I am trying to transpose rows to columns but I didn't find any good answers.
Here is an example of what I want:
Input tables:
TABLE A
ID | NAME
1 | BOB
2 | JIM
3 | ROB
TABLE B
ID | CLUB
1 | 2
1 | 3
1 | 4
2 | 2
2 | 1
3 | 5
OUTPUT will be:
ID | CLUB1 | CLUB2 | CLUB3
1 | 2 | 3 | 4
2 | 2 | 1 |
3 | 5 | |
You need to enumerate the values to pivot them:
select id,
max(case when seqnum = 1 then club end) as club_1,
max(case when seqnum = 2 then club end) as club_2,
max(case when seqnum = 3 then club end) as club_3
from (select b.*,
row_number() over (partition by id order by club) as seqnum
from b
) b
group by id;
use conditional aggregation
select id,
max(case when id=1 then club end) club1,
max(case when id=2 then club end) club2,
max(case when id=3 then club end) club3
from tablename
group by id
use case when
select a.id,max(case when name='BOB' then CLUB end) ,
max(case when name='JIM' then CLUB end),
max(case when name='ROB' then CLUB end)
tablea a join tableb b on a.id=b.id group by a.id
Sample Data
IF OBJECT_ID('tempdb..#TempTab')IS NOT NULL
DROP TABLE #TempTab
;WITH CTE (ID,CLUB)
AS
(
SELECT 1 , 2 UNION ALL
SELECT 1 , 3 UNION ALL
SELECT 1 , 4 UNION ALL
SELECT 2 , 2 UNION ALL
SELECT 2 , 1 UNION ALL
SELECT 3 , 5
)
SELECT ID,
CLUB,
'CLUB'+CAST(ROW_NUMBER()OVER(PARTITION BY ID ORDER BY ID) AS VARCHAR) AS CLUBData
INTO #TempTab
FROM CTE
Dynamic sql
DECLARE #Column nvarchar(1000),#Column2 nvarchar(max),
#Sql nvarchar(max)
SELECT #Column =STUFF((SELECT DISTINCT ', '+QUOTENAME(CLUBData)
FROM #TempTab FOR XML PATH ('')),1,1,'')
SET #Sql = 'SELECT Id,'+#Column +'
FROM
(
SELECT * FROM #TempTab
) AS SRc
PIVOT
(
MAX(CLUB) FOR CLUBData IN ('+#Column+')
) AS pvt
'
PRINT #Sql
EXEC (#Sql)
Result
Id CLUB1 CLUB2 CLUB3
-------------------------
1 3 4 2
2 1 2 NULL
3 5 NULL NULL
Related
I have the table structure below,
I need to merge the CouponNumber to two equal as CouponNumber1 and CouponNumber2 as shown in the figure
SELECT Name, MobileNumber, CouponNumber, IsDispatched, Status
FROM CouponInvoicePrescription
This is my query.
