I wrote this block of code
SELECT max(order)
FROM orders_table
GROUP BY UNIX_TIMESTAMP(timestamp) DIV 30 ;
Order is a column that I'm trying to take the max of every 30 seconds from a table called orders_table. I found the last line of code on here in the answer to someone elses program. However, I get an error when I try to run this code.
Thanks in advance
Your query uses MySQL syntax. In Oracle server, neither DIV nor UNIX_TIMESTAMP exists.
To do integer division, you may just TRUNC the results of the division.
To compute the number of seconds since January 1st, 1970, you could use the following expression (since Oracle, when substracting dates, returns the result as a number of days) :
(date_column - TO_DATE('1970-01-01', 'yyyy-mm-dd')) * 60 *60 *24
You probably want :
SELECT MAX(o.order)
FROM orders_table o
GROUP BY TRUNC(o.timestamp - TO_DATE('1970-01-01', 'yyyy-mm-dd')) / 30 )
Related
I wonder if anyone here can help with a BigQuery piece I am working on.
I'm trying to pull the date, email and last interaction time from a dataset when the last interaction time is equal to or greater than 90 days ago.
I have the following query:
SELECT
date,
user_email,
DATE_FROM_UNIX_DATE(gmail.last_interaction_time) AS Last_Interaction_Date,
DATE_ADD(CURRENT_DATE(), INTERVAL -90 DAY) AS Days_ago
FROM
`bqadminreporting.adminlogtracking.usage`
WHERE
'Last_Interaction_Date' >= 'Days_ago'
However, I run into the following error:
DATE value is out of allowed range: from 0001-01-01 to 9999-12-31
As far as I can see, it makes sense - so not entirely sure why its throwing out an error?
Looks like you have some inconsistent values (data) in filed gmail.last_interaction_time, which you need to handle to avoid error.
Moreover above query will not work as per your expected WHERE conditions, you should use following query to get expected output.
SELECT * FROM
(SELECT
date,
user_email,
DATE_FROM_UNIX_DATE(gmail.last_interaction_time) AS Last_Interaction_Date,
DATE_ADD(CURRENT_DATE(), INTERVAL -90 DAY) AS Days_ago
FROM
`bqadminreporting.adminlogtracking.usage`)
WHERE
Last_Interaction_Date >= Days_ago
Presumably, your problem is DATE_FROM_UNIX_DATE(). Without sample data, it is not really possible to determine what the issue is.
However, you don't need to convert to a date to do this. You can do all the work in the Unix seconds space:
select u.*
from `bqadminreporting.adminlogtracking.usage` u
where gmail.last_interaction_time >= unix_seconds(timestamp(current_date)) - 90 * 60 * 60 * 24
Note that I suspect that the issue is that last_interaction_time is really measured in milliseconds or microseconds or some other unit. This will prevent your error, but it might not do what you want.
I have a syntax formatting issue with the query below.
I am trying to get the difference between two time columns and then subtract 20 to get whatever the difference is minus 20. I also want to take the max value of either that or 0 so anything less than 0 will be 0.
select id, sum(max(0, (date_diff('minute', time_a, time_b)) - 20)) as mins
FROM tbl
What am doing wrong in the query above that is erorring out?
Thanks!
sum(max()) is highly suspicious. Perhaps you intend:
select id, sum(greatest(0, date_diff('minute', time_a, time_b) - 20)) as mins
from tbl
I have one query:
SELECT CAST(((stats.ts_spawn - 1427835600) / 86400) * 86400 +
1427835600 AS INTEGER) AS anon_1 FROM stats WHERE stats.ts_spawn >
1427835600 AND stats.ts_spawn < 1428440399 GROUP BY anon_1 order by anon_1;
I'm expecting to get start of the each day in a week.
Result in Postgresql:
1427835600
1427922000
1428008400
1428094800
1428181200
1428267600
1428354000
Vertica returns start of each hour of each day of the week:
1427839200
1427842800
1427846400
1427850000
... and so on, total 167 records(24 * 7 - 1)
I have no idea how to modify this query.
The second one is obviously resulting in a float not an integer in division. In Vertica documents we can read this:
the Vertica 6 release introduced a behavior change when dividing integers using the / operator
If you want the query to behave the same on both systems either change the configuration option as mentioned in that doc or use the Floor() function on the result of division.
Suppose I have the following query:
select customer_name, origination_date
where origination_date < '01-DEC-2013';
I would like to select all customers that have an origination date older than 30 days. Is there a way in SQL (oracle, if specifics needed) to specify it in a more dynamic approach than manually entering the date so that I don't need to update the query every time I run it?
Thanks!
Sure try something like this:
select customer_name, origination_date where
origination_date >= DATEADD(day, -30, GETUTCDATE());
This basically says where the origination_date is greater or equal to 30 days from now. This works in Microsoft SQL, not sure but there is probably a similar function on Oracle.
in Oracle, when you subtract dates, by default you get the difference in days, e.g.
select * from my_table where (date_1 - date_2) > 30
should return the records whose date difference is greater than 30 days.
To make your query dynamic, you parameterize it, so instead of using hard coded date values, you use:
select * from my_table where (:date_1 - :date_2) > :threshold
If you are using oracle sql developer to run such a query, it will pop up a window for you to specify the values for your paramteres; the ones preceded with colon.
HI all,
i have one sql table and field for that table is
id
name
expireydate
Now i want only those record which one is expired within 45 days or 30 days.
how can i do with sql query .?
I have not much more exp with sql .
Thanks in advance,
If you are using mysql then try DATEDIFF.
for 45 days
select * from `table` where DATEDIFF(now(),expireydate)<=45;
for 30 days
select * from `table` where DATEDIFF(now(),expireydate)<=30;
In oracle - will do the trick instead of datediff and SYSDATE instead of now().[not sure]
In sql server DateDiff is quite different you have to provide unit in which difference to be taken out from 2 dates.
DATEDIFF(datepart,startdate,enddate)
to get current date try one of this: CURRENT_TIMESTAMP or GETDATE() or {fn NOW()}
You can use a simple SELECT * FROM yourtable WHERE expireydate < "some formula calculating today+30 or 45 days".
Simple comparison will work there, the tricky part is to write this last bit concerning the date you want to compare to. It'll depend of your environment and how you stored the "expireydate" in the database.
Try Below:-
SELECT * FROM MYTABLE WHERE (expireydate in days) < ((CURRENTDATE in days)+ 45)
Do not execute directly! Depending of your database, way of obtaining a date in days will be different. Go look at your database manual or please precise what is your database.