I have a table:
Vers | Rev
3 | A
7 | B
13 | C
And a second table:
Info | Version
aab | 1
adr | 2
bhj | 3
bgt | 4
nnh | 4
ggt | 7
I need to have a table:
Info | Version | Rev
aab | 1 | A
adr | 2 | A
bhj | 3 | A
bgt | 4 | B
nnh | 4 | B
ggt | 7 | B
How do I achieve the final table?
Rev A is for Versions 1-3, Rev B is versions 4-7, Rev C is versions 5-13.
If I were trying to do this with VB Excel, I would add a 1 in a new column. Then get the first Vers value (3) - second Vers value (7) then output 4....
Then I would use some logic If <= new column and >= Vers write Rev.
I don't know how to do this in SQL and I need to!
Try this you can do it by joining tables
select
t2.Info Info
,t2.Version Version
,t1.Rev Rev
from table1 t1,table2 t2
where t2.Version=t1.Vers;
Use outer apply:
select t2.*, t1.rev
from table2 t2 outer apply
(select top (1) t1.*
from table1 t1
where t2.version <= t1.vers
order by t1.vers asc
) t1;
This gets the "next" version in table1 relative to each version in table2.
You can also do this with a subquery:
SELECT *
, (SELECT TOP 1 b.rev
FROM Table1 b
WHERE a.version <= b.vers
ORDER BY b.vers)
FROM Table2 a
Or a third version:
declare #t1 table(V int, R char(1))
insert #t1 values (3,'A'),(7,'B'),(13,'C')
declare #t2 table(I char(3), V int)
insert #t2 values ('aab',1),('adr',2),('bhj',3),('bgt',4),('nnh',4),('ggt',7)
select t2.*, t1.R
from #t2 t2
join #t1 t1 on t1.V>=t2.V and not exists(select * from #t1 t3 where t3.V>=t2.v and t3.V<t1.V)
Related
I have two tables of data which I can join using a left join linked on the ID in both tables. Where the course and the person are the same, I need to populate the RegNumber as the same as the RegNumber which is already there for 1 row:
How it is currently: if I join table 1 and table 2 with a left join.
Table 1
ID | Course| Person
67705 | A | 1
68521 | A | 1
85742 | A | 1
89625 | A | 1
67857 | B | 2
86694 | B | 2
88075 | B | 2
88710 | C | 3
47924 | C | 3
66981 | C | 3
12311 | B | 1
12312 | B | 1
12313 | B | 1
Table 2
ID | RegNumber
67705 | N712316
NULL | NULL
NULL | NULL
NULL | NULL
67857 | N712338
NULL | NULL
NULL | NULL
NULL | NULL
47924 | M481035
NULL | NULL
12311 | N645525
NULL | NULL
NULL | NULL
I need table 2 to look like this:
ID | RegNumber
67705 | N712316
68521 | N712316
85742 | N712316
89625 | N712316
67857 | N712338
86694 | N712338
88075 | N712338
88710 | N712338
47924 | M481035
66981 | M481035
12311 | N645525
12312 | N645525
12313 | N645525
That is, I need to insert new rows into Table 2
Can anyone help me please? This is Totally beyond my capability!
insert into table2 (ID,RegNumber)
select t1.ID,reg.regNumber
from table1 t1
cross join (select top 1 regNumber from table2 r2 join table1 r1
on r1.Id = r2.Id
and r1.Course = t1.Course
and r1.Person = t1.person
order by id) reg
where not exists (select 1 from table2 t2 where t1.ID = t2.ID)
you can improve performance a little bit by loading data into temp table first :
select t1.ID , Course,Person,regNumber
into #LoadedData
from table1 t1
join table2 t2 on t1.Id = t2.ID
insert into table2 (ID,RegNumber)
select t1.ID,reg.regNumber
from table1 t1
cross join (select top 1 regNumber from #LoadedData l
where l.Course = t1.Course
and l.Person = t1.person
order by id) reg
where not exists (select 1 from #LoadedData l where t1.ID = l.ID)
in either case having an index on (ID, Course, Person) will help with performance
Assuming:
You are missing items in table 2 that inherit data from other records in table 1.
What makes two different IDs share the same Regnumber is to have BOTH course and person number in common.
You really need to join table 1 to itself to create the mapping that associates ID 67705 with ID 68521, then you can join in table 2 to pick up the Regnumber.
Try this:
Insert into table2 (ID,RegNumber)
Select right1.ID, left2.RegNumber
From (
(table2 left2 INNER JOIN
table1 left1 On (left1.ID=left2.ID)
INNER JOIN table1 right1 On (left1.Course=right1.Course AND left1.Person=right1.Person)
) LEFT OUTER JOIN table2 right2 On (right1.ID=right2.ID)
WHERE right2.ID Is Null
The 4th table join (alias right2) is purely defensive, to handle two records in table2 having identical Person & Course in table1.
