Hope u all fine.
Actually I'm working on a Project and need to calculate daily TOTAL_SALE and TOTAL_CASH and TOTAL_CREDIT ....
Following is my Query but my Query Gives Overall SUM of Payments in TOTAL_CASH and in TOTAL_CREDIT as it has to be like this ..
+------------+------------+--------------+
| TOTAL_SALE | TOTAL_CASH | TOTAL_CREDIT |
+------------+------------+--------------+
| 1000 | 250 | 750 |
+------------+------------+--------------+
Following is my SQL Query :-
SELECT
sss.creation_date , SUM(sss.payment_due) as 'Total Sale',
(SELECT SUM(s.payment_due) FROM sale s WHERE s.payment_method LIKE '%Cash_%' AND s.shop='10'
AND s.DateNum >='20181201000000' AND s.DateNum <='20181231235959' GROUP BY s.creation_date)as 'Total Cash' ,
(SELECT SUM(ss.payment_due) FROM sale ss WHERE ss.payment_method LIKE '%cCredit_%' AND ss.shop='10'
AND ss.DateNum >='20181201000000' AND ss.DateNum <='20181231235959' GROUP BY ss.creation_date)as 'Total Credit' ,
SUM(discount) as 'Total Discount' , SUM(number_of_item_purchased) as 'Total Sold'
FROM Sale sss
WHERE sss.shop='10' AND sss.DateNum >='20181201000000' AND sss.DateNum <='20181231235959'
GROUP BY sss.creation_date
You can try below using conditional aggregation
SELECT
SUM(payment_due) as 'Total Sale',
SUM(case when payment_method LIKE '%Cash_%' then s.payment_due end) as 'Total Cash' ,
SUM(case when payment_method LIKE '%cCredit_%' then payment_due end) as 'Total Credit',
SUM(discount) as 'Total Discount' ,
SUM(number_of_item_purchased) as 'Total Sold'
FROM Sale
WHERE shop='10' AND DateNum >='20181201000000' AND DateNum <='20181231235959'
Related
So I'm running this query to get the name of the customer, total amount ordered, and number of orders they've submitted. With this query, I get their entire history from March to July, what I want is the name, march amount total/# of orders, april amount total/# of orders, may amount total/# of orders, ..... etc.
SELECT customer_name,MONTH(created_on), SUM(amount), COUNT(order_id)
FROM customer_orders
WHERE created_on BETWEEN '2020-03-01' AND '2020-08-01'
GROUP BY customer_name, MONTH(created_on)
If you want the values in separate columns, then use conditional aggregation:
SELECT customer_name,
SUM(CASE WHEN MONTH(created_on) = 3 THEN amount END) as march_amount,
SUM(CASE WHEN MONTH(created_on) = 3 THEN 1 ELSE 0 END) as march_count,
SUM(CASE WHEN MONTH(created_on) = 4 THEN amount END) as april_amount,
SUM(CASE WHEN MONTH(created_on) = 4 THEN 1 ELSE 0 END) as april_count,
. . .
FROM customer_orders
WHERE created_on >= '2020-03-01' AND
created_on < '2020-08-01'
GROUP BY customer_name;
Notice that I changed the date filter so it does not include 2020-08-01.
I am a SQL beginner, so can anyone please help me with this?
I have a table like this
YearMonth | Customer | Currency | BusinessType | Amount
04-2020 | 123 | EUR | Budget | 500
04-2020 | 123 | EUR | Forecast | 300
04-2020 | 123 | EUR | Sales | 700
And now I need it like:
YearMonth | Customer | Currency | Amount Budget | Amount Forecast | Amount Sales
04-2020 | 123 | EUR | 500 | 300 | 700
Is something like this possible?
Thanks in advance for your help!
