I have this code
select Key
,CAST(LEFT(CAST(Key as nvarchar(8)),4)+'0101' as int) as YearaFirstKey
FROM DimDt WHERE Key > 0
I need to change this code to string = cStr() , int as cInt(), use substring mid(). But I don't know how. If I print out the code, it shows this:
SELECT [key], CONVERT(varchar(30), CAST([key] as datetime), 103) as strDate
with your format code chosen from
https://www.w3schools.com/sql/func_sqlserver_convert.asp
+++++
your date is in iso format as a string, so it is simple to change it to a date type, then format the date type using built in SQL functions
Related
I need to change the numeric format into 'AM/PM' format in CONCAT function (I use SSMS v 18.5.1)
Here is my formula. RCLDTE - is a date and RCLTIM is time. I basically need to leave RCLDTE as it is and change the format of RCLTIM from numeric to date and convert to AM/PM format.
How the column looks right now
Format of RCLTIM - numeric
CONCAT(c.RCLDTE, ' & ', MAX(c.RCLTIM)) AS 'Date & Time',
When I tried to use CONVERT function as I tend to use, it raised an error.
CONCAT(c.RCLDTE, ' & ', CONVERT(varchar(15),CAST( MAX(c.RCLTIM) AS TIME),100))
Error
Explicit conversion from data type numeric to time is not allowed.
The number for the date can be concatenated to the number for the time stuffed with colons. So that it can be converted to a DATETIME.
And by using FORMAT the DATETIME can be put in a specific format.
(But use CONVERT if it has the format.)
Test snippet
declare #test table (
ID INT IDENTITY PRIMARY KEY,
RCLDTE int,
RCLTIM int
);
insert into #test (RCLDTE, RCLTIM) values
(20220119, 215250)
, (20220304, 070809)
;
select
FORMAT(TRY_CAST(CONCAT(c.RCLDTE, ' ', STUFF(STUFF(FORMAT(MAX(c.RCLTIM),'000000'),5,0,':'),3,0,':')) AS DATETIME)
, 'd/M/yyyy hh:mm:ss tt') AS [Date & Time]
from #test c
group by RCLDTE;
Date & Time
19/1/2022 09:52:50 PM
4/3/2022 07:08:09 AM
Test on db<>fiddle here
What you're attempting to do is very fragile, but I presume your source system gives you few options.
Converting like this has potential problems with DST & the language in use at the time of running.
Your question lost some of the detail regarding formats, so I can't see the time type you are using, but it looks like a decimal again.
Essentially, you need to put the the numerics in a string and then into datetime columns, but to get there you have to match a string conversion format the sqlserver.
Fortunately you are not far off the us format default.
Something like this will get you a date field, you can then amend the output format if you really need 12hr rather than 24hr.
SET LANGUAGE us_english
DECLARE #rcldte NUMERIC, #rcltim numeric
SET #rcldte=20220119
SET #rcltim = 015250
SELECT
CONVERT(DATETIME, CAST (#rcldte AS VARCHAR)+ ' ' +
LEFT( left('000000', 6-LEN(CAST ( #rcltim AS VARCHAR)))+CAST ( #rcltim AS VARCHAR),2)
+ ':' + substring( left('000000', 6-LEN(CAST ( #rcltim AS VARCHAR)))+CAST ( #rcltim AS VARCHAR),3,2)
+ ':' + RIGHT( left('000000', 6-LEN(CAST ( #rcltim AS VARCHAR)))+CAST ( #rcltim AS VARCHAR),2))
Which will give you:
(No column name)
2022-01-19 01:52:50.000
It's rather ugly though.
If you can guarantee the hours are zero padded then you could remove the complexity associated with that.
And if you're really going to use it then split into proper UDFs...
DECLARE #RCLDTE CHAR(8) = '20220119';
DECLARE #RCLTIM CHAR(6) = '215250';
select CONVERT(VARCHAR(21), (cast(#RCLDTE as DATETIME) + cast(substring(#RCLTIM,1,2)+':'+substring(#RCLTIM,3,2)+':'+substring(#RCLTIM,5,2) as DATEtime) ), 22);
output: 01/19/22 9:52:60 PM
For different formats of the DATETIME, see the docs of the CONVERT function:
https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql?view=sql-server-ver15
NOTE: When specifying another format the value 21 in VARCHAR(21) might need a change...
I have a varchar column with the following format ddmmyyyy and I'm trying to convert it to date in the format dd-mm-yyyy. I'm using the query below but I get the error:
Conversion failed when converting date and/or time from character string.
select *, coalesce(try_convert(date, newdate, 105), convert(date, newdate))
from mydate
You don't have a date, you have a string. So, you can use string operations:
select stuff(stuff(newdate, 5, 0, '-'), 3, 0, '-')
If you want to convert to a date, you can do:
select convert(date, concat(right(newdate, 4), substring(newdate, 3, 2), left(newdate, 2)))
You could then format this as you want.
However, you should not be converting the value to a date. You should be storing it as a date in the first place.
To turn your string to a date, you can just [try_]cast() it; SQL Server is usually flexible enough to figure out the format by itself:
try_cast(newdate as date)
If you want to turn it back to a string in the target format, then you can use format():
format(try_cast(newdate as date), 'dd-MM-yyyy')
Compared to pure string operations, the upside of the try_cast()/format() approach is that it validates that the string is a valid date in the process.
Have to agree with the others. Why are you storing a date as a string in the first place? In a non-standard format, no less? Here's one way, but you should really fix the data model. Store dates as dates.
