I have a field in my database called "Notes". It contains a comma delimited list of values.
I want to perform a SELECT Query that only returns the first value in the "Notes" field.
This query would also return additional fields from the database.
for example
SELECT Name, Phone, Notes (only the first value)
FROM Table1
Is this possible, and how do I do it?
You can use CHARINDEX with SUBSTRING:
SELECT Name, Phone, SUBSTRING(Notes, 1, CHARINDEX(',', Notes)) AS first_value
FROM Table1
Demo
DECLARE #csv varchar(50)
SET #csv = 'comma after this, and another,'
SELECT SUBSTRING(#csv, 1, CHARINDEX(',', #csv)) AS first_value
Result
| first_value |
--------------------
| comma after this |
As mentioned in the comments, you should normalize your structure and not have more than one value stored in a single attribute.
SELECT Name, Phone, Left(Notes, CharIndex(',', Notes + ',')) FirstNote
FROM Table1
You need the Notes + ',' bit in the CharIndex to work correctly - see this example (I have included njk's answer)
with Table1(Name, Phone, Notes) as (
select 'abc', '123', 'Some,notes,here' union all
select 'abd', '124', 'Single-note' union all
select 'abe', '125', '' union all
select 'syz', '126', null
)
---
SELECT Name, Phone, Left(Notes, CharIndex(',', Notes + ',')-1) FirstNote
,SUBSTRING(Notes, 0, CHARINDEX(',', Notes)) AS njk
FROM Table1
Results
Name Phone FirstNote njk
---- ----- --------------- ---------------
abc 123 Some Some
abd 124 Single-note
abe 125
syz 126 NULL NULL
SELECT name,
phones,
split_part(notes, ',', 1) as first_notes
FROM Table1
solutions for Select Value From Comma Delimited List
I was looking for a more general answer (not just the first field but an arbitrarily specified one) so I modified Kermit's answer and put it in a function. Here it is in case it helps save somebody else time
CREATE FUNCTION [dbo].[fnGetFieldXFromDelimitedList] (#SearchIn nvarchar(max)
, #Delimiter char(1), #FieldNum int ) RETURNS nvarchar(max) as BEGIN
/*
fnGetFieldXFromDelimitedList(#SearchIn, #Delimiter, #FieldNum)
Returns the Nth value (specified by #FieldNum, first is 1 not 0)
from #SearchIn assuming #SearchIn is a list of multiple values
delimited by #Delimiter
DECLARE #SearchIn nvarchar(max) = 'F1, Field 2, F3,, F5, F6, F7'
DECLARE #Delimiter char(1) = ','
DECLARE #FieldNum int = 7
--*/
--SELECT dbo.fnGetFieldXFromDelimitedList ('F1, Field 2, F3,, F5, F6, F7', ',', 5)
DECLARE #PosStart int = 1 --SUBSTRING(SearchIn, StartPos, StrLen) considers 1 the first character
DECLARE #PosEnd INT = LEN(#SearchIn)
DECLARE #TempString nvarchar(max) = CONCAT(#SearchIn, #Delimiter)
DECLARE #TempNum INT = 1
DECLARE #RetVal nvarchar(max) = ''
--SElECT SUBSTRING(#SearchIn, 1, 1)
SET #PosEnd = CHARINDEX(#Delimiter, #TempString, #PosStart + LEN(#Delimiter))
WHILE #TempNum < #FieldNum AND #PosStart > 0 AND #PosStart < LEN(#TempString) BEGIN
SET #PosStart = CHARINDEX(#Delimiter, #TempString, #PosStart) + LEN(#Delimiter)
SET #PosEnd = CHARINDEX(#Delimiter, #TempString, #PosStart)
SET #TempNum = #TempNum + 1
--SELECT #PosStart, #PosEnd , #TempNum
END --WHILE
IF #TempNum = #FieldNum AND #PosEnd > 0 BEGIN
SET #RetVal = SUBSTRING(#TempString, #PosStart, #PosEnd - #PosStart)
END ELSE BEGIN
SET #RetVal = NULL
END
--SELECT #RetVal
RETURN #RetVal
END
I got the following entry in my database:
images/test.jpg
I want to trim the entry so I get: test
So basically, I want everything after / and before .
How can I solve it?
use the following function
left(#test, charindex('/', #test) - 1)
If you want to get this out of your table using SQL, take a look at the following functions that will help you: SUBSTRING and CHARINDEX. You can use those to trim your entries.
A possible query will look like this (where col is the name of the column that contains your image directories:
SELECT SUBSTRING(col, LEN(SUBSTRING(col, 0, LEN(col) - CHARINDEX ('/', col))) + 1,
LEN(col) - LEN(SUBSTRING(col, 0, LEN(col) - CHARINDEX ('/', col))) - LEN(SUBSTRING(
col, CHARINDEX ('.', col), LEN(col))));
Bit of an ugly beast. It also depends on the standard format of 'dir/name.ext'.
Edit:
This one (inspired by praveen) is more generic and deals with extensions of different length:
SELECT SUBSTRING(col, LEN(LEFT(col, CHARINDEX ('/', col))) + 1, LEN(col) - LEN(LEFT(col,
CHARINDEX ('/', col))) - LEN(RIGHT(col, LEN(col) - CHARINDEX ('.', col))) - 1);
Before
SELECT SUBSTRING(ParentBGBU,0,CHARINDEX('/',ParentBGBU,0)) FROM dbo.tblHCMMaster;
After
SELECT SUBSTRING(ParentBGBU,CHARINDEX('-',ParentBGBU)+1,LEN(ParentBGBU)) FROM dbo.tblHCMMaster
----select characters before / including /
select SUBSTRING ('abcde/wxyz',0,CHARINDEX('/','abcde/wxyz')+1)
--select characters after / including /
select SUBSTRING('abcde/wxyz',CHARINDEX('/','abcde/wxyz'),LEN('abcde/wxyz'))
declare #T table
(
Col varchar(20)
)
insert into #T
Select 'images/test1.jpg'
union all
Select 'images/test2.png'
union all
Select 'images/test3.jpg'
union all
Select 'images/test4.jpeg'
union all
Select 'images/test5.jpeg'
Select substring( LEFT(Col,charindex('.',Col)-1),charindex('/',Col)+1,len(LEFT(Col,charindex('.',Col)-1))-1 )
from #T
I have made a method which is much more general :
so :
DECLARE #a NVARCHAR(MAX)='images/test.jpg';
--Touch here
DECLARE #keysValueToSearch NVARCHAR(4000) = '/'
DECLARE #untilThisCharAppears NVARCHAR(4000) = '.'
