I have 3 tables as below
Table - travel_requests
id industry_id travel_cost stay_cost other_cost
1 2 1000 500 200
2 4 4000 100 200
3 5 3000 0 400
4 1 3000 250 100
5 1 200 100 75
Table - industry_tech_region
id industry_name
1 Auto
2 Aero
3 Machinery
4 Education
5 MTV
Table - industry_allocation
id industry_id allocation
1 1 500000
2 2 300000
3 3 500000
4 4 300000
5 5 500000
6 1 200000
I want to create a view which has 3 columns
industry_name, total_costs, total_allocation
I created a view as below
SELECT industry_tech_region.industry_name,
SUM(travel_requests.travel_cost + travel_requests.stay_cost + travel_requests.other_cost) AS total_cost,
SUM(industry_allocation.allocation) AS total_allocation
FROM industry_tech_region
INNER JOIN industry_allocation
ON industry_tech_region.id = industry_allocation.industry_id
INNER JOIN travel_requests
ON industry_tech_region.id = travel_requests.industry_id
GROUP BY industry_tech_region.industry_name
But the result I get is as below which is incorrect
industry_name total_cost total_allocation
Aero 1700 300000
Auto 7450 1400000 (wrong should be 3725 and 700000)
Education 4300 300000
MTV 3400 500000
This is probably happening because there are 2 entries for industry_id 1 in the travel_requests table. But they should be counted only once.
Please let me know how do we correct the view statement.
Also I want to add another column in view which is remaining_allocation which is difference of total_allocation and total_cost for each industry.
you shoud join the sum (and not sum the join)
select
a.industry_name
, t1.total_cost
, t2.total_allocation
from dbo.industry_tech_region a
left join (
select dbo.travel_requests.industry_id
, SUM(dbo.travel_requests.travel_cost + dbo.travel_requests.stay_cost + dbo.travel_requests.other_cost) AS total_cost
FROM bo.travel_requests
group by dbo.travel_requests.industry_id
) t1 on a.id = t1.industry_id
left join (
select dbo.industry_allocation.industry_id
, SUM(dbo.industry_allocation.allocation) AS total_allocation
from dbo.industry_allocation
group by dbo.industry_allocation.industry_id
) t2 on a.id = t2.industry_id
this happen because you have two entry for the industry_id 1 and then the row are joined two time if you use the subquery for aggreated the row this can't happen ...
I have used left join because seems that not all the industry_id match for the 3 tables ..
You can use this approach too (without the ORDER BY because views do not allow it).
;WITH q AS (
SELECT industry_id
, sum(allocation) AS total_allocation
FROM #industry_allocation
GROUP BY industry_id
)
SELECT #industry_tech_region.industry_name
, isnull(SUM(#travel_request.travel_cost
+ #travel_request.stay_cost
+ #travel_request.other_cost),0.0) AS total_cost
,q.total_allocation AS total_allocation
FROM #industry_tech_region
LEFT JOIN q ON #industry_tech_region.id = q.industry_id
LEFT JOIN #travel_request ON #industry_tech_region.id = #travel_request.industry_id
GROUP BY #industry_tech_region.industry_name,q.total_allocation
ORDER BY industry_name
Related
I have a table which looks like this:
ID
money_earned
days_since_start
1
1000
1
1
2000
2
1
3000
4
1
2000
5
2
1000
1
2
100
3
I want that rows, without a days_since_start (which means that the money_earned column was empty that day) - will include all the days PER ID, and fill the money_earned with last known value, so it to look like this:
ID
money_earned
days_since_start
1
1000
1
1
2000
2
1
2000
3
1
3000
4
1
2000
5
2
1000
1
2
1000
2
2
100
3
I have tried to look up for something like that, but I don't even know what function does that...
thank you!
You can try to use CTE RECURSIVE with OUTER JOIN and LAG window function to make it.
