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Here it is, I already use two queries but it doesn't seems to work the right way, I should view the latest PREV_BAL "5490"
in you query use order by desc for both columns
row_number() over(partition by tenant_id order by date desc ,time_p desc) rn
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How can I remove the duplicate rows? I have joined two tables now I'm getting duplicate data.
In addition to previous comments, a little bit more complex answer will be construction with PARTITION and ROW_NUMBER
select * from (select *, row_number() over (partition by <duplicate_field> order by <duplicate_field>) as rn from <table>) where rn=1
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From the above table, I want to remove the rows that have the duplicate CODE column. Out of the duplicate rows, the row with the smallest ID_CHECK should be retained.
Output:
If I understand correctly, this should be your SQL query:
Select Names, Code, ID_CHECK
FROM
(
Select Names, Code, ID_CHECK,
ROW_NUMBER() OVER(Partition by Name,Code Order By ID_CHECK) as rnk
FROM table
)tmp
WHERE tmp.rnk=1;
Let me know if this works.
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In SQL how we will write a query that selects all events ordered by a particular customer. Kindly help me there.
Thanks
The table's name is events?...
Select * from events order by custumers asc
if not
select events from Table order by custumers asc
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I have ORDER Table in which I am saving Orders date wise.
Now I want total number of orders placed on specific date
How to do that
Pls Help...
Try this:-
SELECT COUNT(*)
FROM TABLE_NAME
WHERE DATE_COL = 'YOUR_DATE'
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I have a table and I want to display the 3 names (Ted, Ringo, Paul) that have the most records using an SQL query.
It's a primitive question, but please help me.
my table:
SELECT TOP 3 Name
FROM YourTable
GROUP BY Name
ORDER BY COUNT(*) DESC