I have a data set that lists an employee id, code, hours and wages. Any 1 employee can have 1 of either OT1 or OT2, or they could have 1 row of both. The short of it is that I need to sum all of the wages, but if they have both codes to just take the amount for OT1. Then I want to divide total wages by the hours in the condition I stated. Example Data:
+ -------+------+-------+--------+
| ID | CODE | HOURS | AMOUNT |
+ -------+------+-------+--------+
| 123456 | OT1 | 10 | 80 |
| 789000 | OT1 | 8 | 120 |
| 789000 | OT2 | 8 | 60 |
| 654111 | OT2 | 4 | 40 |
+ -------+------+-------+--------+
I'm attempting to add a new column to divide the amount by the hours and will remove the code column so we can sum each employee to have a single record. The catch is, if the employee has both OT1 and OT2, I don't want to sum those , I just want the hours from OT1. That logic manually applied to my previous example
+ -------+-------+--------+---------+
| ID | HOURS | AMOUNT | AVERAGE |
+ -------+-------+--------+---------+
| 123456 | 10 | 80 | 8 |
| 789000 | 8 | 180 | 22.5 |
| 654111 | 4 | 40 | 10 |
+ -------+-------+--------+---------+
You can do this using conditional aggregation:
select id,
coalesce(sum(case when code = 'OT1' then hours end),
sum(hours)
) as hours,
sum(amount) as amount,
(sum(amount) /
coalesce(sum(case when code = 'OT1' then hours end),
sum(hours)
)
) as average
from t
group by id
order by id;
This method explicitly combines values from multiple rows, so it should work as expected if there are duplicates.
You get the hours for the first code with Oracle's KEEP FIRST:
select
id,
min(hours) keep (dense_rank first order by code) as hours,
sum(amount) as amount,
round(sum(amount) / min(hours) keep (dense_rank first order by code), 2) as average
from mytable
group by id
order by id;
Related
I have a Teradata query that generates:
customer | order | amount | days_ago
123 | 1 | 50 | 2
123 | 1 | 50 | 7
123 | 2 | 10 | 19
123 | 3 | 100 | 35
234 | 4 | 20 | 20
234 | 5 | 10 | 10
With performance in mind, what’s the most efficient way to produce an output per customer where orders is the number of distinct orders a customer had within the last 30 days and total is the sum of the amount of the distinct orders regardless of how many days ago the order was placed?
Desired output:
customer | orders | total
123 | 2 | 160
234 | 2 | 30
Given your rules, maybe it takes two steps - de-duplicate first then aggregate:
SELECT customer,
SUM(CASE WHEN days_ago <=30 THEN 1 ELSE 0 END) AS orders,
SUM(amount) AS total
FROM
(SELECT customer, order, MAX-or-MIN(amount) AS amount, MIN-or-MAX(days_ago) AS days_ago
FROM your_relation
GROUP BY 1, 2) AS DistinctCustOrder
GROUP BY 1;
Apologies for the confusing title, I was unsure how to phrase it.
Below is my dataset:
+----+-----------------------------+--------+
| Id | Date | Amount |
+----+-----------------------------+--------+
| 1 | 2019-02-01 12:14:08.8056282 | 10 |
| 1 | 2019-02-04 15:23:21.3258719 | 10 |
| 1 | 2019-02-06 17:29:16.9267440 | 15 |
| 1 | 2019-02-08 14:18:14.9710497 | 10 |
+----+-----------------------------+--------+
It is an example of a bank trying to collect money from a debtor, where first, 10% of the owed sum is attempted to be collected, if a card is managed to be charged 15% is attempted, if that throws an error (for example insufficient funds), 10% is attempted again.
The desired output would be:
+----+--------+---------+
| Id | Amount | Attempt |
+----+--------+---------+
| 1 | 10 | 1 |
| 1 | 15 | 2 |
| 1 | 10 | 3 |
+----+--------+---------+
I have tried:
SELECT Id, Amount
FROM table1
GROUP BY Id, Amount
I am struggling to create a new column based on when value changes in the Amount column as I assume that could be used as another grouping variable that could fix this.
If you just want when a value changes, use lag():
select t.id, t.amount,
row_number() over (partition by id order by date) as attempt
from (select t.*, lag(amount) over (partition by id order by date) as prev_amount
from table1 t
) t
where prev_amount is null or prev_amount <> amount
Here is an example the business problem.
I have 10 sales that resulted in negative margin.
We want to review these records, we generally use the 20/80 rule in reviews.
That is 20 percent of the sales will likely represent 80 of the negative margin.
So with the below records....
+----+-------+
| ID | Value |
+----+-------+
| 1 | 30 |
| 2 | 30 |
| 3 | 20 |
| 4 | 10 |
| 5 | 5 |
| 6 | 5 |
| 7 | 2 |
| 8 | 2 |
| 9 | 1 |
| 10 | 1 |
+----+-------+
I would want to return...
+----+-------+
| ID | Value |
+----+-------+
| 1 | 30 |
| 2 | 30 |
| 3 | 20 |
| 4 | 10 |
+----+-------+
The Total of Value is 106, 80% is then 84.8.
