Im new to DB2 , and tried based on some similar posts, I have a table where I need to find the count of IDs based on where status=P and
the count of(primary=1) more than once.
so my result should be 2 here - (9876,3456)
Tried:
SELECT id, COUNT(isprimary) Counts
FROM table
GROUP BY id
HAVING COUNT(isprimary)=1;
Try the query below:
select ID as IDs,Count(isPrimary) as isPrimary
From Table
where Status = 'p'
Group by ID
Having Count(isPrimary) >1
You are close, I think all you need to do is to add a where clause like:
SELECT id, COUNT(*) as Counted
FROM table
WHERE PrimaryFlag = 1
AND[status] = 'P'
GROUP BY id
EDIT: if you need to count only the distinct IDs, then try:
SELECT COUNT(t.ID) FROM
(
SELECT id, COUNT(*) as Counted
FROM table
WHERE PrimaryFlag = 1
AND[status] = 'P'
GROUP BY id
) as t
Related
Given the following table where the Name value might be repeated in multiple rows:
How can we determine how many times a Name value exists in the table and can we filter on names that have a specific number of occurrances.
For instance, how can I filter this table to show only names that appear twice?
You can use group by and having to exhibit names that appear twice in the table:
select name, count(*) cnt
from mytable
group by name
having count(*) = 2
Then if you want the overall count of names that appear twice, you can add another level of aggregation:
select count(*) cnt
from (
select name
from mytable
group by name
having count(*) = 2
) t
It sounds like you're looking for a histogram of the frequency of name counts. Something like this
with counts_cte(name, cnt) as (
select name, count(*)
from mytable
group by name)
select cnt, count(*) num_names
from counts_cte
group by cnt
order by 2 desc;
You need to use a GROUP BY clause to find counts of name repeated as
select name, count(*) AS Repeated
from Your_Table_Name
group by name;
If You want to show only those Which are repeated more than one times. Then use the below query which will show those occurrences which are there more than one times.
select name, count(*) AS Repeated
from Your_Table_Name
group by name having count(*) > 1;
I am looking to query my Access database from Excel (DAO) to determine if any name in the table has more than one record per date. E.g. If Bob has two records on 05/05/17 then I want to return both records as part of a recordset.
Seems like you are looking for something like:
SELECT *
FROM yourtable
INNER JOIN
(
SELECT count(*), name, date
FROM yourtable
GROUP BY name, date
HAVING COUNT(*) > 1
) multi
ON multi.name = yourtable.name
AND multi.date = yourtable.date
The inner select returns rows with more than 1 entry for the same name and date.
In Access you can do
select name, date
from your_table
group by name, date
having count(*) > 1
I've had a search around and have seen quite a few questions about selecting distinct values, but none of them seem close enough to my query to be able to help. This is the scenario
ID Product_ID Product_type
123 56789 A
123 78901 B
456 12345 A
789 45612 B
The SQL I need would be to search in a table similar to the above, and bring back the rows where the Product_type is B but only if the ID related to it exists once within the table.
So in this case it would bring back only
789 45612 B
The SQL I have tried based on what I've found so far was
SELECT DISTINCT(ID)
FROM "TABLE"
WHERE "PRODUCT_TYPE" = 'B'
As well as
SELECT *
FROM "TABLE"
WHERE "PRODUCT_TYPE" = 'B'
GROUP BY "ID"
HAVING COUNT(ID) = 1
And neither have worked
One way via a list of IDs appearing once:
select * from T where Product_type = 'B' and id in (
select id from T
group by id
having count(id) = 1)
Soltuion 1: Use a sub-query to count id's.
select * from table t1
where Product_type = 'B'
and (select count(*) from table
where id = t1.id) = 1
You can use group by for this type of query. However, you cannot filter down to the 'B's before the aggregation.
So, try this:
SELECT t.id, MAX(t.product_id) as product_id,
MAX(t.product_type) as product_type
FROM "TABLE" t
GROUP BY "ID"
HAVING COUNT(*) = 1 AND
MAX(PRODUCT_TYPE) = 'B';
This may look a little bit arcane. But the having clause is guaranteeing that there is only one row and that row has a 'B'. Hence the MAX() functions are returning the max from that one row -- which is the value on that row.
EDIT:
Many databases will also allow you to take advantage of window functions for this:
select t.*
from (select t.*, count(*) over (partition by id) as id_cnt
from table t
) t
where t.product_type = 'B' and id_cnt = 1;
The following query returns the results that I need but I have to add the ID of the row to then update it. If I add the ID directly in the select statement it will return me more results then I need because each ID is unique so the DISTINCT statement see the line as unique.
