How to make dual table with many rows in one col? - sql

I tried to do so, but it returns me in columns not rows
SELECT 386 ,417,420,421,422,423 ... from dual


Try this:
select column_value col1 from
table(sys.odcinumberlist((386) ,(417),(420),(421),(422),(423)))


use union all
SELECT 386 from dual
union all
SELECT 417 from dual
union all
SELECT 420 from dual
union all
SELECT 386 from dual


You can use UNION or UNION ALL as a work around to get the desired output.
SELECT 386 from dual
UNION ALL
SELECT 417 from dual
UNION ALL
SELECT 420 from dual
...

Related

Union all of 200 select statements failing to even execute. No error thrown. Limitation of number of select statements in union all?

Because of the limitations we have in Amazon Redhshift SQL (which is based on PostgreSQL 8.0.2). I am forced to execute the following query for some other complex query purposes:
create temporary table NS AS (
select 1 as n union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6 union all
select 7 union all
select 8 union all
select 9 union all
select 10 union all
select 11 union all
select 12 union all
select 13 union all
select 14 union all
select 15 union all
select 16 union all
select 17 union all
select 18 union all
select 19 union all
select 20 union all
select 21 union all
select 22 union all
select 23 union all
select 24 union all
select 25 union all
select 26 union all
select 27 union all
select 28 union all
select 29 union all
select 30 union all
select 31 union all
select 32 union all
select 33 union all
select 34 union all
select 35 union all
select 36 union all
select 37 union all
select 38 union all
select 39 union all
select 40 union all
select 41 union all
select 42 union all
select 43 union all
select 44 union all
select 45 union all
select 46 union all
select 47 union all
select 48 union all
select 49 union all
select 50 union all
select 51 union all
select 52 union all
select 53 union all
select 54 union all
select 55 union all
select 56 union all
select 57 union all
select 58 union all
select 59 union all
select 60 union all
select 61 union all
select 62 union all
select 63 union all
select 64 union all
select 65 union all
select 66 union all
select 67 union all
select 68 union all
select 69 union all
select 70 union all
select 71 union all
select 72 union all
select 73 union all
select 74 union all
select 75 union all
select 76 union all
select 77 union all
select 78 union all
select 79 union all
select 80 union all
select 81 union all
select 82 union all
select 83 union all
select 84 union all
select 85 union all
select 86 union all
select 87 union all
select 88 union all
select 89 union all
select 90 union all
select 91 union all
select 92 union all
select 93 union all
select 94 union all
select 95 union all
select 96 union all
select 97 union all
select 98 union all
select 99 union all
select 100 union all
select 101 union all
select 102 union all
select 103 union all
select 104 union all
select 105 union all
select 106 union all
select 107 union all
select 108 union all
select 109 union all
select 110 union all
select 111 union all
select 112 union all
select 113 union all
select 114 union all
select 115 union all
select 116 union all
select 117 union all
select 118 union all
select 119 union all
select 120 union all
select 121 union all
select 122 union all
select 123 union all
select 124 union all
select 125 union all
select 126 union all
select 127 union all
select 128 union all
select 129 union all
select 130 union all
select 131 union all
select 132 union all
select 133 union all
select 134 union all
select 135 union all
select 136 union all
select 137 union all
select 138 union all
select 139 union all
select 140 union all
select 141 union all
select 142 union all
select 143 union all
select 144 union all
select 145 union all
select 146 union all
select 147 union all
select 148 union all
select 149 union all
select 150 union all
select 151 union all
select 152 union all
select 153 union all
select 154 union all
select 155 union all
select 156 union all
select 157 union all
select 158 union all
select 159 union all
select 160 union all
select 161 union all
select 162 union all
select 163 union all
select 164 union all
select 165 union all
select 166 union all
select 167 union all
select 168 union all
select 169 union all
select 170 union all
select 171 union all
select 172 union all
select 173 union all
select 174 union all
select 175 union all
select 176 union all
select 177 union all
select 178 union all
select 179 union all
select 180 union all
select 181 union all
select 182 union all
select 183 union all
select 184 union all
select 185 union all
select 186 union all
select 187 union all
select 188 union all
select 189 union all
select 190 union all
select 191 union all
select 192 union all
select 193 union all
select 194 union all
select 195 union all
select 196 union all
select 197 union all
select 198 union all
select 199 union all
select 200
);
But this executed only once, later it even failed to even execute without throwing any error in all three mediums I'm trying. i.e. SQL Workbech, Amazon Hubble and Amazon ETL Manager. So, this simple query executing only sporadically with most of the time not executing. Can you please let me know if there is a limitaiton in the number of select statements that we can union? If yes, why it is even not throwing an error?
Thanks.