Try this:
WITH
input(ord,name,mobno,couponno,isdispatched,status) AS (
SELECT 0,'amar',8888888888,'CPever901',FALSE,1
UNION ALL SELECT 1,'amar',8888888888,'CP00005' ,FALSE,1
UNION ALL SELECT 2,'pt3' ,7777777777,'cp9090' ,FALSE,1
UNION ALL SELECT 3,'pt3' ,7777777777,'ev2' ,FALSE,1
UNION ALL SELECT 4,'pt3' ,7777777777,'cp9909' ,FALSE,1
UNION ALL SELECT 5,'pt3' ,7777777777,'cp10' ,FALSE,1
)
SELECT
name
, MAX(CASE ord % 2 WHEN 1 THEN couponno END) AS couponno1
, MAX(CASE ord % 2 WHEN 0 THEN couponno END) AS couponno2
, isdispatched
, status
FROM input
GROUP BY
ord / 2
, name
, isdispatched
, status
ORDER BY 1
-- out name | couponno1 | couponno2 | isdispatched | status
-- out ------+-----------+-----------+--------------+--------
-- out amar | CP00005 | CPever901 | f | 1
-- out pt3 | cp10 | cp9909 | f | 1
-- out pt3 | ev2 | cp9090 | f | 1
Try this:
SELECT * FROM
(
SELECT
sub.rn,
sub.Name,
sub.MobileNumber,
sub.CouponNumber as CouponNumber1,
LEAD(sub.CouponNumber,1) OVER (PARTITION BY sub.MobileNumber ORDER BY sub.rn) as CouponNumber2,
sub.IsDispatched,
sub.Status
FROM
(
SELECT
ROW_NUMBER() OVER (PARTITION by MobileNumber ORDER BY Name) as rn,
*
FROM
input
) sub
)
WHERE rn % 2 <> 0
I am using DB Browser for SQLite. I have a table in the following format:
+-----------+-------------------------------------+
| search_id | search_town |
+-----------+-------------------------------------+
| 1 | town1,town3 |
| 2 | town2,town4,town5 |
| 3 | town3,town5 |
| 4 | town2,town5 |
| 5 | town2,town3,town4 |
+-----------+-------------------------------------+
I would like to do a COUNT on the number of times town1 through town5 has appeared under search_town, and then rank in descending order the towns based on their respective counts. So far I have the following query:
SELECT SUM(CASE WHEN search_location LIKE '%town01%' THEN 1 ELSE 0 END) AS town01,
SUM(CASE WHEN search_location LIKE '%town02%' THEN 1 ELSE 0 END) AS town02,
SUM(CASE WHEN search_location LIKE '%town03%' THEN 1 ELSE 0 END) AS town03,
SUM(CASE WHEN search_location LIKE '%town04%' THEN 1 ELSE 0 END) AS town04,
SUM(CASE WHEN search_location LIKE '%town05%' THEN 1 ELSE 0 END) AS town05
FROM searches
...but am unable to do an ORDER BY as the towns and their counts are output as columns instead of rows in this format
+-------+-------+-------+-------+-------+
| town1 | town2 | town3 | town4 | town5 |
+-------+-------+-------+-------+-------+
| 12 | 31 | 12 | 24 | 12 |
+-------+-------+-------+-------+-------+
Is there another approach to this? Appreciate any comments.
You are turning your output in a single row using CASE WHEN, to convert it into multiple rows, you can try like following.
;WITH cte
AS (SELECT *
FROM (VALUES ('Town1'),
('Town2'),
('Town3'),
('Town4'),
('Town5')) T(town))
SELECT Count(*) [Count],
C.town
FROM [TABLE_NAME] T
INNER JOIN cte C
ON T.search_location LIKE '%' + C.town + '%'
GROUP BY C.town
ORDER BY Count(*) DESC
Online DEMO
Another approach can be using UNION ALL.
SELECT *
FROM (SELECT Count(*) s,
'Town1' AS Col
FROM tablename
WHERE search_location LIKE '%town1%'
UNION ALL
SELECT Count(*) s,
'Town2' AS Col
FROM tablename
WHERE search_location LIKE '%town2%'
UNION ALL
SELECT Count(*) s,
'Town3' AS Col
FROM tablename
WHERE search_location LIKE '%town3%'
UNION ALL
SELECT Count(*) s,
'Town4' AS Col
FROM tablename
WHERE search_location LIKE '%town4%'
UNION ALL
SELECT Count(*) s,
'Town5' AS Col
FROM tablename
WHERE search_location LIKE '%town5%') t
ORDER BY s DESC
You can use a recursive common-table expression (CTE) to turn the comma-separated list into a set of rows. When the table is normalized, you can group by town and sort by descending count:
WITH rec(town, remain)
AS (
SELECT SUBSTR(search_town, 0, INSTR(search_town, ',')) -- Before ,
, SUBSTR(search_town, INSTR(search_town, ',')+1) || ',' -- After ,
FROM t1
UNION ALL
SELECT SUBSTR(remain, 0, INSTR(remain, ',')) -- Before ,
, SUBSTR(remain, INSTR(remain, ',')+1) -- After ,
FROM rec
WHERE LENGTH(remain) > 0
)
SELECT town
, COUNT(*)
FROM rec
GROUP BY
town
ORDER BY
COUNT(*) DESC
Idea from this blog post. Working example at sqliteonline.
