I'm having hard time to differentiate between 'UNIQUEIDENTIFIER' & 'varchar' in a data mapping script. Its a mismatch of data.
I tried this so far:
--my_field is a UNIQUEIDENTFIER
SELECT distinct my_field, len(my_field), count(my_field)
FROM my_table_
WHERE len(my_field) < 36 OR len(my_field) > 36
group by my_field
SELECT my_field, len(my_field)
FROM my_table_
WHERE my_field LIKE '%[!#%&+,./:;<=>#`{|}~"()*\\\_\^\?\[\]\'']%' {ESCAPE '\'}
Any help would be much appreciated.
Assuming your SQL Server version is 2012 or higher (and if not, you really should upgrade, since 2012 is the earliest version still supported by Microsoft) - you can use try_cast - it will return null if the cast fails:
Sample data:
DECLARE #T AS TABLE
(
my_field varchar(100)
)
INSERT INTO #T (my_field) VALUES
('608DC3C3-1B2E-47AA-9362-33CD76DA3F6A'), ('A3871EA9-172D-49DD-8874-A850857F01FB'),
('A3871EA9-THIS-IS-WRONG-A850857F01FB'), ('And so is this')
Query:
SELECT my_field
FROM #T
WHERE TRY_CAST(my_Field AS UNIQUEIDENTIFIER) IS NULL
Result:
my_field
A3871EA9-THIS-IS-WRONG-A850857F01FB
And so is this
Related
There is a table in SQL Server which should contain one column discovery_timewith following values:
1998
1700
Middle Age
1493
Stone Age
I want to make querys like
'SELECT ... WHERE discovery_time > 1800'
Which data type is recommendable?
Use with VarChar():
Create Table #tbl
(
val VarChar(15)
)
Insert into #tbl Values
('1998'),
('1700'),
('Middle Age'),
('1493'),
('Stone Age')
Query
With cte As
(
Select
*,
CASE WHEN TRY_CONVERT(Int, val) IS Not NULL Then val End As yr
From #tbl
)
Select val From cte Where yr > 1800
UPDATE: This will also work..
Select * From #tbl
Where Try_Convert(Int, val) > 1800
Result
val
1998
Well, obviously you cannot store string values in a numeric column, so a string is needed.
One method is to change the logic, more like:
WHERE discovery_time > '1800' and discovery_time < '9999'
Then be sure that the strings are all zero padded. So, '0500' rather than '500'. This will not work for BC.
An alternative is to hide the variables. Here is one method:
create table . . . (
discovery_year int, -- a year
discovery_period varchar(255), -- a period
discovery_time as (coalesce(discovery_period, cast(discovery_year as varchar(255))
);
Then do the logic on discovery_year.
Actually, another method is try_convert():
WHERE TRY_CONVERT(int, discovery_time) > 1800
You can also add this in as a computed column:
alter table t add discovery_year as (try_convert(int, discovery_time));
You just need to remember to use discovery_year in the comparisons.
I have a conundrum....
There is a table with one NVARCHAR(50) Float column that has many rows with many numbers of various decimal lengths:
'3304.063'
'3304.0625'
'39.53'
'39.2'
I need to write a query to find only numbers with decimal places >= 4
First the query I wrote was:
SELECT
Column
FROM Tablename
WHERE Column LIKE '%.[0-9][0-9]%'
The above code finds all numbers with decimal places >= 2:
'3304.063'
'3304.0625'
'39.53'
Perfect! Now, I just need to increase the [0-9] by 2...
SELECT
Column
FROM Tablename
WHERE Column LIKE '%.[0-9][0-9][0-9][0-9]%'
this returned nothing! What?
Does anyone have an explanation as to what went wrong as well and/or a possible solution? I'm kind of stumped and my hunch is that it is some sort of 'LIKE' limitation..
Any help would be appreciated!
Thanks.
After your edit, you stated you are using FLOAT which is an approximate value stored as 4 or 8 bytes, or 7 or 15 digits of precision. The documents explicitly state that not all values in the data type range can be represented exactly. It also states you can use the STR() function when converting it which you'll need to get your formatting right. Here is how:
declare #table table (columnName float)
insert into #table
values
('3304.063'),
('3304.0625'),
('39.53'),
('39.2')
--see the conversion
select * , str(columnName,20,4)
from #table
--now use it in a where clause.