DECLARE #keysValueToSearchPattern NVARCHAR(4000) = '%' + #keysValueToSearch + '%'
--Nothing to touch here
SELECT SUBSTRING(
#a,
PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch),
CHARINDEX(
#untilThisCharAppears,
#a,
PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch)
) -(PATINDEX(#keysValueToSearchPattern, #a) + LEN(#keysValueToSearch))
)
SELECT Substring('ravi1234#gmail.com', 1, ( Charindex('#', 'ravi1234#gmail.com')
- 1 ))
Before,
RIGHT('ravi123#gmail.com', ( Charindex('#', 'ravi123#gmail.com') + 1 ))
After
I just did this in one of my reports and it was very simple.
Try this:
=MID(Fields!.Value,8,4)
Note: This worked for me because the value I was trying to get was a constant not sure it what you are trying to get is a constant as well.
I know this has been a while.. but here is an idea
declare #test varchar(25) = 'images/test.jpg'
select
#test as column_name
, parsename(replace(#test,'/','.'),1) as jpg
,parsename(replace(#test,'/','.'),2) as test
,parsename(replace(#test,'/','.'),3) as images
I found Royi Namir's answer useful but expanded upon it to create it as a function. I renamed the variables to what made sense to me but you can translate them back easily enough, if desired.
Also, the code in Royi's answer already handled the case where the character being searched from does not exist (it starts from the beginning of the string), but I wanted to also handle cases where the character that is being searched to does not exist.
In that case it acts in a similar manner by starting from the searched from character and returning the rest of the characters to the end of the string.
CREATE FUNCTION [dbo].[getValueBetweenTwoStrings](#inputString
NVARCHAR(4000), #stringToSearchFrom NVARCHAR(4000), #stringToSearchTo
NVARCHAR(4000))
RETURNS NVARCHAR(4000)
AS
BEGIN
DECLARE #retVal NVARCHAR(4000)
DECLARE #stringToSearchFromSearchPattern NVARCHAR(4000) = '%' +
#stringToSearchFrom + '%'
SELECT #retVal = SUBSTRING (
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom),
(CASE
CHARINDEX(
#stringToSearchTo,
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
WHEN
0
THEN
LEN(#inputString) + 1
ELSE
CHARINDEX(
#stringToSearchTo,
#inputString,
PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
END) - (PATINDEX(#stringToSearchFromSearchPattern, #inputString) + LEN(#stringToSearchFrom))
)
RETURN #retVal
END
Usage:
SELECT dbo.getValueBetweenTwoStrings('images/test.jpg','/','.') AS MyResult
I got some invalid length errors. So i made this function, this should not give any length problems. Also when you do not find the searched text it will return a NULL.
CREATE FUNCTION [FN].[SearchTextGetBetweenStartAndStop](#string varchar(max),#SearchStringToStart varchar(max),#SearchStringToStop varchar(max))
RETURNS varchar(max)
BEGIN
SET #string = CASE
WHEN CHARINDEX(#SearchStringToStart,#string) = 0
OR CHARINDEX(#SearchStringToStop,RIGHT(#string,LEN(#string) - CHARINDEX(#SearchStringToStart,#string) + 1 - LEN(#SearchStringToStart))) = 0
THEN NULL
ELSE SUBSTRING(#string
,CHARINDEX(#SearchStringToStart,#string) + LEN(#SearchStringToStart) + 1
,(CHARINDEX(#SearchStringToStop,RIGHT(#string,LEN(#string) - CHARINDEX(#SearchStringToStart,#string) + 1 - LEN(#SearchStringToStart)))-2)
)
END
RETURN #string
END
if Input= pg102a-wlc01s.png.intel.com and Output should be pg102a-wlc01s
we can use below query :
select Substring(pc.name,0,charindex('.',pc.name,0)),pc.name from tbl_name pc
You can try this:
Declare #test varchar(100)='images/test.jpg'
Select REPLACE(RIGHT(#test,charindex('/',reverse(#test))-1),'.jpg','')
Below query gives you data before '-'
Ex- W12345A-4S
SELECT SUBSTRING(Column_Name,0, CHARINDEX('-',Column_Name)) as 'new_name'
from [abc].
Output - W12345A
Inspired by the work of Josien, I wondered about a simplification.
Would this also work? Much shorter:
SELECT SUBSTRING(col, CHARINDEX ('/', col) + 1, CHARINDEX ('.', col) - CHARINDEX ('/', col) - 1);
(I can't test right now because of right issues at my company SQL server, which is a problem in its own right)
Simply Try With LEFT ,RIGHT ,CHARINDEX
select
LEFT((RIGHT(a.name,((CHARINDEX('/', name))+1))),((CHARINDEX('.', (RIGHT(a.name,
((CHARINDEX('/', name))+1)))))-1)) splitstring,
a.name
from
(select 'images/test.jpg' as name)a
declare #searchStart nvarchar(100) = 'search ';
declare #searchEnd nvarchar(100) = ' ';
declare #string nvarchar(4000) = 'This is a string to search (hello) in this text ';
declare #startIndex int = CHARINDEX(#searchStart, #string,0) + LEN(#searchStart);
declare #endIndex int = CHARINDEX(#searchEnd, #string, #startIndex + 1);
declare #length int = #endIndex - #startIndex;
declare #sub nvarchar(4000) = SUBSTRING(#string, #startIndex, #length)
select #startIndex, #endIndex, #length, #sub
This is a little more legible than the one-liners in this answer which specifically answer the question, but not in a generic way that would benefit all readers. This could easily be made into a function as well with a slight modification.
If there are more than one or none occurences of given character use this:
DECLARE #rightidx int = CASE
WHEN 'images/images/test.jpg' IS NULL OR (CHARINDEX('.', 'images/images/test.jpg')) <= 0 THEN LEN('images/images/test.jpg')
ELSE (CHARINDEX('.', REVERSE('images/images/test.jpg')) - 1)
END
SELECT RIGHT('images/images/test.jpg', #rightidx)
This was the approach I took.
CREATE FUNCTION dbo.get_text_before_char(#my_string nvarchar(255),#my_char char(1))
RETURNS nvarchar(255)
AS
BEGIN;
return IIF(#my_string LIKE '%' + #my_char + '%',left (#my_string, IIF(charindex(#my_char, #my_string) - 1<1,1,charindex(#my_char, #my_string) - 1)),'');
END;
CREATE FUNCTION dbo.get_text_after_char(#my_string nvarchar(255),#my_char char(1))
RETURNS nvarchar(255)
AS
BEGIN;
return IIF ( #my_string LIKE '%' + #my_char + '%' ,RIGHT ( #my_string , IIF ( charindex ( #my_char ,reverse(#my_string) )-1 < 1 ,1 ,charindex ( #my_char ,reverse(#my_string) )-1 ) ) , '' )
END;
SELECT
dbo.get_text_before_char('foo-bar','-')
, dbo.get_text_after_char('foo-bar','-')
declare #test varchar(100)='images/test.jpg'
select right(left(#test, charindex('.', #test) - 1),4)
How do I remove the last character in a string in T-SQL?