How about this way using generate_series() without using 200 unions?
CREATE TEMP TABLE NS AS SELECT * FROM generate_series(1, 200)

how can to_char with zero before number in oracle

I have database like below:
WITH TB AS(
SELECT 1 NONB FROM DUAL UNION ALL
SELECT 89 NONB FROM DUAL UNION ALL
SELECT 193 NONB FROM DUAL
)
SELECT * FROM TB
I want change column NONB to_char(NONB) and display zero before the number like below.
001
089
189
How can I do this? Thanks.

Use lpad():
select lpad(nonb, 3, '0')
from tb;
Here is a rextester.

Use this:
WITH TB AS(
SELECT 1 NONB FROM DUAL UNION ALL
SELECT 89 NONB FROM DUAL UNION ALL
SELECT 193 NONB FROM DUAL
)
SELECT to_char(nonb, 'FM000') FROM TB

Optimize Group by Hour Query

Please help to optimize my query. It looks too bulky.
I guess there is a better way to work with hours (datetime) in sql
There is a table dauditnew that is populated and population datetime is stored inside auditdate column.
Query returns rows count by hour.
SELECT t.Hour, COUNT(t.Hour) as Count FROM dauditnew d,
(SELECT 0 as Hour FROM DUAL UNION
SELECT 1 FROM DUAL UNION
SELECT 2 FROM DUAL UNION
SELECT 3 FROM DUAL UNION
SELECT 4 FROM DUAL UNION
SELECT 5 FROM DUAL UNION
SELECT 6 FROM DUAL UNION
SELECT 7 FROM DUAL UNION
SELECT 8 FROM DUAL UNION
SELECT 9 FROM DUAL UNION
SELECT 10 FROM DUAL UNION
SELECT 11 FROM DUAL UNION
SELECT 12 FROM DUAL UNION
SELECT 13 FROM DUAL UNION
SELECT 14 FROM DUAL UNION
SELECT 15 FROM DUAL UNION
SELECT 16 FROM DUAL UNION
SELECT 17 FROM DUAL UNION
SELECT 18 FROM DUAL UNION
SELECT 19 FROM DUAL UNION
SELECT 20 FROM DUAL UNION
SELECT 21 FROM DUAL UNION
SELECT 22 FROM DUAL UNION
SELECT 23 FROM DUAL) t
where
d.auditdate >= TO_DATE('25.04.2017 ' || t.Hour, 'dd.mm.yyyy HH24') and
d.auditdate <= TO_DATE('25.04.2017 ' || t.Hour || '_59_59', 'dd.mm.yyyy HH24_MI_SS')
group by t.Hour

You want to start with something like this:
select trunc(d.auditdate, 'HH24') as hh, count(*)
from dauditnew d
where d.auditdate >= '2017-04-25' and d.auditdate < '2017-04-26'
group by trunc(d.auditdate, 'HH24')
order by hh;
If this misses hours, then you can use a left join with this as a subquery.