--Return all values where the last digit isn't 0 from STR() the conversion
select *
from #table
where right(str(columnName,20,4),1) != 0
OLD ANSWER
Your LIKE statement would do it, and here is another way just to show they both work.
declare #table table (columnName varchar(64))
insert into #table
values
('3304.063'),
('3304.0625'),
('39.53'),
('39.2')
select *
from #table
where len(right(columnName,len(columnName) - charindex('.',columnName))) >= 4
select *
from #table
where columnName like '%.[0-9][0-9][0-9][0-9]%'
One thing that could be causing this is a space in the number somewhere... since you said the column type was VARCHAR this is a possibility, and could be avoided by storing the value as DECIMAL
declare #table table (columnName varchar(64))
insert into #table
values
('3304.063'),
('3304. 0625'), --notice the space here
('39.53'),
('39.2')
--this would return nothing
select *
from #table
where columnName like '%.[0-9][0-9][0-9][0-9]%'
How to find out if this is the case?
select *
from #table
where columnName like '% %'
Or, anything but numbers and decimals:
select *
from #table
where columnName like '%[^.0-9]%'
The following is working fine for me:
declare #tab table (val varchar(50))
insert into #tab
select '3304.063'
union select '3304.0625'
union select '39.53'
union select '39.2'
select * from #tab
where val like '%.[0-9][0-9][0-9][0-9]%'
Assuming your table only has numerical data, you can cast them to decimal and then compare:
SELECT COLUMN
FROM tablename
WHERE CAST(COLUMN AS DECIMAL(19,4)) <> CAST(COLUMN AS DECIMAL(19,3))
You'd want to test the performance of this against using the character data type solutions that others have already suggested.
You can use REVERSE:
declare #vals table ([Val] nvarchar(50))
insert into #vals values ('3304.063'), ('3304.0625'), ('39.53'), ('39.2')
select [Val]
from #Vals
where charindex('.',reverse([Val]))>4
im using mssql 2008 and Im permanently failing to convert an nvarchar to numeric values.
Can you please advise? I have different solutions I found over the www, but all of them are failing with the error message:
Msg 8114, Level 16, State 5, Line 15 Error converting data type
nvarchar to numeric.
I have built an reduced example for demonstration purpose:
IF OBJECT_ID('tempdb..#temptable', 'U') IS NOT NULL
DROP TABLE dbo.#temptable
create table #temptable(
col1 nvarchar(10),
col2 numeric(10,5)
)
insert into #temptable values ('0,5','0')
select *,convert(numeric(18,2),col1) from #temptable
UPDATE #temptable
SET col2 = CAST(col1 AS numeric(10,5))
WHERE ISNUMERIC(col1) = 1
SELECT col1
, CASE ISNUMERIC(col1)
WHEN 1 THEN CONVERT(numeric(18,2),col1)
ELSE 0.00
END
from #temptable
I alreay found an strong hint whats going wrong... the issue seems to be related to the , as seperator while the SQL server expects an .
if you change the following line to:
insert into #temptable values ('0.5','0')
its working
The problem is you are using ISNUMERIC(col1) = 1 which fails for a ton of cases like ISNUMERIC('1e4') or ISNUMERIC('$') or in your case, ISNUMERIC('1,000,000'). Don't use ISNUMERIC in this fashion.
Instead, try this...
UPDATE #temptable
SET col2 = CAST(col1 AS numeric(10,5))
WHERE col1 not like '%[^0-9.]%'
Use try_convert() in SQL Server 2012+:
UPDATE #temptable
SET col2 = TRY_CONVERT(numeric(10,5), col1)
WHERE ISNUMERIC(col1) = 1;
SQL Server re-arranges expression valuation in a query. So, the CAST() might be implemented before the WHERE -- resulting in the error. You can make a similar change to the SELECT version of your query.
In SQL Server 2008, you should be able to do effectively the same thing using CASE:
UPDATE #temptable
SET col2 = (CASE WHEN ISNUMERIC(col1) = 1 THEN CONVERT(numeric(10, 5), col1) END)
WHERE ISNUMERIC(col1) = 1;
Note: There may be cases where ISNUMERIC() returns "1", but the value cannot be converted (for instance, overflow). In that case, this version would still fail.