I currently run the query
SELECT [PriceAttributeID]
,[PriceID]
,[AttributeID]
,[PriceAttributeComparator]
,[PriceAttributeMin]
,[PriceAttributeMax]
FROM [PriceAttribute]
Which gives the output
1 2 1 1 S NULL
2 3 1 1 M NULL
3 4 1 1 L NULL
4 5 1 1 L NULL
5 5 2 1 Black NULL
I would like to get the output (where _Comp, _Min and _Max relate to PriceAttributeComparator, PriceAttributeMin and PriceAttributeMax)
PriceID 1_Comp 1_Min 1_Max 2_Comp 2_Min 2_Max
2 1 S NULL NULL NULL NULL
3 1 M NULL NULL NULL NULL
4 1 L NULL NULL NULL NULL
5 1 L NULL 1 Black NULL
The same query would also be expected to have 1_ and 2_ prefixes as 4_, 5_, 19_ and 32_ or any other indeterminate number of ID's based on what is in the table at the time.
I have attempted a PIVOT table, but i am new to them and haven't the first clue on how to create what it is i am looking to do.
Part of the problem you are probably having with the PIVOT function is due to the fact you have multiple columns that you want to apply the function to. If you want to use the PIVOT function, then I would suggest first unpivoting the columns PriceAttributeComparator, PriceAttributeMin and PriceAttributeMax. When you unpivot the data you will no longer have multiple columns, you will have multiple rows, then you can apply the pivot to all of the appropriate values.
You did not specify what version of SQL Server you are using but you can use CROSS APPLY with a UNION ALL to unpivot the columns:
select priceid,
col = cast(attributeid as varchar(10))+'_'+ col,
value
from
(
select PriceID,
AttributeID,
comp = cast(PriceAttributeComparator as varchar(10)),
[min] = cast(PriceAttributeMin as varchar(10)),
[max] = cast(PriceAttributeMax as varchar(10))
from PriceAttribute
) d
cross apply
(
select 'comp', comp union all
select 'min', [min] union all
select 'max', [max]
) c (col, value)
See Demo. This process will convert your data into the following format:
| PRICEID | COL | VALUE |
-----------------------------
| 2 | 1_comp | 1 |
| 2 | 1_min | S |
| 2 | 1_max | (null) |
| 3 | 1_comp | 1 |
| 3 | 1_min | M |
| 3 | 1_max | (null) |
Once the data is in multiple rows, then you can apply the PIVOT function to the values in col:
select priceid,
[1_comp], [1_min], [1_max], [2_comp], [2_min], [2_max]
from
(
select priceid,
col = cast(attributeid as varchar(10))+'_'+ col,
value
from
(
select PriceID,
AttributeID,
comp = cast(PriceAttributeComparator as varchar(10)),
[min] = cast(PriceAttributeMin as varchar(10)),
[max] = cast(PriceAttributeMax as varchar(10))
from PriceAttribute
) d
cross apply
(
select 'comp', comp union all
select 'min', [min] union all
select 'max', [max]
) c (col, value)
) src
pivot
(
max(value)
for col in ([1_comp], [1_min], [1_max], [2_comp], [2_min], [2_max])
) piv;
See SQL Fiddle with Demo.