I have solved this myself.
I concatenated the person and course columns and then joined them using that new concatenated field
insert into table 2 (ID,RegNumber)
select X1.ID,X2.Regnumber
from (select concat(course,person) as X,ID from table1) X1
join (select concat(t1.course,t1.person) as X, t2.RegNumber
from table1 t1
join table2 t2 on t1.ID = t2.ID) X2
on X1.X = X2.X
where X1.ID not in (select ID from table2)
I have two tables:
TABLE1
id_attr
-------
1
2
3
TABLE2
id | id_attr | val
----------------------
10 | 1 | A
10 | 2 | B
As a result I want a table that show:
RESULT
id | id_attr | val
----------------------
10 | 1 | A
10 | 2 | B
10 | 3 | NULL
So I want the row with id=10 and id_attr=3 also when id_Attr=3 is missing in TABLE2 (and I know that because I have a NULL value (or something else) in the val column of RESULT.
NB: I could have others ids in table2. For example, after insert this row on table2: {11,1,A}, as RESULT I want:
id | id_attr | val
----------------------
10 | 1 | A
10 | 2 | B
10 | 3 | NULL
11 | 1 | A
11 | 2 | NULL
11 | 3 | NULL
So, for every id, I want always the match with all id_attr.
Your specific example only has one id, so you can use the following:
select t2.id, t2.id_attr, t2.val
from table2 t2
union all
select 10, t1.id_attr, NULL
from table1 t1
where not exists (select 1 from table2 t2 where t2.id_attr = t1.id_attr);
EDIT:
You can get all combinations of attributes and ids in the following way. Use a cross join to create all the rows you want and then a left join to bring in the data you want:
select i.id, t1.id_attr, t2.val
from (select distinct id from table2) i cross join
table1 t1 left join
table2 t2
on t2.id = i.id and t2.id_attr = t1.id_attr;
It sounds like you want to do just an outer join on id_attr instead of id.
select * from table2 t2
left outer join table1 t1 on t2.id_attr = t1.id_attr;
I have 2 tables ex. TABLE1 and TABLE2
TABLE1 TABLE2
ID | SIZE | VALUE ID | SIZE | SCORE
1 | LOW | 1.0 1 | MID | 3232
2 | MID | 3.0 2 | MID | 2321
3 | HIGH | 5.0 3 | HIGH | 3232
what i want is to update TABLE2.SCORE so the values will be TABLE1.value column and the join to be SIZE.
OUTPUT:
ID | SIZE | SCORE
1 | MID | 3.0
2 | MID | 3.0
3 | HIGH | 5.0
I tried:
Update Table2 set SCORE=(select top(1) VALUE from TABLE1 join TABLE2 on table1.size=table2.size ) however this does not work I get this result:
OUTPUT:
ID | SIZE | SCORE
1 | MID | 3.0
2 | MID | 3.0
3 | HIGH | 3.0 <---- wrong
Try this
DECLARE #TABLE1 AS TABLE(ID INT , SIZE VARCHAR(10) , VALUE decimal(2,1))
INSERT INTO #TABLE1
SELECT 1 , 'LOW' , 1.0 UNION ALL
SELECT 2 , 'MID' , 3.0 UNION ALL
SELECT 3 , 'HIGH' , 5.0
DECLARE #TABLE2 AS TABLE(ID INT , SIZE VARCHAR(10) , SCORE INT)
INSERT INTO #TABLE2
SELECT 1 , 'MID' , 3232 UNION ALL
SELECT 2 , 'MID' , 2321 UNION ALL
SELECT 3 , 'HIGH' , 3232
SELECT * FROM #TABLE2
UPDATE t2
SET SCORE=t1.VALUE
FROM #TABLE2 t2 inner join #TABLE1 t1 On t1.SIZE=t2.SIZE
SELECT ID,SIZE, CAST(SCORE AS DECIMAL(2,1)) AS SCORE
FROM #TABLE2
Demo result : http://rextester.com/VFF59681
You can use a JOIN in the UPDATE:
update t2
set t2.score = t1.score
from table2 t2 join
table1 t1
on t2.size = t1.size;
You can also follow your pattern by using a correlated subquery:
update table2
set t2.score = (select t1.score from table1 t1 where t1.size = table2.size);
There is no need for another JOIN in the subquery.
update a
set a.score=b.score
from table2 a join table1 b on a.id=b.id
You don't need to do the JOIN in subquery you can directly express it as :
update table2
set score = (select top (1) t1.score from table1 t1 where t1.size = table2.size);
You can achieve it like this:
update table2
set table2.SCORE = table1.VALUE
from table2
join table1
on table2.SIZE = table1.SIZE
However, to avoid problems, you will need to make sure table1.SIZE is unique.
