am trying to do this query. This is what I have.
My table is: Table
QId InternalId type. priority userid
100 100 1 0 X101
100 100 1 1 X102
100 100 2 0 X103
100 100 2 0 X104
100 100 2 0 X105
100 100 3 0 X106
100 100 3 0 X107
101 101 2 1 X114
101 101 2 0 X115
101 101 3 0 X116
101 101 3 0 X117
For QId and InternalId we have type 1,2,3. I need 1 row for each group based type. Here condition is if priority is 1 then we need take that record. if priority is not set need to take first record.
I need result like below table
QId InternalId type. priority userid
100 100 1 1 X102
100 100 2 0 X103
100 100 3 0 x106
101 101 2 1 X114
101 101 3 0 X116
Can you please help me out in this
Just use row_number():
select t.*
from (select t.*,
row_number() over (partition by QId, InternalId, type order by (select null)) as seqnum
from t
) t
where seqnum = 1;
You can try using row_number()
select * from
(
select *, row_number() over(partition by qid, internalid, type order by priority desc) as rn
from tablename
)A where rn=1
use row_number() window function
select t.* from (select *,row_number()over(partition by QId,InternalId,type order by case when priority=1 then 1 else 2 end) rn
) where t.rn=1
Another approach can be WITH TIES like following.
select top 1 with ties *
from #table
order by row_number() over (partition by QId, InternalId, type order by (select 1))
Online Demo
Related
https://dbfiddle.uk/?rdbms=sqlserver_2016&fiddle=9e6f83edf836f4496afb509eb9411d4a
Edited to include sql code:
CREATE TABLE TMP_PRODUCTS (STORE INT, UPC INT, PROMOCODE CHAR(3), FORSALE CHAR(1))
INSERT INTO TMP_PRODUCTS VALUES
(100,1,'123','Y'),
(100,2,'123','Y'),
(100,3,'123','N'),
(100,4,'124','Y'),
(100,5,'124','N'),
(100,6,'124','N'),
(100,7,'125','N'),
(100,8,'125','N'),
(100,9,'125','N');
SELECT
STORE,
UPC,
PROMOCODE,
DENSE_RANK() OVER (PARTITION BY STORE ORDER BY PROMOCODE) AS 'GroupCode'
FROM
TMP_PRODUCTS
WHERE
FORSALE = 'Y'
I need to return all rows where FORSALE='Y' across all groups of PROMOCODE, and also at least 1 row from all groups where FORSALE='N'. In this example all products from group 125 are FORSALE='N', but I need at least 1 row to return. Here is the output I am currently getting:
STORE UPC PROMOCODE GroupCode FORSALE
100 1 123 1 Y
100 2 123 1 Y
100 4 124 2 Y
But here is the ideal output I would like to get:
STORE UPC PROMOCODE GroupCode FORSALE
100 1 123 1 Y
100 2 123 1 Y
100 4 124 2 Y
100 7 125 3 N
It would also be completely acceptable to return 1 row from PROMOCODE 123 and 124 even though they already have some items that are FORSALE='Y'. So this would also be acceptable outcome:
STORE UPC PROMOCODE GroupCode FORSALE
100 1 123 1 Y
100 2 123 1 Y
100 3 123 1 N
100 4 124 2 Y
100 5 124 2 N
100 7 125 3 N
You can do that with an additional row number window function to always include 1 row from each group regardless of Y/N
select STORE, UPC, PROMOCODE, Dense_Rank() over (partition by STORE order by PROMOCODE) GROUPCODE, FORSALE
from (
select * , Row_Number() over(partition by STORE, PROMOCODE order by UPC) rn
from TMP_PRODUCTS
)x
where FORSALE = 'Y' or rn=1
If I understand correctly, the logic you want is:
SELECT STORE, UPC, PROMOCODE,
DENSE_RANK() OVER (PARTITION BY STORE ORDER BY PROMOCODE) AS GroupCode
FROM (SELECT P.*,
ROW_NUMBER() OVER (PARTITION BY STORE, PROMOCODE, FORSALE ORDER BY (SELECT NULL)) as seqnum
FROM TMP_PRODUCTS P
) P
WHERE FORSALE = 'Y' OR seqnum = 1;
I have something similar to the below dataset...