Oracle hierarchy query

Scoured the interwebs for a few days looking for a solution to this hierarchy riddle but no luck. All solutions I've found have either a row with parent ID null, have only one ultimate parent, or I'm just missing some piece of knowledge that's preventing me from adapting the solutions for the various needs out there to fit my need.
Data appears like so:
SELECT 3225 PARENT_ID,'TYPE2_A' PARENT,3227 CHILD_ID,'TYPE2_C' CHILD FROM DUAL UNION ALL
SELECT 148,'TYPE2_H',150,'TYPE2_G' FROM DUAL UNION ALL
SELECT 3225,'TYPE2_A',3226,'TYPE2_B' FROM DUAL UNION ALL
SELECT 3227,'TYPE2_C',3222,'TYPE3_E' FROM DUAL UNION ALL
SELECT 3220,'TYPE3_D',3221,'TYPE3_I' FROM DUAL UNION ALL
SELECT 3226,'TYPE2_B',3220,'TYPE3_D' FROM DUAL UNION ALL
SELECT 2379,'TYPE1_K',148,'TYPE2_H' FROM DUAL UNION ALL
SELECT 113,'TYPE1_L',91,'TYPE3_F' FROM DUAL UNION ALL
SELECT 148,'TYPE2_H',128,'TYPE3_N' FROM DUAL UNION ALL
SELECT 3223,'TYPE1_J',3226,'TYPE2_B' FROM DUAL UNION ALL
SELECT 2379,'TYPE1_K',150,'TYPE2_G' FROM DUAL UNION ALL
SELECT 150,'TYPE2_G',91,'TYPE3_F' FROM DUAL UNION ALL
SELECT 2487,'TYPE1_A',3225,'TYPE2_A' FROM DUAL UNION ALL
SELECT 98,'TYPE1_M',91,'TYPE3_F' FROM DUAL;
TYPE1 can never be a child, it's always a parent.
TYPE1 can be a parent of either TYPE2 or TYPE3.
TYPE2 can be a parent of either TYPE2 or TYPE3.
TYPE2 can never be a child of TYPE3.
TYPE3 can be a parent of TYPE3.
TYPE2 and TYPE3 always have at least one TYPE1 ultimate parent but can have more than one TYPE1 parent.
The goal of the query is to take a distinct list of all TYPE2 and TYPE3 children like so...
SELECT PARENT FROM
(query from above)
WHERE PARENT LIKE 'TYPE2%' OR PARENT LIKE 'TYPE3%'
UNION
SELECT CHILD FROM
(query from above)
WHERE CHILD LIKE 'TYPE2%' OR CHILD LIKE 'TYPE3%';
...and find who their ultimate TYPE1 parent(s) is.
For example, based on the data set above...
TYPE3_F has ultimate parents TYPE1_L and TYPE1_M
TYPE3_E has ultimate parent TYPE1_A
TYPE2_B has ultimate parents TYPE1_A and TYPE1_J
The result set for inputs TYPE3_F, TYPE3_E, and TYPE2_B would appear like...
Child Ultimate_Parent
TYPE3_F TYPE1_L
TYPE3_F TYPE1_M
TYPE3_E TYPE1_A
TYPE2_B TYPE1_A
TYPE2_B TYPE1_J