The above versions work great if you have a known number of values but if the values are unknown, then you will need to use dynamic SQL to get the result:
DECLARE #cols AS NVARCHAR(MAX),
#query AS NVARCHAR(MAX)
select #cols = STUFF((SELECT ',' + QUOTENAME(cast(attributeid as varchar(10))+'_'+ col)
from
(
select distinct attributeid
from priceattribute
) d
cross apply
(
select 'comp', 1 union all
select 'min', 2 union all
select 'max', 3
) c (col, so)
group by attributeid, col, so
order by attributeid, so
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set #query = 'SELECT priceid, ' + #cols + '
from
(
select priceid,
col = cast(attributeid as varchar(10))+''_''+ col,
value
from
(
select PriceID,
AttributeID,
comp = cast(PriceAttributeComparator as varchar(10)),
[min] = cast(PriceAttributeMin as varchar(10)),
[max] = cast(PriceAttributeMax as varchar(10))
from PriceAttribute
) d
cross apply
(
select ''comp'', comp union all
select ''min'', [min] union all
select ''max'', [max]
) c (col, value)
) x
pivot
(
max(value)
for col in (' + #cols + ')
) p '
execute sp_executesql #query;
See SQL Fiddle with Demo. These solutions will give a result:
| PRICEID | 1_COMP | 1_MIN | 1_MAX | 2_COMP | 2_MIN | 2_MAX |
----------------------------------------------------------------
| 2 | 1 | S | (null) | (null) | (null) | (null) |
| 3 | 1 | M | (null) | (null) | (null) | (null) |
| 4 | 1 | L | (null) | (null) | (null) | (null) |
| 5 | 1 | L | (null) | 1 | Black | (null) |
It might be simplest to do this using conditional aggregation rather than pivot:
SELECT PriceID,
max(case when AttributeID = 1 then PriceAttributeComparator end) as comp_1,
max(case when AttributeID = 1 then PriceAttributeMin end) as min_1,
max(case when AttributeID = 1 then PriceAttributeMax end) as max_1,
max(case when AttributeID = 2 then PriceAttributeComparator end) as comp_2,
max(case when AttributeID = 2 then PriceAttributeMin end) as min_2,
max(case when AttributeID = 2 then PriceAttributeMax end) as max_2
FROM PriceAttribute pa
group by PriceId;
I have a table in my database with the following structure.
ID COMPANY_ID Status
-----------------------
1 10 1
2 10 2
3 12 2
4 12 2
5 12 1
6 13 3
7 14 3
8 14 3
9 10 1
10 10 2
I want to group my results on company ID and count each status and list them as separate columns.
i.e.
COMPANY_ID Status 1 Status 2 Status 3
-------------------------------------------
10 2 2 0
12 1 2 0
13 0 0 1
14 0 0 2
My question is how do I get the results above from my table? and probably join in with the company table.
Tried several possibilities, but didn't get the results.
select company_id
, count(case when status = 1 then 1 end) as [Status 1]
, count(case when status = 2 then 1 end) as [Status 2]
, count(case when status = 3 then 1 end) as [Status 3]
from YourTable
group by
company_id
This type of data transformation is known as a PIVOT. There are several ways that you are pivot the data.
You can use an aggregate function with a CASE expression:
select company_id,
sum(case when status = 1 then 1 else 0 end) status1,
sum(case when status = 2 then 1 else 0 end) status2,
sum(case when status = 3 then 1 else 0 end) status3
from yourtable
group by company_id;
See SQL Fiddle with Demo
Starting in SQL Server 2005+ you can use the PIVOT function:
select company_id,
[1] as Status1,
[2] as Status2,
[3] as Status3
from
(
select company_id, status
from yourtable
)src
pivot
(
count(status)
for status in ([1], [2], [3])
) piv
See SQL Fiddle with Demo.
The two versions above work well if you have a known number of values to transform into columns. But if it is unknown, then you can use dynamic SQL to generate the result:
DECLARE #cols AS NVARCHAR(MAX),
#query AS NVARCHAR(MAX)
select #cols = STUFF((SELECT distinct ',' + QUOTENAME('Status'+cast(status as varchar(10)))
from yourtable
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set #query = 'SELECT company_id,' + #cols + ' from
(
select company_id, ''Status''+cast(status as varchar(10)) Status
from yourtable
) x
pivot
(
count(Status)
for Status in (' + #cols + ')
) p '
execute(#query)
See SQL Fiddle with Demo.
