Need the expected output from Hive/SQL query - hive

Input:
1
2
3
4
.
.
.
Expected Output:
1
2
2
3
3
3
4
4
4
4
.
.
..
.
Need to find the Hive /SQL query for the expected output like this

Below is the query, have used CTE with 3 records as my input.
hive> with t1 as (select 1 as col1 union select 2 as col1 union select 3 as col1) select t11.col1 from t1 as t11,t1 as t12 where t11.col1>=t12.col1;

Related

Create Multiple Rows based on condition

I have a table that looks like this
id
name
count
1
Nishu
4
2
Shivam
2
3
Himanshu
1
I want to get the Output like this:-
id
name
count
1
Nishu
4
1
Nishu
4
1
Nishu
4
1
Nishu
4
2
Shivam
2
2
Shivam
2
3
Himanshu
1
3
Himanshu
1
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
You can use a cross join against generate_series()
select t.*
from the_table t
cross join generate_series(1, t.count) as g
order by t.id;
Online example
Using RECURSIVE CTE you can do:
WITH RECURSIVE cte as (
SELECT 1 as x,m.* FROM mytable m
union all
SELECT x+1,m.*
FROM cte,mytable m
WHERE x<m.count)
SELECT DISTINCT *
FROM cte
ORDER BY count DESC;
see: DBFIDDLE
more info:
WITH Queries (Common Table Expressions)
Learn PostgreSQL Recursive Query By Example

Select field 1 Where Field 2 ='value1' And field 2 ='value2' when Field 1 is Same

I am currently having troubles with filtering my SQL records. I need something like what it results in the following concept: Table is
A B
1 1
1 3
2 1
2 2
2 3
2 4
3 1
3 2
I want to select value of A , where B=1 and B=2 And B=3 when same A .... result is
A
2
Please help
You can use aggregation:
select a
from mytable
where b in (1, 2, 3)
group by a
having count(*) = 3
This assumes no duplicates in the table - else, you need to change the having clause to:
having count(distinct b) = 3

Selecting Last change value per group

I am trying to select the last change value per group.
I have a table
MMID column is incremental
MMID GID MID Value Bundle DateEntered
1 1 1 1 2 17/8/15 05:05:04
2 1 2 2 3 16/8/15 05:05:06
3 1 3 3 2 15/8/15 05:05:07
4 1 1 0 2 18/8/15 05:05:08
5 2 2 1 1 18/8/15 05:05:05
6 2 2 2 2 18/8/15 06:06:06
7 2 4 3 1 17/8/15 06:06:06
8 2 4 3 2 18/8/15 06:06:07
Here, I want the last change 'Value' in the last 24 hour(Having Date 18th August).
From the below query, I can get that. But even if the bundle value is changed, then I get that row.
But I want only rows when 'Value' is changed, or 'Value and Bundle' are changed. But not only when Bundle is changed
Desired output
MMID GID MID Value Bundle DateEntered
4 1 1 0 2 18/8/15 05:05:08
6 2 2 2 2 18/8/15 06:06:06
The query I tried is :
select yt1.*
from Table1 yt1
left outer join Table1 yt2
on (yt1.GID = yt2.GID and yt1.MID = yt2.MID
and yt1.MMID < yt2.MMID)
where yt2.MMID is null and yt2.GID is null and yt2.MID is null and yt1.DateEntered > '2015-08-18 00:00:00' ;
The output i get from here is:
MMID GID MID Value Bundle DateEntered
4 1 1 0 2 18/8/15 05:05:08
6 2 2 2 2 18/8/15 06:06:06
8 2 4 3 2 18/8/15 06:06:07
I should not be getting the last row here.
Can anyone tell me what should I change here.
Not really following the logic of your attempt, but here is how I would get the desired results:
WITH cte AS (
SELECT *,
ROW_NUMBER() OVER (PARTITION BY GID, MID ORDER BY MMID) AS rn
FROM Table
)
, cte2 AS (
SELECT t1.* FROM cte t1
INNER JOIN cte t2
ON t1.GID=t2.GID
AND t1.MID=t2.MID
AND t1.value<>t2.value
AND t1.rn=t2.rn+1
)
SELECT *
FROM cte2
WHERE MMID=(
SELECT TOP 1 MMID
FROM cte2 c2
WHERE cte2.GID=c2.GID
AND cte2.MID=c2.MID
ORDER BY MMID DESC
)
NB: If you don't want to include the rn column in the final results, use a column list instead of SELECT *.