I'm using the connect_by_root function to obtain the parent at the highest level, no matter where in the tree you started.
with parent_child_data
as
(SELECT 2487 PARENT_ID,'TYPE1_A' PARENT, 3225 CHILD_ID,'TYPE2_A' CHILD FROM DUAL UNION ALL
SELECT 3225 ,'TYPE2_A', 3226 ,'TYPE2_B' FROM DUAL UNION ALL
SELECT 3225 ,'TYPE2_A', 3227 ,'TYPE2_C' FROM DUAL UNION ALL
SELECT 3226 ,'TYPE2_B', 3220 ,'TYPE3_D' FROM DUAL UNION ALL
SELECT 3227 ,'TYPE2_C', 3222 ,'TYPE3_E' FROM DUAL UNION ALL
SELECT 113 ,'TYPE1_L', 91 ,'TYPE3_F' FROM DUAL UNION ALL
SELECT 98 ,'TYPE1_M', 91 ,'TYPE3_F' FROM DUAL UNION ALL
SELECT 2379 ,'TYPE1_K', 150 ,'TYPE2_G' FROM DUAL UNION ALL
SELECT 2379 ,'TYPE1_K', 148 ,'TYPE2_H' FROM DUAL UNION ALL
SELECT 150 ,'TYPE2_G', 1291 ,'TYPE3_F' FROM DUAL UNION ALL
SELECT 148 ,'TYPE2_H', 150 ,'TYPE2_G' FROM DUAL UNION ALL
SELECT 148 ,'TYPE2_H', 128 ,'TYPE3_N' FROM DUAL UNION ALL
SELECT 150 ,'TYPE2_G', 1291 ,'TYPE3_F' FROM DUAL UNION ALL
SELECT 3220 ,'TYPE3_D', 3221 ,'TYPE3_I' FROM DUAL UNION ALL
SELECT 3226 ,'TYPE2_B', 3220 ,'TYPE3_D' FROM DUAL UNION ALL
SELECT 3223 ,'TYPE1_J', 3226 ,'TYPE2_B' FROM DUAL UNION ALL
SELECT 3225 ,'TYPE2_A', 3226 ,'TYPE2_B' FROM DUAL UNION ALL
SELECT 2487 ,'TYPE1_A', 3225 ,'TYPE2_A' FROM DUAL)
select * from (
select d.child_id, d.child, d.parent_id, d.parent, connect_by_root d.parent ultimate_parent
from parent_child_data d
where child like 'TYPE3%' or child like 'TYPE2%'
connect by prior child_id = parent_id)
where ultimate_parent like 'TYPE1%'
;

How to insert multimple records of numbers with one statement in ORACLE and Sql-server using the same sentence

In my C++ program I tried something like this:
INSERT INTO TEMP_TABELA (OSE_ID) values (7,12,16,17,19,21,24,26,30,33,35,38,42,46,53,58,59,72,73,74,77,78,82,86,87,88,89,91,92,93,100,101,102,104,106,109,113,115,127,133,139,140,142,143,144,148,149,150,151,153,155,160,164,166,167,170,172,178,188,189,191,192,198,199,200,201,202,203,205,207,208,219,220,223,225,231,233,236,240,241,242,244,245,253);
But all I got was:
Description: There are fewer columns in the INSERT statement than values specified in the VALUES clause. The number of values in the VALUES clause must match the number of columns specified in the INSERT statement.
Source: Microsoft OLE DB Provider for SQL Server
The same sentence must work also on Oracle, because my program works for both.
Can anyone help me?

Oracle's and SQL Server's bulk insertion syntax is different from one another, so the safest means is to use individual INSERT statements:
INSERT INTO TEMP_TABELA (OSE_ID) values (7);
INSERT INTO TEMP_TABELA (OSE_ID) values (12);
INSERT INTO TEMP_TABELA (OSE_ID) values (16);
INSERT INTO TEMP_TABELA (OSE_ID) values (17);
...
INSERT INTO TEMP_TABELA (OSE_ID) values (253);

This works in Oracle, it split's on the string (assuming 10g+)
CREATE TABLE TESTX(NUM NUMBER);
INSERT INTO TESTX(NUM)
select regexp_substr (x, '[^,]+', 1, level) as token
from (SELECT '7,12,16,17,19,21,24,26,30,33,35,38,42,46,53,58,59,72,73,74,77,78,82,86,87,88,89,91,92,93,100,101,102,104,106,109,113,115,127,133,139,140,142,143,144,148,149,150,151,153,155,160,164,166,167,170,172,178,188,189,191,192,198,199,200,201,202,203,205,207,208,219,220,223,225,231,233,236,240,241,242,244,245,253' X FROM DUAL) t
connect by regexp_instr (x, '[^,]+', 1, level) > 0
84 rows inserted