For example:
'TEST STRING'
to return:
'TEST STRIN'
e.g.
DECLARE #String VARCHAR(100)
SET #String = 'TEST STRING'
-- Chop off the end character
SET #String =
CASE #String WHEN null THEN null
ELSE (
CASE LEN(#String) WHEN 0 THEN #String
ELSE LEFT(#String, LEN(#String) - 1)
END
) END
SELECT #String
If for some reason your column logic is complex (case when ... then ... else ... end), then the above solutions causes you to have to repeat the same logic in the len() function. Duplicating the same logic becomes a mess. If this is the case then this is a solution worth noting. This example gets rid of the last unwanted comma. I finally found a use for the REVERSE function.
select reverse(stuff(reverse('a,b,c,d,'), 1, 1, ''))
Try this:
select substring('test string', 1, (len('test string') - 1))
If your string is empty,
DECLARE #String VARCHAR(100)
SET #String = ''
SELECT LEFT(#String, LEN(#String) - 1)
then this code will cause error message 'Invalid length parameter passed to the substring function.'
You can handle it this way:
SELECT LEFT(#String, NULLIF(LEN(#String)-1,-1))
It will always return result, and NULL in case of empty string.
This will work even when source text/var is null or empty:
SELECT REVERSE(SUBSTRING(REVERSE(#a), 2, 9999))
select left('TEST STRING', len('TEST STRING')-1)
#result = substring(#result, 1, (LEN(#result)-1))
This is quite late, but interestingly never mentioned yet.
select stuff(x,len(x),1,'')
ie:
take a string x
go to its last character
remove one character
add nothing
If your coloumn is text and not varchar, then you can use this:
SELECT SUBSTRING(#String, 1, NULLIF(DATALENGTH(#String)-1,-1))
If you want to do this in two steps, rather than the three of REVERSE-STUFF-REVERSE, you can have your list separator be one or two spaces. Then use RTRIM to trim the trailing spaces, and REPLACE to replace the double spaces with ','
select REPLACE(RTRIM('a b c d '),' ', ', ')
However, this is not a good idea if your original string can contain internal spaces.
Not sure about performance. Each REVERSE creates a new copy of the string, but STUFF is a third faster than REPLACE.
also see this
I can suggest this -hack- ;).
select
left(txt, abs(len(txt + ',') - 2))
from
t;
SQL Server Fiddle Demo
you can create function
CREATE FUNCTION [dbo].[TRUNCRIGHT] (#string NVARCHAR(max), #len int = 1)
RETURNS NVARCHAR(max)
AS
BEGIN
IF LEN(#string)<#len
RETURN ''
RETURN LEFT(#string, LEN(#string) - #len)
END
Get the last character
Right(#string, len(#String) - (len(#String) - 1))
Try this
DECLARE #String VARCHAR(100)
SET #String = 'TEST STRING'
SELECT LEFT(#String, LEN(#String) - 1) AS MyTrimmedColumn
I encountered this problem and this way my problem was solved:
Declare #name as varchar(30)='TEST STRING'
Select left(#name, len(#name)-1) as AfterRemoveLastCharacter
My answer is similar to the accepted answer, but it also check for Null and Empty String.
DECLARE #String VARCHAR(100)
SET #String = 'asdfsdf1'
-- If string is null return null, else if string is empty return as it is, else chop off the end character
SET #String = Case #String when null then null else (case LEN(#String) when 0 then #String else LEFT(#String, LEN(#String) - 1) end ) end
SELECT #String
declare #string varchar(20)= 'TEST STRING'
Select left(#string, len(#string)-1) as Tada
output:
Tada
--------------------
TEST STRIN
I love #bill-hoenig 's answer; however, I was using a subquery and I got caught up because the REVERSE function needed two sets of parentheses. Took me a while to figure that one out!
SELECT
-- Return comma delimited list of all payment reasons for this Visit
REVERSE(STUFF(REVERSE((
SELECT DISTINCT
CAST(CONVERT(varchar, r1.CodeID) + ' - ' + c.Name + ', ' AS VARCHAR(MAX))
FROM VisitReason r1
LEFT JOIN ReasonCode c ON c.ID = r1.ReasonCodeID
WHERE p.ID = r1.PaymentID
FOR XML PATH('')
)), 1, 2, '')) ReasonCode
FROM Payments p
To update the record by trimming the last N characters of a particular column:
UPDATE tablename SET columnName = LEFT(columnName , LEN(columnName )-N) where clause
Try It :
DECLARE #String NVARCHAR(100)
SET #String = '12354851'
SELECT LEFT(#String, NULLIF(LEN(#String)-1,-1))
declare #x varchar(20),#y varchar(20)
select #x='sam'
select
case when #x is null then #y
when #y is null then #x
else #x+','+#y
end
go
declare #x varchar(20),#y varchar(20)
select #x='sam'
--,#y='john'
DECLARE #listStr VARCHAR(MAX)
SELECT #listStr = COALESCE(#x + ', ' ,'') +coalesce(#y+',','')
SELECT left(#listStr,len(#listStr)-1)
Try this,
DECLARE #name NVARCHAR(MAX) SET #name='xxxxTHAMIZHMANI****'SELECT Substring(#name, 5, (len(#name)-8)) as UserNames
And the output will be like, THAMIZHMANI
Using SQL Server, how do I split a string so I can access item x?
Take a string "Hello John Smith". How can I split the string by space and access the item at index 1 which should return "John"?
I don't believe SQL Server has a built-in split function, so other than a UDF, the only other answer I know is to hijack the PARSENAME function:
SELECT PARSENAME(REPLACE('Hello John Smith', ' ', '.'), 2)
PARSENAME takes a string and splits it on the period character. It takes a number as its second argument, and that number specifies which segment of the string to return (working from back to front).
SELECT PARSENAME(REPLACE('Hello John Smith', ' ', '.'), 3) --return Hello
Obvious problem is when the string already contains a period. I still think using a UDF is the best way...any other suggestions?
You may find the solution in SQL User Defined Function to Parse a Delimited String helpful (from The Code Project).