All give the result:
| COMPANY_ID | STATUS1 | STATUS2 | STATUS3 |
--------------------------------------------
| 10 | 2 | 2 | 0 |
| 12 | 1 | 2 | 0 |
| 13 | 0 | 0 | 1 |
| 14 | 0 | 0 | 2 |
Have a temp table with schema: ID | SeqNo | Name
ID - Not unique
SeqNo - Int (can be 1,2 or 3). Sort of ID+SeqNo as Primary key
Name - Any text
And sample data in the table like this
1 | 1 | RecordA
2 | 1 | RecordB
3 | 1 | RecordC
1 | 2 | RecordD
4 | 1 | RecordE
5 | 1 | RecordF
3 | 1 | RecordG
Need to select from this table and output like
1 | RecordA/RecordD
2 | RecordB
3 | RecordC/RecordG
4 | RecordE
5 | RecordF
Need to do this without cursor.
If SeqNo is limited to 1,2,3:
select id, a.name + coalesce('/'+b.name, '') + coalesce('/'+c.name, '')
from myTable a
left outer join myTable b on a.id=b.id and b.seqno = 2
left outer join myTable c on a.id=c.id and c.seqno = 3
where a.seqno = 1;
If SeqNo is open ended you can deploy a recursive cte:
;with anchor as (
select id, name, seqno
from myTable
where seqno=1)
, recursive as (
select id, name, seqno
from anchor
union all
select t.id, r.name + '/' + t.name, t.seqno
from myTable t
join recursive r on t.id = r.id and r.seqno+1 = t.seqno)
select id, name from recursive;
If you know SeqNo will never be more than 3:
select Id, Names = stuff(
max(case when SeqNo = 1 then '/'+Name else '' end)
+ max(case when SeqNo = 2 then '/'+Name else '' end)
+ max(case when SeqNo = 3 then '/'+Name else '' end)
, 1, 1, '')
from table1
group by Id
Otherwise, something like this is the generic solution to an arbitrary number of items:
select Id, Names = stuff((
select '/'+Name from table1 b
where a.Id = b.Id order by SeqNo
for xml path (''))
, 1, 1, '')
from table1 a
group by Id
Or write a CLR UDA.
Edit: had the wrong alias on the correlated table!
Edit2: another version, based on Remus's recursion example. I couldn't think of any way to select only the last recursion per Id, without aggregation or sorting. Anybody know?
;with
myTable as (
select * from (
values
(1, 1, 'RecordA')
, (2, 1, 'RecordB')
, (3, 1, 'RecordC')
, (1, 2, 'RecordD')
, (4, 1, 'RecordE')
, (5, 1, 'RecordF')
, (3, 2, 'RecordG')
) a (Id, SeqNo, Name)
)
, anchor as (
select id, name = convert(varchar(max),name), seqno
from myTable where seqno=1
)
, recursive as (
select id, name, seqno
from anchor
union all
select t.id, r.name + '/' + t.name, t.seqno
from myTable t
join recursive r on t.id = r.id and r.seqno+1 = t.seqno
)
select id, name = max(name)
from recursive
group by id;
---- without aggregation, we get 7 rows:
--select id, name
--from recursive;
The solution is good. I have a similar issue, but here I am using 2 different tables. ex:
table1
1 | 1 |
2 | 3 |
3 | 1 |
4 | 2 |
5 | 1 |
1 | 2 |
1 | 3 |
4 | 1 |
5 | 2 |
2 | 2 |
4 | 3 |
table2
1 | RecordA
2 | RecordB
3 | RecordC
I want to get the data from two tables and display in the below format.
1 | RecordA,RecordB,RecordC|
2 | RecordB,RecordC|
3 | RecordA |
4 | RecordA,RecordB,RecordC|
5 | RecordA,RecordB |