Use conditional aggregation:
select yearmonth, customer, currency,
sum(case when businesstype = 'Budget' then amount end) as budget,
sum(case when businesstype = 'Forecast' then amount end) as forecast,
sum(case when businesstype = 'Sales' then amount end) as sales
from t
group by yearmonth, customer, currency;
You can do aggregation :
select yearmonth, customer, currency,
sum(case when businesstype = 'budget' then amount else 0 end),
sum(case when businesstype = 'Forecast' then amount else 0 end),
sum(case when businesstype = 'Sales' then amount else 0 end)
from table t
group by yearmonth, customer, currency;
Also, you may want to add an "Other" to capture any new Business Types:
select yearmonth, customer, currency,
sum(case when businesstype = 'Budget' then amount end) as budget,
sum(case when businesstype = 'Forecast' then amount end) as forecast,
sum(case when businesstype = 'Sales' then amount end) as sales,
sum(case when businesstype not in ('Budget', 'Forecast', 'Sales') then amount end) as other
from t
group by yearmonth, customer, currency;
This type of requirements are usually resolved using T-SQL PIVOT relational operation (https://learn.microsoft.com/en-us/sql/t-sql/queries/from-using-pivot-and-unpivot?view=sql-server-ver15). For the above example I used the following query to achieve this:
-- Create a temporary table to store the data.
IF (OBJECT_ID('tempdb..##temp2') IS NOT NULL) DROP TABLE ##temp2
CREATE TABLE ##temp2 (Id int IDENTITY (1,1) PRIMARY KEY, YearMonth varchar(100), Customer int, Currency varchar(100), BusinessType varchar(100), Amount int)
INSERT ##temp2
VALUES
('04-2020', 123,'EUR','Sales', 700),
('04-2020', 123,'EUR','Budget', 500),
('04-2020', 123,'EUR','Forecast', 300)
-- Using PIVOT allows you to move rows into columns
SELECT pivot_table.YearMonth,
pivot_table.Customer,
pivot_table.Currency,
[Amount Forecast] = pivot_table.Forecast,
[Amount Budget] = pivot_table.Budget,
[Amount Sales] = pivot_table.Sales
FROM
(
SELECT YearMonth,
Customer,
Currency,
BusinessType,
Amount
FROM ##temp2
) t
PIVOT
(
SUM(Amount)
FOR BusinessType IN ([Sales], [Budget], [Forecast])
) AS pivot_table;
I'm quite new to SQL querying so please go easy on me if what I've done so far is really odd :)
I have two tables - A for Income and B for Expenditure:
Business_ID Income_Desc Income_Amount
1 Income A 1000
1 Income B 3000
1 Income C 2000
Business_ID Expen_Amount
1 2500
I'd like to produce a table that shows each of the income amounts, the one expenditure amount, the total income, the total expenditure and a Grand Total of total income-total expenditure.
Something like this if possible
Business_ID Income Description Income Amount Expenditure Amount Total
1 Income A 1000 2500 -
1 Income B 3000 - -
1 Income C 2000 - -
1 All Amounts 6000 2500 3500
This is what I've tried so far
SELECT a. Business_ID, COALESCE (a.Income_Desc, 'All Amounts') AS 'Income Description', SUM(a.Income_Amount) AS 'Income Amount', SUM(b.Expen_Amount) AS Expenditure Amount', (sum(a.Income_Amount)-SUM(b.Expen_Amount)) AS 'Total'
FROM Income AS a LEFT JOIN Expenditure AS b ON a.Business_ID = b. Business_ID
GROUP BY a. Business_ID, a.Income_Desc WITH ROLLUP
The result I'm getting is this
Business_ID Income Description Income Amount Expenditure Amount Total
1 Income A 1000 2500 -1500
1 Income B 3000 2500 500
1 Income C 2000 2500 -500
1 All Amounts 6000 7500 -1500
All Amounts 6000 7500 -1500
Is it possible to get an output like the one I provided above? Could you show me how to achieve it (or something very close) please?