You can use this simple logic:
Declare #products varchar(200) = '1|20|3|343|44|6|8765'
Declare #individual varchar(20) = null
WHILE LEN(#products) > 0
BEGIN
IF PATINDEX('%|%', #products) > 0
BEGIN
SET #individual = SUBSTRING(#products,
0,
PATINDEX('%|%', #products))
SELECT #individual
SET #products = SUBSTRING(#products,
LEN(#individual + '|') + 1,
LEN(#products))
END
ELSE
BEGIN
SET #individual = #products
SET #products = NULL
SELECT #individual
END
END
First, create a function (using CTE, common table expression does away with the need for a temp table)
create function dbo.SplitString
(
#str nvarchar(4000),
#separator char(1)
)
returns table
AS
return (
with tokens(p, a, b) AS (
select
1,
1,
charindex(#separator, #str)
union all
select
p + 1,
b + 1,
charindex(#separator, #str, b + 1)
from tokens
where b > 0
)
select
p-1 zeroBasedOccurance,
substring(
#str,
a,
case when b > 0 then b-a ELSE 4000 end)
AS s
from tokens
)
GO
Then, use it as any table (or modify it to fit within your existing stored proc) like this.
select s
from dbo.SplitString('Hello John Smith', ' ')
where zeroBasedOccurance=1
Update
Previous version would fail for input string longer than 4000 chars. This version takes care of the limitation:
create function dbo.SplitString
(
#str nvarchar(max),
#separator char(1)
)
returns table
AS
return (
with tokens(p, a, b) AS (
select
cast(1 as bigint),
cast(1 as bigint),
charindex(#separator, #str)
union all
select
p + 1,
b + 1,
charindex(#separator, #str, b + 1)
from tokens
where b > 0
)
select
p-1 ItemIndex,
substring(
#str,
a,
case when b > 0 then b-a ELSE LEN(#str) end)
AS s
from tokens
);
GO
Usage remains the same.
Most of the solutions here use while loops or recursive CTEs. A set-based approach will be superior, I promise, if you can use a delimiter other than a space:
CREATE FUNCTION [dbo].[SplitString]
(
#List NVARCHAR(MAX),
#Delim VARCHAR(255)
)
RETURNS TABLE
AS
RETURN ( SELECT [Value], idx = RANK() OVER (ORDER BY n) FROM
(
SELECT n = Number,
[Value] = LTRIM(RTRIM(SUBSTRING(#List, [Number],
CHARINDEX(#Delim, #List + #Delim, [Number]) - [Number])))
FROM (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
FROM sys.all_objects) AS x
WHERE Number <= LEN(#List)
AND SUBSTRING(#Delim + #List, [Number], LEN(#Delim)) = #Delim
) AS y
);
Sample usage:
SELECT Value FROM dbo.SplitString('foo,bar,blat,foo,splunge',',')
WHERE idx = 3;
Results:
----
blat
You could also add the idx you want as an argument to the function, but I'll leave that as an exercise to the reader.
You can't do this with just the native STRING_SPLIT function added in SQL Server 2016, because there is no guarantee that the output will be rendered in the order of the original list. In other words, if you pass in 3,6,1 the result will likely be in that order, but it could be 1,3,6. I have asked for the community's help in improving the built-in function here:
Please help with STRING_SPLIT improvements
With enough qualitative feedback, they may actually consider making some of these enhancements:
STRING_SPLIT is not feature complete
More on split functions, why (and proof that) while loops and recursive CTEs don't scale, and better alternatives, if splitting strings coming from the application layer:
Split strings the right way – or the next best way
Splitting Strings : A Follow-Up
Splitting Strings : Now with less T-SQL
Comparing string splitting / concatenation methods
Processing a list of integers : my approach
Splitting a list of integers : another roundup
More on splitting lists : custom delimiters, preventing duplicates, and maintaining order
Removing Duplicates from Strings in SQL Server
On SQL Server 2016 or above, though, you should look at STRING_SPLIT() and STRING_AGG():
Performance Surprises and Assumptions : STRING_SPLIT()
STRING_SPLIT() in SQL Server 2016 : Follow-Up #1
STRING_SPLIT() in SQL Server 2016 : Follow-Up #2
SQL Server v.Next : STRING_AGG() performance
Solve old problems with SQL Server’s new STRING_AGG and STRING_SPLIT functions
You can leverage a Number table to do the string parsing.
Create a physical numbers table:
create table dbo.Numbers (N int primary key);
insert into dbo.Numbers
select top 1000 row_number() over(order by number) from master..spt_values
go
Create test table with 1000000 rows
create table #yak (i int identity(1,1) primary key, array varchar(50))
insert into #yak(array)
select 'a,b,c' from dbo.Numbers n cross join dbo.Numbers nn
go
Create the function
create function [dbo].[ufn_ParseArray]
( #Input nvarchar(4000),
#Delimiter char(1) = ',',
#BaseIdent int
)
returns table as
return
( select row_number() over (order by n asc) + (#BaseIdent - 1) [i],
substring(#Input, n, charindex(#Delimiter, #Input + #Delimiter, n) - n) s
from dbo.Numbers
where n <= convert(int, len(#Input)) and
substring(#Delimiter + #Input, n, 1) = #Delimiter
)
go
Usage (outputs 3mil rows in 40s on my laptop)
select *
from #yak
cross apply dbo.ufn_ParseArray(array, ',', 1)
cleanup
drop table dbo.Numbers;
drop function [dbo].[ufn_ParseArray]
Performance here is not amazing, but calling a function over a million row table is not the best idea. If performing a string split over many rows I would avoid the function.
This question is not about a string split approach, but about how to get the nth element.
All answers here are doing some kind of string splitting using recursion, CTEs, multiple CHARINDEX, REVERSE and PATINDEX, inventing functions, call for CLR methods, number tables, CROSS APPLYs ... Most answers cover many lines of code.
But - if you really want nothing more than an approach to get the nth element - this can be done as real one-liner, no UDF, not even a sub-select... And as an extra benefit: type safe
Get part 2 delimited by a space:
DECLARE #input NVARCHAR(100)=N'part1 part2 part3';
SELECT CAST(N'<x>' + REPLACE(#input,N' ',N'</x><x>') + N'</x>' AS XML).value('/x[2]','nvarchar(max)')
Of course you can use variables for delimiter and position (use sql:column to retrieve the position directly from a query's value):
DECLARE #dlmt NVARCHAR(10)=N' ';
DECLARE #pos INT = 2;
SELECT CAST(N'<x>' + REPLACE(#input,#dlmt,N'</x><x>') + N'</x>' AS XML).value('/x[sql:variable("#pos")][1]','nvarchar(max)')
If your string might include forbidden characters (especially one among &><), you still can do it this way. Just use FOR XML PATH on your string first to replace all forbidden characters with the fitting escape sequence implicitly.