I am wondering what should I use in SQL Server 2016 or 2017 (CTE, LOOP, JOINS, CURSOR, REPLACE, etc) to match (replace) every value in every row in temp table? What is the best solution from performance perspective?
Source Table
|id |id2|
| 1 | 2 |
| 2 | 1 |
| 1 | 1 |
| 2 | 2 |
Mapping Table
|id |newid|
| 1 | 3 |
| 2 | 4 |
Expected result
|id |id2|
| 3 | 4 |
| 4 | 3 |
| 3 | 3 |
| 4 | 4 |
You may join the second table to the first table twice:
WITH cte AS (
SELECT
t1.id AS id_old,
t1.id2 AS id2_old,
t2a.newid AS id_new,
t2b.newid AS id2_new
FROM table1 t1
LEFT JOIN table2 t2a
ON t1.id = t2a.id
LEFT JOIN table2 t2b
ON t1.id2 = t2b.id
)
UPDATE cte
SET
id_old = id_new,
id2_old = id2_new;
Demo
Not sure if you want just a select here, or maybe an update, or an insert into another table. In any case, the core logic I gave above should work for all these cases.
You'd need to apply joins on update query. Something like this:
Update tblA set column1 = 'something', column2 = 'something'
from actualName tblA
inner join MappingTable tblB
on tblA.ID = tblB.ID
this query will compare eachrow with ids and if matched then it will update/replace the value of the column as you desire. :)
Do the self join only
SELECT t1.id2 as id, t2.id2
FROM table1 t
INNER JOIN table2 t1 on t1.id = t.id
INNER JOIN table2 t2 on t2.id = t.id2
This may have best performance from solutions posted here if you have indexes set appropriately:
select (select [newid] from MappingTable where id = [ST].[id]) [id],
(select [newid] from MappingTable where id = [ST].[id2]) [id2]
from SourecTable [ST]
Following / copying computhomas's question, but adding some twists...
I have the following table in MSSQL2008
id | business_key | result | date
1 | 1 | 0 | 9
2 | 1 | 1 | 8
3 | 2 | 1 | 7
4 | 3 | n | 6
5 | 4 | 1 | 5
6 | 4 | 0 | 4
And now i want to group based on the business_key returning the complete entry with the newest date.
So my expected result is:
id | business_key | result | date
1 | 1 | 0 | 9
3 | 2 | 1 | 7
4 | 3 | n | 6
5 | 4 | 1 | 5
I also bet that there is a way to achieve that, i just can't find / see / think of it at the moment.
edit: sorry about this, I actually meant something else from original question I did. I felt like editing this might be better than accepting a solution and making another question. my original problem was that I am not filtering by id.
SELECT t.*
FROM
(
SELECT *, ROW_NUMBER() OVER
(
PARTITION BY [business_key]
ORDER BY [date] DESC
) AS [RowNum]
FROM yourTable
) AS t
WHERE t.[RowNum] = 1
SELECT
*
FROM
mytable
WHERE
ID IN (SELECT MAX(ID) FROM mytable GROUP BY business_key)
SELECT
MAX(T1.id) AS [id],
T1.business_key,
T1.result
FROM
dbo.My_Table T1
LEFT OUTER JOIN dbo.My_Table T2 ON
T2.business_key = T1.business_key AND
T2.id > T1.id
WHERE
T2.id IS NULL
GROUP BY T1.business_key,
T1.result
ORDER BY MAX(T1.id)
Edited based on clarifications
SELECT M1.*
FROM My_Table M1
INNER JOIN
(
SELECT [business_key], MAX([date]) as MaxDate
FROM My_Table
GROUP BY [business_key]
) M2 ON M1.business_key = M2.business_key AND M1.[date] = M2.MaxDate
ORDER BY M1.[id]
Assuming the combination of business_key & date is unique then....
Working example (3rd time is a charm):
declare #src as table(id int, business_key int,result int,[date] int)
insert into #src
SELECT 1,1,0,9
UNION SELECT 2,1,1,8
UNION SELECT 3,2,1,7
UNION SELECT 4,3,1,6
UNION SELECT 5,4,1,5
UNION SELECT 6,4,0,4
;with bkdate(business_key,[date])
AS
(
select business_key,MAX([date])
from #src
group by business_key
)
select src.* from #src src
inner join bkdate
ON src.[date] = bkdate.date
and src.business_key = bkdate.business_key
order by id
How about (edited after question change):
with latestdate as (
select business_key, maxdate=max(date)
from the_table
group by business_key
), latest as (
select ID = max(id)
from the_table
inner join latestdate
on the_table.business_key=latestdate.business_key
and the_table.date=latestdate.maxdate
group by the_table.business_key
)
select the_table.*
from the_table
inner join latest
on latest.id=the_table.id