Thanks
You can use row_number() for the join:
with ie as (
select i.business_id, i.income_desc, i.income_amount,
e.expen_amount
from (select i.*,
row_number() over (partition by business_id order by income_desc) as seqnum
from income i
) i left join
(select e.*,
row_number() over (partition by business_id order by expen_amount) as seqnum
from expenditure e
) e
on i.business_id = e.business_id and i.seqnum = e.seqnum
)
select ie.*
from ie
union all
select business_id, 'Total', sum(income_amount), sum(expen_amount)
from ie
group by business_id;
You could make a sub query out of your original query and only select values where the business ID is not null. Furthermore, use CASE WHEN to identify those values < 0 and replace it with "-":
SELECT x.Business_ID
, x.`Income Description`
, x.`Income Amount`
, x.`Expenditure Amount`
, x.Total
FROM
(SELECT a. Business_ID
, COALESCE (a.Income_Desc, 'All Amounts') AS 'Income Description'
, SUM(a.Income_Amount) AS 'Income Amount'
, SUM(b.Expen_Amount) AS 'Expenditure Amount'
, CASE WHEN (sum(a.Income_Amount)-SUM(b.Expen_Amount)) < 0
THEN '-'
ELSE (sum(a.Income_Amount)-SUM(b.Expen_Amount))
END AS 'Total'
FROM Income AS a
LEFT JOIN Expenditure AS b ON a.Business_ID = b.Business_ID
WHERE a.Business_ID is not null and b.Business_ID is not null
GROUP BY a.Business_ID, a.Income_Desc WITH ROLLUP) as x
where x.Business_ID is not null
DB Fiddle
SQL question, making monthly and yearly sales as column:
I have two tables:
t_items (item_num, item_name, itm_qnt)
t_items_dtl (item_num, invdate, itm_qnt_out, itm_qnt_in)
Columns are:
itm_qnt = current stock
invdate = invoice date
item_qnt_out = number of sold specific item in the invoice
item_qnt_in = number of returned specific item in the invoice
I want to get the following columns:
item_num | item_name | currnt_stock | QTY sold 2018 | QTY sold:Jan2018 | Feb 2018 | March 2018 .... Dec 2018
For now I used this query but it gives me only the total sales of each item:
SELECT
i.item_num AS ItemNum,
i.item_name AS ItemName,
sum(d.itm_qnt_out-d.itm_qnt_in) AS QTOUT,
i.itm_qnt AS Stock
FROM
dbo.t_items AS i
FULL OUTER JOIN
t_items_dtl AS d ON i.item_num = d.item_num
GROUP BY
i.item_num, i.item_name, i.itm_qnt;
How can I add monthly and yearly sales by column (not rows)?
Depending on the database you are using there may be more elegant ways to get year and month from a date but bottom-line, you probably want something like:
SELECT
i.item_num AS ItemNum,
i.item_name AS ItemName,
sum(d.itm_qnt_out-d.itm_qnt_in) AS QTOUT,
sum(CASE WHEN to_char(invdate,'mm') = '01' THEN d.itm_qnt_out-d.itm_qnt_in ELSE 0 END) AS QTOUTJan,
sum(CASE WHEN to_char(invdate,'mm') = '02' THEN d.itm_qnt_out-d.itm_qnt_in ELSE 0 END) AS QTOUTFeb,
sum(CASE WHEN to_char(invdate,'mm') = '03' THEN d.itm_qnt_out-d.itm_qnt_in ELSE 0 END) AS QTOUTMar,
/*Repeat for every month*/
i.itm_qnt AS Stock
FROM
dbo.t_items AS i
FULL OUTER JOIN
t_items_dtl AS d ON i.item_num = d.item_num
WHERE to_char(invdate, 'yyyy') = '2018'
GROUP BY
i.item_num, i.item_name, i.itm_qnt;
Compared to your code, I have defined a column for each month + added a WHERE to filter the entire thing to 2018.
I am trying to get a running total for 2 stores. The query that I have gets the running total for both stores together. How can I change the query to get the running total for each store separately? Below is my query. The database can be found here.
select store_id,amount, sum(amount) over (order by rental_date)
from payment
join rental on payment.rental_id=rental.rental_id
join store on payment.customer_id=store.store_id
This is the result that I get:
store id amont sum
1 5.99 5.99
1 0.99 6.98
1 9.99 16.97
1 4.99 21.96
2 2.99 24.95
1 4.99 29.94
1 0.99 30.93
1 3.99 34.92
Use partition by store_id in
sum(amount) over (partition by store_id order by store_id, rental_date)
if you want them in different columns you do it like this
select
store_id,
amount,
sum(case when store_id = 1 then amount else 0 end) over (order by rental_date) as store1_sum,
sum(case when store_id = 2 then amount else 0 end) over (order by rental_date) as store2_sum,
from payment
join rental on payment.rental_id=rental.rental_id
join store on payment.customer_id=store.store_id
for different rows you can partition as #BarbarosÖzhan