It's a very special case if - additionally - your delimiter is the semicolon. In this case I replace the delimiter first to '#DLMT#', and replace this to the XML tags finally:
SET #input=N'Some <, > and &;Other äöü#€;One more';
SET #dlmt=N';';
SELECT CAST(N'<x>' + REPLACE((SELECT REPLACE(#input,#dlmt,'#DLMT#') AS [*] FOR XML PATH('')),N'#DLMT#',N'</x><x>') + N'</x>' AS XML).value('/x[sql:variable("#pos")][1]','nvarchar(max)');
UPDATE for SQL-Server 2016+
Regretfully the developers forgot to return the part's index with STRING_SPLIT. But, using SQL-Server 2016+, there is JSON_VALUE and OPENJSON.
With JSON_VALUE we can pass in the position as the index' array.
For OPENJSON the documentation states clearly:
When OPENJSON parses a JSON array, the function returns the indexes of the elements in the JSON text as keys.
A string like 1,2,3 needs nothing more than brackets: [1,2,3].
A string of words like this is an example needs to be ["this","is","an","example"].
These are very easy string operations. Just try it out:
DECLARE #str VARCHAR(100)='Hello John Smith';
DECLARE #position INT = 2;
--We can build the json-path '$[1]' using CONCAT
SELECT JSON_VALUE('["' + REPLACE(#str,' ','","') + '"]',CONCAT('$[',#position-1,']'));
--See this for a position safe string-splitter (zero-based):
SELECT JsonArray.[key] AS [Position]
,JsonArray.[value] AS [Part]
FROM OPENJSON('["' + REPLACE(#str,' ','","') + '"]') JsonArray
In this post I tested various approaches and found, that OPENJSON is really fast. Even much faster than the famous "delimitedSplit8k()" method...
UPDATE 2 - Get the values type-safe
We can use an array within an array simply by using doubled [[]]. This allows for a typed WITH-clause:
DECLARE #SomeDelimitedString VARCHAR(100)='part1|1|20190920';
DECLARE #JsonArray NVARCHAR(MAX)=CONCAT('[["',REPLACE(#SomeDelimitedString,'|','","'),'"]]');
SELECT #SomeDelimitedString AS TheOriginal
,#JsonArray AS TransformedToJSON
,ValuesFromTheArray.*
FROM OPENJSON(#JsonArray)
WITH(TheFirstFragment VARCHAR(100) '$[0]'
,TheSecondFragment INT '$[1]'
,TheThirdFragment DATE '$[2]') ValuesFromTheArray
Here is a UDF which will do it. It will return a table of the delimited values, haven't tried all scenarios on it but your example works fine.
CREATE FUNCTION SplitString
(
-- Add the parameters for the function here
#myString varchar(500),
#deliminator varchar(10)
)
RETURNS
#ReturnTable TABLE
(
-- Add the column definitions for the TABLE variable here
[id] [int] IDENTITY(1,1) NOT NULL,
[part] [varchar](50) NULL
)
AS
BEGIN
Declare #iSpaces int
Declare #part varchar(50)
--initialize spaces
Select #iSpaces = charindex(#deliminator,#myString,0)
While #iSpaces > 0
Begin
Select #part = substring(#myString,0,charindex(#deliminator,#myString,0))
Insert Into #ReturnTable(part)
Select #part
Select #myString = substring(#mystring,charindex(#deliminator,#myString,0)+ len(#deliminator),len(#myString) - charindex(' ',#myString,0))
Select #iSpaces = charindex(#deliminator,#myString,0)
end
If len(#myString) > 0
Insert Into #ReturnTable
Select #myString
RETURN
END
GO
You would call it like this:
Select * From SplitString('Hello John Smith',' ')
Edit: Updated solution to handle delimters with a len>1 as in :
select * From SplitString('Hello**John**Smith','**')
Here I post a simple way of solution
CREATE FUNCTION [dbo].[split](
#delimited NVARCHAR(MAX),
#delimiter NVARCHAR(100)
) RETURNS #t TABLE (id INT IDENTITY(1,1), val NVARCHAR(MAX))
AS
BEGIN
DECLARE #xml XML
SET #xml = N'<t>' + REPLACE(#delimited,#delimiter,'</t><t>') + '</t>'
INSERT INTO #t(val)
SELECT r.value('.','varchar(MAX)') as item
FROM #xml.nodes('/t') as records(r)
RETURN
END
Execute the function like this
select * from dbo.split('Hello John Smith',' ')
In my opinion you guys are making it way too complicated. Just create a CLR UDF and be done with it.
using System;
using System.Data;
using System.Data.SqlClient;
using System.Data.SqlTypes;
using Microsoft.SqlServer.Server;
using System.Collections.Generic;
public partial class UserDefinedFunctions {
[SqlFunction]
public static SqlString SearchString(string Search) {
List<string> SearchWords = new List<string>();
foreach (string s in Search.Split(new char[] { ' ' })) {
if (!s.ToLower().Equals("or") && !s.ToLower().Equals("and")) {
SearchWords.Add(s);
}
}
return new SqlString(string.Join(" OR ", SearchWords.ToArray()));
}
};
What about using string and values() statement?
DECLARE #str varchar(max)
SET #str = 'Hello John Smith'
DECLARE #separator varchar(max)
SET #separator = ' '
DECLARE #Splited TABLE(id int IDENTITY(1,1), item varchar(max))
SET #str = REPLACE(#str, #separator, '''),(''')
SET #str = 'SELECT * FROM (VALUES(''' + #str + ''')) AS V(A)'
INSERT INTO #Splited
EXEC(#str)
SELECT * FROM #Splited
Result-set achieved.
id item
1 Hello
2 John
3 Smith
I use the answer of frederic but this did not work in SQL Server 2005
I modified it and I'm using select with union all and it works
DECLARE #str varchar(max)
SET #str = 'Hello John Smith how are you'
DECLARE #separator varchar(max)
SET #separator = ' '
DECLARE #Splited table(id int IDENTITY(1,1), item varchar(max))
SET #str = REPLACE(#str, #separator, ''' UNION ALL SELECT ''')
SET #str = ' SELECT ''' + #str + ''' '
INSERT INTO #Splited
EXEC(#str)
SELECT * FROM #Splited
And the result-set is:
id item
1 Hello
2 John
3 Smith
4 how
5 are
6 you
This pattern works fine and you can generalize
Convert(xml,'<n>'+Replace(FIELD,'.','</n><n>')+'</n>').value('(/n[INDEX])','TYPE')
^^^^^ ^^^^^ ^^^^
note FIELD, INDEX and TYPE.