I need all the records, sorted descending who sum value gets me to at least 84.8
We use Microsoft APS PDW SQL, but can process on SMP if needed.
Assuming window functions are supported, you can use
with cte as (select id,value
,sum(value) over(order by value desc,id) as running_sum
,sum(value) over() as total
from tbl
)
select id,value from cte where running_sum < total*0.8
union all
select top 1 id,value from cte where running_sum >= total*0.8 order by value desc
One way is to use running totals:
select
id,
value
from
(
select
id,
value,
sum(value) over () as total,
sum(value) over (order by value desc) as till_here,
sum(value) over (order by value desc rows between unbounded preceding and 1 preceding)
as till_prev
from mytable
) summed_up
where till_here * 1.0 / total <= 0.8
or (till_here * 1.0 / total >= 0.8 and coalesce(till_prev, 0) * 1.0 / total < 0.8)
order by value desc;
This link could be useful, it calculates running totals:
https://www.codeproject.com/Articles/300785/Calculating-simple-running-totals-in-SQL-Server
I have a table supplier_account which has five coloumns supplier_account_id(pk),supplier_id(fk),voucher_no,debit and credit. I want to get the sum of debit grouped by supplier_id and then subtract the value of credit of the rows in which voucher_no is not null. So for each subsequent rows the value of sum of debit gets reduced. I have tried using 'with' clause.
with debitdetails as(
select supplier_id,sum(debit) as amt
from supplier_account group by supplier_id
)
select acs.supplier_id,s.supplier_name,acs.purchase_voucher_no,acs.purchase_voucher_date,dd.amt-acs.credit as amount
from supplier_account acs
left join supplier s on acs.supplier_id=s.supplier_id
left join debitdetails dd on acs.supplier_id=dd.supplier_id
where voucher_no is not null
But here the debit value will be same for all rows. After subtraction in the first row I want to get the result in second row and subtract the next credit value from that.
I know it is possible by using temporary tables. The problem is I cannot use temporary tables because the procedure is used to generate reports using Jasper Reports.
What you need is an implementation of the running total. The easiest way to do it with a help of a window function:
with debitdetails as(
select id,sum(debit) as amt
from suppliers group by id
)
select s.id, purchase_voucher_no, dd.amt, s.credit,
dd.amt - sum(s.credit) over (partition by s.id order by purchase_voucher_no asc)
from suppliers s
left join debitdetails dd on s.id=dd.id
order by s.id, purchase_voucher_no
SQL Fiddle
Results:
| id | purchase_voucher_no | amt | credit | ?column? |
|----|---------------------|-----|--------|----------|
| 1 | 1 | 43 | 5 | 38 |
| 1 | 2 | 43 | 18 | 20 |
| 1 | 3 | 43 | 8 | 12 |
| 2 | 4 | 60 | 5 | 55 |
| 2 | 5 | 60 | 15 | 40 |
| 2 | 6 | 60 | 30 | 10 |
Suppose that I have a table name as tblTemp which has data as below:
| ID | AMOUNT |
----------------
| 1 | 10 |
| 1-1 | 20 |
| 1-2 | 30 |
| 1-3 | 40 |
| 2 | 50 |
| 3 | 60 |
| 4 | 70 |
| 4-1 | 80 |
| 5 | 90 |
| 6 | 100 |
ID will be format as X (without dash) if it's only one ID or (X-Y) format if new ID (Y) is child of (X).
I want to add a new column (Total Amount) to output as below:
| ID | AMOUNT | Total Amount |
---------------------------------
| 1 | 10 | 100 |
| 1-1 | 20 | 100 |
| 1-2 | 30 | 100 |
| 1-3 | 40 | 100 |
| 2 | 50 | 50 |
| 3 | 60 | 60 |
| 4 | 70 | 150 |
| 4-1 | 80 | 150 |
| 5 | 90 | 90 |
| 6 | 100 | 100 |
The "Total Amount" column is the calculate column which sum value in Amount column that the (X) in ID column is the same.
In order to get parent ID (X), I use the following SQL:
SELECT
ID, SUBSTRING (ID, 1,
IIF (CHARINDEX('-', ID) = 0,
len(ID),
CHARINDEX('-', ID) - 1)
), Amount
FROM
tblTemp
How Can I query like this in SQL Server 2012?
You can use sqlfiddle here to test it.
Thank You
Pengan
You have already done most of the work. To get the final result you can use your existing query and make it a subquery or use a CTE, then use sum() over() to get the result:
;with cte as
(
SELECT
ID,
SUBSTRING (ID, 1,
IIF (CHARINDEX('-', ID) = 0,
len(ID),
CHARINDEX('-', ID) - 1)
) id_val, Amount
FROM tblTemp
)
select id, amount, sum(amount) over(partition by id_val) total
from cte
See SQL Fiddle with Demo
You can do this using the sum() window function:
select id, amount,
SUM(amount) over (partition by (case when id like '%-%'
then left (id, charindex('-', id) - 1)
else id
end)
) as TotalAmount
from tblTemp t