Do this for Oracle:
INSERT INTO TEMP_TABELA (OSE_ID)
select 7 from dual union all
select 12 from dual union all
select 16 from dual union all
select 17 from dual union all
select 19 from dual union all
select 21 from dual union all
select 24 from dual union all
select 26 from dual union all
select 30 from dual union all
select 33 from dual union all
select 35 from dual union all
select 38 from dual union all
select 42 from dual union all
select 46 from dual union all
select 53 from dual union all
select 58 from dual union all
select 59 from dual union all
select 72 from dual union all
select 73 from dual union all
select 74 from dual union all
select 77 from dual union all
select 78 from dual union all
select 82 from dual union all
select 86 from dual union all
select 87 from dual union all
select 88 from dual union all
select 89 from dual union all
select 91 from dual union all
select 92 from dual union all
select 93 from dual union all
select 100 from dual union all
select 101 from dual union all
select 102 from dual union all
select 104 from dual union all
select 106 from dual union all
select 109 from dual union all
select 113 from dual union all
select 115 from dual union all
select 127 from dual union all
select 133 from dual union all
select 139 from dual union all
select 140 from dual union all
select 142 from dual union all
select 143 from dual union all
select 144 from dual union all
select 148 from dual union all
select 149 from dual union all
select 150 from dual union all
select 151 from dual union all
select 153 from dual union all
select 155 from dual union all
select 160 from dual union all
select 164 from dual union all
select 166 from dual union all
select 167 from dual union all
select 170 from dual union all
select 172 from dual union all
select 178 from dual union all
select 188 from dual union all
select 189 from dual union all
select 191 from dual union all
select 192 from dual union all
select 198 from dual union all
select 199 from dual union all
select 200 from dual union all
select 201 from dual union all
select 202 from dual union all
select 203 from dual union all
select 205 from dual union all
select 207 from dual union all
select 208 from dual union all
select 219 from dual union all
select 220 from dual union all
select 223 from dual union all
select 225 from dual union all
select 231 from dual union all
select 233 from dual union all
select 236 from dual union all
select 240 from dual union all
select 241 from dual union all
select 242 from dual union all
select 244 from dual union all
select 245 from dual union all
select 253 from dual
And this for SQL Server:
INSERT INTO TEMP_TABELA (OSE_ID)
select 7 union all
select 12 union all
select 16 union all
select 17 union all
select 19 union all
select 21 union all
select 24 union all
select 26 union all
select 30 union all
select 33 union all
select 35 union all
select 38 union all
select 42 union all
select 46 union all
select 53 union all
select 58 union all
select 59 union all
select 72 union all
select 73 union all
select 74 union all
select 77 union all
select 78 union all
select 82 union all
select 86 union all
select 87 union all
select 88 union all
select 89 union all
select 91 union all
select 92 union all
select 93 union all
select 100 union all
select 101 union all
select 102 union all
select 104 union all
select 106 union all
select 109 union all
select 113 union all
select 115 union all
select 127 union all
select 133 union all
select 139 union all
select 140 union all
select 142 union all
select 143 union all
select 144 union all
select 148 union all
select 149 union all
select 150 union all
select 151 union all
select 153 union all
select 155 union all
select 160 union all
select 164 union all
select 166 union all
select 167 union all
select 170 union all
select 172 union all
select 178 union all
select 188 union all
select 189 union all
select 191 union all
select 192 union all
select 198 union all
select 199 union all
select 200 union all
select 201 union all
select 202 union all
select 203 union all
select 205 union all
select 207 union all
select 208 union all
select 219 union all
select 220 union all
select 223 union all
select 225 union all
select 231 union all
select 233 union all
select 236 union all
select 240 union all
select 241 union all
select 242 union all
select 244 union all
select 245 union all
select 253

The parentheses in your statement in the example indicate to SQL Server that you want all that to be on one row. You need to enclose each row in parentheses and separate those by commas, i.e:
INSERT INTO TEMP_TABELA (OSE_ID)
values (7),
(12),
(16),
(17),
(19),
(21),
(24),...
I'm not sure if this will work in Oracle or not, but if not you may need to create a condition in your calling application to determine which DB it's working with and modify the query appropriately.

Similar to #OMGPonies can also do something like:
INSERT INTO TEMP_TABLEA(OSE_ID)
SELECT 7 union all
SELECT 12 ...
Not sure which is faster or even if you care about speed given the number of items you're inserting.
Not tested on oracle but I'm about 90% sure it will work.