Let some table with identifiers like
sys.message.1234.warning.A45
sys.message.1235.error.O98
....
Then, you can write
SELECT Source = q.value('(/n[1])', 'varchar(10)'),
RecordType = q.value('(/n[2])', 'varchar(20)'),
RecordNumber = q.value('(/n[3])', 'int'),
Status = q.value('(/n[4])', 'varchar(5)')
FROM (
SELECT q = Convert(xml,'<n>'+Replace(fieldName,'.','</n><n>')+'</n>')
FROM some_TABLE
) Q
splitting and casting all parts.
Yet another get n'th part of string by delimeter function:
create function GetStringPartByDelimeter (
#value as nvarchar(max),
#delimeter as nvarchar(max),
#position as int
) returns NVARCHAR(MAX)
AS BEGIN
declare #startPos as int
declare #endPos as int
set #endPos = -1
while (#position > 0 and #endPos != 0) begin
set #startPos = #endPos + 1
set #endPos = charindex(#delimeter, #value, #startPos)
if(#position = 1) begin
if(#endPos = 0)
set #endPos = len(#value) + 1
return substring(#value, #startPos, #endPos - #startPos)
end
set #position = #position - 1
end
return null
end
and the usage:
select dbo.GetStringPartByDelimeter ('a;b;c;d;e', ';', 3)
which returns:
c
If your database has compatibility level of 130 or higher then you can use the STRING_SPLIT function along with OFFSET FETCH clauses to get the specific item by index.
To get the item at index N (zero based), you can use the following code
SELECT value
FROM STRING_SPLIT('Hello John Smith',' ')
ORDER BY (SELECT NULL)
OFFSET N ROWS
FETCH NEXT 1 ROWS ONLY
To check the compatibility level of your database, execute this code:
SELECT compatibility_level
FROM sys.databases WHERE name = 'YourDBName';
Try this:
CREATE function [SplitWordList]
(
#list varchar(8000)
)
returns #t table
(
Word varchar(50) not null,
Position int identity(1,1) not null
)
as begin
declare
#pos int,
#lpos int,
#item varchar(100),
#ignore varchar(100),
#dl int,
#a1 int,
#a2 int,
#z1 int,
#z2 int,
#n1 int,
#n2 int,
#c varchar(1),
#a smallint
select
#a1 = ascii('a'),
#a2 = ascii('A'),
#z1 = ascii('z'),
#z2 = ascii('Z'),
#n1 = ascii('0'),
#n2 = ascii('9')
set #ignore = '''"'
set #pos = 1
set #dl = datalength(#list)
set #lpos = 1
set #item = ''
while (#pos <= #dl) begin
set #c = substring(#list, #pos, 1)
if (#ignore not like '%' + #c + '%') begin
set #a = ascii(#c)
if ((#a >= #a1) and (#a <= #z1))
or ((#a >= #a2) and (#a <= #z2))
or ((#a >= #n1) and (#a <= #n2))
begin
set #item = #item + #c
end else if (#item > '') begin
insert into #t values (#item)
set #item = ''
end
end
set #pos = #pos + 1
end
if (#item > '') begin
insert into #t values (#item)
end
return
end
Test it like this:
select * from SplitWordList('Hello John Smith')
I was looking for the solution on net and the below works for me.
Ref.
And you call the function like this :
SELECT * FROM dbo.split('ram shyam hari gopal',' ')
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[Split](#String VARCHAR(8000), #Delimiter CHAR(1))
RETURNS #temptable TABLE (items VARCHAR(8000))
AS
BEGIN
DECLARE #idx INT
DECLARE #slice VARCHAR(8000)
SELECT #idx = 1
IF len(#String)<1 OR #String IS NULL RETURN
WHILE #idx!= 0
BEGIN
SET #idx = charindex(#Delimiter,#String)
IF #idx!=0
SET #slice = LEFT(#String,#idx - 1)
ELSE
SET #slice = #String
IF(len(#slice)>0)
INSERT INTO #temptable(Items) VALUES(#slice)
SET #String = RIGHT(#String,len(#String) - #idx)
IF len(#String) = 0 break
END
RETURN
END
The following example uses a recursive CTE
Update 18.09.2013
CREATE FUNCTION dbo.SplitStrings_CTE(#List nvarchar(max), #Delimiter nvarchar(1))
RETURNS #returns TABLE (val nvarchar(max), [level] int, PRIMARY KEY CLUSTERED([level]))
AS
BEGIN
;WITH cte AS
(
SELECT SUBSTRING(#List, 0, CHARINDEX(#Delimiter, #List + #Delimiter)) AS val,
CAST(STUFF(#List + #Delimiter, 1, CHARINDEX(#Delimiter, #List + #Delimiter), '') AS nvarchar(max)) AS stval,
1 AS [level]
UNION ALL
SELECT SUBSTRING(stval, 0, CHARINDEX(#Delimiter, stval)),
CAST(STUFF(stval, 1, CHARINDEX(#Delimiter, stval), '') AS nvarchar(max)),
[level] + 1
FROM cte
WHERE stval != ''
)
INSERT #returns
SELECT REPLACE(val, ' ','' ) AS val, [level]
FROM cte
WHERE val > ''
RETURN
END
Demo on SQLFiddle
Alter Function dbo.fn_Split
(
#Expression nvarchar(max),
#Delimiter nvarchar(20) = ',',
#Qualifier char(1) = Null
)
RETURNS #Results TABLE (id int IDENTITY(1,1), value nvarchar(max))
AS
BEGIN
/* USAGE
Select * From dbo.fn_Split('apple pear grape banana orange honeydew cantalope 3 2 1 4', ' ', Null)
Select * From dbo.fn_Split('1,abc,"Doe, John",4', ',', '"')
Select * From dbo.fn_Split('Hello 0,"&""&&&&', ',', '"')
*/
-- Declare Variables
DECLARE
#X xml,
#Temp nvarchar(max),
#Temp2 nvarchar(max),
#Start int,
#End int
-- HTML Encode #Expression
Select #Expression = (Select #Expression For XML Path(''))
-- Find all occurences of #Delimiter within #Qualifier and replace with |||***|||
While PATINDEX('%' + #Qualifier + '%', #Expression) > 0 AND Len(IsNull(#Qualifier, '')) > 0
BEGIN
Select
-- Starting character position of #Qualifier
#Start = PATINDEX('%' + #Qualifier + '%', #Expression),
-- #Expression starting at the #Start position
#Temp = SubString(#Expression, #Start + 1, LEN(#Expression)-#Start+1),
-- Next position of #Qualifier within #Expression