SELECT DISTINCT ucpse.MemberID, ucpse.ProductID, ucpse.UserID
FROM UserCustomerProductSalaryExceptions as ucpse
WHERE EXISTS (SELECT NULL
FROM UserCustomerProductSalaryExceptions as upcse2
WHERE ucpse.userid = upcse2.userid AND ucpse.MemberID = upcse2.MemberID AND ucpse.ProductID = upcse2.ProductID
GROUP BY upcse2.UserID, upcse2.memberid, upcse2.productid
HAVING COUNT(UserID) >= 2
)
So basically I need to add ucpse.ID in the Select statement while keeping DISTINCT values for MemberID,ProductID and UserID.
Any Ideas ?
Thank you
According to you comment:
If the data has been duplicated 67 times for a given employee with a given product and a given client, I need to keep only one of thoses records. It's not important which one, so this is why I use DISTINC to obtain unique combinaison of given employee with a given product and a given client.
You can use MIN() or MAX() and GROUP BY instead of DISTINCT
SELECT MAX(ucpse.ID) AS ID, ucpse.MemberID, ucpse.ProductID, ucpse.UserID
FROM UserCustomerProductSalaryExceptions as ucpse
WHERE EXISTS (SELECT NULL
FROM UserCustomerProductSalaryExceptions as upcse2
WHERE ucpse.userid = upcse2.userid AND ucpse.MemberID = upcse2.MemberID AND ucpse.ProductID = upcse2.ProductID
GROUP BY upcse2.UserID, upcse2.memberid, upcse2.productid
HAVING COUNT(UserID) >= 2
)
GROUP BY ucpse.MemberID, ucpse.ProductID, ucpse.UserID
UPDATE:
From you comments I think the below query is what you need
DELETE FROM UserCustomerProductSalaryExceptions
WHERE ID NOT IN ( SELECT MAX(ucpse.ID) AS ID
FROM #UserCustomerProductSalaryExceptions
GROUP BY ucpse.MemberID, ucpse.ProductID, ucpse.UserID
HAVING COUNT(ucpse.ID) >= 2
)
If all you want is to delete the duplicates, this will do it:
WITH X AS
(SELECT ID,
ROW_NUMBER() OVER (PARTITION BY MemberID, ProductID, UserID ORDER BY ID) AS DupRowNum<br
FROM UserCustomerProductSalaryExceptions
)
DELETE X WHERE DupRowNum > 1
ID's not necessary - try:
UPDATE uu SET
<your settings here>
FROM UserCustomerProductSalaryExceptions uu
JOIN ( <paste your entire query above here>
) uc ON uc.MemberID=uu.MemberId AND uc.ProductID=uu.ProductId AND uc.UserID=uu.UserId
From the sound of your data structure (which I would STRONGLY advise normalizing as soon as possible), it sounds like you should be updating all the records. It sounds as if each duplicate is important because it contains some information about an employee's relation to a customer or product.
I would probably update all the records. Try this:
UPDATE UCPSE
SET
--Do your updates here
FROM UserCustomerProductSalaryExceptions as ucpse
JOIN
(
SELECT UserID, MemberID, ProductID
FROM UserCustomerProductSalaryExceptions
GROUP BY UserID, MemberID, ProductID
HAVING COUNT(UserID) >= 2
) T
ON ucpse.UserID = T.UserID AND ucpse.MemberID = T.MemberID AND ucpse.ProductID = T.ProductID
Basically my select statement returns below:
ID Status
100 1
100 2
101 1
What i'm looking for is to return if a ID having status as 1 and if the same ID has another status ID as 2 then exclude both
In Short results as below:
ID Status
101 1
Thanks in advance !
The following query returns ID values that occur only once.
SELECT ID
FROM t
GROUP BY ID
HAVING COUNT(*) = 1
It should be sufficient for the sample data you provided. If there are other cases then let me know.
SQL Fiddle
You gonna need subquery and NOT IN here.
The following would work if you have column status as INT datatype
SELECT *
FROM table
WHERE status = 1
AND ID NOT IN (
SELECT ID
FROM table
WHERE status = 2
);
Making a generic query, which will remove all duplicated rows, not only for a particular ID :
select ID
from table where ID NOT IN
(select ID from table GROUP BY ID HAVING count(Status) > 1)
/* Subquery will fetch ID's having multiple entries*/
SQL Fiddle
The CTE 'IDs' retrieves all IDs which have single record in DB. This is then joined to original table to return the result as a pair (ID, Status)
;with IDs as
(
select ID
from yourtable
group by ID
having count(*) = 1
)
select i.ID, y.Status
from yourtable y
inner join IDs i on y.ID = i.ID
order by i.ID