Adding non existing data to SQL query

My SQL query returns the following result (screenshot):
x y count
----------- ----------- -----------
1 1 10
1 2 2
2 4 3
2 5 5
4 1 5
5 1 8
what i want is x, y should always contain 1 to 5 values, even if the query doesn't return them, in the above scenario x is missing 3. How to add the missing values here that are between 1 & 5.
Thanks in Advance
First you need to generate the desired data. You can use a table of numbers for this. Use CROSS JOIN to generate all possible combinations of two tables. Finally, OUTER JOIN the generated data with your table.
In the following query I have used union to build a list of numbers instead of fetching them from a table. But the idea remains same:
SELECT XList.x, YList.y, #temp.count
FROM (
SELECT 1 AS x UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5
) AS XList
CROSS JOIN (
SELECT 1 AS y UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5
) AS YList
LEFT JOIN #temp ON XList.x = #temp.x AND YList.y = #temp.y
Result:
x y count
----------- ----------- -----------
1 1 10
2 1 NULL
3 1 NULL
4 1 5
5 1 8
1 2 2
2 2 NULL
3 2 NULL
4 2 NULL
5 2 NULL
1 3 NULL
2 3 NULL
3 3 NULL
4 3 NULL
5 3 NULL
1 4 NULL
2 4 3
3 4 NULL
4 4 NULL
5 4 NULL
1 5 NULL
2 5 5
3 5 NULL
4 5 NULL
5 5 NULL
You can do it this way:
select t1.x, t2.y, s.count from
(values(1),(2),(3),(4),(5)) t1(x) cross join
(values(1),(2),(3),(4),(5)) t2(y)
left join #temp s on t1.x = s.x and t2.y = s.y