#End = PATINDEX('%' + #Qualifier + '%', #Temp) - 1,
-- The part of Expression found between the #Qualifiers
#Temp2 = Case When #End < 0 Then #Temp Else Left(#Temp, #End) End,
-- New #Expression
#Expression = REPLACE(#Expression,
#Qualifier + #Temp2 + Case When #End < 0 Then '' Else #Qualifier End,
Replace(#Temp2, #Delimiter, '|||***|||')
)
END
-- Replace all occurences of #Delimiter within #Expression with '</fn_Split><fn_Split>'
-- And convert it to XML so we can select from it
SET
#X = Cast('<fn_Split>' +
Replace(#Expression, #Delimiter, '</fn_Split><fn_Split>') +
'</fn_Split>' as xml)
-- Insert into our returnable table replacing '|||***|||' back to #Delimiter
INSERT #Results
SELECT
"Value" = LTRIM(RTrim(Replace(C.value('.', 'nvarchar(max)'), '|||***|||', #Delimiter)))
FROM
#X.nodes('fn_Split') as X(C)
-- Return our temp table
RETURN
END
You can split a string in SQL without needing a function:
DECLARE #bla varchar(MAX)
SET #bla = 'BED40DFC-F468-46DD-8017-00EF2FA3E4A4,64B59FC5-3F4D-4B0E-9A48-01F3D4F220B0,A611A108-97CA-42F3-A2E1-057165339719,E72D95EA-578F-45FC-88E5-075F66FD726C'
-- http://stackoverflow.com/questions/14712864/how-to-query-values-from-xml-nodes
SELECT
x.XmlCol.value('.', 'varchar(36)') AS val
FROM
(
SELECT
CAST('<e>' + REPLACE(#bla, ',', '</e><e>') + '</e>' AS xml) AS RawXml
) AS b
CROSS APPLY b.RawXml.nodes('e') x(XmlCol);
If you need to support arbitrary strings (with xml special characters)
DECLARE #bla NVARCHAR(MAX)
SET #bla = '<html>unsafe & safe Utf8CharsDon''tGetEncoded ÄöÜ - "Conex"<html>,Barnes & Noble,abc,def,ghi'
-- http://stackoverflow.com/questions/14712864/how-to-query-values-from-xml-nodes
SELECT
x.XmlCol.value('.', 'nvarchar(MAX)') AS val
FROM
(
SELECT
CAST('<e>' + REPLACE((SELECT #bla FOR XML PATH('')), ',', '</e><e>') + '</e>' AS xml) AS RawXml
) AS b
CROSS APPLY b.RawXml.nodes('e') x(XmlCol);
In Azure SQL Database (based on Microsoft SQL Server but not exactly the same thing) the signature of STRING_SPLIT function looks like:
STRING_SPLIT ( string , separator [ , enable_ordinal ] )
When enable_ordinal flag is set to 1 the result will include a column named ordinal that consists of the 1‑based position of the substring within the input string:
SELECT *
FROM STRING_SPLIT('hello john smith', ' ', 1)
| value | ordinal |
|-------|---------|
| hello | 1 |
| john | 2 |
| smith | 3 |
This allows us to do this:
SELECT value
FROM STRING_SPLIT('hello john smith', ' ', 1)
WHERE ordinal = 2
| value |
|-------|
| john |
If enable_ordinal is not available then there is a trick which assumes that the substrings within the input string are unique. In this scenario, CHAR_INDEX could be used to find the position of the substring within the input string:
SELECT value, ROW_NUMBER() OVER (ORDER BY CHARINDEX(value, input_str)) AS ord_pos
FROM (VALUES
('hello john smith')
) AS x(input_str)
CROSS APPLY STRING_SPLIT(input_str, ' ')
| value | ord_pos |
|-------+---------|
| hello | 1 |
| john | 2 |
| smith | 3 |
I know it's an old Question, but i think some one can benefit from my solution.
select
SUBSTRING(column_name,1,CHARINDEX(' ',column_name,1)-1)
,SUBSTRING(SUBSTRING(column_name,CHARINDEX(' ',column_name,1)+1,LEN(column_name))
,1
,CHARINDEX(' ',SUBSTRING(column_name,CHARINDEX(' ',column_name,1)+1,LEN(column_name)),1)-1)
,SUBSTRING(SUBSTRING(column_name,CHARINDEX(' ',column_name,1)+1,LEN(column_name))
,CHARINDEX(' ',SUBSTRING(column_name,CHARINDEX(' ',column_name,1)+1,LEN(column_name)),1)+1
,LEN(column_name))
from table_name
SQL FIDDLE
Advantages:
It separates all the 3 sub-strings deliminator by ' '.
One must not use while loop, as it decreases the performance.
No need to Pivot as all the resultant sub-string will be displayed in
one Row
Limitations:
One must know the total no. of spaces (sub-string).
Note: the solution can give sub-string up to to N.
To overcame the limitation we can use the following ref.
But again the above solution can't be use in a table (Actaully i wasn't able to use it).
Again i hope this solution can help some-one.
Update: In case of Records > 50000 it is not advisable to use LOOPS as it will degrade the Performance
Pure set-based solution using TVF with recursive CTE. You can JOIN and APPLY this function to any dataset.
create function [dbo].[SplitStringToResultSet] (#value varchar(max), #separator char(1))
returns table
as return
with r as (
select value, cast(null as varchar(max)) [x], -1 [no] from (select rtrim(cast(#value as varchar(max))) [value]) as j
union all
select right(value, len(value)-case charindex(#separator, value) when 0 then len(value) else charindex(#separator, value) end) [value]
, left(r.[value], case charindex(#separator, r.value) when 0 then len(r.value) else abs(charindex(#separator, r.[value])-1) end ) [x]
, [no] + 1 [no]
from r where value > '')
select ltrim(x) [value], [no] [index] from r where x is not null;
go
Usage:
select *
from [dbo].[SplitStringToResultSet]('Hello John Smith', ' ')
where [index] = 1;
Result:
value index
-------------
John 1
Almost all the other answers are replacing the string being split which wastes CPU cycles and performs unnecessary memory allocations.
