outer join myself
SELECT Field1
FROM table1
WHERE id NOT IN (SELECT id FROM table2)
SELECT Field1
FROM table1
WHERE NOT EXISTS (SELECT * FROM table2 where table2.id = table1.id)
This is something people do but it is deprecated and it does not currently work correctly (it sometimes will return a cross join instead of a left join) so it should NOT be used. I'm telling this only so you avoid using this solution.
SELECT Field1
FROM table1, table2 where table1.id *= table2.id
;WITH t1(c,d) AS
(
SELECT 1,'A' UNION ALL
SELECT 2,'B'
),t2(c,e) AS
(
SELECT 1,'C' UNION ALL
SELECT 1,'D' UNION ALL
SELECT 3,'E'
)
SELECT t1.c, t1.d, t2.c, t2.e
FROM t1, t2
WHERE t1.c = t2.c
UNION ALL
SELECT t1.c, t1.d, NULL, NULL
FROM t1
WHERE c NOT IN (SELECT c
FROM t2
WHERE c IS NOT NULL)
Returns
c d c e
----------- ---- ----------- ----
1 A 1 C
1 A 1 D
2 B NULL NULL
(Equivalent to)
SELECT t1.c, t1.d, t2.c, t2.e
FROM t1
LEFT JOIN t2
ON t1.c = t2.c
For SQL Server, you can just use LEFT JOIN - the OUTER is optional, just like INTO in an INSERT statement.
This is the same for all OUTER JOINs.
For an INNER JOIN you can just specify JOIN with no qualifiers and it is interpreted as an INNER JOIN.
This will give you all the rows in table A that don't have a matching row in table B:
SELECT *
FROM A
WHERE NOT EXISTS (
SELECT 1
FROM B
WHERE A.id = B.id
);
Returns all the matching rows from both tables:
SELECT a.*,b.* FROM table_a a, table_b b
WHERE a.key_field = b.key_field
Potential drawback is non-matches will be skipped.