WITH RECURSIVE CTE
AS
(
SELECT ID,MIN(days_since_start) min_num,MAX(days_since_start) max_num
FROM T
GROUP BY ID
UNION ALL
SELECT ID,min_num+1,max_num
FROM CTE
WHERE min_num+1 <= max_num
)
SELECT c.ID,
CASE WHEN t1.ID IS NULL THEN LAG(money_earned) OVER(PARTITION BY c.ID ORDER BY c.min_num) ELSE money_earned END,
c.min_num days_since_start
FROM CTE c
LEFT JOIN T t1
ON c.min_num = t1.days_since_start
AND c.ID = t1.ID
ORDER BY c.ID
sqlfiddle
I am pulling my hair out over a data retrieval function I'm trying to write. In essence this query is meant to SUM up the count of all voorwerpnummers in the Voorwerp_in_Rubriek table, grouped by their rubrieknummer gathered from Rubriek.
After that I want to keep looping through the sum in order to get to their 'top level parent'. Rubriek has a foreign key reference to itself with a 'hoofdrubriek', this would be easier seen as it's parent in a category tree.
This also means they can be nested. A value of 'NULL' in the hoofdcategory column means that it is a top-level parent. The idea behind this query is to SUM up the count of voorwerpnummers in Voorwerp_in_rubriek, and add them together until they are at their 'top level parent'.
As the database and testdata is quite massive I've decided not to add direct code to this question but a link to a dbfiddle instead so there's more structure.
https://dbfiddle.uk/?rdbms=sqlserver_2017&fiddle=8068a52da6a29afffe6dc793398f0998
I got it working in some degree using this query:
SELECT R2.hoofdrubriek ,
COUNT(Vr.rubrieknummer) AS aantal
FROM Rubriek R1
RIGHT OUTER JOIN Rubriek R2 ON R1.rubrieknummer = R2.hoofdrubriek
INNER JOIN Voorwerp_in_rubriek Vr ON R2.rubrieknummer = Vr.rubrieknummer
WHERE NOT EXISTS ( SELECT *
FROM Rubriek
WHERE hoofdrubriek = R2.rubrieknummer )
AND R1.hoofdrubriek IS NOT NULL
GROUP BY Vr.rubrieknummer ,
R2.hoofdrubriek
But that doesn't get back all items and flops in general. I hope someone can help me.
If I got it right
declare #t table (
rubrieknummer int,
cnt int);
INSERT #t(rubrieknummer, cnt)
SELECT R.rubrieknummer, COUNT(Vr.voorwerpnummer)
FROM Rubriek R
INNER JOIN voorwerp_in_rubriek Vr ON R.rubrieknummer = Vr.rubrieknummer
GROUP BY Vr.rubrieknummer, R.rubrieknummer;
--select * from #t;
with t as(
select rubrieknummer, cnt
from #t
union all
select r.hoofdrubriek, cnt
from t
join Rubriek r on t.rubrieknummer = r.rubrieknummer
)
select rubrieknummer, sum(cnt) cnt
from t
group by rubrieknummer;
applying to your fiddle data returns
rubrieknummer cnt
<null> 42
100 42
101 26
102 6
103 10
10000 8
10100 4
10101 1
10102 3
10500 4
10501 2
10502 2
15000 18
15100 6
15101 2
15102 2
15103 2
15500 12
15501 4
15502 3
15503 5
20000 6
20001 2
20002 1
20003 1
20004 2
25000 4
25001 1
25002 1
25003 1
25004 1
30001 2
30002 1
30004 3
Consider the following table Orders:
OrderID Name Amount
-----------------------
1 A 100
2 A 5
3 B 32
4 C 4000
5 D 701
6 E 32
7 F 200
8 G 100
9 H 12
10 I 17
11 J 100
12 J 100
13 J 11
14 A 5
I need to identify, for each unique 'Amount', if there are 2 or more users that have ordered that exact amount, and then list the details of those orders. So the desired output would be:
OrderID Name Amount
---------------------
1 A 100
8 G 100
11 J 100
12 J 100
3 B 32
6 E 32
please note that user A has ordered 2 x an order of 5 (order 2 and 14) but this shouldn't be in the output as it is within the same user. Only if another user would have made a order of 5, it should be in the output.
Can anyone help me out?