I cover a much better way to do a string split here: http://www.digitalruby.com/split-string-sql-server/
Here is the code:
SET NOCOUNT ON
-- You will want to change nvarchar(MAX) to nvarchar(50), varchar(50) or whatever matches exactly with the string column you will be searching against
DECLARE #SplitStringTable TABLE (Value nvarchar(MAX) NOT NULL)
DECLARE #StringToSplit nvarchar(MAX) = 'your|string|to|split|here'
DECLARE #SplitEndPos int
DECLARE #SplitValue nvarchar(MAX)
DECLARE #SplitDelim nvarchar(1) = '|'
DECLARE #SplitStartPos int = 1
SET #SplitEndPos = CHARINDEX(#SplitDelim, #StringToSplit, #SplitStartPos)
WHILE #SplitEndPos > 0
BEGIN
SET #SplitValue = SUBSTRING(#StringToSplit, #SplitStartPos, (#SplitEndPos - #SplitStartPos))
INSERT #SplitStringTable (Value) VALUES (#SplitValue)
SET #SplitStartPos = #SplitEndPos + 1
SET #SplitEndPos = CHARINDEX(#SplitDelim, #StringToSplit, #SplitStartPos)
END
SET #SplitValue = SUBSTRING(#StringToSplit, #SplitStartPos, 2147483647)
INSERT #SplitStringTable (Value) VALUES(#SplitValue)
SET NOCOUNT OFF
-- You can select or join with the values in #SplitStringTable at this point.
Recursive CTE solution with server pain, test it
MS SQL Server 2008 Schema Setup:
create table Course( Courses varchar(100) );
insert into Course values ('Hello John Smith');
Query 1:
with cte as
( select
left( Courses, charindex( ' ' , Courses) ) as a_l,
cast( substring( Courses,
charindex( ' ' , Courses) + 1 ,
len(Courses ) ) + ' '
as varchar(100) ) as a_r,
Courses as a,
0 as n
from Course t
union all
select
left(a_r, charindex( ' ' , a_r) ) as a_l,
substring( a_r, charindex( ' ' , a_r) + 1 , len(a_R ) ) as a_r,
cte.a,
cte.n + 1 as n
from Course t inner join cte
on t.Courses = cte.a and len( a_r ) > 0
)
select a_l, n from cte
--where N = 1
Results:
| A_L | N |
|--------|---|
| Hello | 0 |
| John | 1 |
| Smith | 2 |
while similar to the xml based answer by josejuan, i found that processing the xml path only once, then pivoting was moderately more efficient:
select ID,
[3] as PathProvidingID,
[4] as PathProvider,
[5] as ComponentProvidingID,
[6] as ComponentProviding,
[7] as InputRecievingID,
[8] as InputRecieving,
[9] as RowsPassed,
[10] as InputRecieving2
from
(
select id,message,d.* from sysssislog cross apply (
SELECT Item = y.i.value('(./text())[1]', 'varchar(200)'),
row_number() over(order by y.i) as rn
FROM
(
SELECT x = CONVERT(XML, '<i>' + REPLACE(Message, ':', '</i><i>') + '</i>').query('.')
) AS a CROSS APPLY x.nodes('i') AS y(i)
) d
WHERE event
=
'OnPipelineRowsSent'
) as tokens
pivot
( max(item) for [rn] in ([3],[4],[5],[6],[7],[8],[9],[10])
) as data
ran in 8:30
select id,
tokens.value('(/n[3])', 'varchar(100)')as PathProvidingID,
tokens.value('(/n[4])', 'varchar(100)') as PathProvider,
tokens.value('(/n[5])', 'varchar(100)') as ComponentProvidingID,
tokens.value('(/n[6])', 'varchar(100)') as ComponentProviding,
tokens.value('(/n[7])', 'varchar(100)') as InputRecievingID,
tokens.value('(/n[8])', 'varchar(100)') as InputRecieving,
tokens.value('(/n[9])', 'varchar(100)') as RowsPassed
from
(
select id, Convert(xml,'<n>'+Replace(message,'.','</n><n>')+'</n>') tokens
from sysssislog
WHERE event
=
'OnPipelineRowsSent'
) as data
ran in 9:20
CREATE FUNCTION [dbo].[fnSplitString]
(
#string NVARCHAR(MAX),
#delimiter CHAR(1)
)
RETURNS #output TABLE(splitdata NVARCHAR(MAX)
)
BEGIN
DECLARE #start INT, #end INT
SELECT #start = 1, #end = CHARINDEX(#delimiter, #string)
WHILE #start < LEN(#string) + 1 BEGIN
IF #end = 0
SET #end = LEN(#string) + 1
INSERT INTO #output (splitdata)
VALUES(SUBSTRING(#string, #start, #end - #start))
SET #start = #end + 1
SET #end = CHARINDEX(#delimiter, #string, #start)
END
RETURN
END
AND USE IT
select *from dbo.fnSplitString('Querying SQL Server','')
if anyone wants to get only one part of the seperatured text can use this
select * from fromSplitStringSep('Word1 wordr2 word3',' ')
CREATE function [dbo].[SplitStringSep]
(
#str nvarchar(4000),
#separator char(1)
)
returns table
AS
return (
with tokens(p, a, b) AS (
select
1,
1,
charindex(#separator, #str)
union all
select
p + 1,
b + 1,
charindex(#separator, #str, b + 1)
from tokens
where b > 0
)
select
p-1 zeroBasedOccurance,
substring(
#str,
a,
case when b > 0 then b-a ELSE 4000 end)
AS s
from tokens
)
I devoloped this,
declare #x nvarchar(Max) = 'ali.veli.deli.';
declare #item nvarchar(Max);
declare #splitter char='.';
while CHARINDEX(#splitter,#x) != 0
begin
set #item = LEFT(#x,CHARINDEX(#splitter,#x))
set #x = RIGHT(#x,len(#x)-len(#item) )
select #item as item, #x as x;
end
the only attention you should is dot '.' that end of the #x is always should be there.
building on #NothingsImpossible solution, or, rather, comment on the most voted answer (just below the accepted one), i found the following quick-and-dirty solution fulfill my own needs - it has a benefit of being solely within SQL domain.
given a string "first;second;third;fourth;fifth", say, I want to get the third token. this works only if we know how many tokens the string is going to have - in this case it's 5. so my way of action is to chop the last two tokens away (inner query), and then to chop the first two tokens away (outer query)
i know that this is ugly and covers the specific conditions i was in, but am posting it just in case somebody finds it useful. cheers
select
REVERSE(
SUBSTRING(
reverse_substring,
0,
CHARINDEX(';', reverse_substring)
)
)
from
(
select
msg,
SUBSTRING(
REVERSE(msg),
CHARINDEX(
';',
REVERSE(msg),
CHARINDEX(
';',
REVERSE(msg)
)+1
)+1,
1000
) reverse_substring
from
(
select 'first;second;third;fourth;fifth' msg
) a
) b
declare #strng varchar(max)='hello john smith'
select (
substring(
#strng,
charindex(' ', #strng) + 1,
(
(charindex(' ', #strng, charindex(' ', #strng) + 1))
- charindex(' ',#strng)
)
))