So, I'm running two queries that returns me the X amount of items per month through a year.
the 1st query gives me the following result
the 'no column name' would be the months, so I have no data in august, november and december.
The second query, gives me the following
only August and Setpember has data.
What I'm trying to figure out is how can I sum both tables to get the 100% value, then define each % (corretivas x preventivas).
In my research, I assume I have to nest the queries, but I just can't reach the logic to get me near the wanted result.
this is my queries so far
select month(workOrderDate), COUNT(*) as preventivas from WorkOrder WHERE
workOrderDescription = 'preventiva'
AND YEAR(workOrderDate) = 2018
AND lastUpdateData IS NOT NULL
AND WorkType = '02'
group BY MONTH(workOrderDate)
ORDER BY MONTH(workOrderDate)
select MONTH(workOrderDate), COUNT(*) AS corretivas from WorkOrder WHERE
YEAR(workOrderDate) = 2018
AND workOrderDescription = 'CORRETIVA'
AND lastUpdateData IS NOT NULL
GROUP BY MONTH(workOrderDate)
ORDER BY MONTH(workOrderDate)
The expected result would be
and so on
Would anybody helpe me with this?
You want conditional aggregation :
SELECT MONTH(wo.workOrderDate), COUNT(*) AS total,
(SUM(CASE WHEN wo.WorkType = '02' AND wo.orkOrderDescription = 'preventiva' THEN 1 ELSE 0 END) * 1.0 / COUNT(*)) * 100 AS preventiva,
(SUM(CASE WHEN wo.orkOrderDescription = 'CORRETIVA' THEN 1 ELSE 0 END) * 1.0 / COUNT(*)) * 100 AS CORRETIVA
FROM WorkOrder wo
WHERE YEAR(wo.workOrderDate) = 2018 AND wo.lastUpdateData IS NOT NULL
GROUP BY MONTH(wo.workOrderDate);
Related
I am struggling to work out combining a query that should give me 3 columns of Month, total_sold_products and drinks_sold_products
Query 1:
Select month(date), count(id) as total_sold_products
from Products
where date between '2022-01-01' and '2022-12-31'
Query 2
Select month(date), count(id) as drinks_sold_products
from Products where type = 'drinks' and date between '2022-01-01' and '2022-12-31'
I tried the union function but it summed count(id) twice and gave me only 2 columns
Many thanks!
Union is for attaching sets of data on top of each other. You need conditional aggregation or a join. See below.
SELECT MONTH(date),
COUNT(*) AS total_sold_products,
COUNT(CASE WHEN type = 'drinks' THEN 1 ELSE 0 END) AS drinks_sold_products,
FORMAT((CASE
WHEN COUNT(*) > 0 THEN
COUNT(CASE WHEN type = 'drinks' THEN 1 ELSE 0 END)/COUNT(*)
ELSE 0 END),
'P') AS Percentage
FROM Products
WHERE date BETWEEN'2022-01-01' AND '2022-12-31'
GROUP BY MONTH(date)
I have a query and it shows the months where there is corresponding data. However, I would like to show all of the months in the year and have the months where there are no data shown as zero.
There is my SQL Statement:
SELECT DATENAME(MONTH, hb_Disputes.OPENED) AS MonthValue,
COUNT(CASE WHEN REV_CLS = 2 THEN 1 END) AS SmallCommercialIndust,
COUNT(CASE WHEN REV_CLS <> 2 THEN 1 END) AS Residential
FROM hb_Disputes
WHERE (hb_Disputes.ASSGNTO = 'E099255') AND (YEAR(hb_Disputes.OPENED) = YEAR(GETDATE()))
GROUP BY hb_Disputes.OPENED
And this is my output:
I also have a table name MonthName that shows all of the months in a year and I know I may need to use this to accomplish what I'm trying to achieve but I'm not sure how to get there:
If you have data in the table for all months, but the where clause is filtering it out, then the simplest method is to extend the conditional aggregation:
SELECT DATENAME(MONTH, d.OPENED) AS MonthValue,
SUM(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS = 2 THEN 1 ELSE 0 END) AS SmallCommercialIndust,
SUM(CASE WHEN d.ASSGNTO = 'E099255' AND d.REV_CLS <> 2 THEN 1 ELSE 0 END) AS Residential
FROM hb_Disputes d
WHERE YEAR(d.OPENED) = YEAR(GETDATE())
GROUP BY DATENAME(MONTH, d.OPENED)
ORDER BY MIN(d.OPENED);
Note: This does not fix the issue in all cases. It should just be a simple way to modify your query -- and will often work.
I have list of line items from invoices with a field that indicates if a line was delivered or picked up. I need to find a percentage of delivered items from the total number of lines.
SALES_NBR | Total | Deliveryrate
1 = Delivered 0 = picked up from FULFILLMENT.