ID RowNumber
101 1
101 2
101 3
101 4
101 5
101 1
101 2
What I would like to get is an additional column as below...
ID RowNumber New
101 1 1
101 2 1
101 3 1
101 4 1
101 5 1
101 1 2
101 2 2
I have toyed with dense_rank(), but no such luck.
Gordon already mentioned, you required a column to specify the order of data. If i consider ID as order by column, this following logic may help you to get your desired result-
WITH your_table(ID,RowNumber)
AS
(
SELECT 101,1 UNION ALL
SELECT 101,2 UNION ALL
SELECT 101,3 UNION ALL
SELECT 101,4 UNION ALL
SELECT 101,5 UNION ALL
SELECT 101,1 UNION ALL
SELECT 101,2
)
SELECT A.ID,A.RowNumber,
SUM(RN) OVER
(
ORDER BY ID
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW
) +1 New
FROM
(
SELECT *,
CASE
WHEN LAG(RowNumber) OVER(ORDER BY ID) > RowNumber THEN 1
ELSE 0
END RN
FROM your_table
)A
Above will always change the ROW NUMBER if the value in RowNumber decreased than previous one. Alternatively, the same output alsoo can be achieved if you wants to change row number whenever value 1 found. This is bit static option-
SELECT A.ID,A.RowNumber,
SUM(RN) OVER
(
ORDER BY ID
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW
) New
FROM(
SELECT *,
CASE
WHEN RowNumber = 1 THEN 1
ELSE 0
END RN
FROM your_table
)A
Output is-
ID RowNumber New
101 1 1
101 2 1
101 3 1
101 4 1
101 5 1
101 1 2
101 2 2
SQL tables represent unordered sets. There is no ordering unless a column specifies the ordering.
Assuming you have such a column, you can do what you want simply by counting the number of "1" up to each point:
select t.*,
sum(case when rownumber = 1 then 1 else 0 end) over (partition by id order by <ordering column>) as new
from t;
As Gordon alluded to, there is no default order in your example so it's difficult to imagine how to get a deterministic result (e.g. where the same values supplied to the same query always resulting in the exact same answer.)
This sample data includes a sequential PK column which is used to define the order of this set.
DECLARE #tbl TABLE (PK INT IDENTITY, ID INT, RowNumber INT)
INSERT #tbl(ID, RowNumber) VALUES (101,1),(101,2),(101,3),(101,4),(101,5),(101,1),(101,2);
SELECT t.* FROM #tbl AS t;
Returns:
PK ID RowNumber
----- ------ -----------
1 101 1
2 101 2
3 101 3
4 101 4
5 101 5
6 101 1
7 101 2
This query uses DENSE_RANK to get you what you want:
DECLARE #tbl TABLE (PK INT IDENTITY, ID INT, RowNumber INT)
INSERT #tbl(ID, RowNumber) VALUES (101,1),(101,2),(101,3),(101,4),(101,5),(101,1),(101,2);
SELECT t.ID, t.RowNumber, New = DENSE_RANK() OVER (ORDER BY t.PK - RowNumber)
FROM #tbl AS t;
Returns:
ID RowNumber New
----- ----------- ------
101 1 1
101 2 1
101 3 1
101 4 1
101 5 1
101 1 2
101 2 2
Note that ORDER BY New does not affect the plan.