SQL: Assembling Non-Overlapping Sets

I have sets of consecutive integers, organized by type, in table1. All values are between 1 and 10, inclusive.
table1:
row_id set_id type min_value max_value
1 1 a 1 3
2 2 a 4 10
3 3 a 6 10
4 4 a 2 5
5 5 b 1 9
6 6 c 1 7
7 7 c 3 10
8 8 d 1 2
9 9 d 3 3
10 10 d 4 5
11 11 d 7 10
In table2, within each type, I want to assemble all possible maximal, non-overlapping sets (though gaps that cannot be filled by any sets of the correct type are okay). Desired output:
table2:
row_id type group_id set_id
1 a 1 1
2 a 1 2
3 a 2 1
4 a 2 3
5 a 3 3
6 a 3 4
7 b 4 5
8 c 5 6
9 c 6 7
10 d 7 8
11 d 7 9
12 d 7 10
13 d 7 11
My current idea is to use the fact that there is a limited number of possible values. Steps:
Find all sets in table1 containing value 1. Copy them into table2.
Find all sets in table1 containing value 2 and not already in table2.
Join the sets from (2) with table1 on type, set_id, and having min_value greater than the group's greatest max_value.
For the sets from (2) that did not join in (3), insert them into table2. These start new groups that may be extended later.
Repeat steps (2) through (4) for values 3 through 10.
I think this will work, but it has a lot of pain-in-the-butt steps, especially for (2)--finding the sets not in table2, and (4)--finding the sets that did not join.
Do you know a faster, more efficient method? My real data has millions of sets, thousands of types, and hundreds of values (though fortunately, as in the example, the values are bounded), so scalability is essential.
I'm using PLSQL Developer with Oracle 10g (not 11g as I stated before--thanks, IT department). Thanks!
For Oracle 10g you can't use recursive CTEs, but with a bit of work you can do something similar with the connect by syntax. First you need to generate a CTE or in-line view which has all the non-overlapping links, which you can do with:
select t1.type, t1.set_id, t1.min_value, t1.max_value,
t2.set_id as next_set_id, t2.min_value as next_min_value,
t2.max_value as next_max_value,
row_number() over (order by t1.type, t1.set_id, t2.set_id) as group_id
from table1 t1
left join table1 t2 on t2.type = t1.type
and t2.min_value > t1.max_value
where not exists (
select 1
from table1 t4
where t4.type = t1.type
and t4.min_value > t1.max_value
and t4.max_value < t2.min_value
)
order by t1.type, group_id, t1.set_id, t2.set_id;
This took a bit of experimentation and it's certainly possible I've missed or lost something about the rules in the process; but that gives you 12 pseudo-rows, and is in my previous answer this allows the two separate chains starting with a/1 to be followed while constraining the d values to a single chain:
TYPE SET_ID MIN_VALUE MAX_VALUE NEXT_SET_ID NEXT_MIN_VALUE NEXT_MAX_VALUE GROUP_ID
---- ------ ---------- ---------- ----------- -------------- -------------- --------
a 1 1 3 2 4 10 1
a 1 1 3 3 6 10 2
a 2 4 10 3
a 3 6 10 4
a 4 2 5 3 6 10 5
b 5 1 9 6
c 6 1 7 7
c 7 3 10 8
d 8 1 2 9 3 3 9
d 9 3 3 10 4 5 10
d 10 4 5 11 7 10 11
d 11 7 10 12
And that can be used as a CTE; querying that with a connect-by loop:
with t as (
... -- same as above query
)
select t1.type,
dense_rank() over (partition by null
order by connect_by_root group_id) as group_id,
t1.set_id
from t t1
connect by type = prior type
and set_id = prior next_set_id
start with not exists (
select 1 from table1 t2
where t2.type = t1.type
and t2.max_value < t1.min_value
)
and not exists (
select 1 from t t3
where t3.type = t1.type
and t3.next_max_value < t1.next_min_value
)
order by t1.type, group_id, t1.min_value;
The dense_rank() makes the group IDs contiguous; not sure if you actually need those at all, or if their sequence matters, so it's optional really. connect_by_root gives the group ID for the start of the chain, so although there were 12 rows and 12 group_id values in the initial query, they don't all appear in the final result.
The connection is via two prior values, type and the next set ID found in the initial query. That creates all the chains, but own its own would also include shorter chains - for d you'd see 8,9,10,11 but also 9,10,11 and 10,11, which you don't want as separate groups. Those are eliminated by the start with conditions, which could maybe be simplified.
That gives:
TYPE GROUP_ID SET_ID
---- -------- ------
a 1 1
a 1 2
a 2 1
a 2 3
a 3 4
a 3 3
b 4 5
c 5 6
c 6 7
d 7 8
d 7 9
d 7 10
d 7 11
SQL Fiddle demo.
If you can identify all the groups and their starting set_id then you can use a recursive approach and do this all in a single statement, rather than needing to populate a table iteratively. However you'd need to benchmark both approaches both for speed/efficiency and resource consumption - whether it will scale for your data volumes and within your system's available resources would need to be verified.
If I understand when you decide to start a new group you can identify them all at once with a query like:
with t as (
select t1.type, t1.set_id, t1.min_value, t1.max_value,
t2.set_id as next_set_id, t2.min_value as next_min_value,
t2.max_value as next_max_value
from table1 t1
left join table1 t2 on t2.type = t1.type and t2.min_value > t1.max_value
where not exists (
select 1
from table1 t3
where t3.type = t1.type
and t3.max_value < t1.min_value
)
)
select t.type, t.set_id, t.min_value, t.max_value,
t.next_set_id, t.next_min_value, t.next_max_value,
row_number() over (order by t.type, t.min_value, t.next_min_value) as grp_id
from t
where not exists (
select 1 from t t2
where t2.type = t.type
and t2.next_max_value < t.next_min_value
)
order by grp_id;
The tricky bit here is getting all three groups for a, specifically the two groups that start with set_id = 1, but only one group for d. The inner select (in the CTE) looks for sets that don't have a lower non-overlapping range via the not exists clause, and outer-joins to the same table to get the next set(s) that don't overlap, which gives you two groups that start with set_id = 1, but also four that start with set_id = 9. The outer select then ignores everything but the lowest non-overlapping with a second not exists clause - but doesn't have to hit the real table again.
So that gives you:
TYPE SET_ID MIN_VALUE MAX_VALUE NEXT_SET_ID NEXT_MIN_VALUE NEXT_MAX_VALUE GRP_ID
---- ------ ---------- ---------- ----------- -------------- -------------- ------
a 1 1 3 2 4 10 1
a 1 1 3 3 6 10 2
a 4 2 5 3 6 10 3
b 5 1 9 4
c 6 1 7 5
c 7 3 10 6
d 8 1 2 9 3 3 7
You can then use that as the anchor member in a recursive subquery factoring clause:
with t as (
...
),
r (type, set_id, min_value, max_value,
next_set_id, next_min_value, next_max_value, grp_id) as (
select t.type, t.set_id, t.min_value, t.max_value,
t.next_set_id, t.next_min_value, t.next_max_value,
row_number() over (order by t.type, t.min_value, t.next_min_value)
from t
where not exists (
select 1 from t t2
where t2.type = t.type
and t2.next_max_value < t.next_min_value
)
...
If you left the r CTE with that and just did sleect * from r you'd get the same seven groups.
The recursive member then uses the next set_id and its range from that query as the next member of each group, and repeats the outer join/not-exists look up to find the next set(s) again; stopping when there is no next non-overlapping set:
...
union all
select r.type, r.next_set_id, r.next_min_value, r.next_max_value,
t.set_id, t.min_value, t.max_value, r.grp_id
from r
left join table1 t
on t.type = r.type
and t.min_value > r.next_max_value
and not exists (
select 1 from table1 t2
where t2.type = r.type
and t2.min_value > r.next_max_value
and t2.max_value < t.min_value
)
where r.next_set_id is not null -- to stop looking when you reach a leaf node
)
...
Finally you have a query based on the recursive CTE to get the columns you want and to specify the order:
...
select r.type, r.grp_id, r.set_id
from r
order by r.type, r.grp_id, r.min_value;
Which gets:
TYPE GRP_ID SET_ID
---- ---------- ----------
a 1 1
a 1 2
a 2 1
a 2 3
a 3 4
a 3 3
b 4 5
c 5 6
c 6 7
d 7 8
d 7 9
d 7 10
d 7 11
SQL Fiddle demo.
If you wanted to you could show the min/max values for each set, and could track and show the min/max value for each group. I've just show then columns from the question though.