SELECT SALES_NBR,
COUNT (ITEMS) as Total,
SUM (case when FULFILLMENT = '1' then 1 else 0 end) as delivered,
(SELECT delivered/total) as Deliveryrate
FROM Invoice_table
WHERE STORE IN '0123'
And SALE_DATE >='2020-02-01'
And SALE_DATE <='2020-02-07'
Group By SALES_NBR, Deliveryrate;
My query executes but never finishes for some reason. Is there any easier way to do this? Fulfillment field does not contain any NULL values.
Any help would be appreciated.
I need to find a percentage of delivered items from the total number of lines.
The simplest method is to use avg():
select SALES_NBR,
avg(fulfillment) as delivered_ratio
from Invoice_table
where STORE = '0123' and
SALE_DATE >='2020-02-01' and
SALE_DATE <='2020-02-07'
group by SALES_NBR;
I'm not sure if the group by sales_nbr is needed.
If you want to get a "nice" query, you can use subqueries like this:
select
qry.*,
qry.delivered/qry.total as Deliveryrate
from (
select
SALES_NBR,
count(ITEMS) as Total,
sum(case when FULFILLMENT = '1' then 1 else 0 end) as delivered
from Invoice_table
where STORE IN '0123'
and SALE_DATE >='2020-02-01'
and SALE_DATE <='2020-02-07'
group by SALES_NBR
) qry;
But I think this one, even being ugglier, could perform faster:
select
SALES_NBR,
count(ITEMS) as Total,
sum(case when FULFILLMENT = '1' then 1 else 0 end) as delivered,
sum(case when FULFILLMENT = '1' then 1 else 0 end)/count(ITEMS) as Deliveryrate
from Invoice_table
where STORE IN '0123'
and SALE_DATE >='2020-02-01'
and SALE_DATE <='2020-02-07'
group by SALES_NBR
I have table that looks like this:
I'm trying to build a query, that will show specific partnerId counters groupped by keywordName and month.
To solve first part(without grouping by month), I've built this query:
SELECT keywordName, COUNT(keywordName) as total, IFNULL(b.ebay_count, 0) as ebay, IFNULL(c.amazon_count, 0) as amazon,
FROM LogFilesv2_Dataset.FR_Clickstats_v2 a
LEFT JOIN
(SELECT keywordName as kw , SUM(CASE WHEN partnerId='eBay' THEN 1 ELSE 0 END) as ebay_count
FROM LogFilesv2_Dataset.FR_Clickstats_v2
WHERE partnerId = 'eBay' GROUP BY kw) b
ON keywordName = b.kw
LEFT JOIN
(SELECT keywordName as kw , SUM(CASE WHEN partnerId='AmazonApi' THEN 1 ELSE 0 END) as amazon_count
FROM LogFilesv2_Dataset.FR_Clickstats_v2
WHERE partnerId = 'AmazonApi' GROUP BY kw) c
ON keywordName = c.kw
WHERE keywordName = 'flipper' -- just to filter out single kw.
GROUP BY keywordName, ebay, amazon
It works quite well and returns following output:
Now I'm trying to make additional group by month, but all my attempts returned incorrect results.
Final output supposed to be similar to this:
You can do this with conditional aggregation:
select
date_trunc(dt, month) dt,
keywordName,
count(*) total,
sum(case when partnerId = 'eBay' then 1 else 0 end) ebay,
sum(case when partnerId = 'AmazonApi' then 1 else 0 end) amazon
from LogFilesv2_Dataset.FR_Clickstats_v2
group by date_trun(dt, month), keywordName
I have a SQLite table called posts. An example is shown below. I would like to calculate the monthly income and expenses.
accId date text amount balance
---------- ---------- ------------------------ ---------- ----------
1 2008-03-25 Ex1 -64.9 3747.56
1 2008-03-25 Shop2 -91.85 3655.71
1 2008-03-26 Benny's -100.0 3555.71
For the income I have this query:
SELECT SUBSTR(date, 0,7) "month", total(amount) "income" FROM posts
WHERE amount > 0 GROUP BY month ORDER BY date;
It works fine:
month income
---------- ----------
2007-05 4877.0
2007-06 8750.5
2007-07 8471.0
2007-08 5503.0
Now I need the expenses and I could of cause just repeat the first statement with the condition amount < 0, but I am wondering if there is an elegant way to get both income and expenses in one query?
Try something like this
select substr(date, 0,7) "Month",
total(case when a > 0 then a else 0 end) "Income",
total(case when a < 0 then a else 0 end) "Expenses"
from posts
group by month
Look into the UNION statement (bottom of the link). This will let you combine the results of two queries, generally in the form:
<SELECT_STATEMENT_1> UNION <SELECT_STATEMENT_2>
Not sure if SQL Lite supports CASE statements, but if it does you could do something like this.
SELECT SUBSTR(date, 0,7) "month"
, total(CASE WHEN Amount > 0 THEN Amount ELSE 0 END) "income"
, -1 * total(CASE WHEN Amount < 0 THEN Amount ELSE 0 END) "expenses"
FROM posts
GROUP BY month
ORDER BY date;