How to select wanted column from select query based on condition - sql

Question

I have select query which returns
id ,name ,description ,price
Im trying to get id,price alone based on condition it should display name ,description
#show =1
select id ,name,if #show = 1 begin name ,description, end ,price from tbl
Thanks

Answer 1

#show =1
if #show = 1
begin
select id, name, description, price from tbl
end
else begin
select id, price from tbl
end

Answer 2

You can join the columns you want and execute the query.
DECLARE #filter AS Integer
DECLARE #columns AS nvarchar(50)
DECLARE #sql AS nvarchar(50)
Set #filter = 1
if #filter = 0
begin
Set #columns = 'id, name, description, price'
end
else begin
Set #columns = 'id, name'
end
set #sql = 'select ' + #columns + ' from tbl'
EXECUTE sp_executesql #sql
print #sql

Answer 3

Based on your comment
i pass show parameter as 0 or 1,if 0 only have to select id , price if i pass 1 it select all 4 column
CREATE PROCEDURE MyProc
#Show BIT = 1 --i pass show parameter as 0 or 1 That means BIT Datatype(True/False)
AS
IF #Show = 0
SELECT ID, Price --if 0 only have to select id , price
FROM Table
ELSE
SELECT * --if i pass 1 it select all 4 column
FROM Table

Answer 4

Your all answer helped me a lot,thanks.
finally i went this method works on string concat
fields are id,name,description,price
declare #id int;
declare #sqlcommand nvarchar(max) ;
declare #visible int ;
set #sqlcommand = 'select id ,'+case when #visible = 1 then 'name ,description' else '' end +',price from tbl
where id = #id'
execute sp_executesql #sqlCommand ,N'#id int',#id=#id
if i pass visible = 1
result will be
id name desc price
visible = 0
id price
Thanks