I have two table. First table(Table1) use to get the records and second table(Table2) used to insert first table record into it. But I am little bit confused after getting result.
In table 1 and table 2 column "Amount" have same data type i.e nvarchar(max)
Table1
Id Amount
1 Null
2 -89437.43
2 -533.43
3 22403.88
If I run this query
Insert into Table2(Amount)
Select Amount from Table1
Then get result like this, I don't know why values are automatically rounded off
Table2
Id Amount
1 Null
2 -89437.4
2 -533.43
3 22403.9
SQL Server will round float values when converting back and to from string types.
And then you have the fun bits of empty string being 0, as well other strange effects
SELECT CAST(CAST('' AS float) AS nvarchar(MAX))
SELECT CAST(CAST('0.E0' AS float) AS nvarchar(MAX))
Use decimal.
If you need to store "blank" (how does this differ from NULL?) use a separate bit column to allow that extra value
Here is good explanation about your question.
Eigher you explicitly give float or decimal or numeric(xx,x) (x means numeric value)
Then it will convert as the data, other wise it round off the last value.
Insert into Table2(Amount)
Select cast(Amount as numeric(18,2) --or , cast (Amount as float)
from Table1
Check this link:-
TSQL Round up decimal number
In my case I was doing the conversion to the correct data type but had decimal(18,0) for the column in the table. So make sure the decimal places are represented properly for the column decimal(18,2).
Perhaps it's your query tool that's truncating to 8 characters.
Check the actual fields lengths to see if the problem is really in the database:
SELECT LEN(Amount)
FROM Table2
WHERE Amount LIKE '%-89437.%'
Unreproducible. Running this script on SQL Server 2012:
DECLARE #T1 TABLE ([Amount] nvarchar(max) NULL);
DECLARE #T2 TABLE ([Amount] nvarchar(max) NULL);
INSERT INTO #T1 ([Amount])
VALUES (NULL),('-89437.43'),('-533.43'),('22403.88');
Insert into #T2(Amount)
Select Amount from #T1;
SELECT * FROM #T2;
Produces this result:
Amount
NULL
-89437.43
-533.43
22403.88
The problem you describe does not exist.
This will show you the problem:
DECLARE #T1 TABLE ([Amount123456789] money NULL);
DECLARE #T2 TABLE ([Amount123456789] nvarchar(max) NULL);
INSERT INTO #T1 ([Amount123456789])
VALUES (NULL),('-89437.43123'),('-533.43456'),('22403.88789'),(22403.88789);
Insert into #T2(Amount123456789)
Select Amount123456789 from #T1;
SELECT * FROM #T1;
SELECT * FROM #T2;
I need to get a node value in an XML data type column.
<CustomContentData>
<prpIsRSSFeed>false</prpIsRSSFeed>
</CustomContentData>
How is this done in SQL Server?
The column name is ClassXML
Use XQuery, a simple example with your data would be:
DECLARE #T TABLE (ClassXML XML);
INSERT #T (ClassXML)
VALUES ('<CustomContentData>
<prpIsRSSFeed>false</prpIsRSSFeed>
</CustomContentData>');
SELECT t.ClassXML.value('CustomContentData[1]/prpIsRSSFeed[1]', 'VARCHAR(5)')
FROM #T AS t;
If the column is already XML data type in SQL Server, then the code below should work by using the value function with XPATH. If it's stored as a varchar, you'd just need to replace ClassXML.value with CONVERT(XML, ClassXML).value. Hope this helps!
DECLARE #Data TABLE (ClassXML XML)
INSERT #Data VALUES ('<CustomContentData><prpIsRSSFeed>false</prpIsRSSFeed></CustomContentData>')
SELECT
CONVERT(BIT, CASE WHEN ClassXML.value ('(/CustomContentData/prpIsRSSFeed)[1]',
'VARCHAR(50)') = 'true' THEN 1 ELSE 0 END) AS IsRssFeed
FROM #Data
Yields output
IsRssFeed
---------
0