I would just use exists:
select o.*
from orders o
where exists (select 1
from orders o2
where o2.amount = o.amount and o2.name <> o.name
);
You can do :
select t.*
from table t
where exists (select 1 from table t1 where t1.amount = t.amount and t1.name <> t.name);
If you want only selected field then
SELECT Amount,name,
count(*) AS c
FROM TABLE
GROUP BY Amount, name
HAVING c > 1
ORDER BY c DESC
if you want full row
select * from table where Amount in (
select Amount, name from table
group by Amount, name having count(*) > 1)
I'm implementing pagination on my BD. My problem is when I want limit the SELECT statement but not the JOIN. Example, a product can got many prices:
SELECT * FROM product
LEFT JOIN price ON product.id == price.id_product
LIMIT 20
But I want to get 20 products with each one with their prices. How I can limit the statement SELECT, but not LEFT JOIN.
Example:
product price.id price.id_pruct price.price
1 1 1 50
2 2 1 30
3 3 1 40
4 1 20
5 2 30
SELECT * FROM product
LEFT JOIN price ON product.id == price.id_product
LIMIT 3
Return:
product price.id id_prodcut price
1 1 1 50
1 2 1 30
1 3 1 40
But I Want
product price.id id_prodcut price
1 1 1 50
1 2 1 30
1 3 1 40
1 4 1 20
2 5 2 30
3 . . .
Three products (limit 3)
Thanks. I hope you can help me.
Modify your query to limit the number of product rows before joining it to the price table. This means we want to to join the results of a query to a table, or in other words, we write a query containing a subquery:
SELECT *
FROM (
SELECT *
FROM product
ORDER BY id_product
LIMIT 3
) p
LEFT JOIN price ON p.id = price.id_product
Hope that helps.
I would write a subquery to get the three first products (or whatever condition you choose) like this:
SELECT id
FROM product
ORDER BY id
LIMIT 3;
Once I have that, I can select everything from the price table as long as the id is in that subquery. You can do this using a join:
SELECT p.*
FROM price p
JOIN(
SELECT id
FROM product
ORDER BY id
LIMIT 3) tmp ON tmp.id = p.product_id;
Here is an SQL Fiddle example using your sample data, and I also added a row that won't be returned so you can see that it works.
I have records as such:
Id ForeignKey Level ValueA ValueB
1 1001 1 2 10
2 1001 1 10 10
3 1001 1 20 20
4 1001 2 20 30
5 1002 1 1 100
6 1003 1 1 100
7 1004 1 1 100
I want to get the Ids of each record of the groups grouped by ForeignKey and Level where the sum of the group's records' ValueA values divided by the sum of ValueB values is greater than 0.5
In this case, I'd like to retrieve the Id of the three first records as (2 + 10 + 20) / (10 + 10 + 20) = 0.8
Here is what I've got so far:
select
ForeignKey,
SUM(ValueA) as ValueASum,
SUM(ValueB) as ValueBSum,
from tableA
group by ForeignKey
having (SUM(ValueA) / SUM(ValueB) > 0.5)
The result is
ForeignKey ValueASum ValueBSum
1001 32 40
How do I get the ids of the records from this point? If I add the Id in the select, I must group on it and then have a group for each record.
Thanks for your time
Hm, how about
select id from your_table where foreignkey = 1001
Is something wrong with working with multiple queries?
If you want you can do a subquery:
select id from your_table where foreignkey in ( select foreignkey from ( <yourQuery> ) sq);
UPDATE:
select t.id from Table1 t
inner join
(
select
ForeignKey, level,
SUM(ValueA) as ValueASum,
SUM(ValueB) as ValueBSum
from Table1
where level = 1
group by ForeignKey, Level
having (SUM(ValueA) / SUM(ValueB) > 0.5) ) sq
ON t.foreignkey = sq.foreignkey AND t.level = sq.level
I added where level = 1 just because your given resultset not what I get when I execute your query.
See it working live in an sqlfiddle.
You were on the right track, but if you wanted it from each "Level", you would need to add that into your group by also.
select
tA2.ID,
tA2.ForeignKey,
tA2.Level,
tA2.ValueA,
tA2.ValueB
from
( select
tA.ForeignKey,
tA.Level,
SUM(tA.ValueA) as ValueASum,
SUM(tA.ValueB) as ValueBSum,
from
tableA tA
group by
tA.ForeignKey,
tA.Level
having
(SUM(tA.ValueA) / SUM(tA.ValueB) > 0.5) ) PreQualified
JOIN tableA tA2
on PreQualified.ForeignKey = tA2.ForeignKey
AND PreQualified.Level = tA2.Level
This would give all values that matched the qualifying condition.