Please try the below
Load the data into Temp table
Select id,RowNumber,Row_number()over(partition by RowNumber Order by id)New from #temp
Order by Row_number()over(partition by RowNumber Order by id),RowNumber
Tbl1
---------------------------------------------------------
Id Date Qty ReOrder
---------------------------------------------------------
1 1-1-18 1 3
2 2-1-18 0 3
3 3-1-18 2 3
4 4-1-18 3< >3
5 5-1-18 2 3
6 6-1-18 0 3
7 7-1-18 1 3
8 8-1-18 0 3
---------------------------------------------------------
I want the result like below
---------------------------------------------------------
Id Date Qty ReOrder
---------------------------------------------------------
1 1-1-18 1 3
5 5-1-18 2 3
---------------------------------------------------------
if ReOrder not same with Qty then date will be same upto after reorder=Qty
You can use cumulative approach with row_number() function :
select top (1) with ties *
from (select *, max(case when qty = reorder then 'v' end) over (order by id desc) grp
from table
) t
order by row_number() over(partition by grp order by id);
Unfortunately this will require SQL Server, But you can also do:
select *
from (select *, row_number() over(partition by grp order by id) seq
from (select *, max(case when qty = reorder then 'v' end) over (order by id desc) grp
from table
) t
) t
where seq = 1;
Example:
id Pricemoney time/date
1 100 01/20/2017
1 10 01/21/2017
1 1000 01/21/20147
2 10 01/23/2017
2 100 01/24/2017
3 1000 01/19/2017
3 100 01/22/2017
3 10 01/24/2017
I want to run a SQL query where I can display all the Id and it's pricemoney BUT NOT include the first record (based on time/date) per unique
Just to clarify what I do not want to be displayed
userid Pricemoney issuedate
1 100 01/20/2017 -- not included
1 10 01/21/2017
1 1000 01/21/20147
2 10 01/23/2017 --- not inlcuded
2 100 01/24/2017
3 1000 01/19/2017 -- not included
3 100 01/22/2017
3 10 01/24/2017
Expected result:
id Pricemoney time/date
1 10 01/21/2017
1 1000 01/21/20147
2 100 01/24/2017
3 100 01/22/2017
3 10 01/24/2017
You can use row_number():
select t.*
from (select t.*,
row_number() over (partition by id order by time_date asc) as seqnum
from <tablename> t
) t
where seqnum > 1;
If you want to keep single rows, you can do:
select t.*
from (select t.*,
row_number() over (partition by id order by time_date asc) as seqnum,
count(*) over (partition by id) as cnt
from <tablename> t
) t
where seqnum > 1 and cnt > 1;
You may use EXISTS
select t1.*
from data t1
where exists (
select 1
from data t2
where t1.id = t2.id and t2.time_date < t1.time_date
)
you can try this :
select data1.id,data1.Date,data1.Pricemoney from data1
left join (
select id ,min(Date) date from data1
group by id
) as t
on data1.date= t.date and t.id = data1.id
where t.id is null
group by data1.id,data1.Date,data1.Pricemoney
above query not duplicated records also ignore, if want
not duplicated records then use having count(id) > 1 in left query e,g.
select data1.id,data1.Date,data1.Pricemoney from data1
left join (
select id ,min(Date) date from data1
group by id
having COUNT(id) > 1
) as t
on data1.date= t.date and t.id = data1.id
where t.id is null
group by data1.id,data1.Date,data1.Pricemoney
I have different versions of the charges in a table. I want to grab and sum the last charge grouped by Type.
So I want to add 9.87, 9.63, 1.65.
I want the Parent ID , sum(9.87 + 9.63 + 1.65) as the results of this query.
We use MSSQL
ID ORDER CHARGES TYPE PARENT ID
1 1 6.45 1 1
2 2 1.25 1 1
3 3 9.87 1 1
4 1 6.54 2 1
5 2 5.64 2 1
6 3 0.84 2 1
7 4 9.63 2 1
8 1 7.33 3 1
9 2 5.65 3 1
10 3 8.65 3 1
11 4 5.14 3 1
12 5 1.65 3 1
WITH recordsList
AS
(
SELECT Type, Charges,
ROW_NUMBER() OVER (PArtition BY TYPE
ORDER BY [ORDER] DESC) rn
FROM tableName
)
SELECT SUM(Charges) totalCharge
FROM recordsLIst
WHERE rn = 1
SQLFiddle Demo
Use row_number() to identify the rows to be summed, and then sum them:
select SUM(charges)
from (select t.*,
ROW_NUMBER() over (PARTITION by type order by id desc) as seqnum
from t
) t
where seqnum = 1
Alternatively you could use a window aggregate MAX():
SELECT SUM(Charges)
FROM (
SELECT
[ORDER],
Charges,
MaxOrder = MAX([ORDER]) OVER (PARTITION BY [TYPE])
FROM atable
) s
WHERE [ORDER] = MaxOrder
;
SELECT t.PARENT_ID, SUM(t.CHARGES)
FROM dbo.test73 t
WHERE EXISTS (
SELECT 1
FROM dbo.test73
WHERE [TYPE] = t.[TYPE]
HAVING MAX([ORDER]) = t.[ORDER]
)
GROUP BY t.PARENT_ID
Demo on SQLFiddle