awk - writing values from file - awk

Question

How to write in awk a script that will write 10 values from the input file plase? Thank you.
I tried this:
BEGIN
$2 == 0 && $3 == 2 { print $7}
$2 == 0 && $3 == 4 { print $7}
$2 == 0 && $3 == 5 { print $7}
$2 == 2 && $3 == 2 { print $7}
$2 == 2 && $3 == 4 { print $7}
$2 == 2 && $3 == 5 { print $7}
$2 == 3 && $3 == 2 { print $7}
$2 == 3 && $3 == 4 { print $7}
$2 == 3 && $3 == 5 { print $7}
$1 == "achil" { print $3}
Should I write everything in one row?
When is it necessary to write BEGIN in code and when not?
Input file is:
achil 1 197524.72437205614 197524.72437205614 0.43066284286002637
o 0 1 0 1 1 5.732821000
o 0 2 0 1 1 54002.804084586
o 0 3 0 1 1 0.088300000
o 0 4 0 1 1 150.924210421
o 0 5 0 1 1 108.520740945
o 0 6 0 1 1 0.380000000
o 0 7 0 1 1 0.004220000
o 0 8 0 1 1 0.000000000
o 0 9 0 1 1 0.000000000
o 0 10 0 1 1 0.000000000
o 0 11 0 1 1 0.000000000
o 2 1 0 1 1 73413.000000000
o 2 2 0 1 1 36176.166543543
o 2 3 0 1 1 0.560000000
o 2 4 0 1 1 229.480202654
o 2 5 0 1 1 7.032947038
o 2 6 0 1 1 0.480000000
o 2 7 0 1 1 0.000000000
o 2 8 0 1 1 0.000000000
o 2 9 0 1 1 0.000000000
o 2 10 0 1 1 0.000000000
o 2 11 0 1 1 0.000000000
o 3 1 0 1 1 365.256360000
o 3 2 0 1 1 51550.294729034
o 3 3 0 1 1 0.016710220
o 3 4 0 1 1 299.430719769
o 3 5 0 1 1 0.001070537
o 3 6 0 1 1 0.000036626
o 3 7 0 1 1 0.000009111
o 3 8 0 1 1 0.000000000
o 3 9 0 1 1 0.000000000
o 3 10 0 1 1 0.000000000
o 3 11 0 1 1 0.000000000
I would like an output consisting of these 10 numbers:
197524.72437205614
54002.804084586
150.924210421
108.520740945
36176.166543543
229.480202654
7.032947038
51550.294729034
299.430719769
0.001070537

Answer 1

The script you have is just about right, but you don't need the BEGIN clause when using it as a script. Because any actions you include in the BEGIN clause gets executed before any of the input lines are processed. For example consider a case when you had to print a title for your output, you can just print it as
BEGIN { print "my-title-string-in-double quotes" }
Writing it one line or in multiple lines is purely a matter of style and what you have looks neat and much readable. So all you need to do now is define a awk script with content as
#!/usr/bin/awk -f
$2 == 0 && $3 == 2 { print $7}
$2 == 0 && $3 == 4 { print $7}
$2 == 0 && $3 == 5 { print $7}
$2 == 2 && $3 == 2 { print $7}
$2 == 2 && $3 == 4 { print $7}
$2 == 2 && $3 == 5 { print $7}
$2 == 3 && $3 == 2 { print $7}
$2 == 3 && $3 == 4 { print $7}
$2 == 3 && $3 == 5 { print $7}
$1 == "achil" { print $3}
Add execute permissions to it,
chmod +x script.awk
and run it as
awk -f script.awk input-file
But that said, your conditions could very well simply be written using pattern matching operators as
$2 ~ /^(0|2|3)$/ && $3 ~ /^(2|4|5)$/ { print $7; next } $1 == "achil" { print $3 }