DECLARE #badIdea table (dt char(8));
INSERT #badIdea(dt) VALUES('21052020');
SELECT newdate = TRY_CONVERT(date, RIGHT(dt,4) + SUBSTRING(dt,3,2) + LEFT(dt,2))
FROM #badIdea;
BTW 105 won't work because it requires dashes. This works:
SELECT CONVERT(date, '21-05-2020', 105);
That's a bad format too, IMHO, because who knows if 07-08-2020 is July 8th or August 7th. But at least that one is supported by SQL Server. Your current choice is not.
SQL doesn't store date data types in different formats, and it's probably not a good idea to try and adjust this.
If, however, you are wanting a result set to simply display the date in a different format, you are on the right track. You just need to convert your date data type to a string.
SELECT *
, COALESCE ( TRY_CONVERT ( CHAR(10), newdate, 105 ), CONVERT ( CHAR(10), newdate ) )
FROM mydate
I have the following datetime format ( as varchar ) in my database 13-04-2018 1:05:00.
I need to convert it to the following format: 2018-04-13 01:05:00. As datetime.
Normal convert functions can't do this because they try to take the 13th month, and that month doesn't exist. This error:
The conversion of a varchar data type to a datetime data type resulted
in an out-of-range value.
Does someone know how to convert this date issue?
Using datetimes is always a pain regardless of the language because of all the different formats across the world.
To sort your issue out currently, you need to use a format style which is a third parameter to CONVERT. Personally what I would suggest here is to store as a datetime, because storing datetimes as strings is never a good idea. It just gets too messy later on, but if saved in the format you would like, it would be saved as yyyy-MM-dd hh:mm:ss
SELECT CONVERT(DATETIME, '13-04-2018 1:05:00',103)
You can create your own function to format it in your desired output string.
CREATE FUNCTION FormatMyDate
(#Date DATETIME) RETURNS VARCHAR(20)
AS
BEGIN
RETURN FORMAT(#Date,'yyyy-dd-MM hh:mm:ss')
END
And then you can call it in SELECT statements like this:
SELECT dbo.FormatMyDate(yourDateCol)
FROM yourTable
this takes the date from the format where month comes before day and reverses the 2 values (month and day)
SELECT CONVERT(DATETIME, '2018-13-04 01:05:00', 103);
Results:
2018-04-13 01:05:00.000
This should work for you requirement...
SELECT FORMAT(yourdate, 'yyyy-dd-MM')
Your Solution Bro...
DECLARE #d DATETIME = GETDATE()
SELECT FORMAT ( #d, 'MM-dd-yyyy hh:mm:ss', 'de-de' ) AS 'Hoping your result'
Say I have a field UserAddedInfo with a string "User was added to the system and removed from list on 16/05/2016 by User Annon" and a field DateAdded in the same table.
Is there any way in SQL to extract that 16/05/2016 date from the string field and insert it into the DateAdded field as a datetime?
The date in the string is always going to be dd/MM/yyyy.
Thanks!
Use PATINDEX to get the start position of the date string in the column and extract 10 characters from that position. To convert the extracted string to date, use CONVERT with format 103.
103 = dd/mm/yyyy
select
convert(date,
substring(UserAddedInfo,patindex('%[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]%',UserAddedInfo),10)
,103)
from table_name
where patindex('%[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]%',UserAddedInfo) > 0
To update the dateadded field in the table, use
update table_name
set dateadded = convert(date,
substring(UserAddedInfo,patindex('%[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]%',UserAddedInfo),10)
,103)
where patindex('%[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]%',UserAddedInfo) > 0
Use try_cast or try_convert to return null when the substring returns invalid dates.
select
try_cast(
substring(UserAddedInfo,patindex('%[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]%',UserAddedInfo),10)
as date)
--or
--try_convert(date,
--substring(UserAddedInfo,patindex('%[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]%',UserAddedInfo),10)
--)
from table_name
where patindex('%[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]%',UserAddedInfo) > 0
You can use patindex to find date string, and use cast to convert it to datetime
select
cast(substring('User was added to the system and removed from list on 27/08/2014 by User Annon',
patindex('%[0-9][0-9]/[0-9][0-9]/[0-9][0-9][0-9][0-9]%',
'User was added to the system and removed from list on 27/08/2014 by User Annon'), 10) as datetime)
In my table I have myDate column of type nvarchar(50).
The result I need is to select this date/time: 07/11/2013 11:22:07
And I need to get 07/11/2013 11:22:07 am from it (add am/pm to the original date&time).
I tried everything but get only the original data without am/pm.
This is an example from my query :
select convert(dateTime,myDate,100) as Date from Info
or
select convert(dateTime,myDate,0) as Date from Info
What am I missing ?
try this !!
declare #date datetime
set #date='07/11/2013 11:22:07'
SELECT cast(convert(varchar(20),substring(convert(nvarchar(20),#date, 9), 0, 21)
+ ' ' + substring(convert(nvarchar(30), #date, 9), 25, 2),105) as datetime)
Your field is a NVARCHAR field so just return it without any conversion. In your query you convert string representation into the DATETIME type and returns it. Your browser software which shows query results convert DateTime value into string representation to show it to you and conversion format depends on this software usually you can change it changing Windows Regional Settings.
You can get AM/PM data using following query
declare #date datetime
select #date= CAST('07/11/2013 11:22:07' AS datetime)
select RIGHT ( CONVERT(VARCHAR,#date,9),2)